1.

The combustion to benzene (l) gives CO_(2)(g) and H_(2)O(l) . Given that heat of combustion of benzene at constant volume is -3263.9 "kJ mol^(-1) at 25^(@)C , heat of combustion in ("kJ mol^(-1)) of benzene at constant pressure will be (R=8.314 "JK^(-1) mol^(-1))

Answer»

`-3267.6`
`4152.6`
`-452.4`
`3260`

SOLUTION :`DeltaH=DeltaU+Deltan_(G)RT`


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