Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Tautomerism is not exhibit by:

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ANSWER :D
2.

Tautomerism is exhibited by -

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ALLTHE above

Answer :D
3.

Tautomerism is exhibited by:

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ANSWER :A::C
4.

Tautomerism is exhibited by :

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SOLUTION :N/A
5.

Tautomerism is exhibited by-

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`(Me_(3)C CO)_(3)CH`


SOLUTION :
6.

Tautomerism is/are exhibited by

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`(Me_(3)"CCO")_(3)` CH


SOLUTION :(a, b, d): TAUTOMERISM is exhibited by molecules CONTAINING one or more `alpha`-HYDROGEN (s).
7.

Tautomer of ethyl methyl ketone is

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but -2- EN -2-ol
but -2- en - 1- ol
but -2- en -1- OIC
PROP -1- en -2- ol

ANSWER :A
8.

Tartronic acid is obtained from tartaric acid by :

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HBr
HI
Tollen's REAGENT
`PCl_5`

ANSWER :C
9.

Tartaric acid [HO_(2)CCH(OH)CH(OH)CO_(2)H] was an important compound in history of stereochemistry. Two naturally occuring formsof tartaric acid are optically inactive. One optically inactive form (P) has a melting point of 210-212^(@)C and can be separated into two optically acitve forms, whereas other optically inactive form (Q) cannot be resolved further. A optically inactive form P is :

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OPTICALLY inactive due to INTERNAL compensation.
Optically inactive due to presence of PLANE of symmetry.
Optically inactive due to external compensation.
Optically inactive due to intramoleuclarhydrogen bonding.

ANSWER :C
10.

Tartaric acid is a weak diprotic acid with K_1 = 1 xx 10^(-3)and K_2 = 4.6 xx 10^(-5) .(a) Letting the symbol H_2Arepresent tartaric acid, write the chemical equationsthat represent K_1 and K_2. Write the chemical equation that represents K_1 xx K_2.(b) Qualitatively describe the relative concentrations of H_2A , HA^(-) , A^(2-)and H_3O^+in a solution that is about 0.5 M in tartaric acid.(c) Calculate the pH of a 0.025 M tartaric acid solution and the equilibrium concentration of H_2A(d) What is the A^(2-) concentration?

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SOLUTION :
11.

Tartaric acid [HO_(2)CCH(OH)CH(OH)CO_(2)H] was an important compound in history of stereochemistry. Two naturally occuring formsof tartaric acid are optically inactive. One optically inactive form (P) has a melting point of 210-212^(@)C and can be separated into two optically acitve forms, whereas other optically inactive form (Q) cannot be resolved further. Optically inactive form Q is

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NONE of these

Answer :B
12.

Tartaric acid is not used in :

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DYEING CLOTHES
COSMETICS
PHOTOGRAPHY
medicines

Answer :D
13.

Tars'are produced due to oxidationwhile ______ ofaniline

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Bromination
SULPHONATION
NITRATION
HYDROLYSIS

ANSWER :C
14.

Tarnishing of silver is an example of

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rusting
CORROSION
OXIDATION
reduction

SOLUTION :Tarnishing of silver is CALLED corrosion .
15.

Tantalum and nobonium have sinmilar ionic radii because

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of diagonal relationship
both are in same group
the have same chemical PROPERTIES
of LANTHANIDE CONTRACTION

Answer :D
16.

Tanning of leather is

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colouring of LEATHER by CHEMICALS
drying PROCESS to make the leather hard
polishing of leather to make it took attractive
HARDENING of leather by COAGULATION

Solution :Tannin obtained from plants contains negatively charged colloidal particles. Animal hides contain positlvely charge darticles. When they are socked in tannin, mutual coagulation takes and leather becomes hard.
17.

Tanning makes leather get hardened - Explain why?

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Solution :Skin and hides are protein containing POSITIVELY charged particles which are coagulated by adding TANNIN which is negatively charged to GIVE HARDENED LEATHER for further application.
18.

Tamarind contains :

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(+) TARTARIC ACID
(-) tartaric acid
Citric acid
LACTIC acid

ANSWER :A
19.

