Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In thegivenreaction , CH_(3)- overset(O)overset(||)C-C_(2)H_(5)overset([x])to CH_(3)-CH_(2)-C_(2)H_(5) X will be :

Answer»

`LiAIH_(4)`
`NaBH_(4)`
`BU_(3)SNH`
`NH_(2)-NH_(2)//OH^(-)`

Answer :D
Discussion
2.

In the given reaction: CH_(3)-underset(CH_(3))underset(|)CH=CH-CH_(2)-Br+HOH//NaOHto[X] as major product will be:

Answer»

`H_(3)C-UNDERSET(CH_(3))underset(|)overset(OH)overset(|)C-CH_(2)-CH_(2)-BR`
`H_(3)C-underset(CH_(3))underset(|)overset(OH)overset(|)C-CH=CH_(2)`
`H_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-CH_(2)-OH`
`H_(3)C-underset(CH_(3))underset(|)C=CH-CH_(2)OH`

Answer :B
Discussion
3.

In the given reaction CH_(3)-CH_(2)-underset(NaOH)underset(||)(C)-CH_(3)underset((H_(2)O //H^(+)),Delta)overset(H_(2)SO_(4))to(A)+(B) A and B are:

Answer»

`CH_(3)COOH and C_(2)H_(5)NH_(2)`
`CH_(3)CH_(2)COOH and CH_(3)NH_(2)`
`CH_(3)NH_(2) and C_(2)H_(5)NH_(2)`
`CH_(3)COOH and CH_(3)CH_(2)COOH`

ANSWER :A
Discussion
4.

Intheextractionbyelectrolysisofbrine. .............

Answer»

oxidation of` Cl^(-) `ionto chlorinegas occurs
reductionof ` Cl^(- ) `iontochlorine gasoccurs
foroverallreaction` DeltaG^(@) `has negativevalue
a displacementreactiontakesplace

Solution :Forextractionofmetalsandnon-metalsby electrolysis,`DELTA G ^(@) `FORTHE overallreactionis+ve. THUS,option (a) i.e.,oxidation` Cl ^(- ) `ion to ` Cl_ 2`GAS ISCORRECT.
Discussion
5.

In the experiment set up for the measurement of EMF of a half cell using a reference electrode and a salt bridge. When the salt bridge is removed, the voltage

Answer»

Does not change
Decreases to half the value
Increase to maximum
Drops to zero

Solution :It CONNECT TWO SOLUTIONS and complete the CIRCUIT.
Discussion
6.

In the given reaction CH_(3)-cH_(2)COOHoverset((i)CH_(3)Li" (excess)"(ii)H_(3)O^(o+))rarr [X] [X] will be

Answer»

`CH_(3)-cH_(2)COOLi`
`CH_(3)-CH_(2)-overset(O)overset(||)C-CH_(3)`
`CH_(3)-CH_(2)-CH_(2)OH`
`CH_(3)-CH_(2)-CH_(2)-CH_(3)`

Answer :B
Discussion
7.

In the experiment on elecro-osmosis, in which of the following the level of the dispersion medium will fall on the cathode side ?

Answer»

GOLD sol
STARCH sol
`Fe(OH)_(3)` sol
`As_(2)S_(3)`sol

Solution :Level on cathode side will fall when dispersion MEDIUM MOVES TOWARDS anode, i.e., dispersion medium carries -ve charge or colloidal paraticles carry +ve charge, viz, `Fe(OH)_(3).`
Discussion
8.

In the given reaction: CH_3-CH_2-COOH underset((ii) Br_2,C Cl_4//Delta)overset((i) AgNO_3)to [X]. [X] will be

Answer»

ethyl bromide
propyl bromide
propyl propanoate
all of these.

Solution :`CH_3CH_2COOH UNDERSET((II) Br_2,C Cl_4//Delta)overset((i) AgNO_3)to underset((X))(CH_3CH_2Br)`
Discussion
9.

In the excess of air, the major oxides formed by Li, Na and K are Li_(2)O, Na_(2)O_(2)and KO_(2) respectively. Arrange all the given oxides in the decreasing order of their stability.

Answer»

`Li_(2)O gt Na_(2)O_(2)gt KO_(2)`
`KO_(2)gt Na_(2)O_(2)gt Li_(2)O`
`Na_(2)O_(2)gt KO_(2)gt Li_(2)O`
`Li_(2)O gt KO_(2)gt Na_(2)O_(2)`

SOLUTION :The increasing STABILITY of the PEROXIDE or superoxide, as the size of the metal ion increases, is DUE to the stabilisation of large anions by larger cations.
Discussion
10.

