Quiz about Chemistry in Class 12

Question 1

Amines can be considered as derivatives of _______ obtained by the replacement of hydrogen atom with alkyl or aryl groups.

Accepted Answer

NA

Question 2

Amines can be considered as derivatives of ammonia.  What is the significance of the Hoffmann bromamide reaction?

Accepted Answer

NA

Question 3

Amines can be considered as derivatives of ammonia.  Represent a reaction to explain the basic character of aniline.

Accepted Answer

NA

Question 4

Amines can be considered as derivatives of ammonia.  Name the reagents used in the hoffmanns bromamide reaction.

Accepted Answer

NA

Question 5

Amines can be considered as derivatives of ammonia.  Give one chemical test to distinguish between methyl amine and dimethyl amine. Write down the chemical reaction.

Accepted Answer

NA

Question 6

Amines can be considered as derivatives of ammonia.  Arrange the following in increasing order of their basic strength. C_6H_5NH_2C_2H_5NH_2(C_2H_5)_2NHNH_3

Accepted Answer

NA

Question 7

Amines behave as nucleophiles due to the presence of unshared election pair.

Accepted Answer

NA

Question 8

Amines behave as

Accepted Answer

NA

Question 9

Amines are well known to be stronger bases and nucleophiles than alkcnes. Why do enamines such as 1-dimethylaminocyclopentene preferentially react with electrophiles at a double bond carbon rather than at nitrogen?

Accepted Answer

NA

Question 10

Amines are versatile fuctional groups useful in the preparation of many organic compounds. How can you convert.

Accepted Answer

NA

Question 11

Amines are the basesbut

Accepted Answer

NA

Question 12

Amines are versatile fuctional groups useful in the preparation of many organic compounds. How can you convert.

Accepted Answer

NA

Question 13

Amines are more basic than comparable alcohols.

Accepted Answer

NA

Question 14

Aminesare polar compounds because of the

Accepted Answer

NA

Question 15

Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile.  The leaving group in quartenary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. The reaction of a quartenary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group the reaction requires heat. The carbon to which the tertiary amine is attached is designated as alpha carbon.  When the hydroxide ion starts to remove a beta H from a quartenary ammonium ion the leaving group does not immediately start to leave because a tertiary amine is not a good leaving group. As a result a partial negative charge builds up on the carbon from which the proton is removed.  The compounds C in question number 31 on heating with moist silver oxide gives

Accepted Answer

NA

Question 16

Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile.  The leaving group in quartenary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. The reaction of a quartenary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group the reaction requires heat. The carbon to which the tertiary amine is attached is designated as alpha carbon.  When the hydroxide ion starts to remove a beta H from a quartenary ammonium ion the leaving group does not immediately start to leave because a tertiary amine is not a good leaving group. As a result a partial negative charge builds up on the carbon from which the proton is removed.  Which of the following statements are true regarding Hoffmann elimination ?

Accepted Answer

NA

Question 17

Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile.  The leaving group in quartenary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. The reaction of a quartenary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group the reaction requires heat. The carbon to which the tertiary amine is attached is designated as alpha carbon.  When the hydroxide ion starts to remove a beta H from a quartenary ammonium ion the leaving group does not immediately start to leave because a tertiary amine is not a good leaving group. As a result a partial negative charge builds up on the carbon from which the proton is removed.  Which of the following statements is correct?

Accepted Answer

NA

Question 18

Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quarternary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. the reaction of a quarternary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group the reaction requires heat. The carbon to hwich the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H form from a quarternary ammonium ion the leaving group does not immediately start to leave because a tertiaryamine is not a good leaving group. As a result a partial negative charge bulds up on the carbon from which the proton is removed.  Which compounds of question number 31 are optically active

Accepted Answer

NA

Question 19

Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quarternary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. the reaction of a quarternary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group the reaction requires heat. The carbon to hwich the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H form from a quarternary ammonium ion the leaving group does not immediately start to leave because a tertiaryamine is not a good leaving group. As a result a partial negative charge bulds up on the carbon from which the proton is removed.  Which of the following statements are true regarding Hoffmann elimination?