Taking two examples of heterogeneously calalytic reaction, explain how a heterogeneous catalyst helps in the reaction.

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Solution :When the reactants and products are in different physical state from the catalyst, it is a case of heterogeneous catalysis. `V_2O_5` and Pt are heterogeneous CATALYSTS in Contact PROCESS and Ostwald Process, respectively.
(i) Contact Process : `2SO_2(G) + O_2(g) overset(V_2O_5)iff 2SO_3(g)`
(ii) Ostwald.s Process : `4NH_3(g) + 5O_2 (g) underset(1120K) overset(Pt)to 4NO(g) + 6H_2O (g)`
Reacting gases get adsorbed on heterogeneous solid catalyst, their concentration on the surface increases and probability of collisions increases which result in increase in number of effective collisions, RESULTING in increase in rate of reaction.
Products FORMED get desorbed from the catalyst and more reacting gases get adsorbed and react leading the formation of more products.
20.

Talc contains which of the following

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Zinc, calcium and OXYGEN
Calcium , oxygen and tin
MAGNESIUM , silicon and oxygen
Zinc, tin and sulphur

SOLUTION :Talc is `Mg_(3)(OH)_(2)Si_(4)O_(10)`.
21.

Taking N_(2) and O_(2) as main compounts of air (79% N_(2),21%O_(2) by volume ) what is the molecular mass of air? How has it been arrived at ?

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Solution :For a mixture of GASES, the average molecular mass is taken.
`"Average molecular mass "=Sigmax_(i)M_(i)=x_(N_(2))M_(N_(2))+x_(O_(2))M_(O_(2))` where `x_(N_(2)) and x_(O_(2))` are mole fractions of `N_(2)` MOLES, therefore, their MOLAR ratio is same as ratio of their volumes.
`therefore x_(N_(2))=0.79,x_(O_(2))=0.21.` Also `M_(N_(2))=28u, M_(O_(2))=32U`
`therefore"Average molecular mass "=0.79xx28+0.21xx32u=22.12+6.72u=28.84u`
22.

Taking the example of Al_(2)(SO_(4))_(3), derive the relation between molar conductivity and equivalent conductivity.

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SOLUTION :Molar conductivity, `wedge_(m)=(kappaxx1000)/(c_(m)("Molarity"))`, Equivalent conductivity, `wedge_(eq)=(kappaxx1000)/(c_(eq)("Normality"))`
Eq. wt. of `Al_(2)(SO_(4))_(3)=(Mol." " wt.)/(6)` (Total +ve VALENCY of AL in `Al_(2)(SO_(4))_(3)=6`) `therefore`Normality`=6xx`Molarity
Hence, `(wedge_(m))/(wedge_(eq))=("Normality")/("Molarity")=6` or `wedge_(m)=6wedge_(eq)`
Alternatively, `wedge_(eq)=(wedge_(m))/(v_(+)z_(+))=(wedge_(m))/(2xx3)=(wedge_(m))/(6)`
23.

Taking CFSE value of octahedral complex (Delta_(0)) as 10 Dq, the e_(g) orbitals are …… Dq above the bari centre

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SOLUTION :The `e_(G)` ORBITALS are 6 Dq above the BARI centre.
24.

Tailing of mercury can be removed by :

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`H_2O_2`
`O_3`
`O_2`
NONE of these

Answer :A
25.

Taj mahal is thretened by pollution from

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Oxygen
CARBOND DIOXIDE
SULPHUR dioxide
Chlorine

SOLUTION :Chloroflurocarbons (CFCs)are the mainculpritsfor thedepletion ofozonelayer.
26.

Taj Mahal is threatened due to the effect of

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Chlorine
Sulphur dioxide
Oxygen
Hydrogen

Solution :`SO_2` combines with atmoshperic water vapours to PRODUCE ACIDS rains which imparts YELLOW colour to the WHITE MARBLE.
27.

Taj Mahal is threatened by pollution from :-

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Chlorine
Sulphur dioxide
Hydrogen
Oxygen

Answer :B
28.

