Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Metal is precipitated from Au(CN)_(4)^(3-) using zinc as a precipitant. Along with Au, a complex compound of zinc is also formed as product. The 1^@ and 2^@ valencies in the complex are

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`2,3`
`2,6`
`1,4`
`2,4`

ANSWER :D
2.

Metal hydroxide is added as an ........... for making noble metal sols.

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SOLUTION :STABILISING AGENT
3.

Metal extracted from molten cryolite is

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Al
Fe
Zn
Ag

Answer :A
4.

Metal excess defect is possible in …………………………………

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`AgCl`
`AGBR`
`KCI`
`FES`

ANSWER :C
5.

Metal ion responsible for the Minamata disease is

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`Co^(2+)`
`Hg^(2+)`
`CU^(2+)`
`Zn^(2+)`

Answer :B
6.

Metal hydrides are ionic covalent or molecularin nature amongLiH ,NaH,KH ,RbH,CsHthe correct orderof increasingionic character is

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`LiHltNaHgtCsHgtKHgtRbH`
`LiHltNaHltKHltRbHltCsH`
`RbHgtCsHgtNaHgtKHgtLiH`
`NaHgtCsHgtRbHgtLiHKH`

ANSWER :B
7.

Metal deficiency defects is observed in

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NIO 
FeS
FeO
All of these 

ANSWER :D
8.

Metal halide X,Y respectively

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`I_(2),I^(-)`
`I^(-) , I_(2)`
`I_(2),KI_(3)`
`Br_(2),KBr_(3)`

SOLUTION :`underset("(X)") ( 4KI) + 2CuSO_(4) rarr underset("BROWN ppt. (Y)")(Cu_(2)I_(2)+I_(2)+2K_(2)SO_(4))`
`underset("(Y)")(I_(2))+underset("Hypo")(2Na_(2)S_(2)O_(3)) rarrunderset("Colourless")(2NaI + Na_(2)S_(4)O_(6))`
9.

Metal halide which is insoluble in water is

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AgI
`CaCl_(2)`
`AgF`
`KBr`

ANSWER :A
10.

Metal chloride contains 71% chlorine. Then calculate equivanlent weight of that metal bromide (at. Wt. of Br = 80)

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`14.5`
85
`94.5`
100

Answer :C
11.

Metal generally present in polluted air is

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CADMIUM
Lead
Mercury
Zinc

Answer :B
12.

Metal commonly present in bronze, brass and German silver is

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Cu
Ag
ZN
Fe

Answer :A
13.

Metal carbonate is converted to the corresponding metal oxide usually by :

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ROASTING PROCESS
calcination process
reduction process
OXIDATION process

Answer :B
14.

Metal among the following is:

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As
Sb
P
Bi

Answer :D
15.

Metal always found in free state is

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GOLD
silver
copper
sodium

Answer :A
16.

Metal alloy crystal consisting eight coordination number is obtained during crystallization of Li and Ag^(+), then which type of crystal arrangement will observed ?

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bcc 
SIMPLE CUBE 
HEXAGONAL 
(A), (B) and (C) all three 

ANSWER :A
17.

Metal A,B and C has reduction potentials, 0.34 volt, -0.80 volt and -0.46 volt respectively. So give order of their capacity as reducing agent.

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`C gt A gt B`
`AgtBgtC`
`BgtCgtA`
`CgtBgtA`

Solution :
So, order of reducing agent is : `B gt C gt A`
Metal with less reduction POTENTIAL `(E_(RED)^(@))` will liberate electrons and easily get OXIDIZED. Hence, it is strongest reducing agent.
18.

Metal always found in free state is :

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Gold
Aluminium
Copper
Sodium

ANSWER :A
19.

Metal alkoxides contain:

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Metal-carbon bond
Metal-carbon bond
Metal-methyl bond
None

Answer :B
20.

Metaformaldehyde is called bakelite.

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SOLUTION :trioxane
21.

Metaformaldehyde is called bakelite. True / False

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SOLUTION :trioxane
22.

Metabolic function in human bodies is carried out by

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Lipids
Peptides
Nucleic acids
ENZYMES

Solution :Enzymes are specific BIOLOGICAL catalysts that possess WELL defined ACTIVE SITES.
23.

Metabolism of C_6H_5COONa finally excreated as

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Benzene
Hippuric acid
BHT
BHA

ANSWER :B
24.

Meta phosphoric acid is chemically

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<P>`H_(3)PO_(4)`
`HPO_(3)`
`H_(4)P_(2)O_(6)`
`H_(3)PO_(2)`

Answer :2
25.

Meta-directing and deactivating group in aromatic electrophilic substitution is :

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`-CH_3`
`-OH`
`-NO_2`
`-CL`

ANSWER :C
26.

Mesotartaric acid is optically inactive. This is because of :

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ABSENCE of chirality
racemisation of d and L optical FORMS
EXTERNAL compensation
internal compensation

Answer :D
27.

