94420 + Interview Questions in Chemistry in Class 12

1.	n-Butyl bromide has higher boiling point than t-butyl bromide. Give reasons.
Answer» SOLUTION :For the SAMME alkyl group, the b.p. decreases as the branching increases or the SURFACE area decreases. Since n-butyl bromide has no branching while t-butyl bromide has two branches, therefore, b.p., of n-butyl bromide is higher than that of t-butyl bromide. <BR> `underset("No branching, surface area is more and hence has higher b.p. (i.e., 375 K)")(CH_(3)CH_(2)CH_(2)CH_(2)-Br)""underset("Two branches at "alpha"-carbon, surface area is LESS and hence has lower b.p. (i.e., 346 K)")(CH_(3)-underset(CH_(3))underset(\|)overset(CH_(3))overset(\|)(.^(alpha)C)-Br)`

Discussion

2.	n-butyl amineand isobutylamine are
Answer» chainisomers positionisomers OPTICAL ISOMERS FUNCTIONAL isomers Answer :A

Discussion

3.	n-butyl amine and isobutyl amine are --- isomers
Answer» optical functional chain positional Answer :C

Discussion

4.	n-Butyl alcohol and isobutyl alcohol are :
Answer» CHAIN isomers position isomers Metamers Tautomers Answer :A

Discussion

5.	n-Butane reacts with Br_(2) at 130^(@) to give more amount of
Answer» `CH_(3)-CH_(2)-underset(BR)underset(\|)CH-CH_(3)` `CH_(3)CH_(2)-CH_(2)-CH_(2)Br` `CH_(3)CH_(2)-CH_(2)-CH_(2)Br` all in EQUAL amounts Answer :C

Discussion

6.	n-butane on monobromination gives three isomers.The numver of product(s) obtained when the major product is heated with KOH in CH_3CH_2OH is/are…............
Answer» ANSWER :3

Discussion

7.	N-Butaneis producedby monobromination ofethanefollowedby the Wurtz reaction, calculatethevolume of ethane at NTP required to prduce 55 g n- butane,if the brominatiintakes placewith 90% yield and the Wrtz reactionwith 85% yield .
Answer» Solution :` {:(C_(2)H_(6),+Br_(2)to, C_(2)H_(5)BR+HBr","),(30g,,109g):}` `{:( 2C_(2) H_(5) Br+2Na to, C_(4)C_(10)+2NaBr),(2xx109g,58g):}` 55 g butanewill be PRODUCTS from `(2xx109)/(58)xx55g` ethyl bromide As the yeeld is 85% the actual ethyl bromiderequired `(2xx109)/(58)xx55xx100(100)/(85)=243.2g`243.2 g of ethy, bromide will producedfrom `=(30)/(109)xx243.2=66.93`g ethane As the yieldis 90 , theacturalethanerequired `=(100)/(90)xx66.93=74.37 g` Volume of the ethaneAt NTP`=(74.37)/(30)xx22.4=55.5L]`*

Discussion

8.	n-butane is produced by the monobromination of ethane followed by Wurtz reaction. Calculate the volume of ethane at NTP required to produce 55g of n-butane, if the bromination takes place with 90% and the Wurtz reaction with 85% yield.
Answer» Solution :`C_(2)H_(6) rarr C_(2)H_(5)Br` `2C_(2)H_(5)Br + 2NA underset("reaction")overset("Wurtz")rarr C_(4)H_(10)+ 2NaBr` 1 mole of `C_(2)H_(6)` gives 1 mole of `C_(2)H_(5)Br` and 2 moles of `C_(2)H_(5)Br` give 1 mole of `C_(4)H_(10)`.Let the number of moles of `C_(2)H_(6)` be N `therefore` n moles of `C_(2)H_(6)` will give 0.9n moles of `C_(2)H_(5)Br` (90%) and 0.9n moles of `C_(2)H_(5)Br` will give `(0.45 n xx 0.85)` moles of n-butane (85%). Thus, `0.45n xx 0.85= (55)/(58) (C_(4)H_(10)=58)` n= 2.789 moles `therefore` volume of `C_(4)H_(10)` at NTP= `2.789 xx 22.4` =55.53 litres

