Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

An isotope of 'parent' is produced, when its nucleus loses

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One `ALPHA-`particle
One `BETA-`particle
One `alpha` and two `beta`-particles
One `beta` and two `alpha-`particles

Solution :`._(Z)A^(m) rarr ._(Z)B^(m-4) + ._(2)He^(4) + 2 ._(-1)e^(0)`
2.

An isotope of oxygen has mass number 18. Other isotopes of oxygen will have the same

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MASS NUMBER
Atomic weight
Number of NEUTRONS
Number of PROTONS

Solution :Isotopes differ in number of neutrons but have same number of protons.
3.

An isotope of ""^(231)Th can be converted into ""^(227)Th by the emission of :

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one `BETA-`particle
one `ALPHA`-particle
TWO `alpha-` and two `beta`-PARTICLES
one `alpha`- and two `beta`-particles.

Answer :D
4.

An isotope ""_(a)^(b)X undergoes x alpha and y beta disintegrations to from a stable isotope ""_(a-10)^(b-32)Y The values of x and y are :

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6,6
8,6
6,8
4,6

Answer :B
5.

An isotonic solution will produce an osmotic pressure of 10.00 atm measured against pure water at 37^@C. How many grams of NaCl must be dissolved in one litre of water to produce at isotonic solution

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11.46 G
0.196 g
9.01 g
10 g

Answer :A
6.

An isotone of ._(32)^(76)Ge is (one or more are correct)

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`._(32)^(77)GE`
`._(33)^(77)As`
`._(34)^(77)SE`
`._(34)^(78)Se`

SOLUTION :Both have 44 neutrons, Isotones have same number of neutrons.
7.

An Isotone of ""_(32)^(76)Ge is :

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`""_(32)^(77)Ge`
`""_(33)^(77)As`
`""_(34)^(77)Se`
`""_(36)^(77)Se`

Solution :Isotones are ATOMS having same number of neutrons but different mass numbers. `""_(32)^(76)Ge` (neutrons=44 and `""_(33)^(77)As` (neutrons =44)
8.

An isonitrile on reduction gives

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`1^@` amine
`2^@`amine
`3^@` amine
quaternary AMMONIUM SALT

Solution :`2^@`amine
9.

An isonitrile on reduction gives:

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`3^(@)` AMINE
`2^(@)` amine
`1^(@)` amine
quaternary AMMONIUM salts.

Answer :B
10.

An isomerr of the complex CoBrCl_(2)(en)_(2)(H_(2)O), on reaction with concentrated H_(2)SO_(4) (dehydrating agent), suffers no loss in weight and on reaction with AgNO_(3) solution it gives only white precipitate, which is soluble in NH_(3) solution. Q. The correct formula of the complex is:

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`[CoBrH_(2)O(en)_(2)]Cl_(2)`
`[COCL(en)_(2)H_(2)O]BrCl`
`[CoBrCl(en)_(2)]CL*H_(2)O`
`[CoCl_(2)(en)_(2)]Br*H_(2)O`

SOLUTION :`[CoBr(en)_(2)(H_(2)O)]Cl_(2)`
11.

An isomer of the complex Co(en)_(2)(H_(2)O)IC l_(2), on reaction with concentrated H_(2)SO_(4), it suffers loss in weight and on reaction with AgNO_(3) solution gives a yellow precipitated which is isoluble in NH_(3) solution. Q. Total number of space isomers of the formula of the above complex is:

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2
3
4
1

Answer :B
12.

An isomerr of the complex CoBrCl_(2)(en)_(2)(H_(2)O), on reaction with concentrated H_(2)SO_(4) (dehydrating agent), suffers no loss in weight and on reaction with AgNO_(3) solution it gives only white precipitate, which is soluble in NH_(3) solution. Q. The incorrect statement about complex is:

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It can show geometrical isomerism
cis isomer is OPTICALLY active
Trans isomer is optically active
it can exhibit solvate isomerism

Solution :`[CoBr(en)_(2)(H_(2)O)]Cl_(2)`: Its trans isomer is optically INACTIVE.
13.