Meson was discovered by :

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Chadwick
Yukawa
Powell
Stassman and Hahn.

Answer :B
28.

Mesomeric effect involves delocalisation of

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PROTONS
SIGMA electrons
pi electrons
NONE of these

Solution :The mesomeric effect refers to the polarity produced in a molecules as a RESULT of interaction between two `pi` bonds or a `pi` - bond and a lone pair of electrons.
29.

Mesodibromobutane on debromination gives

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Trans-2-butene
Cis-2-butene
1-butene
1-butyne

Solution :SYMMETRICAL OPTICAL ISOMERS are CALLED as MESOMERS.
.
30.

Meso tartaric acid is optically inactive due to the presence of:

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MOLECULAR symmetry
Molecular asymmetry
External compensation
Two ASYMMETRIC CARBON atoms

Answer :A
31.

Mesomeric effect involves :

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DELOCALISATION of `PI`-electrons
delocalisation of `SIGMA`-electrons
partial DISPLACEMENT of electrons
delocalisation of `pi and sigma`-electrons

Answer :A
32.

Meso-tartaric acid is optically inactive due to the presence of

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MOLECULAR SYMMETRY
Molecular asymmetry
External compensation
Two asymmetric C-atoms

Solution :Molecular symmetry

Mesotartaric acid is opticallly inactive due to internal compensation i.e. the effect ONE half of the molecule is neutralized by other.
33.

Meso tartaric acid and d-tartaric acid are:

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POSITION ISOMERS
RACEMIC MIXTURE
ENANTIOMERS
diastereomers

Answer :D
34.

Meso Tartaric acid

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RIBOSE
ARABINOSE
MANNOSE
Talose

Answer :A
35.

Meso compounds do not show optical activity because ?

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they CONTAIN PLANE of symmetry
they do not contain chiral carbon atoms
they do not contain plane of symmetry
they have non-superimposable MIRROR IMAGES

Answer :A
36.

meso-2,3-Dibromobutane is treated with NaI in acetone. The mojor compound formed is

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cis-but`-2`-ne
`2-`BROMO`-3-`iodobutane
trans-but`-2-`ene
meso`-2,3-`diiodobutane

Solution :DEHALOGENATION by sodium IODIDE proceeds by an `E2` ELIMINATION mechanism. `E2` elimination, which is both stereoselective and stereospecific, TYPICALLY involves antielimination.
37.

Mesityl oxide is formed by the condensation of

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ACETALDEHYDE
ACETONE
propanal
FORMALDEHYDE

ANSWER :B
38.

Mesityl oxide is

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KETONE
aldehyde
ester
ethers

ANSWER :A
39.

Meso compounds do not show optica activity because :

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they do not contain chiral carbon ATOMS
they have non-superimposable MIRROR images.
they contain PLANE of symmetry
they do not contain plane of symmetry.

Answer :C
40.

Mercury tree can be prepared :

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By MIXING up mercuric thicyanate and gum
By adding Nessler.s REAGENT to a ammonium salt solution
By pouring little mercury into `AgNO_3` solution
By heating mercuric CHLORIDE

Answer :C
41.

Mercury on heating with aqua - regia yields :

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`HG(NO_3)_2`
`HgCl_2`
`Hg(NO_2)_2`
`Hg_2Cl_2`

ANSWER :B
42.

Mercury sticks to glass when it comes in contact with

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`H_(2)O`
`HNO_(3)`
`I_(2)`
`O_(3)`

ANSWER :D
43.

Mercury sol is obtained by subjecting it to sound waves of frequency more than ............

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20 HZ
20 KHZ
200 kHz
2000 kHz

Solution : 20 kHz
44.

Mercury on heating with aqua-regia gives:

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`Hg(NO_(3))_(2)`
`HgCl_(2)`
`Hg(NO_(2))_(2)`
`Hg_(2)Cl_(2)`

ANSWER :B
45.

Mercury is transported in the containers made of :

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Ag
Pb
Al
Fe

Answer :D
46.

Mercury meniscus is regained by addition of:

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`H_2O`
`H_2O_2`
ALCOHOL
`CCl_4`

ANSWER :B
47.

Mercury is transported in metal containers made up of :

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Fe
Pb
Zn
Sn

Answer :A
48.

Mercury is transpored in metal containers made of :

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Silver
Lead
IRON
`ALUMIUM

ANSWER :C
49.

Mercury is the only metal which is liquid at 0^(@)C. This is due to its:

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Very high ionisation ENERGY and weak METALLIC bond
Low ionisation potential
High ATOMIC weight
High VAPOUR pressure

Answer :A
50.

Mercury is the one metal which is liquid at room temperature. This is due to its

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very HIGH IONIZATION ENERGY and weak metallic bond
low ionization potential
high atomic weight
high vapour pressure

Solution :Due to high ionization energy and weak metallic BONDING, mercury is a liquid at room TEMPERATURE.