Accepted Answer

NA

Question 20

Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quarternary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. the reaction of a quarternary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group the reaction requires heat. The carbon to hwich the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H form from a quarternary ammonium ion the leaving group does not immediately start to leave because a tertiaryamine is not a good leaving group. As a result a partial negative charge bulds up on the carbon from which the proton is removed.  The compound C in question number 31 on heating with moist silver oxide gives

Accepted Answer

NA

Question 21

Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quarternary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. the reaction of a quarternary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group the reaction requires heat. The carbon to hwich the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H form from a quarternary ammonium ion the leaving group does not immediately start to leave because a tertiaryamine is not a good leaving group. As a result a partial negative charge bulds up on the carbon from which the proton is removed.  Which of the following compounds when subjected to Hoffmann elimination gives an alkene which can exhibit geometrical isomerism?

Accepted Answer

NA

Question 22

Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quarternary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. the reaction of a quarternary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group the reaction requires heat. The carbon to hwich the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H form from a quarternary ammonium ion the leaving group does not immediately start to leave because a tertiaryamine is not a good leaving group. As a result a partial negative charge bulds up on the carbon from which the proton is removed.  Which of the following statements is correct?

Accepted Answer

NA

Question 23

Amines are derivatives of ammonia and are classified as 1^(@) 2^(@) and 3^(@) Primary and secondary (but not teritiary amines) form intermolecular hydrogen bonds and thus they boil at highter temperatures than expected. Like ammonia all amines are basic although they differ in their basic nature.  As amines are considered as derivatives of ammonia quaternary ammonium salts are considered as derivatives of ammonium salts. Only the quaternary ammonium salts can shown optical activity. Methylethylpropyl amine is optically inactive because

Accepted Answer

NA

Question 24

Amines are derivatives of ammonia and are classified as 1^(@) 2^(@) and 3^(@) Primary and secondary (but not teritiary amines) form intermolecular hydrogen bonds and thus they boil at highter temperatures than expected. Like ammonia all amines are basic although they differ in their basic nature.  As amines are considered as derivatives of ammonia quaternary ammonium salts are considered as derivatives of ammonium salts. Only the quaternary ammonium salts can shown optical activity. Which of the following shows configurational isomerism ?

Accepted Answer

NA

Question 25

Amines are derivatives of ammonia and are classified as 1^(@) 2^(@) and 3^(@) Primary and secondary (but not teritiary amines) form intermolecular hydrogen bonds and thus they boil at highter temperatures than expected. Like ammonia all amines are basic although they differ in their basic nature.  As amines are considered as derivatives of ammonia quaternary ammonium salts are considered as derivatives of ammonium salts. Only the quaternary ammonium salts can shown optical activity.  When nitrogen is bounded to three different groups

Accepted Answer

NA

Question 26

Amines are derivatives of ammonia and are classified as 1^@ 2^@ and 3^@ Primary and secondary (but not teritary amines) form intermolecular hydrogen bonds and thus they boil at higher temperature than expected.Like ammonia all amines are basic although they differ in their basic nature.As amines are considered as derivatives of ammonia quatemary ammonium salts are considered as derivatives of ammonium salts.Only the quatemary ammonium salts can show optical activity.  Methylethylpropyl amine is optically inactive because

Accepted Answer

NA

Question 27

Amines are derivatives of ammonia and are classified as 1^@ 2^@ and 3^@ Primary and secondary (but not teritary amines) form intermolecular hydrogen bonds and thus they boil at higher temperature than expected.Like ammonia all amines are basic although they differ in their basic nature.As amines are considered as derivatives of ammonia quatemary ammonium salts are considered as derivatives of ammonium salts.Only the quatemary ammonium salts can show optical activity.  Which of the following statement is correct ?

Accepted Answer

NA

Question 28

Amines are derivatives of ammonia and are classified as 1^@ 2^@ and 3^@ Primary and secondary (but not teritary amines) form intermolecular hydrogen bonds and thus they boil at higher temperature than expected.Like ammonia all amines are basic although they differ in their basic nature.As amines are considered as derivatives of ammonia quatemary ammonium salts are considered as derivatives of ammonium salts.Only the quatemary ammonium salts can show optical activity.  Which of the following shows configurationally isomerism ?