An isomer of the complex Co(en)_(2)(H_(2)O)IC l_(2), on reaction with concentrated H_(2)SO_(4), it suffers loss in weight and on reaction with AgNO_(3) solution gives a yellow precipitated which is isoluble in NH_(3) solution. Q. If one mole of original is treated with excess Pb(NO_(3))_(2) solution, then the number of moles of white precipitate formed will be

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`2.0`
`1.0`
`0.0`
`3.0`

ANSWER :C
14.

An isomer of the complex Co(en)_(2)(H_(2)O)IC l_(2), on reaction with concentrated H_(2)SO_(4), it suffers loss in weight and on reaction with AgNO_(3) solution gives a yellow precipitated which is isoluble in NH_(3) solution. Q. If all the ligandsin the co-ordination sphere of the above complex are replaced by CN^(-) ion, then the magnetic moment of the complex ion will be:

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0.0 BM
5.9 BM
4.9 BM
1.73 BM

Answer :A
15.

An isomer of ethanol is :

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METHANOL
DIETHYL ether
Acetone
Dimethyl ether

Answer :D
16.

An isomer of ethanol is:

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Methanol
Dimethyl ether
Diethyl ether
Ethylene glycol

Answer :B
17.

An isomer of C_(6)H_(14) forms three monochloro derivaties. The isomer may be- (Excluding stereo isomer)

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neo - pentane
N - hexane
2 , 3 - DIMETHYLBUTANE
iso - hexane

ANSWER :B
18.

An isomer of C_(3)H_(6)Cl_(2) on boiling with aq. KOH give acetone. Hence, the isomer is ,

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2,2- dichloropane
1,2-dichloropropane
1,1-dichloropane
1,3-dichloropropane

Solution :`CH_(3)C Cl_(2)CH_(3) + 2KOH OVERSET(aq.) toCH_(3) COCH_(3) + 2 KCL`
19.

An isomer of C_(3)H_(6)Cl_(2) on boiling with aqueous KOH gives acetone. Hence, the isomer is

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2,2-dichloropropane
1,2-dichloropropane
1,1-dichloropropane
1,3-dichloropropane

Solution :`underset("2,2-dichloropropane "("isomer of "C_(3)H_(6)Cl_(2)))(CH_(3)-underset(CL)underset(|)overset(Cl)overset(|)(C)-CH_(3)+underset("AQUEOUS")(2KOH) underset(2-KCl)overset(boil)to underset("unstable")(CH_(3)-underset("Unstable")(CH_(3)-overset(O)overset(||)(C)-CH_(3))`
20.

An isolated system is that system in which

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There is no EXCHANGE of ENERGY with the surroundings
There is exchange of MASS and energy with the surroundings
There is no exchange of mass and energy with the surroundings
There is exchange of mass with surroundings.

Answer :D
21.

An isolated system is that system in which:

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There is no EXCHANGE of ENERGY with the surroundings
There is exchange of MASS and energy with the surroundings
There is no exchange of mass or energy with the suroundings
There is EXCHANGES of mass with the surroundings

Answer :C
22.

An isocyanide on reduction with hydrogen in the presence of Pt gives:

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Amide
Primary AMINE
Secondary amine
Alcohol.

Answer :C
23.

An isolated system comprises the liquid in equilibrium with vapours . At this stage the molar entropy of the vapour is :

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LESS than that of liquid
more than that of liquid
Equal to zero
Equal to that of liquid

Solution :N//A
24.

An irreversible process occuring isothermally in an isolated system leads to

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ZERO ENTROPY
An increase in the total entropy of the system
A decrease in the total entropy of the system
None of these

Solution :Entropy of the system increases as the process occur irreversibly and isothermally in an isolated system.
25.

An iron cylinder contains helium at a pressure of 250 K P_(a) at 300 K. Then room in which cylinder is placed catches fire. Predict whether the cylinder will blow up before it melts or not (melting point of cylinder =1800 K)

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Solution :Given `P_(1)=250 K P_(a) T_(1)=300 K, P_(2)=1xx10^(6) P_(a), T_(2)=?`
Since, Volume of cylinder remains CONSTANT.
Therefore `(P_(1))/(T_(1))=(P_(2))/(T_(2))`
`rArr (250xx10^(3))/(300) =(1xx10^(6))/(T_(2))`
`rArr T_(2)=1200 K`
The cylinder will blow up at 1200 K before its melting (m.pt. =1800 K)
26.