Discussion

9.	n-Butane (C_(4)H_(10)) is produced by monobromination of C_(2)H_(5) followed by Wurtz reaction. Calculate the volume of ethane al S.T.P. required to produce 55gin of n-butane. The bromination takes place with 90% yield and the Wurtz reaction with 85% yield
Answer» 27.75 litres 55.5 litres 111 litres 5.55 litres Solution :`2C_(2)H_(6)+2Br_(2) to 2C_(2)H_(5)Br+2HBr` (Bromination) …............(1) `2C_(2)H_(5)Br+2Na to C_(4)H_(10)+2NaBr` (wurtz reaction) …............(2) Wurtzreaction with 85% yeild As PER equation …...(2) 2 moles of `C_(2)H_(5)Br …................ 58g "of" C_(4)H_(10) , "x moles" xx (85)/(100) ........ 55 g "of" C_(4)H_(10)` `implies (2 xx 55)/(85 xx 58) xx 100=2.23` moles of `C_(2)H_(5)Br` As per equation .........(1) (Bromination with 90%) `2 xx 22.4` litres of `C_(2)H_(6)` ......... 2 moles of `C_(2)H_(5)Br` `x xx (90)/(100)` litres of `C_(2)H_(6)` ....... 2.23 moles of `C_(2)H_(5)Br implies (2 xx 22.4 xx 2.23 xx 100)/(2 xx 90)=55.5` litres

Discussion

10.	n being the number of unpaired electrons, the magnetic moment mu of a molecule is given by
Answer» `SQRT(N(n-2))` `mu=sqrt(n(n+2))` `sqrt(n(n-1))` `mu=sqrt(n(n+1))` ANSWER :B

Discussion

11.	n atomic reacotrs, graphite is used as a
Answer» Lubricant Moderator to show down NEUTRONS Fuel Liner of the reactor Solution :GRAPHITE is USED as moderator to slow down the speed of neutrons in atomic REACTORS

Discussion

12.	In a given mixture of gases which do not react with one another, the ratio of partial pressure to total pressure of each employment is equal to its
Answer» Critical pressure Weight PER CENT Mole fraction VOLUME per cent Answer :C

Discussion

13.	(n-1)d^(10)ns^(2) is the general electric configuration of
Answer» Fe,Co,Ni Cu,Ag,Au Zn,Cd,Hg Se,Y,La Answer :C

Discussion

14.	Myoglobin stores oxygen for metabolic process in muscle. Chemical analysis shows that it contains 0.32%Fe by mass. If there is one Fe atom per molecule of myoglobin, what is the molar mass of myoglobin? (at. mass of Fe = 56 u)
Answer» `1.75 XX 10^4 g/mol` `3.5 xx 10^5 g/mol` `1 xx 10^4 g/mol` `2.5 xx 10^5 g/mol` ANSWER :A

Discussion

15.	Myoglobin protein has
Answer» Primary STRUCTURE Secondary structure TERTIARY structure Quaternary structure SOLUTION :Tertiary structure

Discussion

16.	Myosin is a globular protein.
Answer» ANSWER :MYOGLOBIN is a GLOBULAR PROTEIN.

Discussion

17.	MY and NY_(3), two nearly insoluble salts, have the same K_(sp) values of 6.2 xx 10^(-13) at room temperature. Which statement would be true in regard to MY and NY_(3
Answer» The molar solubilities of MY and `NY_(3)` in water are identical The molar SOLUBILITY of MY in water is less than that of `NY_(3)` The salts MY and `NY_(3)` are more soluble in 0.5 M KY than in pure water The addition of the salt of KY to solution of MY and `NY_(3)` will have no EFFECT on their solubilities Solution :`MY rarr K_(sp) = s^(2) = 6.2 XX 10^(-13)` `s = sqrt(6.2 xx 10^(-13))` `s = 7.87 xx 10^(-7) mol L^(-1)` `NY_(3) rarr K_(sp) = 27 s^(4) = 6.2 xx 10^(-13)` `s = ((6.2 xx 10^(-13))/(27))^(1//4) = s = 3.89 xx 10^(-4) mol L^(-1)` `:.` Molar solubility of `NY_(3)` is more than MY in water.