Accepted Answer

NA

Question 29

Amines are basic in nature due to the presence of lone pair of electrons on N atom of -NH_(2) group. The basic strength of amines can be expressed by their dissociation constant K_(b) or pK_(b).  RNH_(2) + H_(2) to R NH_(3)^(+) + OH^(-)  K_(b) = ([RHH_(3)^(+)][OH^(-)])([RNH_(2)]) and pK_(b) = -log K_(b)  Greater the K_(b) value or smaller the pK_(b) value more is the basic strength of amine. Aliphatic amines are stronger bases than ammonia due to the electron releasing effect of alkyl groups. The basic strength among amines decreases as 2^(@) gt 1^(@) gt 3^(@)  Aryl amines such as aniline are less basic than aliphatic amines due to the involvement of lone pair of electrons on N atom with the resonance in benzene. In derivatives of aniline the electron releasing groups increase the basic strength while electron withdrawing groups decrease the basic strength. The base weakening effect of electron withdrawing group and base strengthening effect of electron releasing group is more marked at p-position than at m-position. Every o- substituted aniline is less basic than aniline due to ortho effect.  Maximum pK_(b) value is of

Accepted Answer

NA

Question 30

Amines are classifie as primary secondary and teritary Write the IUPAC name of the following compoundNH_2-(CH_2)_6-NH_2

Accepted Answer

NA

Question 31

Account for the following  Amines are basic substances while amides are neutral

Accepted Answer

NA

Question 32

Amines are basic in nature due to the presence of lone pair of electrons on N atom of -NH_(2) group. The basic strength of amines can be expressed by their dissociation constant K_(b) or pK_(b).  RNH_(2) + H_(2) to R NH_(3)^(+) + OH^(-)  K_(b) = ([RHH_(3)^(+)][OH^(-)])([RNH_(2)]) and pK_(b) = -log K_(b)  Greater the K_(b) value or smaller the pK_(b) value more is the basic strength of amine. Aliphatic amines are stronger bases than ammonia due to the electron releasing effect of alkyl groups. The basic strength among amines decreases as 2^(@) gt 1^(@) gt 3^(@)  Aryl amines such as aniline are less basic than aliphatic amines due to the involvement of lone pair of electrons on N atom with the resonance in benzene. In derivatives of aniline the electron releasing groups increase the basic strength while electron withdrawing groups decrease the basic strength. The base weakening effect of electron withdrawing group and base strengthening effect of electron releasing group is more marked at p-position than at m-position. Every o- substituted aniline is less basic than aniline due to ortho effect.  Which of the following has lowest pK_(b) value ?

Accepted Answer

NA

Question 33

Aromatic and aliphatic amines are basic in nature like ammonia. Arrange the following compounds in the increasing order of their basic strngth CH_3NH_2(CH_3)_2NHNH_3C_6H_5-NH_2

Accepted Answer

NA

Question 34

Amines are basic compounds They act as Lewis base due to the presence of lone pair electrons at nitrogen    Amines aho behave as base as well as Bronsted inductive effect steric hindrance and resosnance.  CH_(3)-NH_(2)+HOH hArr CH_(3)-NH_(3)^(+)+OH^(-)  CH_(3)-NH_(2)+H^(+)Cl^(-)hArr CH_(3)-NH_(3)^(+)+Cl^(-) Alkyl groups and electron groups hence these groupsincreases the electron density at nitrogen as well as the basic amines character of amines. Basic character of teritary amines is reduced due to the steric hindrance of three alkyl groups. Experimentally it is observed that stronger bases have smaller values of pK_(b) greater value of K_(b).  Which among the following factors in fluence the basicity of amines?  I-the inductive effect of alkyl group  II-the polar effect  III-the resonance

Accepted Answer

NA

Question 35

Amines are basic in character because they have

Accepted Answer

NA

Question 36

Amines are basic. Arrange the following amines in the increasing order of base strength CH_3NH_2 (CH_3)_2NH (CH_3)_3N C_6H_5NH_2

Accepted Answer

NA

Question 37

Amines are

Accepted Answer

NA

Question 38

TF Amines act as Lewis bases

Accepted Answer

NA

Question 39

NH_3 acts as a Lawis base. Comment.