An iron cylinder contains helium at a pressure of 250 k pa and27^(@)C. The cylinder can withstand a pressure of 1 xx 10^(6) pa. The room in which cylinder is palced catches fire. Predict whether the cylinder will blow up before it melts or not. [melting point of cylinder =1800 k]

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ANSWER :YES
27.

An iron compound yielded C= 64.4%, H= 5.5% and Fe= 29.9%. What is the simple formula of the compound?

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SOLUTION :`(C_(10)H_(10)FE)`
28.

An iron catalyst is used in the Haber process in which process N_2 and H_2 react to produce NH_3 What is the role of this catalyst ?

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It provides a PATHWAY with a lower ACTIVATION energy
It INCREASES the equilibrium constant of the reaction
It rasises the kinetic energies of the REACTANTS
It interacts with the `NH_3`

Answer :C
29.

An iorganic white crystalline compound (A) has a rock salt structure. (A) on reaction with conc. H_(2)SO_(4) and MnO_(2), evolves a pungent smelling, greenish-yellow gas (B). Compound (A) gives white ppt. of ( C) with AgNO_(3) solution. Compounds (A), (B) and (C) will be respectively:

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`NACL,Cl_(2)AGCL`
`NABR,Br_(2),NaBr`
`NaCl,Cl_(2),Ag_(2)SO_(4)`
`Na_(2)CO_(3),CO_(2),Ag_(2)CO_(3)`

Answer :A
30.

An ionizing solvent has

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Low VALUE of dielectric constant
High value of dielectric constant
A dielectric constant EQUAL to 1
Has a high MELTING point

Solution :HIGHER the dielectric constant of a solvent more of its ionising power.
31.

An Ionic Solid A^(+)B^(-) Crstalise like rock salt if all atoms along one body diagonalare removed then what is the formula of substance ?

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`A_12B_15`
`A_12B_17`
`A_13B_15`
`A_13B_14`

ANSWER :A
32.

An ionic solid PQ crystallises in rock salt structure with density 4.0 gm//cm^(3) . If the radius of cation and anion is 83 and 167 pm respectively, then the molar mass of solid is [N_(A) = 6 xx 10^(23)]

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`75 gm//mol`
`50 gm//mol`
`25 gm//mol`
`150 gm//mol`

SOLUTION :`a = 2[83+167]=500 "pm"`
`d = (Z xx M)/(N_(A)XXA^(3)xx10^(-30))`
`=(4xxM)/(6XX10^(23)xx[500]^(3)xx10^(-30))=4`.
`M = 75 gm//"MOLE"`.
33.

An ionic solid is a poor conductor of electricity, because

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the charge on the ions is UNEQUALLY distributed
ions do not CONDUCT electricity
ions are RIGIDLY held in solid
none of the above.

Solution :ions are rigidly held in solid
34.

An ionic solid AB crystallizes as a bcc structure . The distance between cation and anion in the lattice is 338 pm . Calculate the edge length of the unit cell .

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`195.15` PM
`97.58` pm
`390.3` pm
`780.6` pm

Answer :C
35.

An ionic crystal lattice has r+//r- radius ratio of0.524, its coordination number is

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2
4
6
8

Answer :C
36.

An ionic compound when dissolved in water has produced m A^(n-), n B^(m-) ions. What is the formula of the compound ?

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`A_(m)B_(n)`
`A_(n)B_(m)`
`A_(m)B_(m)`
`A_(n)B_(n)`

SOLUTION :Ionic compound :

`THEREFORE` The FORMULA of he compound is `A_(m)B_(n)`
37.

An ionic compound MCl is simultaneously doped with 10^(-6) mole % NCl_2 and 10^(-7) mole % RCl_3.Calculate the concentration of cationic vacancies x. Express your answer as x/9xx10^14. (take N & R =divalent & trivalent cations)

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SOLUTION :Conc.of cationic VACANCIES
`=10^(-6)xx6xx10^(23)+10^(-9)xx6xx10^(23)xx2=6xx10^(15)+12xx10^(14)=(60+12)xx10^14=72xx10^(14)`
38.

