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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 2. |
The commercialname of polyacrylonitrile is |
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Answer» DACRON |
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| 3. |
The commercial name of polyacrylonitrile is ………….......... |
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Answer» Dacron The commercial NAME of POLYACRYLONITRILE is orlon (acrilan) 
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| 4. |
The commercial name of polyacrylonitrile is ............... |
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Answer» DACRON |
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| 5. |
The combustion to benzene (l) gives CO_(2)(g) and H_(2)O(l) . Given that heat of combustion of benzene at constant volume is -3263.9 "kJ mol^(-1) at 25^(@)C , heat of combustion in ("kJ mol^(-1)) of benzene at constant pressure will be (R=8.314 "JK^(-1) mol^(-1)) |
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Answer» `-3267.6` |
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| 6. |
The comcept of redistribution of energy in different orbitals of an atom associated with different energies to give new orbitals of equal(or somethimes it may be non-equal) energy oriented in space in definite directions is called hybridization and formed new orbitals are called hybrid orbitals. The bonds formed by such orbitals are called hybrid bonds. The process of mixing of orbitals itself requiressome energy. Thus, some additional energy, is needed for the hybridisation (mixing) of atomic orbitals. Q. Select from each set the molecule or ion having the smallest bond angle : (i) H_(2)Se, H_(2)Te and PH_(3) (ii) NO_(2)^(-) and NH_(2)^(-) (iii) POF_(3) and POCl_(3) (X-P-X angle) (iv) OSF_(2)Cl_(2) and SF_(2)(CH_(3))_(2) (F-S-F angle) |
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Answer» `H_(2)Se, NH_(2)^(-) POF_(3) and OSF_(2)Cl_(2)` `(I)PH_(3)gtH_(2)SegtH_(2)Te``(II)NO_(2)^(-)gtNH_(2)^(-)``(III)POCl_(3)gtPOF_(3)(X-P-X`angle)`(iv)OSF_(2)Cl_(2)gtSF_(2)(CH_(3))_(2)(angleF-S-F)` |
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| 7. |
The commercial name for peroxydisulphuric acid is: |
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Answer» SULPHURIC ACID |
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| 8. |
The comlexes [Co(NH_3)_6] [Cr(CN)_6] and [Cr(NH_3)_6] [Co(CN)_6] are the examples of which type of isomerism? |
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Answer» GEOMETRICAL ISOMERISM |
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| 9. |
The combustion of solidum is excess air yeilds a higher oxide. What is the oxidation state of the oxygen in the product? Neglect the negative sign. |
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Answer» |
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| 10. |
The combustion of benzene (1) gives CO_(2)(g) and H_(2)O(1). Given that heat of combustion of benzene at constant volume is .^(-)3263.9 kJ mol^(-1) " at "25^(@)C,heat of combustion (in kJ mol^(-1)) of benzene at constant pressure will be(R=8.314 JK^(-1) mol^(-1)) |
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Answer» `- 452.46` `Deltan_((g))=6-7.5=-15` `DeltaH=DeltaE+Deltan_((g))RT` `DeltaH=-3263.9kJ-(1.5xx8.314xx298)/(1000)KJ=-3267.6 kJ` |
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| 11. |
The combustion of benzene (l) gives CO_(2)(g) and H_(2)O(l). Given that heat of combustion of benzene at constant volume is -3263.9 kJ*mol^(-1) at 25^(@)C, heat of combustion (in kJ*mol^(-1)) of benzene at constant pressure will be (R=8.314J*K^(-1)*mol^(-1))- |
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Answer» 4152.6 `Deltan=6-(15)?(2)=-(3)/(2)` `DeltaH=DeltaU+DeltanRT` `DeltaH=[-3263.9-(3)/(2)xx8.314xx10^(-3)xx298]KJ*MOL^(-1)` `=-3267.6kJ*mol^(-1)`. |
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| 12. |
The combination which produces f-butyl alcohol when treated with grignard reagent: |
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Answer» `CH_3MgBr + CH_3COCH_3` |
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| 13. |
The combination which produces isopropyl alcohol: |
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Answer» `CH_3MgBr + CH_3CHO` |
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| 14. |
The combination of two layers of opposite charges aroung the colloidal particle is called Helmholtz electrical double layer. The potential difference between the fixed layer and the diffused layer of opposite charge is called |
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Answer» electrode potential |
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| 15. |
The colourless species is (are): |
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Answer» `VCl_3` (B)`VO^(2+) , V^(4+) , [Ar]^18 3d^2=1` unpaired electrons. (C )`[VO_4]^(3-) , V^(5+) , [Ar]^18 3d^0=no` unpaired electrons. (D)`[V (H_2O)_6]^(2+) , V^(2+) , [Ar]^18 3d^3=3` unpaired electrons. |
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| 16. |
The colours produced by electronic transitions with the ______ of a transition metal ion occur frequently in everyday life. |
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Answer» |
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| 17. |
The colourless species is…… |
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Answer» `VCl_(3)` |
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| 18. |
The colourless solution formed in step B contains |
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Answer» `[Hg(CN)_(4)]^(2-)` |
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| 19. |
The colourless gas liberted by passing excess of chlorine through NH_(3) gas is |
| Answer» Answer :D | |
| 20. |
The colourless gas liberated by passing excess of chlorine through NH_3 gas is: |
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Answer» `NCl_3` |
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| 21. |
Four colourless salt solutions are placed in separate test tubes and a strip of copper is dipped in each. Which solution finally turns blue ? |
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Answer» `Pb(NO_(3))_(2)` |
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| 22. |
The colourless and paramagnetic compound is : |