Accepted Answer

NA

Question 40

Amine that cannot be prepared by Gabrielphthalimide synthesis is

Accepted Answer

NA

Question 41

Amine that cannot be prepared by Gabriel pthalimide synthesis is

Accepted Answer

NA

Question 42

Amine that cannot be prepared by Gabriel Phthalimide synthesis is………..

Accepted Answer

NA

Question 43

Amine that cannot be prepared by Gabriel-phthalimide synthesis is

Accepted Answer

NA

Question 44

Amine that cannot be prepared by Gabriel phthalimide synthesis is

Accepted Answer

NA

Question 45

Amine produced by the Hoffmann degradation of benzamide is

Accepted Answer

NA

Question 46

Amine may contain

Accepted Answer

NA

Question 47

Amine is obtained as major product in

Accepted Answer

NA

Question 48

AminehavehigherB.P thancorrespondingalkane orethersdue to .

Accepted Answer

NA

Question 49

______amine does not react with Hinsbergs reagent.

Accepted Answer

NA

Question 50

Aminebehaveas

Accepted Answer

NA

Explore topic-wise InterviewSolutions in Current Affairs.

Amines can be considered as derivatives of _______ obtained by the replacement of hydrogen atom with alkyl or aryl groups.

Amines can be considered as derivatives of ammonia. What is the significance of the Hoffmann bromamide reaction?

Amines can be considered as derivatives of ammonia. Represent a reaction to explain the basic character of aniline.

Amines can be considered as derivatives of ammonia. Name the reagents used in the hoffmann's bromamide reaction.

Amines can be considered as derivatives of ammonia. Give one chemical test to distinguish between methyl amine and dimethyl amine. Write down the chemical reaction.

Amines can be considered as derivatives of ammonia. Arrange the following in increasing order of their basic strength. C_6H_5NH_2,C_2H_5NH_2,(C_2H_5)_2NH,NH_3

Amines behave as nucleophiles due to the presence of unshared election pair.

Amines behave as

Amines are well known to be stronger bases and nucleophiles than alkcnes. Why do enamines, such as 1-dimethylaminocyclopentene, preferentially react with electrophiles at a double bond carbon rather than at nitrogen?

Amines are versatile fuctional groups useful in the preparation of many organic compounds. How can you convert.

Amines are the basesbut

Amines are versatile fuctional groups useful in the preparation of many organic compounds. How can you convert.

Amines are more basic than comparable alcohols.

Aminesare polar compounds because of the

Amines are classifie as primary, secondary and teritary Write the IUPAC name of the following compound:NH_2-(CH_2)_6-NH_2

Account for the following Amines are basic substances while amides are neutral

Aromatic and aliphatic amines are basic in nature like ammonia. Arrange the following compounds in the increasing order of their basic strngth: CH_3NH_2,(CH_3)_2NH,NH_3,C_6H_5-NH_2

Amines are basic in character because they have

Amines are basic. Arrange the following amines in the increasing order of base strength: CH_3NH_2, (CH_3)_2NH, (CH_3)_3N, C_6H_5NH_2

Amines are

T/F Amines act as Lewis bases

NH_3 acts as a Lawis base. Comment.

Amine that cannot be prepared by Gabrielphthalimide synthesis is

Amine that cannot be prepared by Gabriel pthalimide synthesis is

Amine that cannot be prepared by Gabriel Phthalimide synthesis is………..

Amine that cannot be prepared by Gabriel-phthalimide synthesis is

Amine that cannot be prepared by Gabriel phthalimide synthesis is

Amine produced by the Hoffmann degradation of benzamide is

Amine may contain :

Amine is obtained as major product in

AminehavehigherB.P thancorrespondingalkane orethersdue to .

______amine does not react with Hinsberg's reagent.

Aminebehaveas

1.	Amines can be considered as derivatives of _______ obtained by the replacement of hydrogen atom with alkyl or aryl groups.
Answer» ANSWER :AMMONIA

2.	Amines can be considered as derivatives of ammonia. What is the significance of the Hoffmann bromamide reaction?
Answer» Solution :The amine formed contains ONE carbon ATOM less than the amide. So the reaction is used for descending (or STEPPING down) in a HOMOLOGOUS series.

