Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The coenzymes are derived from :

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VITAMINS
LIPIDS
HORMONES
Carbohydrates.

Answer :A
2.

The coefficients x, y and z in the following balanced equation : xZn+yNO_(3)^(-)tozZn^(2+)+NH_(4)^(+) (in basic medium) are

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`4,1,4`
`2,2,2`
`4,2,4`
`4,4,4`

ANSWER :A
3.

The coefficient of viscosity of a solution and its solvent are respectively etaand eta_(0). The specific viscosity eta_(sp)may be expressed as:

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`ETA/eta_(0)`
`(eta-eta_(0))/eta_(0)`
`(eta-eta_(0))/eta`
`eta_(0)/eta`

ANSWER :B
4.

The CoCl_(2) lattice is

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BODY centred cubic closed pack
Body centred TETRAGONAL
There are 16 formula units PER unit cell.
The number of molecules which the basis consist is 2

Solution :Choice (a) is correct because in `CaCl_(2)` there is a body centred cubic closed packing.
Choice (B) is correct because there is tetragonal body centre observed.
Choice (c) is also correct because there are 16 `CaCl_(2)` present in one `CaCl_(2)` unit lattice.
5.

The coal tar fraction which contains phenol is

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 MIDDLE OIL
GREEN oil
 HEAVY oil
 LIGHT oil.

Answer :A
6.

The coal form containing maximum percentage of carbon is:

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Lignite
Anthracite
Bituminous
Peat

Answer :B
7.

The coagulation valus of the electrolytes AlCl_(3) and NaCl for As_(2)S_(3) sol are 0.093 and 52 respectively. How many times has AlCl_(3) greater coagulating power than NaCl ?

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Solution :It may be noted that the coagulating POWERS of the electrolytes are inversely proportionsl to their coagulating VALUE. THUS, `("coagulating power of" AlCl_(3))/("Coagulating power of NaCl")=(52)/(0.093)=559`
Thus, coagulating power of `AlCl_(3)` is 559 times more than that of NaCl.
8.

The coagulation values of the electrolytes AlCl_3 and NaCl for As_2S_3 sol are 0.093 and 52 respectively. How many times AlCl_3 has greater coagulating power than NaCl

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SOLUTION :It MAY be noted that the coagulating POWERS of the ELECTROLYTES are inversely proportional to their coagulating VALUES. Thus,
`(Coagu lati ng power of AlCl_3)/(Coagu lati ng power of NaCl)=52/0.093=559`
Thus, coagulating power of `AlCl_3` is 559 times more than that of NaCl.
9.

The coagulation values in millimoles per litre of the electrolytes used for the coagulation of As_(2)S_(3) are given : I. (NaCl) = 52 II. (BaCl_(2)) = 0.69 "" III. (MgSO_(4)) = 0.22 Correct order of their coagulating power is

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IgtIIgtIII
IIgtIgtIII
IIIgtIIgtI
IIIgtIgtII

Answer :C
10.

The coagulation values of AICI_(3) and NaCI are 0.093 and 52 respectively . Then coagulating power of AICI_(3) as compared to that of NaCI is

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`52xx0.093` times
`52//0.093` times
`0.093 //52` times
`52-0.093` times

Solution :`("COAGULATION power of NACI")/("Coagulation power of AICI"_(3))`
11.

The coagulation values in millimolesper litreof the electrolytes used for the coagulation of AS_2S_3 are given below (I) (NaCl)=52 (II) (BaCl)=0.69 (III) (MgSO_4)=0.22 The correct orderof their coagulating poweris ................

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`III GT II gt I `
`I gt II gt III`
`I gt III gt II `
`II gt III gt I`

Solution :`III gt II gt I`
coagulating power `pm""(1)/(" COAGULATION VLAUE ")`
12.

The coagulation values in millimoles per litre of the electrolytes used for the coagulation of As_(2)S_(3) are given below : I. (NCl) = 52 , II. (BaCl_(2)= 0.69 III. (MgSO_(4)) = 0.22 The correct order of their coagulating power is -

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`III GT I gt II`
`I gt II gt III`
`II gt I gt III`
`III gt II gt I`

ANSWER :D
13.

The coagulation values in millimoles per litre of the electrolytes used for the coagulation of As_(2)O_(3) are given below : I(NaCl)=52, II(BaCl_(2))=0.69,III (MgSO_(4))=0.22 The correct order of their coaguolating power is

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`III GT II gt I`
`IIII gt I gt II`
`I gt II gt III`
`II gt Igt III`

Solution :Coagulating POWER `prop (1)/("Coagulation value")`
Hence, the order is `III gt II gt I.`
14.

The coagulation value in millimoles per litre of the electrolyes used for the coagulation of As_(2)S_(3) are given below: I. (NaCl)=52 ,II. (BaCl_(2))=0.69 III. (MgSO_(4))=0.22 The correct order of their coagulating power is

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III GT I gt II
I gt II gt III
II gt I gt III
III gt II gt I

Answer :D
15.

