This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Aniline reacts with carbonyl chloride and forms : |
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Answer» CHLORO benzene
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| 2. |
Aniline reacts with bromine water to give a white precipitate. Give the chemical formula of the white precipitate formed in the above reaction. |
Answer» SOLUTION :WHITE PRECIPITATE FORMED is 2,4,6- TRIBROMOANILINE.
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| 3. |
Aniline reacts with bromine water to give a white precipitate. Write the chemical reaction involved. |
Answer» SOLUTION :
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| 4. |
Aniline reacts with bromine in acetic acid to give a white solid compound. The number of bromine atoms present in compound is |
Answer»
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| 5. |
Aniline reacts with Br_(2) in acetic acid to give |
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Answer»
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| 6. |
Aniline reacts with Br_2"/"H_2O to give a tribromo derivative. How would you convert aniline to get a monobromo derivate? |
Answer» SOLUTION :To GET mono bromo compounds, `-NH_2` is first acylated to REDUCE its activity.
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| 7. |
Aniline reacts with alkyl halide to give |
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Answer» Amino compound |
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| 8. |
Aniline reacts with benzoyl chloride to give a product. The reaction is known as |
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Answer» Schmidt REACTION `+C_(6)H_(5)COCl to C_(6)H_(5)NH-overset(O)overset(||)C-C_(6)H_(5)+HCl` Schotten Baumann `"Rea"^(N)` |
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| 9. |
Aniline on treatment with sodium hypochlorite gives |
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Answer» <P>`p-`Aminophenol |
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| 10. |
Anilinereact with NaNO_(2) + dil. HClgives |
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Answer» PHENOL |
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| 12. |
Aniline reacts with acetyl chloride to give |
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Answer» phenol
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| 13. |
Aniline react with benzoyl chloride in the presence of sodium hydroxide and gives benzanilide. This reaction is known as |
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Answer» GATTERMANN reaction |
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| 14. |
Aniline on treating with NaNO_2/ HCl at 0^@C followed by alkaline B-naphthol solution , gives : |
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Answer» A brilliant red DYE |
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| 15. |
Aniline on treatment with bromine water gives____. |
| Answer» SOLUTION :2,4,6-tribromoaniline. | |
| 16. |
Aniline on treatment with HCl and NaNO_2 at low temperature gives |
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Answer» Amino phenol |
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| 17. |
Aniline on reaction with conc. HNO_3 produces : |
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Answer» `C_6H_5NO_2 ` |
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| 18. |
Aniline or reaction with con. H_(2)SO_(4) gives X. If X is heated, the product is |
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Answer» sulphanilic acid |
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| 19. |
Aniline on reaction with acetyl chloride gives |
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Answer» Phenol |
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| 20. |
Aniline on reaction with aqueous solution of bromine gives: |
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Answer» <P>o - Bromoaniline
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| 21. |
Aniline on reaction with acetic anhydride to give |
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Answer» Acctanilidc
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| 22. |
Aniline on oxidation with Na_(2)Cr_(2)O_(7) and H_(2)SO_(4) gives : |
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Answer» <P>BENZOIC acid
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| 23. |
Aniline onnitroationunexpectedly gives |
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Answer» o-nitroaniline |
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| 24. |
Aniline on nitration gives |
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Answer»
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| 25. |
Anilineon nitrationgives |
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Answer» o-nitroaniline |
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| 26. |
Aniline on heating with conc.H_2SO_4 at 180^@C gives : |
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Answer» P-aminobenzene sulphonic ACID |
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| 28. |
Aniline on heating with alc. KOH and CS_2 gives : |
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Answer» Thio urea |
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| 29. |
Aniline is weaker base than methylamine. Explain. |
| Answer» Solution :Because `C_6H_5` group is ELECTRON WITHDRAWING in ANILINE WHEREAS `CH_3 -` group is electron in methyl amine. | |