3.	Amines can be considered as derivatives of ammonia. Represent a reaction to explain the basic character of aniline.
Answer» Solution :Aniline REACTS with HCl to form ANILINIUM chloride `(ANE_PKE_CHE_XII_C13_E02_023_S01.png" WIDTH="80%">

4.	Amines can be considered as derivatives of ammonia. Name the reagents used in the hoffmann's bromamide reaction.
Answer» SOLUTION :Bromine in aqueous or ethanolic solution of NAOH is USED as the REAGENT.

5.	Amines can be considered as derivatives of ammonia. Give one chemical test to distinguish between methyl amine and dimethyl amine. Write down the chemical reaction.
Answer» SOLUTION :Methylamine on WARMING with chloroform and ethanolic KOH solution give foul smelling ISOCYANIDE. This is known as CARBYLAMINE reaction. Diethylamine does not answer this test. `(ANE_PKE_CHE_XII_C13_E02_026_S01.png" WIDTH="80%">

6.	Amines can be considered as derivatives of ammonia. Arrange the following in increasing order of their basic strength. C_6H_5NH_2,C_2H_5NH_2,(C_2H_5)_2NH,NH_3
Answer» SOLUTION :`C_6H_5NH_2ltNH_3ltC_2H_5NH_2lt(C_2H_5)_2NH`

7.	Amines behave as nucleophiles due to the presence of unshared election pair.
Answer» ANSWER :1

8.	Amines behave as
Answer» APROTIC acid neutral compound Lewis acids Lewis BASE Solution :`R-NH_(2)`(AMINES) behaves as a Lewis base because it is capable of DONATING a lone PAIR of electron.

9.	Amines are well known to be stronger bases and nucleophiles than alkcnes. Why do enamines, such as 1-dimethylaminocyclopentene, preferentially react with electrophiles at a double bond carbon rather than at nitrogen?
Answer» The NITROGEN is stcrically HINDERED by alkyl subst.ituents. Nitrogen is more elcctoncgativc than carbon. The carbocation formed by electrophilic attack at C-2 is stabilized by `pi` BONDING with the lone PAIR of electrons on nitrogen. Ammonium cations are less stable than carbocations. Solution :

10.	Amines are versatile fuctional groups useful in the preparation of many organic compounds. How can you convert.
Answer» SOLUTION :

11.	Amines are the basesbut
Answer» Monoacidic Diacidic Triacidic Tetraacidic SOLUTION :NITROGEN inaminebaresonlyone lonepairof ELECTRON

14.	Aminesare polar compounds because of the
Answer» hydrogen bonding DIFFERENCEIN electronegativitybetweenC,H and N `-NH_(2)` GROUP alkylgroup Answer :B

37.	Amines are
Answer» mono alkyl DERIVATIVEOF AMMONIA dialkylderivativeof ammonia trialky dervationof AMMOINA all of these ANSWER :D

40.	Amine that cannot be prepared by Gabrielphthalimide synthesis is
Answer» aniline benzyl amine methyl amine iso-butylamine Solution :Only `1^(@)` amines can be obtained by Gabriel synthesis. Aniline cannot be obtained by this method as aryl halides `(C_(6)H_(5)Cl or C_(6)H_(5)Br)` do not undergo nucleophilic SUBSTITUTION (i.e., cleavage of C-X BOND in haloarene is difficult) with potasium phthalimide under ordinary CONDITIONS to give N-phenyl phthalimide

13.	Amines are more basic than comparable alcohols.
Answer» Solution :Amines are more basic than camparable alcohols because of the following two reasons: (i) N being less electronegative is more willing to donate its lone pair of ELECTRONS to a proton than the more electronegative O atom. Therefore, amines are more basic than alcohols. (ii) when an amine ACCEPTS a proton, ammonium salt is formed and when an ALCOHOL accepts a proton oxonium salt is formed. Since N being less electronegative can accommodate the positive CHARGE better than the more electronegative O atom, therefore, ammonium salts are more stable than oxonium salts. as a result, amines are more BASI than alcohols.

