Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

If there be a compound of the formuls CH_3C(OH)_3 which one of the following compounds would be obtained from it without treatment with any reagent :

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Methanol
Ethanol
Acetic acid
Formaldehyde

Answer :C
2.

If there are three possible values for spin quantum number, then possible number of elements in the 5^(th) perid of periodic table would be :

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18
27
32
48

Answer :B
3.

If the yeild of chloroform obtainable from acetone and bleching powder is 58% . What is the weight of acetone required for producing 23.9 gm of chloroform ? 2CH_(3)COCH_(3) +6CaOCl_(2) to Ca(CH_(3)C"OO")_(2) + 2CHCl_(3) + CaCl_(2) + 2Ca(OH)_(2)

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ANSWER :20 GM
4.

If the Zn^(2+)//Zn electrode is diluted to 100 times then the change in e.m.f.

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Increase of 59 mV
Decrease of 59 mV
Increase of 29.5 mV
Decrease of 29.5 mV

Solution :`E_(cell)=(0.059)/(n)log((1)/(C))=-(0.059)/(2)log((1)/(100))`
`=-(0.059)/(2)(-2)=0.059V=59mV`. (increase)
5.

If the work function (w) of an arbitrary metal is 3.1 eV, find its threshold wavelength and the maximum kinetic energy of the electron emitted when radiation of 300 nm strike the metal surface. ("Take" hc=12400 eV Å)

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ANSWER :(a) `4000 Å` (B) `1.033 EV`
6.

If the wavelength of light is 5.89 xx 10^(-5) cm, what will be the energy in one photon in the given region of light ? (h= 6.63 xx 10^(-27) " erg".s, c= 3 xx 10^(10)cm//s)

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Solution :We have, E= hv
and `C= v lamda`
From which we get, `E= (hc)/(lamda)`
`=(6.63 XX 10^(-27) xx 3 xx 10^(10))/(5.89 xx 10^(-5))`
`=3.37 xx 10^(-12)` erg
7.

If the volume of the vessel in which the reaction 2 NO + O_(2) to 2NO_(2) is occuringis diminished to 1/3 rd of its initial volume . The rate of the reaction will be increased by

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3 times
9 times
27 times
36 times

Solution :For a given reaction
`2NO_((g)) + O_(2(g)) hArr 2NO_(2(g))`
Rate of reaction = `k[NO]^(2) [O_(2)]`
Rate of reaction directly proportional to CONCENTRATION of the compound or inversely proportional to the volume of the vessel
i.e.` C prop (n)/(v)` lt brgt If volume of vessel is reduced by 1/3 rd of its INITIAL value , then concentration of compound is INCREASED by 3 times and CONSEQUENTLY the rate of reaction by 27 times.
8.

If the volume of the vessel in which the reaction 2NO_((g)) + O2_((g)) rarr 2NO_(2(g)) is occurring is diminished to 1//3^(rd) of its initial volume. The rate of the reaction will be increased by

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3 TIMES
9 times
27 times
36 times

Solution :For a given reaction
`2NO_((G)) + O_(2(g))hArr2NO_(2(g))`
Rate of reaction = `k[NO]^(2)[O_2]`
Rate of reaction directly proportional to concentration of the COMPOUND or inversely proportional to the VOLUME of the vessel.
i.e. `Cpropn/V`
If volume of vessel is reduced by 1/3rd of its initial value, then concentration of compound is increased by 3 times and consequently the rate of reaction by 27 times.
9.

If the wave number of 1^(st) line of Balmer series of H-atom is 'x' then :

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Wave number of `1^(st)` line of lyman series of the `He^(+)` ION will be `(108 x)/5`
Wave number of `1^(st)` line of lyman series of the `He^(+)` ion will be `(36X)/5`
The wave length of `2^(nd)` line of lyman series of H-atom is `5/(32X)`
The wave length of `2^(nd)` line of lyman series of H-atom is `(32x)/5`

SOLUTION :`barv=RZ^2(1/n_1^2-1/n_2^2)implies x=R(1/2^2-1/3^2)=(5R)/36`
`barv_1=Rxx2^2(1-1/2^2)=3R=36/5x xx3=(108x)/5`
WAVELENGTH of `2^(nd)` line of lyman series of H-atom
`1/lambda=Rxx1^2(1/1^2-1/3^2)implies 1/lambda=Rxx8/9`
`1/lambda=(36x)/5xx8/9 implies lambda=5/32 x`
10.

If the volume of a given mass of a gas at constant temperature becomes three times, the pressure will be

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3p
p/3
9p
p

Answer :B
11.

If the volume occupied in a crystal by a molecule of NaCl is 47xx10^(-24)mL calculate the volume of the crystal weighing 1g. .