In the given reaction CH_(2)-cH_(2)-overset(O)overset(||)C-CH_(2)COOC_(2)H_(5)overset([X])rarr (A) overset((i)LiAlH_(4))underset((ii)H_(2)O //H^(o+))rarr CH_(3)-CH_(2)-overset(O)overset(||)C-CH_(2)-CH_(2)OH+C_(2)H_(5)OH [X] will be

Answer»

`HCHO`
`{:(CH_(2)-OH),(|),(CH_(2)OH):},H^(o+)`
`{:(CH_(2)-OH),(|),(CH_(2)OH):},OH^(o+)`
`HCN`

ANSWER :B
Discussion
11.

In the estimation of sulphur, organic compound on treating with conc. HNO_(3) is converted to

Answer»

`SO_(2)`
`H_(2)S`
`H_(2)SO_(4)`
`SO_(3)`

Solution :In CARIUS method sulphur of organic compound is converted into `H_(2)SO_(4)`.
`S + H_(2)O + 3O UNDERSET(HNO_(3)) overset(Delta)rarrH_(2)SO_(4)`.
Discussion
12.

In the estimation of sulphur by carius methode 0.480g of organic compound give 0.699g of Barium sulphate. The percentage of sulphur in the compound is (Atomic masses , Ba=137, S=32, O=16)

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`15%`
`35%`
`20%`
`30%`

Answer :C
Discussion
13.

In the estimation of sulphur by Carius method, 0.480g of an organic compound gives 0.699g of barium sulphate. The percentage of sulphur in this compound is [Atomic masses : Ba=137, S=32, O=16]

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`20%`
`15%`
`35%`
`30%`

Solution :Percentage of `S=(32)/(233)xx("Mass of"BaSO_(4)"formed")/("Mass of compound taken")xx100`
`=(32)/(233)xx(0.699)/(0.480)xx100=20%`
Discussion
14.

In the given reaction C_6H_5-underset(O)underset(||)C-CH_3overset(NH_2OH//H^(o+))rarr[X]overset(Na//C_2H_5OH)rarr[Y] [Y] willbe

Answer»

`C_6H_5-UNDERSET(CH_3)underset(|)(CH)-NH_2`
`C_6H_5-underset(CH_3)underset(|)(CH)-NH-CH_3`
`C_6H_5-OVERSET(O)overset(||)C-NH-CH_3`
`CH_3-overset(O)overset(||)C-NH-C_6H_5`

ANSWER :A
Discussion
15.

In the estimation of nitrogen by Kjeldahl's method, 2.8 gm of an organic compound required 20 millimole of H_(2)SO_(4) for the complete neutralization of NH_(3) gas evolved. The percentage of nitrogen in the sample is:

Answer»

0.2
0.1
0.4
0.3

Solution :Kjeldhars METHOD % `N=(1.4 xx "meq of" H_(2)SO_(4))/("mass of ORGANIC compound")=(1.4 xx 20 xx 2)/(2.8)=20%`
Discussion
16.

In the estimation of nitrogen by Duma 's method 1.18 g of an organic compound gave 224 mL of N_2 at NTP. The percentage of nitrogen in the compound is about :

Answer»

20
11.8
47.5
23.7

Answer :D
Discussion
17.

In the given reaction A+3B to 2C, the rate of formation of C is 2.5xx10^(-4)mol L^(-1)s^(-1). Calculate the (i) rate of reaction, and (ii) rate of disapperance of B.

Answer»

Solution :Rate of REACTION `=-([Delta A])/(Delta t)=-(1)/(3)([Delta B])/(Delta t)=(1)/(2)([Delta C])/(Delta t)`
Rate of FORMATION of `C=([Delta C])/(Delta t)=2.5xx10^(-4)MOL L^(-1)s^(-1)`
`:."""Rate of reaction"=(1)/(2)([Delta C])/(Delta t)=(1)/(2)xx2.5xx10^(-4)mol L^(-1)s^(-1)=1.25xx10^(-4)mol L^(-1)s^(-1)`
and Rate of disapperance of `B=([Delta B])/(Delta t)=(3)/(2)([Delta C])/(Delta t)=(3)/(2)xx2.5xx10^(-4)mol L^(-1)s^(-1)`
`=3.75xx10^(-4)mol L^(-1)s^(-1)`
Discussion
18.