15.	Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group, but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quartenary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. The reaction of a quartenary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group, the reaction requires heat. The carbon to which the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H from a quartenary ammonium ion, the leaving group does not immediately start to leave because a tertiary amine is not a good leaving group. As a result, a partial negative charge builds up on the carbon from which the proton is removed. The compounds 'C' in question number 31 on heating with moist silver oxide gives
Answer» Propene 1-Butene ETHYLENE 2-Butene Solution :Ethylene

16.	Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group, but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quartenary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. The reaction of a quartenary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group, the reaction requires heat. The carbon to which the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H from a quartenary ammonium ion, the leaving group does not immediately start to leave because a tertiary amine is not a good leaving group. As a result, a partial negative charge builds up on the carbon from which the proton is removed. Which of the following statements are true regarding Hoffmann elimination ?
Answer» it follows anti-zaitsev ELIMINATION it forms only zaitsev product no polar COMPOUNDS are formed at the END of the reaction it is given by only `1^(0)` amines Solution :If follow anti - zaitser elimination

17.	Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group, but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quartenary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. The reaction of a quartenary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group, the reaction requires heat. The carbon to which the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H from a quartenary ammonium ion, the leaving group does not immediately start to leave because a tertiary amine is not a good leaving group. As a result, a partial negative charge builds up on the carbon from which the proton is removed. Which of the following statements is correct?
Answer» `PK_(N)` value of protonated amine is more than that of protonated alcohol `PK_(a)` VALUED of the protonated amine is less than that of protonated alcohol `PK_(a)` value for protonated amine is equals to that protonated alcohol `PK_(a)` value of amine is less than that of alcohol Solution :`P^(ka)` : Protonated amine `gt` Protonated alchol Alchols more acidic than AMINES

18.	Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group, but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quarternary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. the reaction of a quarternary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group, the reaction requires heat. The carbon to hwich the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H form from a quarternary ammonium ion, the leaving group does not immediately start to leave because a tertiaryamine is not a good leaving group. As a result, a partial negative charge bulds up on the carbon from which the proton is removed. Which compounds of question number 31 are optically active
Answer» A and B B and C A,B and C All are inactive Solution :C is notoptically ACTIVE

20.	Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group, but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quarternary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. the reaction of a quarternary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group, the reaction requires heat. The carbon to hwich the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H form from a quarternary ammonium ion, the leaving group does not immediately start to leave because a tertiaryamine is not a good leaving group. As a result, a partial negative charge bulds up on the carbon from which the proton is removed. The compound 'C' in question number 31 on heating with moist silver oxide gives
Answer» Propene 1-Butene Ehtylene 2-Butene Solution :ETHYLENE is FORMED in all

21.	Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group, but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quarternary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. the reaction of a quarternary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group, the reaction requires heat. The carbon to hwich the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H form from a quarternary ammonium ion, the leaving group does not immediately start to leave because a tertiaryamine is not a good leaving group. As a result, a partial negative charge bulds up on the carbon from which the proton is removed. Which of the following compounds when subjected to Hoffmann elimination gives an alkene which can exhibit geometrical isomerism?
Answer» None Solution :Ehtylene is FORMED in all

22.	Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group, but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quarternary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. the reaction of a quarternary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group, the reaction requires heat. The carbon to hwich the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H form from a quarternary ammonium ion, the leaving group does not immediately start to leave because a tertiaryamine is not a good leaving group. As a result, a partial negative charge bulds up on the carbon from which the proton is removed. Which of the following statements is correct?
Answer» `PK_(a)` VALUE of protonated amine is more than that of protonated alcohol `PK_(a)` VALUED of the protoned amine is less than that of protonated alcohol `PK_(a)` value of protonated amine is EQUALS to that of protonated alcohol `PK_(a)` value of amine is less than that of alcohol Solution :Based on relative strengths of AMINES and ALCOHOLS

23.	Amines are derivatives of ammonia and are classified as 1^(@), 2^(@), and 3^(@), Primary and secondary (but not teritiary amines) form intermolecular hydrogen bonds and thus they boil at highter temperatures than expected. Like ammonia, all amines are basic, although they differ in their basic nature. As amines are considered as derivatives of ammonia, quaternary ammonium salts are considered as derivatives of ammonium salts. Only the quaternary ammonium salts can shown optical activity. Methylethylpropyl amine is optically inactive because
Answer» it is not tetrahederal its molecule is superimposable on its mirror image The enantiomers are RAPIDLY interconverted The nitrogen is `sp^(2)` HYBRIDIZED Answer :B