| 30. |
Aniline is treated with excess of CH_(3)I. The final product is |
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Answer» `C_(6)H_(5)NHCH_(3)` |
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| 31. |
Aniline is used : |
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Answer» In CRIMPING of wool |
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| 32. |
Aniline is usaully purified by : |
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Answer» chromatograhic |
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| 33. |
Aniline is weaker base than ethyl amine because : |
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Answer» LONE pair of ELECTRONS of N-atom is not freely available for Co-ordination with a PROTON due to resonance than in ethly amine |
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| 34. |
Aniline is treated with bromine water to give an organic compound 'X' which when treated with NaNO_2 and HCl at 0^@C gives a water soluble compound 'Y'. Compound 'Y' on treatment with CuCl_2 and HCl gives compound 'Z'. Compound 'Z' is |
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Answer» o-bromochlorobenzene
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| 35. |
Aniline is treated with bromine water to give an organic compound 'X' which when treated with NaNO_(2) and HCl at 0^(@)C gives a water soluble compound 'Y'. Compound 'Y' on treatment with CuCl_(2) and HCl gives compound Z. Compound Z is |
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Answer» o-bromochlorobenzene |
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| 36. |
Aniline is separated from a mixture by : |
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Answer» fractional crystallisation |
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| 37. |
Aniline is reacted with bromine water and the resulting product is treated with an aqueous solution of sodium nitrite in presence of dilute hydrochloric acid. The compound so formed is converted into. The compound so formed is converted into a tetrafluoroborate which is subsequently heated. The final product is |
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Answer» 1,3,5-tribromobenzene
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| 38. |
Aniline is seoarated from aniline-water mixture is |
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Answer» Ceptallization |
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| 39. |
Aniline is reacted with bromine water and the resulting product is treated with an aqueous solution of sodium nitrite in presence of dilute HCl. The compound so formed is converted into tetrafluoroborate which is subsequently heated dry. The final product is |
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Answer» p-bromofluorobenzene
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| 40. |
Anilineis reacted with Br_(2)/ watergives(withoutproctecting - NH_(2)/ group |
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Answer» o-bromonailine |
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| 41. |
Aniline is reacted withaceticanhyldirdegives |
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Answer» PHENOL |
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| 42. |
Aniline is purified by |
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Answer» STEAM distillation |
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| 43. |
Aniline is purified by : |
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Answer» FRACTIONAL distillation |
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| 44. |
Aniline is prepared in presence of Fe/HCl from |
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Answer» Benzene Mechanism: (i) `3Fe+6HCLrarr3FeCl_(2)+6H` (ii) `C_(6)H_(5)NO_(2)+6HrarrC+6H_(5)NH_(2)+2H_(2)O` (III) `FeCl_(2)+2H_(2)OrarrFe(OH)_(2)+2HCl` (iv) `C_(6)H_(5)NO_(2)+2FE(OH)_(2)+4H_(2)OrarrC_(6)H_(5)NH_(2)+Fe(OH)_(3)` |
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| 45. |
Aniline is obtained by reacting chlorobenzene with |
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Answer» `NH_(3)` |
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| 46. |
Aniline is not the major product in o0ne of the following reacvtions, identify that reactions. |
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Answer» `C_6H_5OH+CH_3underset(300^(@) C) overset(ZnCl_2) to ` |
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| 47. |
Aniline ismorestablethananiliniumion because of |
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Answer» differentcharges |
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| 48. |
Aniline is less basic than |
| Answer» Answer :D | |
| 49. |
Aniline is diazotized and the diazonium salt hydrolysed to yield phenol which is brominated to produce C_(6)H_(2)(Br_(3))OH. Calculate the mass of the final product obtained from 9.3 g of aniline if the yield in the two steps is 45% and 70% (Atomic mass of Br=80) |
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Answer» 1.04 g<BR>10.43 g Mol of `C_(6)H_(5)OH "formed"=(9.3)/(93) XX (45)/(100)=0.045` Mol of `C_(6)H_(2)(Br_(3))OH=0.045 xx (70)/(100)=0.0315` Mass of `C_(6)H_(2)(Br_(3))OH "formed" =0.0315 xx 331=10.43 g` |
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| 50. |
Aniline is converted into chlorobenzene by using |
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Answer» Balz - Shiemann REACTION
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