In the given reaction [C_6H_5-CH_2-CH_2-overset(o+)(N)(CH_3)_2-CH_2-CH_3]overset(Theta)(OH)overset(Delta)rarr (X) as major product will be

Answer»

`C_6H_5-CH=CH_2`
`CH_2=CH_2`
`C_6H_5-CH=CH-CH_3`
`CH_3-CH=CH-CH_3`

ANSWER :B
Discussion
19.

In the estimation of nitrogen by Duma 's method 0.59 g to organic compound gave 112 mL nitrogen at NTP .The percentage of nitrogen in the compound is about :

Answer»

23.7
11.8
20
47.5

Answer :A
Discussion
20.

In the estimation of chlorine in a given compound, it was found that 0.0811g of a compound gave 0.2368g of silver chloride. Calculate the percentage of chlorine in the given compound.(Ag= 108, Cl= 35.5)

Answer»

Solution :Moles of Cl in AgCl `= 1 xx` MOLE of AgCl
`=(0.2368)/(143.5)` (AgCl= 143.5)
Weight of CHLORINE `= (0.2368)/(143.5)xx 35.5`
0.0586g
PERCENTAGE of Cl in the compound `= (0.0586)/(0.0811) xx 100`
= 72.27%
Discussion
21.

In the given reaction C_6 H_5 CHO + X underset((ii) HOH//NH_4 Cl)overset((i)Zn)to C_6 H_5 -overset(OH)overset(|)CH-CH_2-COOC_2 H_5. [X]will be

Answer»

`CH_3-COOC_2 H_5`
`CH_3-CH_2-COOC_2H_5`
`Br-CH_2 COOC_2H_5`

ANSWER :C
Discussion
22.

In the esterfication C_(2)H_(5)OH(1) + CH_(3)COOH(1)hArrCH_(3)COOC_(2)H_(5)(l)+H_(2)O(l) an equimolar mixture of alcohol and acid taken initially yields under equilibrium, the water with mole fraction = 0.333. Calculate the equilibrium constant.

Answer»


ANSWER :K=4
Discussion
23.

In the given reaction 2X_((g))+Y_((g))iff2Z_((g))+80kcal, which combination of pressure and temperature will give the highest yield of Z at equilibrium?

Answer»

1000 atm and `200^(@)C`
500 atm and `500^(@)C`
1000 atm and `100^(@)C`
500 atm and `100^(@)C`

Solution :As `n_(p)ltn_(R)`, higher the pressure, greater will be yield of Z. As reaction is exothermic in the forward direction, lower the TEMPERATURE, greater is the yield of Z (as at low temperature the reaction is SLOW, usually optimum temperature is used).
Discussion
24.

In the esterificaiton reaction: Which of the following is formed as an intermediate ?

Answer»




ANSWER :A
Discussion
25.

In the given reaction ._(92)U^(235) overset(-alpha)rarr (A) overset(-beta)rarr (B) overset(-beta)rarr (C) isotopes are

Answer»

A and C
`._(92)U^(235)` and C
A and B
A, B and C

Solution :`._(92)U^(235) overset(-alpha)RARR (A) overset(-beta)rarr (B) overset(-beta)rarr (C)`
(i) `._(92 -2)A^(235-4) = ._(90)A^(231)`
(ii) `._(90)A^(231) overset(-beta)rarr ._((90 +1))B^((231)) = ._(91)B^(231)`
(III) `._(91)B^(231) overset(-beta)rarr ._((91 +1))C^(231) = ._(92)C^(231)`
Isotopes are `._(92)U^(235) and C`
Discussion
26.

In the equilibrium SO_2CI(g) hArr SO_2(g) +CI_2(g) at 2000 k and 10 atm pressure , % CI_2 =% SO_2=40 (byvolume) then

Answer»

`K_c=0.1 MOL "It"^(-1)`
`(N(SO_2CI_2))/(n(SO_2))=1/4` at equilibrium
`n(SO_2CI_2)=n(SO_2)=n(CI_2)`
`K_p=8` atm

ANSWER :D
Discussion
27.

In the given oxides of chromium, the oxide with higher ionic character and the oxide with higher basic nature respectively are: (i) CrO (ii) CrO_(3) (iii) Cr_(2)O_(3) (iv) CrO_(2)

Answer»

`CrO_(3) and CRO`
`CrO and CrO_(3)`
`CrO_(2) and CrO_(3)`
`CrO and CrO`

ANSWER :D
Discussion
28.

