Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Maximum value ( n + l + m )for an unpaired electron in excited state of chlorine ""_(71) Cl is

Answer»

28
8
7
none of these

Answer :C
2.

Maximum possible hydrogen bonds are present in

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`3.6^(13)` Helix
Keratin
Silk FIBROIN
`BETA`-D - FRUCTOSE 

ANSWER :A
3.

Maximum pK_(b) value is of

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`(CH_(3))_(2)NH`
`(CH_(3))CH_(2))_(2)NH`

SOLUTION : is least basic and THEREFORE has maximum value of `pK_(b)`.
4.

Maximum percentage of available Cl_(2) as per formula CaOCl_(2). H_(2)O is x xx 7. Where the value of 'x' ?

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Solution :`underset( 145 G m)(CaOCl_(2).H_(2)O) RARR underset( 71 g m ) ( Cl_(2)) , ` Valu of x `xx 7 = 49.``:. x = ( 49)/( 7) = 7`
5.

Maximum paramagnetism in 3d -series shown by :

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Mn
Co
Ni
Fe

Answer :A
6.

Maximum paramagnetism in 3d series is shown by

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Mn
Co
Ni
Fe

Answer :A
7.

Maximum P-O-P linkage present in :-

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`P_(4)O_(6)`
`P_(4)O_(10)`
`(HPO_(3))_(3)`
same for (1) & (2)

Solution :P-O-P linkage in `P_(4)O_(6)` and `P_(4)O_(10)` are SIX
8.

Maximum oxidation state of Zn, Cd and Hg are :

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`+3`
`+4`
`+2`
`+1`

Answer :C
9.

Maximum oxidation state of Cr is

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3
4
6
7

Solution :MAXIMUM OXIDATION STATE for `CR` is +6.
10.

Maximum oxidation state exhibited by manganese in its compounds is .....

Answer»


ANSWER :C
11.

Maximum number of unpaired electrons are present in….

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`Gd^(3+)`
`YB^(2+)`
`TB^(2+)`
`"Pm"^(3+)`

Solution :`Gd^(3+): [Xe] 4F^(7)`
12.

Maximum number of phases at equilibrium of pure substance is

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ANSWER :3
13.

Maximum number of oxygen molecules bond around a heamoglobin is (are)

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SOLUTION :
14.

Maximum number of moles of Ac_(2)O consumed by reactant (A) is :

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Solution :
No. of ALCOHOL = No. of moles of `Ac_(2)O` CONSUMED.
`=4`
15.

Maximum number of oxidation states of the transition metals is derived from the following configuration:

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NS ELECTRONS
(n-1)d electrons
(n+1)d electrons ns + (n-1)d electrons

Answer :D
16.

Maximum number of mono chloro derivatives possible for structural only)

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4

8 
14 

ANSWER :C
17.

Maximum number of molecules of CH_(3)I that can react with a molecule of CH_(3)NH_(2) are

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3
4
2
1

Solution :`CH_(3)NH_(2) + CH_(3)I RIGHTARROW (CH_(3))_(2)NH overset(+CH_(3)I) to(CH_(3))_(3)N overset(+CH_(3)I)to (CH_(3))_(4)NI^(+ -)`
18.

Maximum number of isomers of alkene C_(4)H_(8) are

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2
3
4
6

Solution :SIX ISOMERS of `C_(4)H_(8)`
19.

Maximum number of lone pair electrons present in the molecules among the following :

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`XeF_(2)`
`XeF_(4)`
`XeOF_(4)`
`H_(2)O`

Answer :A
20.

Maximum number of mole of oxygen gas that can be obtained by the electrolytic decomposition of 90 g of water will be

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1
2.5
5
9

Answer :B
21.

Maximum number of isomers formed when is treated with N-Bromo succinamide is

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1
2
3
4

Answer :D
22.

Maximum number of identical bond length are present in

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`SF_(6)`
`IF_(7)`
`PCl_(5)`
`SO_(4)^(-2)`

ANSWER :A
23.

Maximum number of isomers for an alkene with molecular formula, C_(4)H_(8) is:

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5
4
3
2

Answer :B
24.

Maximum number of ionisation energies possible for a carbon atom is :-

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1
2
4
6

Solution :`6^(C):1s^(2)2S^(2)2P^(2)`, TOTAL `e^(-)=6`
total IP=6.
25.

Maximum number of hydrogen bonding in H_(2)O is

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1
2
3
4

Answer :D
26.

Maximum number of electrons which can be accommodated in a g subshell is:

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14
18
12
20

Answer :B
27.

Maximum number of electronsthat can beaccommodatedin the subshellwithazimuthalquantumnumberl=4, is

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10
8
16
18

Solution : `l=4 to` 'g'subshell
`THEREFORE"no of " E^(-)= 2(2l+1)`
`=2(2xx4+1)=18e^(-)`
28.