24.	Amines are derivatives of ammonia and are classified as 1^(@), 2^(@), and 3^(@), Primary and secondary (but not teritiary amines) form intermolecular hydrogen bonds and thus they boil at highter temperatures than expected. Like ammonia, all amines are basic, although they differ in their basic nature. As amines are considered as derivatives of ammonia, quaternary ammonium salts are considered as derivatives of ammonium salts. Only the quaternary ammonium salts can shown optical activity. Which of the following shows configurational isomerism ?
Answer» Diethyldimethylammonium iodide Dimethylpropylamine Methylallylphenylbenzyl AMMONIUM bromide None of these ANSWER :C

25.	Amines are derivatives of ammonia and are classified as 1^(@), 2^(@), and 3^(@), Primary and secondary (but not teritiary amines) form intermolecular hydrogen bonds and thus they boil at highter temperatures than expected. Like ammonia, all amines are basic, although they differ in their basic nature. As amines are considered as derivatives of ammonia, quaternary ammonium salts are considered as derivatives of ammonium salts. Only the quaternary ammonium salts can shown optical activity. When nitrogen is bounded to three different groups
Answer» The molecule is optically INACTIVE The molecule is tetrahedral The molecule is not superimposable on its MIRROR image The amine BOILS at nearly similar b.p as the `1^(@)`, and `2^(@)` amine of comparable molecular WEIGHT. Answer :C

26.	Amines are derivatives of ammonia and are classified as 1^@, 2^@ , and 3^@ Primary and secondary (but not teritary amines) form intermolecular hydrogen bonds and thus they boil at higher temperature than expected.Like ammonia, all amines are basic, although they differ in their basic nature.As amines are considered as derivatives of ammonia, quatemary ammonium salts are considered as derivatives of ammonium salts.Only the quatemary ammonium salts can show optical activity. Methylethylpropyl amine is optically inactive because
Answer» It is not tetrahedral Its molecules are superimposable on their MIRROR image The enantiomers are rapidly interconverted into each other the nitrogen is `sp^2` hybridized Solution :Although the mirror image of `R_1 R_2 R_3` N type of AMINE is not superimposable on its object, YET the molecule is OPTICALLY INACTIVE because of rapid inversion of configuration between the two arrangements i.e. the two enantiomers are only hypothetical are not isolated.

27.	Amines are derivatives of ammonia and are classified as 1^@, 2^@ , and 3^@ Primary and secondary (but not teritary amines) form intermolecular hydrogen bonds and thus they boil at higher temperature than expected.Like ammonia, all amines are basic, although they differ in their basic nature.As amines are considered as derivatives of ammonia, quatemary ammonium salts are considered as derivatives of ammonium salts.Only the quatemary ammonium salts can show optical activity. Which of the following statement is correct ?
Answer» All classes of amines form hydrogen bonds with each other Only primary and secondary amines form hydrogen bonds with water All classes of amines can form hydrogen bonds with water All amines are completely SOLUBLE in water Solution :All amine have a loan pair of electrons on N which ENABLES them to form H-bond.However, tertiary amines ALTHOUGH can form H-bond with water or other hydroxylic solvents, it does not form H-bond with its second molecule because of absence of H on N.only lower amines (`1^@,2^@` as well as `3^@`)are quite soluble in water solubility in water DECREASES with the INCREASE in the size of the alkyl group.

28.	Amines are derivatives of ammonia and are classified as 1^@, 2^@ , and 3^@ Primary and secondary (but not teritary amines) form intermolecular hydrogen bonds and thus they boil at higher temperature than expected.Like ammonia, all amines are basic, although they differ in their basic nature.As amines are considered as derivatives of ammonia, quatemary ammonium salts are considered as derivatives of ammonium salts.Only the quatemary ammonium salts can show optical activity. Which of the following shows configurationally isomerism ?
Answer» Diethyldimethylammonium iodide Methylethylpropylamine Methylallylphenylbenzyl AMMONIUM bromide None of the above Solution :Quaternary ammonium salts having four DIFFERENT groups have tetrahedral ARRANGEMENT and therefore exist as configurationally ENANTIOMERS.

