Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Peroxide bond is present in

Answer»

MgO
CaO
`Li_(2)O`
`BaO_(2)`

ANSWER :D
2.

Pernitric acid is

Answer»

`HNO_2`
`HNO_3`
`HNO_4`
`HNO`

ANSWER :C
3.

Permutit is:

Answer»

HYDRATED SODIUM ALUMINIUM silicate
Sodium hexametaphosphate
Sodium silicate
Sodium META aluminate

Answer :A
4.

Permonosulphuric acid is known as

Answer»

Marshall's ACID
CARO's acid
Sulphuric acid
fSulphurous acid

Answer :B
5.

Permissible noise levels in a residential area at night time is

Answer»

35 db
40 db
50 db
45 db

Answer :C
6.

Permeanganate ion is not isostructural with

Answer»

managanate ion
Cromate ion
Chlorate ion
Perchlorate ion

Answer :C
7.

Permanganate ion oxidises manganous ion to manganese dioxide in presence of zinc oxide as catatalyst asMnO_(4)^(-) + Mn^(2+) + H_(2)O rarr MnO_(2) + H^(+). The number of H^+ ion added to the product side in the balanced ionic equation is

Answer»


SOLUTION :`2MnO_(4)^(-) + 3Mn^(+2) + 2H_2O RARR 2MnO_2+ 3MnO_4 + 4H^(+)`
8.

Permanganate ion oxidize S_2O_3^(2-) in fairly alkaline solutions to give

Answer»

`SO_(4)^(2-)`
`SO_(3)^(2-)`
`S^(-2)`
S

Answer :A
9.

Permanganate ion has ……….geometry in which Mn^(7+) is …….. hybridised

Answer»

SOLUTION : TETRAHEDRAL, `SP^(3)`
10.

Permanganate ion is not isostructural with

Answer»

MANGANATE ION
Cromate ion
CHLORATE ion
Perchlorate ion

ANSWER :C
11.

Permanganate ion is isostructural with

Answer»

Chlorate ion
PERCHLORATE ion
CHLORITE ion
Nitrate ion

ANSWER :B
12.

Permanganate ion changes to……………. in acidic medium.

Answer»

`MnO_(4)^(2-)`
`Mn^(2+)`
`Mn^(3+)`
`MnO_(2)`

Solution :`MnO_(4)^(-)+ 8H^(+)+ 5e^(-) to Mn^(2+)+ H_(2)O`
13.

Permanganateion changes to ________ inacidicmedium

Answer»

`MnO_(4)^(2-)`
`MN^(2+)`
`Mn^(3+)`
`MnO_(2)`

Solution :`MnO_(4)^(-)+8H^(+)+5e^(-)toMn^(2+)+4H_(2)O`
14.

Permanent magnets are generaly made of alloys of :

Answer»

Co
Zn
Sb
Pb

ANSWER :A
15.

Permanent magnets are generally made of alloys of

Answer»

Fe
Co
Ni
Any ONE of these

Answer :d
16.

Permanent magnet is made from:

Answer»

CAST iron
Steel
Wrought iron
All of these

Answer :B
17.

Permanent hardness of water cannot be removed by which one of the following methods ?

Answer»

Treatment with washing soda
CALGON's method
Boiling
Ion exchange method

Solution :Magnesium is a chemical element with symbol Mg.
Magnesium is the ninth most abundant element in the universe . Its use as a structural MATERIAL is limited SINCE it burns at relatively low temperatures . Magnesium is frequently alloyed with aluminium , which makes aluminium EASIER to roll , EXTRUDE and weld.
18.

Permanent hardness of wateris due to the presence of

Answer»

bnicarbonates of sodiumand POTASSIUM
CHLORIDES and suphatesof SODIUM andpotassium
chlorids and sulphates of calcium and MAGNESIUM
BICARBONATES of calcium and magnesium

Answer :C
19.

Permanenet hardness of water is removed by adding

Answer»

SODIUM bicarbonate
Washing soda
Calcium hydroxide
Sodium chloride

Answer :B
20.

Permaganate oxidises aqueous iodide to iodine and itself is reduced to manganese dioxide. How many moles of iodine is liberated with one mole of permanganate ?