Discussion

18.	MY and NY_3, two nearly insoluble salts have the same -K_(sp) values of 6.4xx10^(13) at room temperature. Which statement would be true in regard to MY and NY_3
Answer» The salts of My and `NY_3` are more SOLUBLE in 0.5 (M) KY than in pure water the ADDITION to the salt of KY to solutions of MY and `NY_3` will have no effect on their solubilities Themolar solubilities of MY and `NY_3` in water are identical The molar solubility of MY in water is less than that of `NY_3` Solution :`MY(s) `K_(sp)=S_1^2` or `S_1=SQRT(K_(sp))=sqrt(6.2xx10^(-13))molL^(-1)` `NY_3(s) `K_(sp)=S_2(3S_2)^3=27S_2^4` [`S_1`=Solubility of `NY_3` salt `(molL^(-1)`) `S_2^4=(6.2xx10^(-13))/(27)` or, `S_2=((6.2xx10^(-13))/(27))^(1//4)" ":.S_1ltS_2`

Discussion

19.	MX_(2)dissociates into M^(2+) and X^(-) ions in an aqueous solution with a degree of dissociation (alpha) of 0.5. The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is
Answer» Solution :`UNDERSET(1-alpha)(MX_(2))hArrunderset(alpha)(M)^(2+)+underset(2alpha)(2X)^(-)` `i=1-alpha+alpha+2alpha=1+2alpha` But `alpha=0.5, therefore i=1+2xx0.5=2` This is the REQUIRED RATIO.

Discussion

20.	MY and NY_3 are insoluble salts and have the same K_(sp) values of 6.2 times 10^-13 at room temperature. Which statement would be true with regard to to MY and NY_3?
Answer» The SALTS MY and `NY_3` are more soluble in 0.5M KY than in pure water The additionof the SALT of KY to the suspension of MY and `NY_3` will have no effect on their solubility The molar solubilities of MY and `NY_3` in water are identical The molar solubility of MY in water is LESS than of `NY_3` Solution :Addition of salt KY (having a common ion `Y^-`) decreases the solubility of MY and `NY_3` due to common ion effect. Option (a) and (b) are wrong `K_(SP)=(s) (s)` `6.2 times 10^-13=s^2` `therefores=sqrt(6.2 times 10^-13)approx10^-7` for salt `NY_3,NY_3 leftrightarrow N^(3+) +3Y^-` `K_(sp)=(s) (3s)^3` `K_(sp)27s^4` `s=((6.2 times 10^-13)/27)^(1//4)` `s approx 10^-4` the molar solubility of MY in water is less than of `NY_3`

Discussion

21.	MY and NY_3, are insoluble salts and have the same K_(sp) value of 6.2xx10^(-13) at room temperature. Which statement would be true with regard to MY and NY_3 ?
Answer» The salts `MY and NY_3` are more SOLUBLE in 0.5 M KY than in pure water. The ADDITION of the salt of KY to thesuspension of MY and `NY_3` will have no effect on their solubility's The MOLAR solubility of MY and `NY_3` in water are identical The molar solubility of MY in water is less than that of `NY_3` ANSWER :D

