This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The colour of Mohr's salt, (NH_4)_2SO_4 Fe(SO_4).6H_2O is : |
| Answer» Answer :B | |
| 2. |
The colour of liquid O_(2)is __________. |
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Answer» Red |
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| 3. |
The colour of light absorbed by an aqueous solution of CuSO_(4) is…. |
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Answer» Orange-red |
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| 4. |
The colour of lead chromate is : |
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Answer» Red |
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| 5. |
The colour of lanthoanoids and actinoids is dueto : |
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Answer» s-f TRANSITIONS |
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| 6. |
The colour of KMnO_(4) is due to |
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Answer» `L RARR M` charge TRANSFER transition |
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| 7. |
The colour of KMnO_(4) is due to….. |
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Answer» `L RARR M` CHARGE TRANSFER transition |
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| 8. |
The colour of K_2Cr_2O_7 changes from redorange to lemon yellow on treatment with KOH(aq.) because of : |
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Answer» Reduction of CR (vi) to Cr (III) |
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| 9. |
ThecolourOf k_(2)Cr_(2)O_(7)and Fe^(2+)ions arerespectivelydue to |
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Answer» Crystaldefects andchargtransferspectra |
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| 10. |
The colour of I_2 is violet because it: |
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Answer» ABSORBS VIOLET light |
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| 12. |
The colour of FeSO_4.(NH_4)_2SO_4 6H_2O is: |
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Answer» Red |
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| 13. |
The colour of FeF_3 is: |
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Answer» Brown |
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| 14. |
The colour of CuCr_(2)O_(7) solutioin is water is green because |
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Answer» `Cr_(2)O_(7)^(2-)` IONS are GREEN |
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| 15. |
The colour of copper sulphide is : |
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Answer» Solution :CuSobtainedas ppt. with `H_2S` is black . `Cu^(2+) + H_2S to UNDERSET("Black")(CuS) + 2H^(+)` |
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| 16. |
The colour of d-block elements is due to : |
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Answer» <P>ND-(n + 1)s transition |
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| 17. |
The colour of [Cr(H_(2)O)_(6)]^(3+) is…. |
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Answer» Violet |
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| 18. |
The colour of Co(H_(2)O)_(6)^(2+) is best attributed to electronic transitions : |
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Answer» between different n levels in the METAL. |
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| 19. |
The colourof CoCl_(3).5NH_(3).H_(2)O is |
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Answer» ORANGE yellow |
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| 20. |
The colour of CoCl_(3).5NH_(3).H_(2)O is |
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Answer» ORANGE yellow |
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| 21. |
The colour of an electrolytesolution depends on |
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Answer» The NATURE of the anion e.g. `CuSO_(4)` is blue because `CU^(2+)` ions are blue. |
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| 22. |
The colour of blue glass is due to the presence of the oxide of : |
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Answer» Cr |
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| 23. |
The colour in the coordination compounds can be readily explained in terms of crystal field theory. Consider, for example, the complex [Ti(H_(2)O)_(6)]^(3+), which is violet in colour. This is an octahedral complex where the single electron [Ti^(3+) is a 3d^(1) system] in the metal d-orbital is in the t_(2g) level in the ground state of the complex. The next higher state available for the electron is the empty e_(g) level. If light corresponding to the energy of blue-green region is absorbed by the complex, it would excite the electron from t_(2g) level to the e_(g) level (t_(2g)^(1)e_(g)^(0)to t_(2g)^(0)e_(g)^(1)). Consequently, the complex appears violet in colour. The crystal field theory attributes the colour of the coordination compounds to d-d transition of the electron. It is important to note that in the absence of ligand, crystal field splitting does not occur and hence the substance in colourless. For example, removal of water from [Ti(H_(2)O)_(6)]Cl_(3) on heating renders it colourless. Similarly, anhydrous CuSO_(4) is white, but CuSO_(4).5H_(2)O is blue in colour. What will happen to [Ti(H_(2)O)_(6)]Cl_(3) on heating ? |
