Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Blue colouredpseudonitrolis formedfromnitrous acidand what

Answer»

`CH_(3) - NO_(2)`
`CH_(3) - UNDERSET(NO_(2))underset(|)(CH) - CH_(3)`
`C_(2)H_(5) - NO_(2)`
`(CH_(3))_(2) - NO_(2)`

Solution :Secondary nitroalkanegive bluecolouredpseudonitoralwith`HNO_(2)`
2.

Blue coloured compound are obtained when

Answer»

`Fe^(2+)` ion REACT with potassium ferriyanide
`Fe^(3+)` ion react with potassium FERROCYANIDE
`Fe^(3+)` ion react with potassium ferriyanide
`Fe^(2+)` ion react with potassium ferroyanide

Answer :a,B
3.

Blue coloured compound is obtained when :

Answer»

`Fe^(2+)` ions react with POTASSIUM ferrocyanide
`Fe^(3+)` ions react with potassium ferrocyanide
`Fe^(3+0` ions react with potassium ferrocyanide
`Fe^(3+)` ions react with potassium sulphocyanide .

SOLUTION :`4FeCl_3 + underset("Pot. Ferrocyanide")(3K_4[Fe(CN)_6]) to underset("Deep blue colouration")(Fe_4[Fe(CN)_6]) + 12 KCl `
4.

Blue colour/ precipitate will be obtained when K_4[Fe(CN)_6] reacts with :

Answer»

Fe(II) IONS
CU(II) ions
Fe(III) ions
Cu(I) ions

Answer :C
5.

Blue colour of the sky is due to

Answer»

SCATTERING of blue LIGHT by DUST particles
Scattering of blue light by water
scattering of blue light by dust particles and water
None of the above

Answer :C
6.

Blue colour of copper sulphate is slowly discharged when an iron rod is dipped into it. Explain this by calculating DeltaG^(@)with the help of the following data : [E_(Cu^(2+)//Cu)^(@) = 0.34 V, E_(Fe^(2+)//Fe)^(@) = -0.44 V and 1 Faraday = 96500 C mol^(-1)]

Answer»

Solution :`E_("cell")^(@) = E_("Cu^(2+)//Cu)^(@) - E_(Fe^(2+)//Fe)^(@) = +0.34 V - (-0.44 V) = +0.78 V`
We have the equation
`DeltaG^(@) =-nFE_("cell")^(@) = -2 xx 96500 C MOL^(-1) xx 0.78 V = -19301 J mol^(-1) = -19.3 kJ mol^(-1)`
As the value of `DeltaG^(@)`is NEGATIVE, the reaction will take PLACE. That means BLUE colour of copper sulphate is slowly discharged.
7.

Blue colour of 'C' is due to the formation of

Answer»

`Mn^(+2)`
`CrO_(5)`
`I_(2)`
`H_(2)TiO_(4)`

Solution :`H_(2)TiO_(4)` (Yellow Colour) (A)
8.

Blue borax bead is obtained with

Answer»

Zn
COBALT
Chromium
Fe

Solution :`CoO+B_(2)O_(3) OVERSET(HEAT)tounderset("Cobalt metaborate (blue)")(Co(CO_(2))_(2)`
9.

Blow holes of steel are removed by adding:

Answer»

C
Ni
Sand
Spiegeleisen

Answer :D
10.

Blood transports:

Answer»

Oxygen
CARBON dioxide
Oxygen and carbon dioxide
None of the above

Answer :C
11.

Blood sugar is the same as,

Answer»

Fructose
Galactose
GLUCOSE
GLYCOGEN

ANSWER :C
12.

Blood sugar is the same as

Answer»

Glucose
Galactose
GLYCOGEN
FRUCTOSE

ANSWER :A
13.

Blood red colour solution is produced when ferric chloride solution is treated with:

Answer»

`KCN`
`KSCN`
`KCNO`
`K_3[Fe(CN)_6]`

ANSWER :B
14.

Bloodsugar is thesame as …….. .

Answer»

GLUCOSE
GALACTOSE
GLYCOGEN
FRUTOSE

ANSWER :D
15.

Blood sugar and grape sugar are respectively

Answer»

GLUCOSE, FRUCTOSE
fructose, glucose
glucose ( of both )
fructose (of both)

ANSWER :C
16.