Discussion

22.	MX_(2) dissociates into M^(2+) and X^(-) ions in an aqueous solution, with a degree of dissociation (alpha) of 0.5. The ratio of solution to the value of depression of freezing point in the absence of ionic dissociation is
Answer» Solution :`MX_(2)HARR M^(2+)+2X^(-)` `m_(0)(1-alpha) "" m_(0)alpha "" 2m_(0)alpha , m=m_(0)(1+2alpha)` `therefore m=m_(0)(1+2xx0.5)=2m_(0)` (as given) `((-Delta T_(f))_("OBSERVED"))/((-Delta T_(f))_("undissociated"))=i=(m)/(m_(0))=2`

Discussion

23.	MX_(2) dissociates into M^(2+) and X^(-) ions in an aqeous solution, with a degree dissociation (alpha) of 0.5. The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is
Answer» SOLUTION :`((DeltaT_(F))_(OBS))/((DeltaT_(f))_(CAL))=i=1+2alpha`

Discussion

24.	M^(x+) ion has magnetic moment 2.84 BM. Then 'x' is (Z of M = 23)
Answer» 3 2 4 1 Answer :A

Discussion

25.	Mutations arise due to :
Answer» Infection by microorganisms Abrupt CHANGES in genes Hybridisation DOMINANT character of ONE of the parents ANSWER :B

Discussion

26.	Mutation of DNA occurs due to changes in the sequence of one of the following
Answer» Bases Ribose units Phosphate units Sugar units Solution :Mutation is a CHEMICAL change in the SEQUENCE of nitrogenous bases along the DNA which can lead to the synthesis of protein with altered amino ACID sequence.

Discussion

27.	Mutation of DNA occurs due to changes in the sequence of one of the following.
Answer» BASES RIBOSE UNITS Phosphate units SUGAR units Answer :A

Discussion

28.	Mutation in DNA occurs because of changes in the sequence of:
Answer» PHOSPHATE UNITS ribose units nitrogeneous bases none of these. Answer :C

Discussion

29.	Mutarotation is observed maltose and lactose. Why?
Answer» Solution :All REDUCING sugar EXHIBIT mutarotation Being MALTOSE and LACTOSE reducing sugar, they exhibit mutarotation.

Discussion

30.	Mutarotation of glucose is an example of :
Answer» Acid-base catalysis Homogeneous catalysis Both (a) and (B) None Answer :C

Discussion

31.	Mutarotation is not observed in …………………….
Answer» (+) MALTOSE (-) FRUCTOSE (+) SUCROSE Lactose Solution :(+) Sucrose

Discussion

32.	Mustard gas can be prepared by the reaction of ethylene with
Answer» `SF_6` `SF_4` `S_2Cl_2` `SCl_4` ANSWER :C

Discussion

33.	Muntz metal is an alloy of:
Answer» CU and Sn Cu and Zn Ag and Zn Zan and Mn Answer :B

Discussion

34.	Multiple covalent bonds exist in the moleculeof :
Answer» `F_2` `H_2` `N_2` `C_2H_6` ANSWER :C

Discussion

35.	MULTIPLE CHOICE QUESTIONS (CHOOSE THE CORRECT OPTION)
Answer» The half-cell in which OXIDATION TAKES PLACE is anode. It has a negative potential with RESPECT to solution. The half-cell in which oxidation takes place is anode. It has a POSITIVE potential with respect to solution. The half-cell in which oxidation takes place is cathode. It has a negative potential with respect to solution. The half-cell in which oxidation takes place is cathode. It has a positive potential with respect to solution. Answer :A

Discussion

36.	Multimolecular colloids are present in?
Answer» Sol of SULPHUR Sol of PROTEIN Sol of GOLD Soap SOLUTION Solution :N//A

Discussion

37.	Stability of multimolecular colloids is due to extensive solvation of colloidal particles.
Answer»

Discussion

38.	Muffle furnace is used in the metallurgy of
Answer» ZN SN PB CU SOLUTION :It isusedin metallurgyof zn .

Discussion

39.	Much of the world supply of planinam group metal Le, desived from the residues recovered from the electrolytic retining of copper and nickyl. The residues when heated with aquaria the sold, and pd go in to solution. This is filtered off and to the filiate on adding Ferrous sphate solution gold is preciated the platinum and palladium remain in solution. The structures of compounds of Pt and Pd remained in the solution are
Answer» Square planar and square planar Square planar and Tetrahedral Tetrahedral and Square planar Octahedral and Square planar Solution :`H_(2)PtCl_(6) to `octahedral complex with C.N-6 `H_(2)PtC_(4) to` square planar with C.N. 4