In the equlibrium N_(2)+2H_(2)hArr2NH_(3)+22 kcal, the formation of ammonia is fovoured by

Answer»

INCREASING the PRESSURE
Increasing the TEMPERATUE
Decreasing the pressure
ADDING AMMONIA

Answer :A
Discussion
29.

In the given reaction

Answer»




Discussion
30.

In the equlibriumAB hArr A+B, if the equlibrium concentration of A is doubled, the equlibrium concentratio of B would become

Answer»

TWICE
HALF
`1//4^(TH)`
`1//8^(th)`

ANSWER :B
Discussion
31.

In the given reaction ,

Answer»

A POSITIONAL isomer of X
Identical to X
Chain isomer of X
An oxidation product of X

Solution :
Discussion
32.

In the equilibrium reaction A+BhArrC+D, the activation energy for the forward reaction is 25 kcals "mole"^(-1) and that of backward reaction is 15 kcals "mole"^(-1). Which one of the following statements is correct?

Answer»

it is an EXOTHERMIC process
it is an endothermic process
it is a reaction for which `DELTA H=0`
it is a SUBLIMATION process

Answer :B
Discussion
33.

In the given isotherm select the incorrect statement?

Answer»

<P>`x//m prop P^(1//n)` along `OA`
`x//m prop P^(@)` when ppoint `B` reached
`x//m` does not increase as rapidly with pressure along `BC` due to LESS surface AREA available for adsorption
Nature of isotherm is different for TWO gases for same adsorbent.

Solution :N//A
Discussion
34.

In the equilibrium N_(2)+3H_(2)hArr2NH_(3), the maximum yield of ammonia will be obtained with the process having

Answer»

LOW PRESSURE and HIGH TEMPERATURE
low pressure and low temperature
high temperature and high pressure
high pressure and low temperature

Answer :D
Discussion
35.

In the equilibrium, H_(2)+I_(2)iff2HI, if at a given temperature the concentrations of the reactants are increased, the value of the equilibrium constant, K_(c), will

Answer»

increase
decrease
remain the same
cannot be predicted with certainty

Solution :The value of EQUILIBRIUM constant for a particular REACTION is always constant depending only UPON the TEMPERATURE of reaction and is independent of concentration of reactants.
Discussion
36.

In the given following complex compound / ions, how many exist in enantiomeric form ? [Pt(NH_(3))_(3)Cl_(3)]^(+)""[Co(NH_(3))_(2)(H_(2)O)_(2)Cl_(2)]^(+) [Cr(H_(2)O)_(3)BrClI],""[Pt(en)_(2)Cl_(2)]^(2+), [Cr(bipy)_(2)BrCl]^(+),""[Fe(edta)]^(-)

Answer»


SOLUTION :`[Co(NH_(3))_(2)(H_(2)O)_(2)Cl_(2)]^(+),"" [Cr(H_(2)O)_(3)BrClI]`,
`[Pt(en)_(2)Cl_(2)]^(2+), "" [Cr(bipy)_(2)BRCL]^(+)`,
`[Fe(EDTA)]^(-)`
Discussion
37.

In the given irreversible reaction, H_2O+HCl to H_3O^++Cl^- the species that acts as Bronsted base is

Answer»

`H_2O`
`HCL`
`H_3O^+`
`CL^-`

ANSWER :A
Discussion
38.

in the given equation 4Fe(s)+3O_(2)(g) to 2Fe_(2)O_(3)(s) the entropy change is =-549.4 JK^(-1) mol^(-1)at 298 K (Delta_rH^(-)=-1648 xx10^(3)Jmol^(-1)).the above reactions is

Answer»

spontaneous
non-spontaneous
both (a) and (b)
none of these

Solution :At temperature, T entropy cahange of the surroundingsis
`DeltaS_(surr)=(Delta_(r)H^(THETA))/T ` ( atconstant pressure) `-(-1648xx10^(3)Jmol^(-1))/(298K) `
` 5530JK ^(-1) MOL^(-1)`
`Delta_(r)S("TOTAL")=5530+(-549.4)`
`4980.6 JK^(-1)mol^(-1)`
Hence , the abouve REACTION is spontaneous.
Discussion
39.

In the given energy graph for cyclohexane, the point "B" represent.