Taj Mahal is threatened by pollution form:

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chrlorine
sulphur dioxide
hydrogen
oxygen

Answer :B
29.

Tailing of mercury is due to formation of _______.

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SOLUTION :mercurous OXIDE
30.

T_(50) of first - order reaction is 10 min . Starting with 10 mol L^(-1) , rate after 20 min is

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`0.0693` mol `L^(-1) "min"^(-1)`
`0.0693 xx 2.5 mol L^(-1) "min"^(-1)`
`0.0693 xx 5 mol L^(-2) "min"^(-1)`
`0.0693 xx 10 mol L^(-1) "min"^(-1)`

SOLUTION :`T_(50) = 10` min
K = 0.693/10 = 0.0693 `"min"^(-1)`.
CONCENTRATION at starting = 10 M
Concentration after 20 min (two half-lives) = 2.5 M
`((dx)/(dt)) = k[A] = 0.0693 xx 2.5` mol `L^(-1) "min"^(-1)`.
31.

t_(1//4) can be taken as the time taken for the concentration of a reactant to drop to 3//4 of its initial value. If the rate constant for a first order reaction is k, the t_(1//4) can be written as

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`0.10//k`
`1.4//k`
`0.29//k`
`0.75//k`

ANSWER :B
32.

t_(1//4) can be taken as the time taken for the concentration of a reactant of drop to (3)/(4) of its initial value. If the rate constant for a first order reaction is K, then t_(1//14) can be written as

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`0.10//K`
`0.29//K`
`0.69//K`
`0.75//K`

SOLUTION :`t_(1//4) = (2*303)/(k)LOG (a)/((3//4)a) = (2*303)/(K)log ""(4)/(3)`
`=(2*303xx 0*125)/(K) = (0*29)/(K)`
33.

t_(1//2) of the reaction increases with increases in initial concentration of the reaction means the order of reaction will be ......

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FIRST ORDER
zero order
SECOND order
third order

Answer :B
34.

(t_(1))/(4) can be taken as the time taken for the concentration of a reactant to drop to (3)/(4) of its initial value. If the rate constant for a first order reaction is k, the (t_(1))/(4) can be writen as

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`(075)/(K)`
`(0.69)/(k)`
`(0.29)/(k)`
`(0.10)/(k)`

Solution :`t_((1)/(4))=(2.303)/(k)"LOG"(1)/((3)/(4))=(2.303)/(k)"log"(4)/(3)=(2.303)/(k)("log"4-"log"3)=(2.303)/(k)(2"log"2-"log"3))=(2.303)/(k)(2times0.301-0.4771)=(0.29)/(k)`
35.

T_(1//2) " of "C^(14) isotope is 5770 years. Time after which 72% of isotope left is

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2740 YEARS
274 years
2780 years
278 years

Solution :`K = (0.693)/(T_(1//2)) = (0.693)/(5770)`
`:. t = (2.303)/(K)"LOG"(100)/(72) = (2.303 xx 5770)/(0.693) "log" (100)/(72)`
`= 19175.05 xx (log 100 - log 72)`
`19175.05 xx 0.143 = 2742.03` years
36.

t-Butyl chloride underset("cut")overset(u)toAoverset("n-Pentyl bromide")toB B is

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2-methyl heptane
2-methyl hexane
2,2-dimethyl heptane
2,2-dimethyl hexane

Answer :C
37.

T'shaped interhalogen is

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`ICL`
`ClF_3`
`BrF_5`
`IF_7`

ANSWER :B
38.

(T) impartsorange colour overset(compd (U) + conc. H_2SO_4)to (V) Red gas overset(NaOH + AgNO_3)to (W) Red ppt.overset(NH_3 soln.)to(X) (W) Red ppt. overset(dil. HCl)to(Y) white ppt. (U) undersetDeltaoverset(NaOH)to (Z) gas (gives white fumes with HCl)sublimes on heating . Identify (T) to (Z) .