Discussion

40.	Much of the world supply of planinam group metal Le, desived from the residues recovered from the electrolytic retining of copper and nickyl. The residues when heated with aquaria the sold, and pd go in to solution. This is filtered off and to the filiate on adding Ferrous sphate solution gold is preciated the platinum and palladium remain in solution. The role of Ferrous sulphate in the recipitation of gold is
Answer» Oxidation Reductant COMPLEX agent Substituent SOLUTION :FERROUS SULPHATE acts a reducing agent in the precipitation of GOLD

Discussion

41.	Much of the world supply of planinam group metal Le, desived from the residues recovered from the electrolytic retining of copper and nickyl. The residues when heated with aquaria the sold, and pd go in to solution. This is filtered off and to the filiate on adding Ferrous sphate solution gold is preciated the platinum and palladium remain in solution. The solubility of the gold platinum and palladium in aquaregia is due to the formation of
Answer» `AuCl, PtCl_(2), PdCl_(2)` `AuCl_(3),PtCl_(4),PdCl_(4)` `HAuCl_(4), H_(2)PtCl_(6),H_(2)PdCl_(4)` `HAuCl_(4),H_(2)PtCl_(4),H_(2)PdCl_(4)` SOLUTION :AU, Pt & PD are dissolved in AQUAREGIA due to formation of `AuCl_(4)^(-)-[PtCl_(6)]^(-2)[PdCl_(4)]^(-2)`

Discussion

42.	MSO_(4)overset(NH_(4)OH)rarr underset("White")(Xdarr)underset("Excess")overset(NH_(4)OH)(rarr)Y overset (H_(2)S)(rarr)Zdarr Here, M and Z are
Answer» Cu,ZNS Zn,ZnS Fe,FeS `Al,Al_(2)S_(3)` SOLUTION : so , M and Z are Zn and ZnS, RESPECTIVELY.

Discussion

43.	Msot electronegative element is
Answer» Al C Si Be Answer :B

Discussion

44.	MSO_4 overset(NH_4OH)to darr underset("White")(X) underset("excess")overset(NH_4OH)to Y overset(H_2S)todarr Z Here M and Z are
Answer» `Al, Al_2S_3` `Fe,FeS` `Zn,ZNS` `CU,ZnS` SOLUTION :`ZnSO_4 overset(NH_4OH)to underset((X))(Zn(OH)_2) underset("Excees")overset(NH_4OH)to underset((Y))("Clear solution")overset(H_2S)tounderset((Z))(ZnS)` Here,`M = 2Z_a and Z = ZnS`

Discussion

45.	M("Salt")+"Dil. "HCl overset(Warm)to Pdarr+N uarr gas 'N' changes colour of FeSO_(4) solution into yellow solution then salt M in above reaction is
Answer» `BaS_(2)O_(3)` `Ag_(2)SO_(3)` `AgNO_(2)` `Pb(NO_(3))_(2)` Solution :`BaS_(2)O_(3)+HCl overset(warm) toBaCl_(2)+SO_(2)uarr overset(FeSO_(4)sol)to`No reaction hence solution remains green. `Ag_(2)SO_(3)+HCl overset(warm)toAgCl darr+SO_(2)uarr overset(FeSO_(4)sol.)to`No reaction hence solution remains green. `AgNO_(2)+HCl overset(warm) to AGCL darr+NO_(2) uarr underset(air)overset(FeSO_(4)sol.)Fe^(3+)(aq.)` (yellow sol.) `impliesPb(NO_(3))_(2)` salt is not DECOMPOSE by done HCl acid.