Answer»

CHAIR conformation
Half chair conformation
Twist BOAT conformation
Boat conformation

Solution :INFACT "B" is the half chair conformation of cyclohexane.
Discussion
40.

In the equilibrium H_(2)+I_(2)hArr2HI the number of moles of H_(2),I_(2) and HI are 1,2,3 moles respectively. Total pressure of the reaction mixture is 60 atm. Calculate the partial pressures of H_(2),I_(2) and HI in the mixture.

Answer»


ANSWER :10 ATM, 20 atm, 30 atm
Discussion
41.

In the given conformation , ifC_(2) is rotated aboutC_(2)-C_(3)bond anticlockwise by an angle of 120^(@)then the conformation obtained is

Answer»

FULLY ECLIPSED CONFORMATION
partiallyeslipsedconformation
gaucheconformation
staggered conformation

SOLUTION :N/A
Discussion
42.

In the equilibrium H_(2) + I_(2) hArr 2HI , if at a given temperature the concentration of the reactants are increased , the value of equilibrium constant , K_(c) , will be -

Answer»

Increase
DECREASE
REMAIN the same
Cannot be predictedwith CERTAINTY

ANSWER :C
Discussion
43.

In the given E_2 reaction CH_3-overset(F)(CH)-CH_2-CH_3 + CH_3-CH_2 -overset(o.)(O) overset(CH_3-CH_2OH)(rarr)CH_3-underset(("major product"))(CH_2-CH)=CH_2 + underset(("minor product"))(rarr)CH_3-CH=CH-CH_3 The transition state has

Answer»

carbanion-like CHARACTER 
carbocation-like character 
free RADICAL character 
MUCH like alkene character

Answer :A
Discussion
44.

In the given compounds how many are unsaturated hydrocarbon ?

Answer»


ANSWER :3
Discussion
45.

In the equilibrium CH_(3)COOH + HF hArr CH_(3)COOH_(2)^(+) + F^(-)

Answer»

`F^(-)` is the conjugate acid of `CH_(3)COOH`
`F^(-)` is the conjugate base of HF
`CH_(3)COOH` is the conjugate base of `CH_(3)COOH_(2)^(+)`
`CH_(3)COOH_(2)^(+)` is the conjugate base of `CH_(3)COOH`

Solution :`CH_(3)COOH + HF HARR CH_(3)COOH_(2)^(+) + F^(-)`. HF gives `H^(+)` to the `CH_(3)COOH`. So it is a conjugate base of HF.
Discussion
46.

In the general electronic configuration (n-2)^f(1-14) (n-1)^d(0-1) ns^2,if the value of n=7,the configuration will be of

Answer»

Lanthanoids
Actinides
Transition elements
p-block elements

Answer :B
Discussion
47.

In the given sequence HOCH_2-CHOH-CH_2OH overset(Br_2//H_2O)(rarr)A + B overset(dil.NaOH)(rarr)(X), X is

Answer»

GLYCERALDEHYDE
DIHYDROXYACETONE
Fructose
Glucose

ANSWER :C
Discussion
48.

In the geometry of a complex compound, the molecule is trigonal bipyramidal. What is the hybridisation of the central atom ?

Answer»

SOLUTION :`DSP^(3)` or `SP^(3)d` HYBRIDISATION.
Discussion
49.

In the equilibrium, 2AhArrB+C, the equilibrium concentrations of A.B and C at 300K are 3xx10^(-4)M, 1xx10^(-4)M and 4.5xx10^(-4)M respectively. Thte vlue of K_(c) for the above equilibrium at 300 K is

Answer»

`0.5`
`0.05`
`5.0`
`1.5`

Solution :For the equlibrium,
`2AhArrB+C`
`K_(c)=([B][C])/([A]^(2))`
`where [B]=1XX10^(-4)M,[C]=4.5xx10^(-4)M and [A]=3XX10^(-4)M`
Then `k_(c)=((1xx10^(-4))(4.5xx10^(-4)))/((3xx10^(-4))^(2))=(4.5)/(9)=0.5`
Discussion
50.

In the equiliberium 2SO_2 (g) + O_2 (g) ⇌2SO_3, the partial pressure of SO_2 , O_2 AND SO_3 are 0.662, 0.101 and 0.331 atm respectively. What should be the partiaal pressure of oxygen so that the equiliberium of SO_2 and SO_3 are equal ?

Answer»

0.4 atm
1.0 atm
0.8 atm
0.25 atm

Answer :A
Discussion