The coagulation values in milimoles per litre of the electrolytes used for the coagulation of As_(2)S_(3) are given below : (I) NaCl=52 (II) BaCl_(2)=0.69 (III) MgSO_(4)=0.22 The correct order of their coagulating power is

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III gt II gtI
III gt I gt II
I gt II gt III
II gt I gt III 

Solution :COAGULATION POWER `prop (1)/("Coagulation VALUE")
So, the order is III > II > I
16.

The coagulation values in millimoles per litre of the electrolytes used for the coagulation of As_2 S_3are given below (I) (NaCl) = 52 (II) (BaCl_2) = 0.69 (III) (MgSO_4) = 0.22 The correct order of their coagulating power is

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`IIIgtIIgtI`
`IgtIIgtIII`
`IgtIIIgtII`
`IIgtIIIgtI`

Solution :Hint : COAGULATING POWER `+-(1)/("COAGULATION VALUE")`
17.

The coagulation power of an effective ion carrying the charge opposite to the sol particles has been illustrated by

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Brownian MOVEMENT
GOLD number
Tyndal effect
Hardy-Schulz rule

Answer :D
18.

The coagulation power of an electrolyte for arsenous suphide sol is maximum for :

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`AlCl_3`
`Na_3PO_4`
`K_4[FE(CN)_6]`
`HCL`

ANSWER :A
19.

The coagulation of colloidal particles of the sol can be caused by

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HEATING
ADDING oppositely CHARGED sol
Adding ELECTROLYTE
All the above

ANSWER :D
20.

The coagulation of 100ml gold sol is completely prevented by adding 0.25g of starch to it before adding 10ml of 10% NaCl solution. Calculate the gold number of starch.

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Solution :10ml of 10% NaCl solution is added to 100ml of gold SOL. THUS, 1ml of 10% NaCl has been added to each 10ml of gold sol.
Weight of starch REQUIRED for 100ml gold sol=0.25g =250MG and in 10ml sol=25mg.
Gold number of starch =25.
21.

For the coagulation of 100ml of a positive sol 10mlof 1M sodium chloride is required. Calculate the flocculation value.

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0.365 
36.5 
100 
200 

SOLUTION :`200 RARR 0.73 gr : 1000 rarr ? `
3.65 gr of HCI=0.1 mole = 100 MILLI mole
22.

The coagulation of 100 mL of a colloidal solution of gold is completely prevented by adding 0.25 g of starch to it before adding 10 mL of 10% NaCl solution. Find out the gold number of starch.

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SOLUTION :10 mL of 10% NaCl solution is added to 100 mL of solution of gold.
Thus, 1 mL of 10% NaCl solution has been added to 10 mL solution of gold.
SINCE, 100 mL gold solution required = 0.25 g starch
`=0.25xx10^(3)` mg starch
So, 10 mL gold solution required
`=(0.25 xx 10^(3))/(100)xx10`
`=25 mg` starch
Thus, by definition, the gold NUMBER of starch is 25.
23.

The coagulation of 10 ml of colloidal solution of gold is completely prevented by addition of0.25 g of a substance "X"to it before addition of 1 mlof10% NaCl solution. The gold number of "X"is

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ANSWER :250
24.

The coagulation of 10 ml of gold sol is just prevented on adding 1 ml solution of 10% NaCl in the presence of 0.025 g of starch. The gold number of starch is:

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`0.25`
`0.025 `
`2.5 `
`250.`

Solution :MILLIGRAMS of STARCH used `0.025 xx 1000= 25` MG`
25.

The coagulation of 100 ml gold sol is completely prevented by adding 0.25 g of starch to it before adding 10 ml of 10% NaCl solution. Calculate the gold number of starch.

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SOLUTION :GOLD no is EXPRESSED in m.GR = 0.005 gr = 5 m.gr
26.

The coagulating power of electrolytes having ions Na^(+), Al^(3+) and Ba^(2+) for arsenic sulphide sol increases in the order :

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`AL^(3+) LT BA^(2+) lt Na^(+)`
`NA^(+) lt Ba^(2+) lt Al^(3+)`
`Ba^(2+) lt Na^(2+) lt Al^(3+)`
`Al^(3+) lt Na^(+) lt Ba^(+)`

Solution :`NA^(+) lt Ba^(2+) lt Al6(3+)`
27.

The coagulating power of an electrolyte for blood decrease in the order.

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`Na^(+), AL^(+3), Ba^(+2)`
`PO_(4)^(-3), SO_(4)^(-2), CL^(-)`
`Al^(+3), Ba^(+2), Na^(+)`
`Cl^(-),SO_(4)^(2-), PO_(4)^(-3)`

Answer :C
28.

The coagulating power of clcctrolytcs having inos Na ^(+), Al ^(3+) and Ba ^(2+) for arsenic culphide sol increase in the order :

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`AL^(3+) lt Na^(+) lt Ba^(2+)`
`Al^(3+) lt Ba^(2+) lt Na^(+)`
`Na^(+) lt Ba^(2+) lt Al^(3+)`
`Ba^(2+) lt Na^(+) lt Al^(3+)`

ANSWER :C
29.