Answer»


ANSWER :1.5 MOLES
21.

Perlong is another name of :

Answer»

NYLON - 6
Nylon - 66
Nylon 6,10
Terylene

Answer :A
22.

Perkin's reaction is used for the preparation of which acid?

Answer»

BENZOIC acid
SALICYLIC acid
Cinnamic acid
PHTHALIC acid

Answer :C
23.

Periodic acid splits glucose and fructose into formaldehyde and formic acid. Ratio of moles of formic acid in glucose and fructose is

Answer»

`1:2`
`5:3`
`1:1`
`2:3`

Solution :`CHO-CHOH - CHOH - underset("Glucose")(CHOH) - CHOH - CH_(2)OH overset(5HIO_(4)) to5HCOOH + HCHO + 5HIO_(3)`
`CH_(2)OH - overset(O)overset(||)(C)- underset("FRUCTOSE")(CHOH)- CHOH - CHOH - CH_(2)OH overset(5HIO_(4))to 3HCOOH+ 2HCHO + 5HIO_(3) + CO_(2) + H_(2)O`
`therefore ` molar ratio is 5:3
24.

Perform the following calculations and calculate the answer to the proper number of significant figures : 144.3 m^2 + (2.54 m x 8.4 m)

Answer»

`165.336 m^2`
`165m^2`
`165.3 m^2`
`165.34 m^2`

SOLUTION :`2.54 m XX 8.4 m = 21.336m^2 " or" 21m^2`
` 144.3m^2`
` +(21)/(165.3m^2)`
25.

Periodic acid is formed by hydrolysis of

Answer»

ICl
`IP_(3)`
`IF_(5)`
`IF_(7)`

ANSWER :D
26.

Perfluorocarbons are remarkable stable, why?

Answer»

Solution :The prefix per implies that all the HYDROGEN atoms of a particualr hydrocarbon have been replaced by F atoms. For example.
`underset("Perfluorooctane")(CF_(3)(CF_(2))_(6)" or "CF_(3)-CF_(2)-CF_(2)-CF_(2)-CF_(2)-CF_(2)-CF_(2)-CF_(2)`.
Since F atom is strongly electronegative and have a very high negative electron gain enthalpy, `C-F` bond is of polar nature. with the increase in the number of F atoms around the CARBON atom, the MAGNITUDE of `+delta` charge on it increases and it acquires more electrostatic force of attraction of `delta`-charge on F atoms. As a result, strenlth of `C-F` bond increases and perfluorocarbons become QUITE stable as well as inert.
27.

Perchromic acid (CrO_5) in ether will demposes radily in the presence of H_2SO_4 to form oxygen will produce in thi process

Answer»


SOLUTION :`CrO_(5) + H_(2)SO_(4) RARR Cr_2(SO_4)_3 + O_2`
28.

Perchloric acid is strongest acid, but weakest oxidising agent. Why?

Answer»

Solution :`HClO_(4)` has `pK_(a) lt -10`. Its ability to provide proton is highest. This is due to resonance stabilisation of perchlorate ion. `CIO_(4)^(-)` has four CANNONICAL structures and six delocalised pi ELECTRONS.
`CIO_(4)^(-)` is resonance stabilised. It does not furnish OXYGEN and hence a weak oxidant.
29.

Perchloric acid is a stronger acid than sulphuric acid.

Answer»

Solution :The oxidation state of Cl in perchloric acid is +7 while that of S in sulphur acid is +6

Due to higher oxidation state and higher electronegativity of Cl, `ClO_(3)` part of `HClO_(4)` pulls the electrons of the O-H BOND more strongly and hence can break the O-H bond more easily to liberate a proton than `SO_(2)` partin `H_(2)SO_(4)`. Thus, perchloric acid is a stronger acid than sulphuric acid.
30.

Percentages of the free space in cubic close packed structure and is body centered packed structure and is body centered packed structure are respectively.