An ionic compound is made up of A & B only. lons of A occupy all the corners and alternate face centers while that of B occupy body center and edge centers. If B contains -1 charge then charge on atom A will be

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1
2
3
4

Answer :B
39.

An ionic compound is made up of A cations and B anions. if A cations are present at the alternate corners and B anion is present on the body of the diagonal, what is the formula of the ionic compound ?

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Solution :(i) As cations A are present at alternate COMERS, i.e. 4 comers, the NUMBER of A cations in the UNIT cell = `4 xx 1/8 = 1/2`
(ii) As anions B are present at the body centre, THEREFORE, the number of B ions in the unit cell = 1.
Hence, the formula of the compound = `A_(0.5) B_1 ` or `AB_2`
40.

An ionic compound is made up of A & B only. lons A occupy all the corners and alternate edge centers while atoms B occupy all the face centers. The formula of compound will be

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`AB_2`
`A_2 B_3`
`A_2 B`
`AB_3`

ANSWER :B
41.

An ionic compound has unit cell consisting A ions at the corners of a cube and B ions on the centres of the faces of cube. The empirical formula of compound would be ....

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`A_3B`
`AB_3^(-)`
`A_2B`
`AB`

Solution :Total number of A ions `= ( 8 XX 1/8) = 1`
Total number of B ions `= (6 xx 1/2) = 3`
`THEREFORE A:B = 1:3`
42.

An ionic compound is :

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`C Cl_4`
`SnCl_2`
`SiCl_4`
`SeCl_4`

ANSWER :B
43.

An ionic compound dissolves in water if …………. Energy is greater than……………energy.

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SOLUTION :HYDRATION, LATTICE
44.

An ionic compound crystallises in FCC type structure with 'A' ions at the centre of each face and 'B' ions occupying corners of the cube. The formula of compound is -

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`AB_(4)`
`A_(3)B`
`AB`
`AB_(3)`

ANSWER :A::B::C
45.

An ionic compound crystallises in FCC type structure with 'A' ions at the center of each face and 'B' ions occypying corners of the cube. The formula of compound is-

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`AB_(4)`
`A_(3)B`
AB
`AB_(3)`

Answer :A::B::C
46.

An ionic compound A_(x)B_(y) crystallizes in fcc type crystal structure with B ions at the centre of each face and A ion occupying centre of the cubic, the correct formula A_(x)B_(y) is …………..

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AB
`AB_(3)`
`A_(3)B`
`A_(8)B_(6)`

SOLUTION :Hint : `"Number of A ions"=((N_(c))/(8))=((8)/(8))=1`
`"Number of B ions "=((N_(f))/(2))=((6)/(2))=3" Simplest formula AB"_(3)`
47.

An ionic compound A^(+)B^(-) is most likely to be formed when :

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the ionization energy of A HIGH and electron AFFINITY of B is LOW
the ionization energy of A is low and electron affinity of B is high
both, the ionization energy of A and electron affinity of B are high
both, the ionization energy of A and electron affinity of B are low

Answer :B
48.

An ion M^(2+) forms the complexes. [M(H_(2)O)_(6)]^(2+)""[M(en)_(3)]^(2+)""[MBr_(6)]^(4-) Match the complex with the appropriate colour respectively :

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Green, blue and red <BR>Blue, red and green
Green, red and blue
Red, blue and green

Solution :Observed colours are green, blue, red, Complimentary colours are red, ORANGE, green.

`Delta_(0)` for ligands : `en gt H_(2)O gt Br^(-)`
49.

An ion M^(2+), forms the complexes [M(H_(2)O)_(6)]^(2+),[M(en)_(3)]^(2+) and [MBr_(6)]^(4-), match the complex with the appropriate colour:

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GREEN, BLUE and RED
Blue, and greenn
Green, red and blue
Red, blue and green

Answer :D
50.

An ion is reduced to the element when it absorbs6 xx 10^(20) electrons. The number of equivalence of the ion is

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`0.1`
`0.01`
`0.001`
`0.0001`

SOLUTION :`6 XX 10^(23)E^(-) to 1 "equilit" , 6 xx 10^(20)e^(-) to y = 9 , y=(6 xx 10^(20))/( 6 xx 10^(23)) = 10^(-3) eq `