Discussion

46.	Mr. Santa has to decode a number “ABCDEF” where each alphabet is represented by a single digit. Suppose an orbital whose radial wave functional is represented as : psi_((r))=k _(1)e ^(-r//k_(2))(r ^(2) -5k_(3) r + 6k_(3)^(2)) From the following information given about each alphabet then write down the answers in the form of “ABCDEF”, for above orbital. Info A = Value of n where “n” is principal quantum number. Info B = No. of angular nodes Info C = Azimuthal quantum number of subshell to orbital belongs Info D = No. of subshells having energy between (n+5) s to (n +5) p where n is principal quantum number. Info E = Orbital angular momentum of given orbital. Info F = Radial distance of the spherical node which is farthest from the nucleus. (Assuming k _(3) =1))
Answer» ANSWER :300303

Discussion

47.	Mr. Roy, the principal of one reputed school organized a seminar in which he invited parents and principals to discuss the serious issue of diabetes and depression in students. They all resolved this issue by strictly banning the junk food in schools and to introduce healthy snacks and drinks like soup, lassi, milk, etc. in school canteens. They also decided to make compulsory half an hour physical activities for the students in the morning assembly daily. After six months, Mr. Roy conducted the health survey in most of the schools and discovered a tremendous improvement in the health of students. After reading the above passage, answer the following questions : (i)What are the values (at least two) displayed by Mr. Roy ? (ii) As a student, how can you spread awareness about this issue ? (iii) What are tranquilizers ? Give an example.(iv) Why is use of aspartame limited to cold foods and drinks ?
Answer» Solution :(i)Mr. Roy displayed values about general health and physical fitness of the students. He was PARTICULARLY CONCERNED about the serious issue of diabetes and depression in students (ii) As a student you can spread awareness about the bad effects of these two diseases on the general health of the students by conducting seminars, group discussions, holding health workshops for students as well as parents and by writing articles in SCHOOL magazines and newspapers. You may also request the principal of the school to invite some renowned medical PRACTITIONER of the town to deliver a talk on the causes of diabetes and depression in students and their treatment/cure (iii)DRUGS which are used for treatment of stress, fatigue, mild and severe mental diseases are calledtranquillizers. For example, quail, barbiturates such as veronal, luminal, etc. and the alkaloid reserpine. (iv) Aspartame in a widely used artificial sweetener. Its use is, however, limited to cold foods and drinks because it decomposes at cooking temperature

Discussion

48.	Mr. Raju has determined the molecular masses of different solutes in different solvents by osmotic pressure measurements and present them in the following table. Please help him to complete the table .
Answer» SOLUTION :

Discussion

49.	Movement of particles when electricity is passed through a colloidal solution is called as
Answer» Brownian movement cataphoresis electro-osmosis Tyndall effect. Solution :The COLLOIDAL particles carry charge and thus MOVE TOWARDS oppositely CHARGED electrodes under the influence of electrical field. This phenomenon is called as cataphoresis or electrophoresis.

Discussion

50.	Movement of dispersion medium under the influence of electric field is known as
Answer» Electrodialysis Electrophoresis Electroosmosis Cataphoresis. Answer :C

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

n-Butyl bromide has higher boiling point than t-butyl bromide. Give reasons.

n-butyl amineand isobutylamine are

n-butyl amine and isobutyl amine are --- isomers

n-Butyl alcohol and isobutyl alcohol are :

n-Butane reacts with Br_(2) at 130^(@) to give more amount of

n-butane on monobromination gives three isomers.The numver of product(s) obtained when the major product is heated with KOH in CH_3CH_2OH is/are…............

