Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Sulpha drugs work like antibiotics but they are not. Is this a valid statement and why ?

Answer»

Solution : This is a VALID STATEMENT since sulpha drugs LIKE antibiotics kill microorganisms. However, sulpha drugs are purely synthetic but antibiotics may be EITHER wholly or partially OBTAINED from microorganisms. For example, penicillin is wholly obtained from microorganisms while amoxycillin and ampicillin are semi-synthetic.
Discussion
2.

Sulphaguadine is used for

Answer»

Dysentery
Antiseptic
URINARY INFECTIONS
ANTIPYRETIC

ANSWER :A
Discussion
3.

Sulpha drugs work like antibiotics but they are not antibiotics. Is this a valid statement and why?

Answer»

Solution : This is a VALID statement since sulpha drugs like ANTIBIOTICS kill microorganisms. However, sulpha drugs are purely synthetic but antibiotics may be EITHER wholly or partially obtained from microorganisms. For example, PENICILLIN is wholly obtained from microorganisms while amoxycillin and ampicillin are semi-synthetic.
Discussion
4.

Sullphurdioxide can be used for …………….and…………….in agriculture.

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SOLUTION :DISINFECTING CROPS and PLANTS
Discussion
5.

Sulpha drugs are used for :

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Precipitating BACTERIA
REMOVING bacteria
Decreasing the SIZE of bacteria
Stopping the growth of bacteria

ANSWER :D
Discussion
6.

Sulpha drugs are derivatives of

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<P>BENZENE sulphonic acid
Sulphanilic acid
SULPHANILAMIDE
P- aminobenzoic acid

Answer :C
Discussion
7.

Sulfuric acid having concentration greater than 98.5% H_2SO_4cannot be obtained by distillation of an aqueous solution of H_2SO_4. Why?

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SOLUTION :Sulfuric acid having 98.5% `H_2SO_4` FORMS a constant boiling mixture having B.P. of 611 K. Hence, dilute sulfuric acid cannot be CONCENTRATED beyond 98.5% by distillation.
Discussion
8.

Sulfur disappears when boiled with sodium sulfite. Why?

Answer»

Solution :On boiling SULFUR with sodium sulfite, sulfur disappears DUE to the FORMATON of sodium thiosulfate.
`S + Na_2SO_3 OVERSET("Boil") RARR underset("Sodium thiosulfate")(Na_2S_2O_3)`
Discussion
9.

Which form of sulphur shows paramagnetic behaviour ?

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Solution :On boiling sulfur with SODIUM SULFITE, sulfur DISAPPEARS due to the formaton of sodium thiosulfate.
`S + Na_2SO_3 OVERSET("Boil") rarr underset("Sodium thiosulfate")(Na_2S_2O_3)`
Discussion
10.

Sulphur sol contains

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DISCRETE S- atoms
discrete S - molecules
large AGGREGATES of S - molecules
WATER dispersed in solid sulphur.

Solution : : sulphur SIL consists of particles contaning a thousand or more of `S_(8)` Sulphur molecules .
Discussion
11.

Suitable reagents A and B for the following reactions respectively are

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BR and `Br_(2)`
`Br_(2)` and NBS
NBS and NBS
NBS and `Br_(2)`

SOLUTION :
Discussion
12.

Suitable reaction to prepare chlorbenzene is

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SANDMEYER's REACTION
WURTZ reaction
Fittig reaction
Grignards reaction

Answer :A
Discussion
13.

Suggest two materials other than hydrogen that can be used as fuels in fuel cells.

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SOLUTION :METHANE and METHANOL.
Discussion
14.

Suggest two material other than hydrogen that can be used as fuels in fuels cells.

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SOLUTION :METHANE, METHANOL
Discussion
15.

Suggest the structure of nylon 2-nylon 6.

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Solution :Nylon 2-nylon 6 is a BIODEGRADABLE polymer.It is an alternating copolymer obtained by the condensation of glycine and AMINO caproic acid.
It is CHEMICALLY a polyamide. Structure of nylon 2- nylon 6 is given as :
`[--underset(H)underset(|)N-CH_(2)-underset(O)underset(||)C-underset(H)underset(|)N-(CH_(2))_(5)-underset(O)underset(||)--]_(n)`
Discussion
16.

Suggest the reagent for conversion of ethanol to ethanoic acid.

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Solution :`to` Acidified `KMnO_(4)` or acidified `K_(2)Cr_(2)O_(7)` oxidizes the ethanol to ethanoic ACID.
`CH_(3)CH_(2)OH overset([O])to CH_(3)CHO overset([O])to CH_(3)COOH`
Discussion
17.