| Answer» Solution :It will become colourless because `H_(2)O` molecules which ACT as ligands are REMOVED on HEATING. | |
| 24. |
The colour in the coordination compounds can be readily explained in terms of crystal field theory. Consider, for example, the complex [Ti(H_(2)O)_(6)]^(3+), which is violet in colour. This is an octahedral complex where the single electron [Ti^(3+) is a 3d^(1) system] in the metal d-orbital is in the t_(2g) level in the ground state of the complex. The next higher state available for the electron is the empty e_(g) level. If light corresponding to the energy of blue-green region is absorbed by the complex, it would excite the electron from t_(2g) level to the e_(g) level (t_(2g)^(1)e_(g)^(0)to t_(2g)^(0)e_(g)^(1)). Consequently, the complex appears violet in colour. The crystal field theory attributes the colour of the coordination compounds to d-d transition of the electron. It is important to note that in the absence of ligand, crystal field splitting does not occur and hence the substance in colourless. For example, removal of water from [Ti(H_(2)O)_(6)]Cl_(3) on heating renders it colourless. Similarly, anhydrous CuSO_(4) is white, but CuSO_(4).5H_(2)O is blue in colour. Which theory explains the colour of coordination compounds ? |
| Answer» Solution :CRYSTAL field theory explains the COLOUR of COORDINATION COMPOUNDS. | |
| 25. |
The colour in the coordination compounds can be readily explained in terms of crystal field theory. Consider, for example, the complex [Ti(H_(2)O)_(6)]^(3+), which is violet in colour. This is an octahedral complex where the single electron [Ti^(3+) is a 3d^(1) system] in the metal d-orbital is in the t_(2g) level in the ground state of the complex. The next higher state available for the electron is the empty e_(g) level. If light corresponding to the energy of blue-green region is absorbed by the complex, it would excite the electron from t_(2g) level to the e_(g) level (t_(2g)^(1)e_(g)^(0)to t_(2g)^(0)e_(g)^(1)). Consequently, the complex appears violet in colour. The crystal field theory attributes the colour of the coordination compounds to d-d transition of the electron. It is important to note that in the absence of ligand, crystal field splitting does not occur and hence the substance in colourless. For example, removal of water from [Ti(H_(2)O)_(6)]Cl_(3) on heating renders it colourless. Similarly, anhydrous CuSO_(4) is white, but CuSO_(4).5H_(2)O is blue in colour. Why is anhydrous CuSO_(4) white but CuSO_(4) dissolved in water gives a blue solution ? |
| Answer» Solution :In the absence of WATER (ligands), there is no splitting and no excitation of electrons. HENCE it is WHITE. When dissolved in water, they act as ligands, splitting of ORBITALS takes PLACE and excitation of electrons takes place and colour is produced. | |
| 26. |
The colour in the coordination compounds can be readily explained in terms of crystal field theory. Consider, for example, the complex [Ti(H_(2)O)_(6)]^(3+), which is violet in colour. This is an octahedral complex where the single electron [Ti^(3+) is a 3d^(1) system] in the metal d-orbital is in the t_(2g) level in the ground state of the complex. The next higher state available for the electron is the empty e_(g) level. If light corresponding to the energy of blue-green region is absorbed by the complex, it would excite the electron from t_(2g) level to the e_(g) level (t_(2g)^(1)e_(g)^(0)to t_(2g)^(0)e_(g)^(1)). Consequently, the complex appears violet in colour. The crystal field theory attributes the colour of the coordination compounds to d-d transition of the electron. It is important to note that in the absence of ligand, crystal field splitting does not occur and hence the substance in colourless. For example, removal of water from [Ti(H_(2)O)_(6)]Cl_(3) on heating renders it colourless. Similarly, anhydrous CuSO_(4) is white, but CuSO_(4).5H_(2)O is blue in colour. Out of the t_(2g) and e_(g) d-orbitals, which has a higher energy? |
| Answer» SOLUTION :`e_(g)` ORBITALS have higher ENERGY. | |
| 27. |
The colour in the coordination compounds can be readily explained in terms of crystal field theory. Consider, for example, the complex [Ti(H_(2)O)_(6)]^(3+), which is violet in colour. This is an octahedral complex where the single electron [Ti^(3+) is a 3d^(1) system] in the metal d-orbital is in the t_(2g) level in the ground state of the complex. The next higher state available for the electron is the empty e_(g) level. If light corresponding to the energy of blue-green region is absorbed by the complex, it would excite the electron from t_(2g) level to the e_(g) level (t_(2g)^(1)e_(g)^(0)to t_(2g)^(0)e_(g)^(1)). Consequently, the complex appears violet in colour. The crystal field theory attributes the colour of the coordination compounds to d-d transition of the electron. It is important to note that in the absence of ligand, crystal field splitting does not occur and hence the substance in colourless. For example, removal of water from [Ti(H_(2)O)_(6)]Cl_(3) on heating renders it colourless. Similarly, anhydrous CuSO_(4) is white, but CuSO_(4).5H_(2)O is blue in colour. Show diagrammatically the excitation of electron in the coordination compound [Ti(H_(2)O)_(6)]^(3+). |