The coagulating power of an electrolyte for arsenious sulphide decreases in the order

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`Na^(+) gt AL^(3+) gt Ba^(2+)`
`PO_4^(3-) gt SO_4^(2-) gt CL^(-)`
`Cl^(-) gt SO_4^(2-) gt PO_4^(3-)`
`Al^(3+) gt Be^(2+) gt Na^(+)`

Answer :D
30.

The coagulating power of an electrolyte for arsenious sulphide sol decreases in the order:

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`Na ^(+) GT Al ^(3+) gt Ba ^(2+)`
`PO _(4) ""^(3-) gt SO _(4)^(2-) gt Cl ^(-)`
`Cl ^(-) gt SO _(4) ^(2-) gt PO _(4) ^(3-)`
`Al ^(3+) gt Ba ^(2+) gt Na ^(+)`

Solution :`As _(2) S _(3)` is a negative sol and therefore coagulating power DECREASES as `Al ^(3+) gt Ba ^(2+) gt Na ^(+)`
31.

The coagulating power of an electrolyte for Aresenious sulphide sol decreases in the order

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`Na^(+)gtAl^(3+)gtBa^(2+)`
`PO_(4)^(3-)gtSO_(4)^(2-)GTCL^(-)`
`CL^(-)gtSO_(4)^(2-)gtPO_(4)^(3-)`
`Al^(3+)gtBe^(2+)gtNa^(+)`

ANSWER :D
32.

The co-ordination numbre of the metal in sodium nitro prusside is

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Solution :`Na_(2)[Fe(CN)_5NO],` Co-ordination No = 6
33.

The co-ordination number of the element M in the complex M(DMG)_(2) ( where DMG is dimethylglyoxime ?

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SOLUTION :
34.

The co-ordination number of the central ion may be obtained from:

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The NUMBER of IONIC bonds FORMED with the surrounding atoms
The number of Co-ordinate bonds formed with the surrounding atoms
The number of ions of opposite CHARGE immediately surrounding the SPECIFIC ion
None of the above

Answer :B
35.

The co-ordination number of Ni in [Ni(H_2O)_6]^(2+) complex is :

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2
4
6
5

Answer :C
36.

The co-ordination number of Cu in Cu(NH_3)_4^(2+) is:

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4
5
3
6

Answer :A
37.

The co-ordination number of Cu in copper ammonium sulphate is:

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2
4
3
6

Answer :B
38.

The co-ordination number of Cr in [Cr(NH_3)_3(H_2O)_3]Cl_3 is:

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3
4
6
2

Answer :C
39.

The co-ordination number of copper which crystallise in close-packed structure is…

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12 
4 

Answer :C
40.

The co-ordination number of copper in the complex formed by adding excess of NH_3 to CuSO_4 solution is:

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4
2
6
5

Answer :A
41.

The co-ordination number of cobalt in[Co(en)_2Br_2]Cl_2 is :

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2
4
6
8

Answer :C
42.

The coordination number of cobalt in [Co(NH_(3))_(3)Cl_(3)] is

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6
5
4
3

Answer :A
43.

The co-ordination number of Al in Al_(2)Cl_(6) is

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ANSWER :4
44.

The co-ordination number of a central metal atom in a complex is determined by :

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the number of only ANIONIC ligands BONDED to metal ion
the number of ligands around a metal ion bounded by pi bonds
the number of ligands around a metal ion bondedby SIGMA and pi-bonds
the number of ligands around a metal ion bonded by sigma bonds

Answer :C
45.

The co-ordination number of a metal crystallising in a hexagonal close paced structure is :

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12
4
8
6

Answer :A
46.

The co-ordination number in ccp and hcp arrangement of metal atoms are respectively

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6,6
12,6
12,12
8,6

Solution :The coordination number in both ccp and HCP arrangement of METAL atoms is 12.
47.

The co-ordination number and the oxidation state of the element .M. in the complex [M(en)_2(C_2O_4)] NO_2 {where (en) is ethan-1, 2-diamine} are respectively

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6 and 3
6 and 2
4 and 2
4 and 3

Solution :(a) For the GIVEN COORDINATE compound, `[M(en)_2(C_2O_4)]NO_2`
(i) All the (3) lignnds are bi dented thus is coordinate NUMBER - 6
`X+0+2 xx (-2) = 0 -1`
`THEREFORE` x(Oxidation number ofM) = +3
`therefore` Option (a) is the correct answer.
48.

The co-ordination number and the oxidation state of the element 'M' in the complex [M(en)_2(C_2O_4)]NO_2 [where (en) is ethan-1, 2 diamine] are respectively

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6 and 3
4 and 3
6 and 2
4 and 2

ANSWER :A
49.

The co-ordination number and the oxidation state of the element E in the complex. are respectively ?

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6 and 3
6 and 2
4 and 2
4 and 3

Solution :CN of E = 6 , OXIDATIOIN state of E(x)
x + `2(0)` + - 2 = +1
x = +1 +2 = +3
50.

The co-ordinationnumber and the oxidation state of an element 'E' in the complex [E(en)_(2)(C_(2)O_(4))]NO_(2) (where (en) is ethylene diamine), respectively are

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6 and 3
6 and 2
4 and 2
4 and 3

ANSWER :A