29.	Amines are basic in nature due to the presence of lone pair of electrons on N atom of -NH_(2) group. The basic strength of amines can be expressed by their dissociation constant, K_(b) or pK_(b). RNH_(2) + H_(2) to R NH_(3)^(+) + OH^(-) K_(b) = ([RHH_(3)^(+)][OH^(-)])/([RNH_(2)]) and pK_(b) = -log K_(b) Greater the K_(b) value or smaller the pK_(b) value, more is the basic strength of amine. Aliphatic amines are stronger bases than ammonia due to the electron releasing effect of alkyl groups. The basic strength among amines decreases as : 2^(@) gt 1^(@) gt 3^(@) Aryl amines such as aniline are less basic than aliphatic amines due to the involvement of lone pair of electrons on N atom with the resonance in benzene. In derivatives of aniline, the electron releasing groups increase the basic strength while electron withdrawing groups decrease the basic strength. The base weakening effect of electron withdrawing group and base strengthening effect of electron releasing group is more marked at p-position than at m-position. Every o- substituted aniline is less basic than aniline due to ortho effect. Maximum pK_(b) value is of
Answer» `(CH_(3)CH_(2))_(2)NH` `(CH_(3))_(2)NH` ANSWER :B

30.	Amines are classifie as primary, secondary and teritary Write the IUPAC name of the following compound:NH_2-(CH_2)_6-NH_2
Answer» SOLUTION :Hexane-1, 6-diamine

31.	Account for the following Amines are basic substances while amides are neutral
Answer» SOLUTION :In amines alkyl GROUP is electron RELEASING which increases electron density on nitrogen making them basic whereas in amindes R-CO-group is electron withdrawing. THEREFORE they are neutral.

32.	Amines are basic in nature due to the presence of lone pair of electrons on N atom of -NH_(2) group. The basic strength of amines can be expressed by their dissociation constant, K_(b) or pK_(b). RNH_(2) + H_(2) to R NH_(3)^(+) + OH^(-) K_(b) = ([RHH_(3)^(+)][OH^(-)])/([RNH_(2)]) and pK_(b) = -log K_(b) Greater the K_(b) value or smaller the pK_(b) value, more is the basic strength of amine. Aliphatic amines are stronger bases than ammonia due to the electron releasing effect of alkyl groups. The basic strength among amines decreases as : 2^(@) gt 1^(@) gt 3^(@) Aryl amines such as aniline are less basic than aliphatic amines due to the involvement of lone pair of electrons on N atom with the resonance in benzene. In derivatives of aniline, the electron releasing groups increase the basic strength while electron withdrawing groups decrease the basic strength. The base weakening effect of electron withdrawing group and base strengthening effect of electron releasing group is more marked at p-position than at m-position. Every o- substituted aniline is less basic than aniline due to ortho effect. Which of the following has lowest pK_(b) value ?
Answer» ANSWER :C

33.	Aromatic and aliphatic amines are basic in nature like ammonia. Arrange the following compounds in the increasing order of their basic strngth: CH_3NH_2,(CH_3)_2NH,NH_3,C_6H_5-NH_2
Answer» SOLUTION :In AQUEOUS solution BASIC STRENGTH ORDER is `(CH_3)_2NHltCH_3NH_2lt(CH_3)_3NltNH_3ltC_6H_5NH_2`

34.	Amines are basic compounds They act as Lewis base due to the presence of lone pair electrons at nitrogen Amines aho behave as base as well as Bronsted inductive effect, steric hindrance and resosnance. CH_(3)-NH_(2)+HOH hArr CH_(3)-NH_(3)^(+)+OH^(-) CH_(3)-NH_(2)+H^(+)Cl^(-)hArr CH_(3)-NH_(3)^(+)+Cl^(-) Alkyl groups and electron groups hence these groupsincreases the electron density at nitrogen as well as the basic amines character of amines. Basic character of teritary amines is reduced due to the steric hindrance of three alkyl groups. Experimentally it is observed that stronger bases have smaller values of pK_(b) greater value of K_(b). Which among the following factors in fluence the basicity of amines? I-the inductive effect of alkyl group II-the polar effect III-the resonance
Answer» I,II I,III II,III I,II,III Answer :D