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`T=KMnO_4 , U=HCl , V=Cl_2 , W=HgI_2 , X =Hg(NH_2)NO_3 , Y=Hg_2Cl_2, Z=N_2`
`T=K_2Cr_2O_7 , U=NH_4Cl , V=CrO_2Cl_2,W=Ag_2CrO_4 , X=[AG(NH_3)_2]^+ , Y=AgCl , Z=NH_3`
`T=K_2CrO_4 , U=KCl ,V=CrO_2Cl_2 , W=HgI_2 , X=Na_2CrO_4 ,Y=BaCO_3 , Z=NH_4Cl`
`T=K_2MnO_4 , U=NaCl ,V=CrO_3 , W=AgNO_2, X=(NH_4)_2CrO_4 , Y=CaCO_3 , Z=SO_2`

Answer :B
39.

(T) imparts violet colour in the flame test overset("compound"(U)+conc.H_(2)SO_(4))to(V)_("Red gas")overset(NaOH+AgNO_(3))to(W)_("Red ppt.")overset(NH_(3)" soln")to(X) (W)_("Red ppt.")overset(dil.HCl)to(Y)_("White ppt.") (U) Sublimes on heating underset(Delta)overset(NaOH)to(Z)_(gas) Identify (T) to (Z).

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`T=KMnO_(4),U=HCl,V=Cl_(2),W=HgI_(2),X=Hg(NH_(2))NO_(3),Y=Hg_(2)Cl_(2),Z=N_(2)`
`T=K_(2)Cr_(2)O_(7),U=NH_(4)Cl,V=CrO_(2)Cl_(2),W=Ag_(2)CrO_(4),X=[Ag(NH_(3))_(2)]^(+),Y=AgCl,Z=NH_(3)`
`T=K_(2)CrO_(4),U=KCl,V=CrO_(2)Cl_(2),W=HgI_(2),X=Na_(2)CrO_(4),Y=BaCO_(3),Z=NH_(4)Cl`
`Y=K_(2)MnO_(4),U=NaCl,V=CrO_(3),W=AgNO_(3),X=(NH_(4))_(2)CrO_(4),Y=CaCO_(3),Z=SO_(2)`

ANSWER :B
40.

t-butyl alcohol is heated with Al_2O_3 gives

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`CH_3CH=CHCH_3`
`CH_3CH_2CH=CH_2`
`(CH_3)_2C=CH_2`
all of these

Solution :`(CH_3)_3COH OVERSET(Al_2O_3)to (CH_3)_2C=CH_2+H_2O`
41.

(t)-2-Chloro-2-phenylethane in toluene racemises slowly in the presence of small amount of SbCl_(5). due to the formation of

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carbanion
carbene
free-radical
carbocation.

Solution :In presence of `SbCl_(5), `2-chloro-2-Phenlethane forms a carbocation as SHOWN below:
`CH_(3) - "CHCl" - C_(6) H_(5) + "SbCl"_(5) rarr [ CH_(3) - overset(+)(C)H - C_(6) H_(5) ] SbCl_(6)^(-)`
Since the carbocation is a planar species, therefore, it can be attacked by `SbCl_(6)`either from the top or the bottom face with EQUAL case. As a result, a 50: 50 mixture of two enantiomers of 2-chloro-2-phenylethane are FORMED, i.e., (+)-2-chloro-2- phenylethane undergoes racemization due to the FORMATION of carbocation intermediate.
42.

Systems which "has"//"have" not been correctly characterised is

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cubic, a = b = c, `alpha=beta=gamma= 90^@`
cubic, a = b =c, `alpha=beta=gamma NE 90^@`
MONOCLINIC , `a ne b ne c`, `alpha=gamma=90^@` `beta ne 90^@`
tetragonal, `a = b ne c`, `alpha=beta=gamma=90^@`.

Solution :cubic, a = b =c, `alpha=beta=gamma ne 90^@`
43.