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Answer» `Na_(3)[FeF_(6)]` |
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| 23. |
The colouring matter which gets adsorbed on activated charcoal is called : |
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Answer» Adsorbent |
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| 24. |
The coloured spotofKMnO_(4) on any article can be bleached by |
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Answer» `SO_(2)+H^(+)` |
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| 26. |
The colour of transition metal ions is due to ............... in d-subshell and .............. transition. |
| Answer» SOLUTION :UNPAIRED ELECTRONS d-a | |
| 27. |
The colour of [Ti(H_(2)O)_(6)]^(3+) is violet to the transition of electrons from _________ orbital to _________ orbital by absorption of light of __________ colour. |
| Answer» SOLUTION :`t_(2G), e_(G)`, YELLOW | |
| 29. |
The colour of[Ti(H_2O)_6]^(3+) + is due to: |
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Answer» TRANSFER of an electron from ONE TI to another |
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| 30. |
The colour of [Ti(H_(2)O)_(6)]^(3+) is due to |
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Answer» TRANSFER of electron from Titanium to another atom of Titanium |
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| 31. |
The colour of the transition metal ions is due to |
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Answer» d-d transition |
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| 32. |
The colour of the solid produced by adding Sncia in excess to a solution of HgCl_2 is |
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Answer» white |
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| 33. |
The colour of the following ions V^(2), V^(3+), V^(4-) , Fe^(2+), Fe^(3+) are respectively |
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Answer» green, violet, blue, green, YELLOW |
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| 34. |
The colour of the precipitate formed when a reducing sugar is heated with Fehling solution is : |
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Answer» brown |
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| 35. |
The colour of the light absorbed by an aqueous solution of CuSO_(4) is |
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Answer» orange-red |
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| 36. |
The colour of the dye obtained by coupling benzene diazonium chloride with aniline is |
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Answer» red |
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| 37. |
The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, [Co(NH_(3))_(6)]^(3+),[Co(CN)_(6)]^(3-), [Co(H_(2)O)_(6)]^(3+) : |
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Answer» `[Co(CN)_(6)]^(3-)gt[Co(NH_(3))_(6)]^(3+)gt[Co(H_(2)O)_(6)]^(3+)` `Delta_(0) PROP (1)/(lambda)` |
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| 38. |
The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light of the visible region, for the complexes, [Co(NH_(3)_(6)]^(3+). [Co(CN)_(6)]^(3+). [Co(H_(2)O)_(6)]^(3+) |
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Answer» `[CO(CN)_(6)]^(3-)GT,[CO(NH_3)_(6)]^(3+)gt[CO(H_(2)O)_(6)]^(3+)` |
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| 39. |
The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region for the complexes, [Co(NH_(3))_(6)]^(3+),[Co(CN)_(6)]^(3-),[Co(H_(2)O)_(6)]^(3+) |
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Answer» `[Co(CN)_(6)]^(3-)GT[Co(NH_(3))_(6)]^(3+)gt[Co(H_(2)O)_(6)]^(3+)` |
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| 40. |
The colour of the complex of d - block elements depends on the nature of the ligands whereas that of f - block elements does not. Give reason. |
| Answer» Solution :In the complexes of transition elements, the d - ORBITALS of the central metal ion splits into two sets of `t_(2g)` and `e_(g)` - orbitals in the presence of ligands. The CRYSTAL FIELD splitting, or the d - d transition of electrons is responsible for the colour of the complexes. The extent of splitting depends on the nature of the ligands. Hence, the colour of the complexes formed by the d - block elements, depends on the nature of the ligands. Similarly, the colour of the complexes formed by the f - block elements depends on the f - f transition of the electrons. Since the antipenultimate (n - 2) f - orbitals lie deep within the atom, the VALUE of crystal field splitting of the f - orbitals of the central metal ion does not depend on the nature of the ligands. Hence, the colour of the complexes formed by the d - block elements depend on the nature of ligands whereas those formed by the f - block elements does not. | |
| 41. |
The colloidal solutions of gold prepared by different methods have different colors due to : |
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Answer» variable VALENCY of GOLD |
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| 42. |
The colour of the colloidal particles of gold obtained by different methods differ because of : |
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Answer» variabel valency of gold |
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| 43. |
The colour of the co-ordination compounds is explained in terms of : |
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Answer» spectrochemical series |
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| 44. |
The colour of the borax bead is due to the formation of a/an |
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Answer» Glass LIKE metal metaborate bead |
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| 45. |
The colour of solution obtained by adding excess of KI in the solution of HgCl_2 is : |
| Answer» ANSWER :D | |
| 47. |
The colour of p-aminoazobenzene is |
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Answer» Orange |
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| 49. |
Nitroso compoundare |
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Answer» yellow |
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| 50. |
The colour of (NH_(4))_(2)SO_(4)Fe_(2)(SO_(4))_(3).24H_(2)O is |
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Answer» White |
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