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SOLUTION :NUMBER of MOLECULES of NaCl.
`=("Mass")/("Molar mass")xx6.023xx10^(23)`
`=(1)/(58.5)xx6.023xx10^(23)=1.03xx10^(22)` ltbr. VOLUME of crystal `=1.03xx10^(22)xx47xx10^(-24)=0.484mL`.
12.

If the velocity of an elelctron moving in first bohr 's orbit of hydrogen has to be reduced to 7.272 xx 10^(5) ms^(-1)it shouldbe shifted by

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4.23 A awayfrom NUCLEUS
4.23 A TOWARDS nucleus
4.76 A AWAY from nucleus
4.76 A towards nucleus

ANSWER :A
13.

If the vapour pressure of pure liquids A and B are 300 mm and 800 mmHgat 75^@C , calculate the composition of the mixture such that it boils at 75^@C. Find the composition of the vapour phase.

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SOLUTION :0.08, 0.92, 0.0316, 0.9684
14.

If the various terms in the given below expressions have usual meanings, the van't Hoff factor (i) cannot be calculated byb which one of the expressions

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`pi V = sqrt("in")RT`
`Delta T_(f)=ik_(f).m`
`Delta T_(b)=ik_(b).m`
`(.^(@)P_("solvent")-P_("solution"))/(.^(@)P_("solvent"))=i((n)/(N+n))`

Solution :(a) Vant' Hoff equation is
`piV` = inRT
(b) For depression in FREEZING POINT.
`Delta T_(f)=ixx k_(f)xx m`
(c ) For elevation in boiling point.
`Delta T_(b)= ixx k_(b)xx m`
(d) For lowering of VAPOUR pressure,
`(P_("solvent")-P_("solution"))/(P_("solvent"))=i((n)/(N+n))`.
15.

If the various terms in the following expressions have usual meanings, the van't Hoff factor 'i' cannot be calculated by which of the following expression ?

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<P>`PI V = inRT`
`DeltaT_(F) = iK_(f)m`
`DeltaT_(b) = iK_(b)m`
`(p_("solvent")^(@)-p_("solution"))/(p_("solvent")^(@)) = i((N)/(N+n))`

Solution :For relative lowering of V.P., expression is
`(p^(@)-p_(s))/(p^(@)=(i n)/(N+ i n)`
For very dilute solution,
`(p^(@)-p_(s))/(p^(@)=(i n)/((N)`
16.

If the value of equilibrium constant (K_f) for the operation Zn_((aq))^(2+) + 4OH_((aq))^(-) iff Zn(OH)_(4(aq))^(2-) is 10^(10x), then x is (Given : Zn_((aq))^(2+) + 2e^(-) to Zn_((s)) , E^(@)=-0.76 V, Zn(OH)_(4(aq))^(2-) + 2e^(-) to Zn_((s)) + 4OH_((aq))^(-) , E^(@) = - 1.36 V, 2.303 (RT)/(F) = 0.06)

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Solution :(1) `ZN^(+2) + 2e^(-) to Zn ,(-0.76 xx 2)`
(2) `Zn + 4OH^(Ɵ) to [Zn(OH)_4]^(-2) + 2e^(-) , ( + 1.36 xx 2)`
(3) `Zn^(+2) + 4OH^(Ɵ) to [Zn(OH)_4],(E_(3)^(0) xx 2 ) (3) = (1) + (2)`
` E_(3)^(0) = ((-0.76 xx 2)+ (1.36 xx 2))/(2) ,E_(3)^(0) = + 0.60 V = (0.0591)/(2) log K_c`
`log K_(c) = (0.60 xx 2)/(0.0600 ) =2 xx 10^(2) , log K_(c) = 10 xx 2 = 20 , K_(c) (10)^(10 xx 2) , K_(c)(10)^(10xx2) = (10)^(10 x) , x = 2 `
17.

If the value of n+l is more than 3 and less than 6, what will be the possible number of orbitals?

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10
11
13
6

Solution :For n+l more than 3 and less than 6, then the possible SUBSHELLS are 3P, 3d, 4P and 5s. Therefore the NUMBER for orbtials `=3+5+1+3+1=13`.
18.

If the value of Avogadro's number is 6.023xx10^(23)"mol"^(-1) and the value of Boltzman constant is 1.380xx10^(-23)JK^(-1). The number of significant digits in the calculated value of the universal gas constant is:

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Solution :`K=(R)/(N_(A)),R=kxxN_(A)=(1.380xx10^(-23))XX(6.023xx10^(23))`
Since both numbers have four significant DIGITS hence, the RESULT will ALSO have 4 significant digits.
19.

If the value of Avogadro number is6.023 xx 10^(23) mol^(-1) and the value of Boltzmann constant is 1.380 xx 10^(-23)J K^(-1), then the number of significant digits in the calculated value of the universal gas constant is

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SOLUTION :`K= (R)/(N_(A)):. R = k.N_(A)`
`=6.023 xx 10^(23)xx1.380 xx10^(-23)J.mol^(-1) .k^(-1)`
There are 4 significant figures in each term.
HENCE, these be 4 significant FIGURE in R.
20.