Answer»

48% and 26%
30% and 26%
26% and 32%
32% and 48%

Solution :For FCC or CCP
`4r=SQRT(2)arArr P.F.=(nxx(4)/(3)pir^(3))/(a^(3))`
`n=4,a=2sqrt(2)r`
`P.F.=(4xx(4)/(3)pir^(3))/((2sqrt(2)r)^(3))P.F.=74%`
Free space =100-74=26%
For BCC
`4r=sqrt(3)a`
P.F. `=(2xx(4)/(3)pir^(3))/((4)/sqrt(3)r)^(3)`
31.

Percentages of free space in cubic close packed structure and in body centered packed structme are respectively

Answer»

30% and 26%
26% and 32%
32% and 48
48% and 26%

Solution :Packing fraction is DEFINED as the ratio of the volume of the tmit cell that is occupied by the spheres to the total volume of the UNIT cell. P.F. for ccp and bee are 0.74 and 0.68 respectively. So, the free space in ccp and bee are 26% and 32% respectively
32.

Percentages of copper and zinc present in a alloy brass, are respectively

Answer»

60 % and 40%
40% and 60%
0 % and100%
100 % and 0%

ANSWER :A
33.

Percentage strength of the above H_(2)O_(2) solution is :

Answer»

`0.126`
`0.272`
`0.544`
`0.136`

Solution :Strength = EQ. MASS `xx` NORMALITY
` = 17 xx 0.16 = 2.72gl^(-1)`
` :. 1000 ` ml SOLN contains ` 2.72` G
`:. 100` ml slon contains `0.272` g
` :. ` Percentage of `H_(2)O_(2)` in soln ` = 0.272 %`
34.

Percentage strength of 20 volume H_2O_2 solution is

Answer»

0.03
`6%`
0.2
0.15

Answer :B
35.

Percentage of silver in the alloy of German silver

Answer»

1.5
2.5
10
zero

Answer :D
36.

Percentage of H_(2) is maximum in

Answer»

`CH_(4)`
`C_(6)H_(6)`
`C_(2)H_(4)`
`C_(2)H_(2)`

ANSWER :A
37.

Percentage of silver in German silver is :

Answer»

`1.5 %`
`2.5%`
`10%`
ZERO PERCENT

ANSWER :D
38.

Write down the composition of German silver.

Answer»

`1.5 %`
`2.5%`
`10%`
ZERO PER CENT

ANSWER :D
39.

Percentage of silver in german silver…..

Answer»


SOLUTION :NA
40.

Percentage of nickel in nickel steel is :

Answer»

`19%`
`35%`
`39.5%`
`8.5%`

ANSWER :B
41.

Percentageofhydrogenismaximum n :

Answer»

`C_(2) H_(2)`
`C_(2)H_(4)`
`C_(2) H_(6)`
`CH_(4)`

Answer :D
42.

Percentage of gold in Fool’s gold is:

Answer»

0
0.08
0.16
0.29

Answer :A
43.

Percentage of gold in 20 carat gold is :

Answer»

21.6
90
83.3
70

Answer :B
44.

Percentage of gold in 14 carat gold is :

Answer»

`58`
`80`
`40`
`14`

ANSWER :A
45.

Percentage of free space in cubic close packed structure and in body centred packed structure are respectively :

Answer»

32% and 48%
48% and 26%
30% and 26%
26% and 32%

Solution :Percentage of FREE space in ccp= 26% and in BCC = 32 %
46.

Percentage of free space in a body-centred cubic unit cell is

Answer»

0.32
0.34
0.28
0.3

Answer :A
47.

Percentage of empty space in a bcc arrangement is :

Answer»

`74%`
`68%`
`32%`
`26%`

Answer :C
48.

Percentage of carbon in the steels is nearly

Answer»

0.03
0.02
0.002
0.1

Answer :B
49.

Percentage of carbon in steel is _____.

Answer»

SOLUTION :0.25 to `2.5%`
50.

Percentage of a radioactive element decayed after 20 s when half-life is 4 s

Answer»

92.25
96.87
50
75

Solution :`n = (20)/(4) = 5, (N_(t))/(N_(0)) = ((1)/(2))^(5) = (1)/(32), :.` decayed
`= (1-(1)/(32)) XX 100 = (31)/(32) xx 100 = 96.87`