N-Butaneis producedby monobromination ofethanefollowedby the Wurtz reaction, calculatethevolume of ethane at NTP required to prduce 55 g n- butane,if the brominatiintakes placewith 90% yield and the Wrtz reactionwith 85% yield .

n-butane is produced by the monobromination of ethane followed by Wurtz reaction. Calculate the volume of ethane at NTP required to produce 55g of n-butane, if the bromination takes place with 90% and the Wurtz reaction with 85% yield.

n-Butane (C_(4)H_(10)) is produced by monobromination of C_(2)H_(5) followed by Wurtz reaction. Calculate the volume of ethane al S.T.P. required to produce 55gin of n-butane. The bromination takes place with 90% yield and the Wurtz reaction with 85% yield

n being the number of unpaired electrons, the magnetic moment mu of a molecule is given by

n atomic reacotrs, graphite is used as a

In a given mixture of gases which do not react with one another, the ratio of partial pressure to total pressure of each employment is equal to its

(n-1)d^(10)ns^(2) is the general electric configuration of

Myoglobin stores oxygen for metabolic process in muscle. Chemical analysis shows that it contains 0.32%Fe by mass. If there is one Fe atom per molecule of myoglobin, what is the molar mass of myoglobin? (at. mass of Fe = 56 u)

Myoglobin protein has

Myosin is a globular protein.

MY and NY_(3), two nearly insoluble salts, have the same K_(sp) values of 6.2 xx 10^(-13) at room temperature. Which statement would be true in regard to MY and NY_(3

MY and NY_3, two nearly insoluble salts have the same -K_(sp) values of 6.4xx10^(13) at room temperature. Which statement would be true in regard to MY and NY_3

MX_(2)dissociates into M^(2+) and X^(-) ions in an aqueous solution with a degree of dissociation (alpha) of 0.5. The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is

MY and NY_3 are insoluble salts and have the same K_(sp) values of 6.2 times 10^-13 at room temperature. Which statement would be true with regard to to MY and NY_3?

MY and NY_3, are insoluble salts and have the same K_(sp) value of 6.2xx10^(-13) at room temperature. Which statement would be true with regard to MY and NY_3 ?

MX_(2) dissociates into M^(2+) and X^(-) ions in an aqueous solution, with a degree of dissociation (alpha) of 0.5. The ratio of solution to the value of depression of freezing point in the absence of ionic dissociation is

MX_(2) dissociates into M^(2+) and X^(-) ions in an aqeous solution, with a degree dissociation (alpha) of 0.5. The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is

M^(x+) ion has magnetic moment 2.84 BM. Then 'x' is (Z of M = 23)

Mutations arise due to :

Mutation of DNA occurs due to changes in the sequence of one of the following

Mutation of DNA occurs due to changes in the sequence of one of the following.

Mutation in DNA occurs because of changes in the sequence of:

Mutarotation is observed maltose and lactose. Why?

Mutarotation of glucose is an example of :

Mutarotation is not observed in …………………….

Mustard gas can be prepared by the reaction of ethylene with

Muntz metal is an alloy of:

Multiple covalent bonds exist in the moleculeof :

MULTIPLE CHOICE QUESTIONS (CHOOSE THE CORRECT OPTION)

Multimolecular colloids are present in?

Stability of multimolecular colloids is due to extensive solvation of colloidal particles.

Muffle furnace is used in the metallurgy of

MSO_(4)overset(NH_(4)OH)rarr underset("White")(Xdarr)underset("Excess")overset(NH_(4)OH)(rarr)Y overset (H_(2)S)(rarr)Zdarr Here, M and Z are

Msot electronegative element is

MSO_4 overset(NH_4OH)to darr underset("White")(X) underset("excess")overset(NH_4OH)to Y overset(H_2S)todarr Z Here M and Z are

M("Salt")+"Dil. "HCl overset(Warm)to Pdarr+N uarr gas 'N' changes colour of FeSO_(4) solution into yellow solution then salt M in above reaction is

Mr. Raju has determined the molecular masses of different solutes in different solvents by osmotic pressure measurements and present them in the following table. Please help him to complete the table .

Movement of particles when electricity is passed through a colloidal solution is called as

Movement of dispersion medium under the influence of electric field is known as