Suggest the most important type of intermolecular interaction in the following pairs : (iv) methanol and acetone

Answer»

Solution :Both are POLAR MOLECULES. Hence, intermolecular INTERACTIONS in them will be dipole-dipole interactions.
Discussion
18.

Suggest the most important type of intermolecular interaction in the following pairs : (v) Acetonitrile (CH_(3)CN) and acetone (C_(3)H_(6)O).

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SOLUTION :Both are POLAR MOLECULES. Hence, intermolecular INTERACTIONS in them will be dipole-dipole interactions.
Discussion
19.

Suggest the most important type of intermolecular interaction in the following pairs : (iii) NaClO_(4) and water

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Solution :`NaClO_(4)` gives `NA^(+) and ClO_(4)^(-)` IONS in the solution while water is a polar MOLECULE. Hence, intermolecular interactions in them will be ion-dipole interactions.
Discussion
20.

Suggest the most important type of intermolecular interaction in the following pairs : (i) n-hexane and n-octane

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SOLUTION :Both are non-polar. Hence, INTERMOLECULAR interactions in them will be LONDON dispersion FORCES
Discussion
21.

Suggest the most important type of intermolecular interaction in the following pairs : (ii) I_(2) and "CCl"_(4)

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Solution :Both are non-polar. Hence, INTERMOLECULAR INTERACTIONS in them will be London DISPERSION FORCES
Discussion
22.

Suggest the most important type of intermolecular attractive interaction in the following pairs :(i) n - hexane and n - octane(ii) I_(2) and C Cl_(4)(iii) NaClO_(4)and water(iv) Methanol and acetone(v) Acetonitrile (CH_(3)CN)and acetone (C_(3)H_(6)O).

Answer»

Solution :(i) Van der wall FORCES of attraction as both are non - polar.
(ii) Van der Wall forces of attraction as they are non - polar.
(iii)ION - diople interaction as `NaClO_(4)` is IONIC in nature.
(iv) Dipole - dipole interaction as they are polar.
(v) Dipole - dipole interaction as they are polar.
Discussion
23.

Suggest the most important type of intermolecular attractive interaction in the following pairs : (i) n-hexane and n-octane(ii) I_2 and "CCl"_4 (iii) NaClO_4 and water (iv) methanol and acetone (v) acetonitrile (CH_3CN) and acetone (C_3H_6O).

Answer»

SOLUTION :(i) Both are non-POLAR. Hence, intermolecular interactions will be London DISPERSION forces.
(ii) Same as (i).
(iii) `NaClO_4`gives `NA^+` and `ClO_4^-`ions in the solution and water is a polar molecule. Hence,intermolecular interactions will be ion-dipole interactions.
IV) Both are polar molecules. Hence, intermolecular interactions in them will be dipole-dipole interactions.
(v) Same as (iv).
Discussion
24.

Suggest the most important type of intermolecular attractive interaction in the following pairs : (i) n-hexane and n-octane (ii) I_2 and C Cl_4 (iii) NaC1O_4 and water (iv) methanol and acetone (v) acetonitrile (CH_3 CN) and acetone (C_3H_6O).

Answer»

Solution :(i) van der Waal.s INTERACTIONS, (II) van der Waal.s interactions (III) ion-dipole (iv) HYDROGEN bonding (v) dipoledipole interactions.
Discussion
25.

Suggest the most important type of intermolecular attractive interaction in NaClO_(4) and water

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SOLUTION :Ion-dipole INTERACTION
Discussion
26.

Suggest the most important type of intermolecular attractive interaction in n - hexane and n-octane

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SOLUTION :VANDER WAALS INTERACTION
Discussion
27.

Suggest the most important type of intermolecular attractive interaction in I_(2) and C Cl_(4)

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SOLUTION :VANDER WAALS INTERACTION
Discussion
28.

Suggest reagents for the transformations CH_(3)Ito CH_(3)OH

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SOLUTION :`CH_(3)I OVERSET(NaOH)to CH_(3)OH`
Discussion
29.

Suggest reagents for the transformations

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SOLUTION :
Discussion
30.

Suggest reagents for the transformations

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SOLUTION :
Discussion
31.

Suggest reagents for the transformations

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SOLUTION :
Discussion
32.

Suggest onemethodfor separationof nickelfromcobalt ?