Maximum number of electrons present in "N" shell is:

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18
32
2
8

Answer :B
29.

Maximum number of electrons in a subshell with l=3 and n=4 is

Answer»

12
14
16
10

Solution :n=4,l=3 is 4F
4f SUBSHELL has 14 ELECTRONS.
30.

Maximum number of dative bonds that can be formed by EDTA

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Solution :EDTA can donate maximum of 6 LONE PAIRS of ELECTRON.
31.

Maximum number of atoms which are in the same plane in [Ni(CO)_(4)] :

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3
2
9
5

Solution :
32.

Maximum number of bonds in

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`CO_(2)`
`H_(2)`O
`H_(2)`S
All have same NUMBER of BONDS because all are triatomic molecule

Answer :A
33.

Maximum number of atoms present in one interhalogen atom.

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SOLUTION :INTERHALOGEN having MAXIMUM number of atom is `IF_3` when total number of ATOMS =1+7=8
34.

Maximum mass of sucrose C_(12)H_(22)O_(11) produced by mixing 84 gm of carbon , 12 gm of hydrogen and 56 lit. O_(2) at 1 atm & 273K according to given reaction, is C(s) + H_(2)(g) + O_(2) (g) to C_(12)H_(22)O_(11)(s)

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138.5
155.5
172.5
199.5

Answer :B
35.

maximum for :-

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FE
Cr
Co
MN

ANSWER :C
36.

Maximum group valancy of halogens with respect to oxygen is :

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One
Five
Six
Seven

Answer :D
37.

Maximum ferromagnetism is found in:

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Fe
Ni
Co
None

Answer :A
38.

Maximum enolisation takes place in:

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`CH_(3)COCH_(3)`
`CH_(3)COCH_(2)CHO`
`CH_(3)COCH_(2)COCH_(3)`

Solution :
39.

Maximum enol content is in

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SOLUTION :`undersetunderset("(keto form-24%)")("acetyl ACETONE")(CH_(3)-overset(O)overset(||)(C)-CH_(2)-overset(O)overset(||)(C)-CH_(3))`

In acetyl acetone, the enol form is stabilised by H BONDING, hence it has more enol content than others.
40.

Maximum entropy will be in which of the following

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Ice
Liquid WATER
Snow
Water vapours

Solution :ENTROPY is the measure of randomness in the molecules. Randomness is MAXIMUM in case of gases. HENCE, entropy is maximum for water vapours.
41.

Maximum enol content is in:

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ANSWER :C
42.

Maximum depression in freezing point is caused by

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`Na_(2)SO_(4)`
NaCl` gtBaCl_(2) GT ` GLUCOSE
Glucose
KCl

Solution :Depression in freezing point depends upon the number of particles .`Na_(2)SO_(4)` gives 3 particles AQUEOUS solution.
43.

Maximum covalent character is shown by ______

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`PCl_(3)`
`NCl_(3)`
`AsCl_(3)`
`SbCl_(3)`

Answer :B::C
44.

Maximum dehydration takes place in

Answer»




Solution :DEHYDRATED PRODUCT will be conjugated with `C=C` that is why more TENDENCY of DEHYDRATION and as carbocation is more stable further.
45.

Maximum covalency of sulphur is :

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2
4
6
8

Answer :C
46.

Maximum covalency of oxygen is 4. Why?

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Solution :VALENCE shell electronic CONFIGURATION of `O` `2s^2p^4`. Due to ABSENCE of d-orbitals in its valence shell, maximum covalency of oxygen is 4.
47.

Maximum covalency of nitrogen is ____

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3
5
4
6

Solution :Maximum COVALENCY of N is FOUR as in `NH_(4)^(+)`because it cannot extend its OCTET beyond 8 due to the absence of vacant d-orbitals.
48.

Maximum covalency of nitrogen is

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3
5
4
6

Solution :Maximum covalency of N is FOUR as in `NH_(4)^(+)`because it cannot extend its octet BEYOND 8 due to the absence of vacant d-orbitals.
49.

Maximum covalency of nitrogen is ...... .

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3
5
4
6

Solution :N at the maximum can have 8 ELECTRONS, i.e., four PAIRS of electrons in the valence SHELL and hence has a maximum COVALENCY of 4.
50.

Maximum covalency of nitrogen is four. Explain.

Answer»

Solution :NITROGEN has no VALENCE d-orbitals. Excitation of 2S electron to 3s orbital is difficult. Hence nitrogen does not form five bonds. `N(Z=7):[He] 2s^(2)2p^(1)2p^(1) 2p^(1)`. Nitrogen can form three covalent bonds and one dative bond as in `NH_(4)^(+)` or in `C_(6)H_(5)NH_(3)^(+)` IONS. Its maximum covalency is four.