Blood protein is

Answer»

Albumin
Haemoglobin
Both (a) and (B)
None

Answer :C
17.

Blood is a colloidal solution of water containing

Answer»

LIQUID fat as dispersed phase
Albuminoid as dispersed phase
BUTTER as dispersed phase
Proteins as dispersed phase

Answer :B
18.

Blood is:

Answer»

STRONG acidic
Strongly basic
Neutral
Slightly basic

Answer :D
19.

Blood is isotonic with

Answer»

`0.16 M NACL`
CONC. NaCl
`50% NaCl`
`30% NaCl`

ANSWER :A
20.

Blood has not bee synthesized in the laboratory so far. Therefore, we always depend on the supply of human blood to save the life of patients. To meet the ever increasing demand of human blood, blood donation camps are organised in schools/colleges and other organisations dedicated to social work. to meet the challenge of short supply of human blood, chemists have been making efforts to find out some substitutes for human blood which can atleast supply enough oxygen to save the life of patients. theiir efferts have resulted in the discovery of such chemicals called blood extenders. these compounds have been used to treat premature babies, whose lungs are often under developed. (i) What is the composition of blood extenders? (ii)Discuss the mode of their action.

Answer»

Solution :(i) Blood EXTENDERS are perfluorocarbons such as perfluorodecalin.
(ii) Blood extenders DISSOLVE gases like `O_(2)` and `CO_(2)` and thus serve as temporary SUBSTITUTES for haemoglobin-the oxygen carrying protein in blood.
21.

Blood has been found to be isotonic with :

Answer»

Normal SALINE SOLUTION
SATURATED NaCl solution
Saturated KCL solution
Staurated solutionof a 1 : 1 mixture of NaCl and KCl

Answer :A
22.

Blood haemoglobin contains the metal

Answer»

Al
Mg
Cu
Fe

Answer :D
23.

Blood haemoglobin contains:

Answer»

Al
Mg
Cu
Fe

Answer :C
24.

Blood clots due to :

Answer»

RBC
WBC
Platelets
Globulins

Answer :C
25.

Blood cells retain their normal shapes in solutions which are :

Answer»

Isotonic to blood
HYPOTONIC to blood
Hypertonic to blood
Isoelectronic to blood

ANSWER :A
26.

Blood cells do not shrink in blood because blood is :

Answer»

Hypotonic
Isotonic
Equimolar
Hypertonic.

Answer :B
27.

Blood cells are isotonic with 0.9% sodium chloride solution. What happens if we place blood cells in a solution containing. (a) 1.2% sodium chloride solution? (b) 0.4% sodium chloride solution.

Answer»

Solution :(II) (a) exosmosis TAKES place RESULTING in shrinking of cells (B) endosmosis takes place resulting in swelling of cells.
28.

Blood cells are isotonic with 0.9% sodium chloride solution. What happens if we palace blood cells in a solution containing 1.2% sodium chloride solution (ii) 0.4% soldium chloride solution

Answer»

SOLUTION :(i) BLOOD CELLS shring (II) Blood cells SWELL.
29.

Blood calcium level can be increased by the administration of

Answer»

GLUCOGON
calcitionin
thyroxine
paratharmone

ANSWER :D
30.

Blood calcium level can be increased by the admiistration of

Answer»

Glucogon
Calcitonin
Thyroxine
Parathormone

Answer :D
31.

Blocks of magnesium metal are often strapped to the steel hulls of ocean going ships in order to :

Answer»

Provide cathodic protection
Protect OXIDATION of steel
Both (a) and (b) correct
Neither (a) nor (b) is correct

Answer :C
32.

Blister Cu is about :

Answer»

60% CU
98% Cu
90% Cu
100% Cu

Answer :C
33.

Blistered copper is………………

Answer»

98% PURE COPPER
96% pure copper
97% pure copper
88% pure copper

Answer :A
34.

Blister copper obtained during extraction from cuprous oxide is called so because

Answer»

it has blister like eruptions due to evolution of GAS.
it has a shining SURFACE like blister
it is the most impure FORM of copper
its surface is uneven due to different thickness at different places.