Answer» SOLUTION :
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| 28. |
The colour imparted by excess potassium in KCI crystal is͟͟͟͟͟͟͟͟ |
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Answer» |
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| 29. |
The colour given to the flame by sodium salts is |
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Answer» LIGHT RED |
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| 30. |
The colour given to the flame by sodium salt is |
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Answer» Violet |
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| 31. |
The colour exhibited by one of the iron ions in aqueous solutions is pale green. The primary valency and secondary valency respectively in the green complex are |
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Answer» 2,4 |
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| 32. |
Thecolour developedwhensodiumsulphide is added to sodium nitroprusside is |
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Answer» VIOLET |
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| 33. |
The colour developedwhen Na_(2)S is added to Na_(2)[Fe(CN)_(5)(NO)] is, |
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Answer» Violet |
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| 34. |
The colour chage observed when excess ethyne is passed through the solution of bromine water is |
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Answer» COLOURLESS to REDDISH BROWN |
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| 35. |
The color of KMnO_(4) is due to : |
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Answer» `M to L` charge transfer |
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| 36. |
The colloidal system sonsisting of a liquid adsorbate in a solid adsorbent is termed as: |
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Answer» AERSOL |
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| 37. |
The colloiidal dispresion of a liquid in another liquid is called…………and the substance added to stabilized it is called………… |
| Answer» SOLUTION :EMULSION, EMULSIFIER | |
| 38. |
The colour and magnetic nature of manganate ion (MnO_(4)^(2-)) is |
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Answer» green, process |
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| 39. |
The colloidal system in which the disperse phase and dispersion medium are both liquids is known |
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Answer» a gel |
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| 40. |
The colloidal system consisting of a liquid adsorbete in a solid adsorbent is termed as: |
| Answer» ANSWER :D | |
| 41. |
The colloidal system in which the disperse phase and dispersion medium are both liquids is known as : |
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Answer» a gel |
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| 42. |
The colloidal suspension of milky rubber with water is called ....................... |
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Answer» LATEX |
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| 43. |
Colloids are purified by |
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Answer» Peptisation |
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| 44. |
The colloidal gold is obtained by ......... |
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Answer» peptisation |
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| 45. |
The colloidal sol of cellulose nitrate in ethyl alcohol is called…………. |
| Answer» SOLUTION :COLLODION | |
| 46. |
The colloid used for stomach disorder is_______. |
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Answer» COLLOIDAL silver |
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| 47. |
The colligative property of a sol compared to the aqueous solution of glucose of same concentration will be: |
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Answer» MUCH smaller |
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| 48. |
The colligative properties of a solution are |
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Answer» `prop` molality |
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| 49. |
The colligative properties of a solution depend on : |
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Answer» NUMBER of SOLUTE PARTICLES PRESENT in it |
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