Answer»

Solution :CO ispassedover aheatedmixture ofNiand Co at330- 350KwhenNiformsvolatile` Ni(CO)_ 4`butCodoes not. The volatile` Ni(CO ) _4`isseparatedandthenheatedat450- 470 KtogetpureNi.
`underset ("IMPURE nickel")(Ni (s) ) +4CO(g)overset ( 330 - 350 K ) tounderset ("Nickeltetracarbonyl") (Ni(CO)_4(g)) overset (450- 470 K ) tounderset ("Purenickel") (Ni(s))+ 4CO(g) `
Discussion
33.

Suggest one method for carrying out anti-Markovnikov's addition of water indirectly to propylene. Give one example.

Answer»

Solution :Hydroboration-oxidation gives ALCOHOLS which correspond to anti-Markovnikov's addition of `H_(2)O` to alkenes.
`UNDERSET("propene")(6CH_(3)CH=CH_(2))underset(("Hydroboration"))overset(B_(2)H_(6)//THF)to underset("Tri-n-propylborane")(2(CH_(3)CH_(2)CH_(2))_(3)B) underset(("Oxidation"))overset(H_(2)O_(2)-NAOH)to underset("Propan-1-ol")(6CH_(3)CH_(2)CH_(2)OH)`
Discussion
34.

Suggest four ways in which the concentration of hydrazine, N_(2)H_(4), could be increased in an equilibrium described by the equation. N_(2)(g)+2H_(2)(g)hArrN_(2)H_()(g)DeltaH=95k J

Answer»

Solution :ADD `N_(2)`, add `H_(2)`, increase the PRESSURE, HEAT the reaction
Discussion
35.

Suggest epxplanation for the following The pK_(a1) for all of the dicarboxylic acids in Table 17.2 is smaller tyhan the pK_(a) for a monocarboxylic acid with the same number of carbon atoms.

Answer»

Solution :The CARBOXYL gropu is electron- withdwaring, THUS, in a dicarboxylic ACID such as those in Table 17.2 onecarboxylic acid group INCREASES the acidtiy of the other.
Discussion
36.

Suggest epxplanation for the following The difference between pK_(a1) and pK_(a2) for dicarboxylic acid of the type HO_(2)C(CH_(2))_(n)CO_(2)H decreases as n increases.

Answer»

SOLUTION :As the distance between the CARBOXYL gropus INCREASES, the acid-strengthening, inductive effect decreases.
Discussion
37.

Suggest appropriate reagents for following conversion.

Answer»

SOLUTION :.
Discussion
38.

Suggest appropriate structures for the missing compounds. (The number of carbon atoms remains the same throughout the reactions). underset(Delta)overset( dil KMnO_(4))rarr(A)overset(HIO_(4))rarr(B)overset(OH^(-))rarr(C)

Answer»


ANSWER :`(##ALN_CHM_C09(II)_E01_650_A01##)`
Discussion
39.

Suggest chemical reactions for the following conversions: (i) Cyclohexanol to Cyclohexylamine, (ii) 1-Hexanenitrile to 1-Aminopentane

Answer»

SOLUTION :
(ii) `CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)C-=N underset(("HYDROLYSIS"))OVERSET(H^(+)//H_(2)O)to underset("Hexanoic ACID")(CH_(3)(CH_(2))_(4)COOH overset(NH_(3))to CH_(3)(CH_(2))_(4)COONH_(4) underset(-H_(2)O)overset(Delta)to underset("Hexanamide")(CH_(3)(CH_(2))_(4)CONH_(2)) underset(("Hofmann bromamide reaction"))overset(NaOH//Br_(2))to underset("1-Aminopentane")(CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)NH_(2)`
Discussion
40.

Suggest any two uses of carbohydrates.

Answer»

SOLUTION :Carbohydrates acts as biofuels to provide ENERGY for the functioning of living systems.
They act as CONSTITUENTS of cell membrane.
Discussion
41.

Suggest any two fluorides ofXenon

Answer»

SOLUTION :XENON DIFLUORIDE `(XeF_2)`Xenon TETRAFLUORIDE `(XeF_4)` .
Discussion
42.

Suggest any two methods to prevent corrosion of iron.

Answer»

SOLUTION :BARRIER PROTECTION.
Sacrifical protection
ALLOYING
CATHODE protection
Discussion
43.

Suggest a simple method to remove peroxides from ethers.

Answer»

Solution :By shaking the ETHER with an AQUEOUS solution of KI or a FERROUS SALT.
Discussion
44.

Suggest a way to determine the wedge_(m)^(@) value of water.