Synthetic tranquillisersare mostly barbituric acid derivatives (e.g. veronal, luminal, seconal, amytal and nembutal). Other tranquillisers which are not barbituric acid derivatives are chlordiazepoxide, equanil meprobamate, valium (diazepam), etc. Opium alkaloids such as morphine and codeine are powerful analgesics (reduce pain). Heroin which is morphine diacetate is a widely used narcotic analgesic. Drugs which are used to cure diseases caused by microbes are called antimicrobials. These may be either sulpha drugs such as sulphapyridine, sulphadiazine, sulphaguanidine or they may be antibiotics. Antibiotics such as erythromycin, tetracycline, chloramphenicol which inhibit or arrest the growth of microbes are called bacteriostatic while others which kill the microbes are called bactericidal antibiotics. Which of the following is/are antibacterials ?

Answer»

PENICILLIN
Sulphapyridine
Ofloxacin
All

Answer :D
44.

Synthetic tranquillisersare mostly barbituric acid derivatives (e.g. veronal, luminal, seconal, amytal and nembutal). Other tranquillisers which are not barbituric acid derivatives are chlordiazepoxide, equanil meprobamate, valium (diazepam), etc. Opium alkaloids such as morphine and codeine are powerful analgesics (reduce pain). Heroin which is morphine diacetate is a widely used narcotic analgesic. Drugs which are used to cure diseases caused by microbes are called antimicrobials. These may be either sulpha drugs such as sulphapyridine, sulphadiazine, sulphaguanidine or they may be antibiotics. Antibiotics such as erythromycin, tetracycline, chloramphenicol which inhibit or arrest the growth of microbes are called bacteriostatic while others which kill the microbes are called bactericidal antibiotics. Among the following the narcotic analgesic is

Answer»

heroin
ibuprofen
naproxen
aspirin

Answer :A
45.

Synthetic tranquillisersare mostly barbituric acid derivatives (e.g. veronal, luminal, seconal, amytal and nembutal). Other tranquillisers which are not barbituric acid derivatives are chlordiazepoxide, equanil meprobamate, valium (diazepam), etc. Opium alkaloids such as morphine and codeine are powerful analgesics (reduce pain). Heroin which is morphine diacetate is a widely used narcotic analgesic. Drugs which are used to cure diseases caused by microbes are called antimicrobials. These may be either sulpha drugs such as sulphapyridine, sulphadiazine, sulphaguanidine or they may be antibiotics. Antibiotics such as erythromycin, tetracycline, chloramphenicol which inhibit or arrest the growth of microbes are called bacteriostatic while others which kill the microbes are called bactericidal antibiotics. Which of the following tranquillisers is not a derivative of barbituric acid ?

Answer»

Veronal
Equanil
Seconal
Luminal

Answer :B
46.

Synthetic tranquillisersare mostly barbituric acid derivatives (e.g. veronal, luminal, seconal, amytal and nembutal). Other tranquillisers which are not barbituric acid derivatives are chlordiazepoxide, equanil meprobamate, valium (diazepam), etc. Opium alkaloids such as morphine and codeine are powerful analgesics (reduce pain). Heroin which is morphine diacetate is a widely used narcotic analgesic. Drugs which are used to cure diseases caused by microbes are called antimicrobials. These may be either sulpha drugs such as sulphapyridine, sulphadiazine, sulphaguanidine or they may be antibiotics. Antibiotics such as erythromycin, tetracycline, chloramphenicol which inhibit or arrest the growth of microbes are called bacteriostatic while others which kill the microbes are called bactericidal antibiotics. The bactericidal and bacteriostatic antibiotics respectively are

Answer»

PENICILLIN, ofloxacin
Erythromycin, tetracycline
Penicillin, chloramphenicol
Tetracycline and penicillin

Answer :C
47.

Systamatic name of Pb-CH_(2)-COOH is:

Answer»

benzeneceticacid
phenylmethylcarboxylicacid
2-phenylethanoicacid
2-phenylmethanoicacid

Answer :C
48.

Synthetic testosterone promotes

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MENSTRUAL CYCLE
MUSCLE growth
Respiration
Birth CONTROL lagents

Answer :B
49.

Synthetic rubber is a vulcanisable rubber like polymer Write the method of preparation of the above synthetic rubber

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SOLUTION :
50.

Write two examples of synthetic rubber

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SOLUTION :NEOPRENE