Solution :Solified copper obtained is called blister copper since it has BLISTERED appearance due to the evolution of sulphur DIOXIDE gas.
`2Cu_(2)O + Cu_(2)S to 6Cu + SO_(2)`
35.

Blister copper is refined by stirring moltem impure metal with green logs of wood because such a wood liberated hydrocarbon gases like (CH_(4)). The process X is called _____ and the Metal contains impurity of Y is ____:

Answer»

X = POLING, `Y=cuO_(2)`
X = CUPELLATION, `Y=CuO`
X = cupellation, `Y=ZnO`
X = poling, `Y=Cu_(2)O`

ANSWER :D
36.

Blister copper is obtained by:

Answer»

Bessemerisation
Roasting
poling
Refining

Answer :A
37.

Blister copper is :

Answer»

Pure COPPER
ALLOY of copper
Copper CONTAINING some impurity
ORE of copper

Answer :C
38.

Blister copper is ________.

Answer»

99% PURE copper
99.95% pure copper
99.99% pure copper
99.95-99.99% pure copper

Answer :A
39.

Bleeding of blood is stopped due to

Answer»

the COAGULATION of BLOOD by appplying `FeCl_3` and blood vessel is SEALED 
the coagulation of blood by applying Alum and blood vessel is sealed 
blood COMBINES with the `FeCl_3`
blood combines with Alum 

Solution :Blood is -ve COLLOID coagulated by adding alum (or) `FeCl_3`
40.

Bleeding is stopped by the application of ferric chloride. This is because ...

Answer»

ferric chloride SEAL the blood CELLS
blood starts FLOWING in ohter DIRECTION
blood is coagulated and blood vessel is sealed
blood is peptised

Solution : blood is coagulated and blood vessel is sealed
41.

Bleeding gums are caused by deficiency of :

Answer»

Thiamine
Ascorbic acid
Folic acid
Vitamin E

Answer :B
42.

Bleeding due to a cut can be stopped by applying ferric chloride solution in the laboratory. This is due to

Answer»

COAGULATION of NEGATIVELY charged blood particles by`Fe^(3+)` ions
Coagulation of positively charged blood particles byClior
Reaction taking PLACE between ferric ions and the haemoglobin forming a complex
Common element, iron, in both FeCl3 and haemoglobin

Solution :The colloidal blood particles are negatively charged which are coagulated by `Fe^(3+)`ions and the bleeding of the cut stops.
43.

Bleching powder is used as

Answer»

Oxidisingagnet
bleaching agent
Chlorinating agent
All the above

Solution :Bleaching POWDER slowly LOSES its ACTIVITY when it STANDS in air. This is DUE to loss of avaialable chlorine
44.

Bleaching powder when treated with excessof dil. H_(2) SO_(4) liberates

Answer»

`Cl_(2)`
`O_(2)`
both `O_(2)` and `Cl_(2)`
NONE

ANSWER :A
45.

Bleaching properties of bleaching powder are due to its:

Answer»

OXIDISING properties
Reducing properties
Basic properties
Disinfecting properties

Answer :A
46.

Bleaching powder reacts with insufficient dilute acids the gas liberated is

Answer»

`Cl_(2)`<BR>`O_(2)`
`Br_(2)`
`I_(2)`

ANSWER :B
47.

Bleaching powder slowly loses its activity when it stands in air. This is due to:

Answer»

REACTION with moisture to liberate `O_2`
Reaction with `CO_2` to evolve `Cl_2`
LOSS of `CaCl_2`
Formation of `CA(OH)_2`

Answer :B
48.

Bleaching powder slowly loses its activity when its stand in air. This is due to

Answer»

reaction with water to EVOLVE `O_(2)`
reaction with `H_(2)O` to evolve `H_(2)`
Due to DISPROPORTIONATION
formation of clacium hydroxide

Answer :C
49.

Bleaching powder slowly decomposes to form

Answer»

`CaCl_(2) and CA(ClO_(3))`
`CAO and Cl_(2)`
`CaCl_(2) and Ca(OCl)_(2)`
`CaCO_(3) and Cl_(2)`

ANSWER :A
50.

Bleaching powder on standing forms mixture of:

Answer»

`CAO + Cl_2`
`HOCL + Cl_2`
`CaCl_2 + Ca(ClO_3)_2`
`CaO + CaCl_2`

Answer :C