Answer»

Solution :`wedge_(m)^(@)(H_(2)O)=lamda_(H^(+))^(@)+lamda_(OH^(-))^(@)`
we find out `wedge_(m)^(@)(HCl),wedge_(m)^(@)(NaOH) and wedge_(m)^(@)(NaCl)`. Then
`wedge_(m)^(@)(H_(2)O)=wedge_(m)^(@)(HCl)+wedge_(m)^(@)(NaOH)-wedge_(m)^(@)(NaCl)`
Discussion
45.

Suggest a way to determine wedge_(m^(@)) value of water.

Answer»

SOLUTION :`Lambda_(m)^(@)(H_(2)O)=ambda_(mH^(+))^(@)+Lambda_(mOH^(-))^(@)`
It can be determine from the value of `Lambda_(m)^(@)(HCL), Lambda_(m)^(@)(NAOH) and Lambda_(m)^(@)(NACL)`
Then,
`Lambda_(m)^(@)(H_(2)O)=Lambda_(m)^(@)(HCl)+Lambda_(m)^(@)(NaOH)-Lambda_(m)^(@)(NaCl)`
Discussion
46.

Suggest a way to determine the Lambda_(m)^(0)value of water.

Answer»

Solution :`Lambda_(m)^(@)(H_(2)O) = Lambda_(H+)^(@) + Lambda_(OH^(-))^(@)`
We find out `Lambda_(m)^(@) (HCL), Lambda_(m)^(@)(NaOH)` and `Lambda_(m)^(@) (NaCl)`. Then, APPLYING Kohlaursch LAW, we can calculate `Delta_(m)^(@)`
`Lambda_(m)^(@)(H_(2)O) =Lambda_(m)^(@)(HCl) + Lambda_(m)^(@) (NaOH) - Lambda_(m)^(@)(NaCl)`.
Discussion
47.

Suggest a way to determine the A_m^0 value of water.

Answer»

Solution :We know that water is a weak electrolyte. Its molar conductivity at infinite dilution i.e., `A_m^0` can be DETERMINED in terms of `A_m^0` for strong electrolytes. This is in accordance with Kohlrausch.s law.
`A_m^0H_2O=A_m^0(HCl)+A_m^0(NAOH)-A_m^0(NACL)`
Discussion
48.

Suggest a way to determine lambda_m^@ value of water.

Answer»

Solution :`lambda_m^@ (H_2O) = lambda_H^@ + lambda_(OH^-)^@`
We find out `lambda_m^@ (HCL) , lambda_m^@(NAOH) and lambda_m^@ (NACL)`
Then `lambda_m^@(H_2O) = lambda_m^@ (HCl) + lambda_m^@ (NaOH) - lambda_m^@ (NaCl)`.
Discussion
49.

Suggest a way to determine at Lamda_(m)^(@) value of water.

Answer»

Solution :* There is less IONIZATION of pure water.
`H_(2)O_((l)) hArr H_((aq))^(+)+OH_((aq))^(-)`
* Applying Kohlrausch.s law of INDEPENDENT migration of ions, the `Lamda_(m)^(@)` value of water can be DETERMINED as follows:
`Lamda_(m)^(@)(H_(2)O)=lamda_(m)^(@)(H^(+))+lamda_(m)^(@)(OH^(-))`
Now, `HCl +NAOH to NaCl+H_(2)O`, so,
`Lamda_(m)^(@)(HCl)+Lamda_(m)^(@)(NaOH)-Lamda_(NaCl)^(@)=Lamda_(m)^(@)(H_(2)O)`
or `Lamda_(m)^(@)(HCl)+Lamda_(m)^(@)(KOH)-Lamda_(m)^(@)(KCl)=Lamda_(m)^(@)(H_(2)O)`
* Hence, by knowing the `Lamda_(m)^(@)` values of HCl, NaOH and NaCl, the `Lamda_(m)^(@)` value of water can be determined.
Discussion
50.

Suggest a suitable oxidising agent for the conversion, (CH_(3))_(2)C=CHCOCH_(3)to(CH_(3))_(2)C=CHCO_(2)H

Answer»

Solution :ALKALINE `KMnO_(4)`, acidified `K_(2)Cr_(2)O_(7)` or `HNO_(3)` cannot be used since all of these will cleave the molecule at the SITE of the double bond giving a mixture of ketones/acid. The most suitable reagent for this oxidation is NaOI `(I_(2)//NaOH)` since methyl ketones on treatment with NaOI undergo iodoform reaction to GIVE iodoform along with the NA salt of a carboxylic acid having one carbon atom less than the starting methyl ketone.
.
Discussion