If the value of an equilibrium constant for a particular reaction is 1.6xx10^(12), then at equilibrium the system will contain

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Mostly reactants
Mostly PRODUCTS
SIMILAR amounts of reactants and products
All reactants

Solution :`K=1.6xx10^(12)=[("Product")/("Reactan t")]`
k have high VALUE of products have very high conc than reactant.
21.

If the units of rate constant ia a reaction is mol^-1LS^-1 then mention its order.

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SOLUTION :SECOND ORDER or 2 or order=2.
22.

If the unit of the rate constantof a reaction isdm^(3//2).mol^(-1//2).s^(-1), then the overall order of the reaction will be -

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`(1)/(2)`
2
`(3)/(2)`
`(2)/(3)`

ANSWER :C
23.

If the unit length of the unit cell is5 Åthe smallest distance is A^(@)between two neigghbouring metal atoms is a fcc is

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`2.5`
`5.00`
`7.07`
`3.535`

Solution :Unitcell LENGTH a`=5A^(@)`
NEAREST neighbouring distance
`=(1)/(2)sqrt(2xx5^(2))=(sqrt(50))/(2)=(7.07)/(2)`
`=3.535A^(@)`
24.

If the unit of rate constant of a reaction is mol^(-1)Ls^(-1) then mention its order.

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SOLUTION : Second ORDER (or) 2 (or) Order = 2 (or) TWO (any ONE)
25.

If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with m fraction of octahedral holes occupied by aluminium ions and n fraction of tetrahedral holes occupied by magnesiums ions, m and n respectively, are

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`1/2, 1/8`
`1,1/4`
`1/2,1/2`
`1/4, 1/8`

Solution :c.c.p. is f.c.c. arrangement (z = 4) so number of `O^(2-)` ions are 4. Octahedral and TETRAHEDRAL holes are 4 and 8 respectively. As 8 negative CHANGES can be neutralised by `2AL^(3+)`and `1Zn^(2+)` ion, m and n are `2/4=1/2`and `1/8`respectively.]
26.

If the uncertainty in the positioin of an electron is zero, the uncertainty in its momentum would be

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zero
`gt h//4pi`
`LT h//4pi`
infinite

Solution :`Delta X XX Delta p=h/(4pi)`
If `Deltax=0,Deltap=h/(4pi xx 0)=` INFINITY.
27.

If the two alkyl groups attached to the oxygen atom are the same, then it is calleld _______ ether.

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SIMPLE
SYMMETRICAL
UNSYMMETRICAL
both (a) and (b) are CORRECT

ANSWER :D
28.

If the total energy of anelectron in a hydrogen like atom in excited state is -3.4eV,then the de Broglie wavelength of the electron is

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`6.6xx10^(-12)m`
`3xx10^(-10)m`
`6.6xx10^(-10)m`
`9.3xx10^(-12)m`

Solution :`E_(n)=(E_(1))/(n^(2))`
`-3.4eV=-13.6/(n^(2))` or `n^(2)=13.6/3.4=4`,
`:.n=2`
VELOCITY of ELECRON isn=2 is `(v_(1))/2`
`=(2.19xx10^(6))/2ms^(-1)`
`:.lamda=h/(mv)=(6.6xx10^(-34)xx2)/(9.1xx10^(-31)xx2.19xx10^(6))`
`=6.6xx10^(-10)m`
29.

If the two chlorine atoms are attached to the same carbon atom of an alkane, it is termed as :

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ALKYL DICHLORIDE
alkylene HALIDE
alkyl halide
ALKYLIDENE halide

ANSWER :D
30.

If the total energy of an electron in a hydrogenatom in excited state is - 3.4 eV, then the de Broglie wavelength of the electron is

Answer»

`6.6xx10^(-12)` m
`3xx10^(-10)` m
`6.6xx10^(-10)` m
`9.3xx10^(-12)` m

SOLUTION :`E_n=E_1/n^2 RARR -3.4 eV = -13.6/n^2 rArr n^2= 13.6/3.4 =4`
`therefore` n=2
VELOCITY of electron in n =2 is
`V=(2.19xx10^6)/2 m s^(-1)`
`therefore lambda=h/(mv)=(6.6xx10^(-34)xx2)/(9.1xx10^(-31)xx2.19xx10^6)=6.6xx10^(-10)` m
31.

If the third layer arrangement is aba arrangement, it is called ………………….. arrangement.

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SOLUTION :HCP or HEXAGONAL CLOSE PACKED
32.

If the temperature of an ideal gas is increased by 25% then by what percentage would its volume increase?

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SOLUTION :As per Charle’s Law `(V_(1))/(T_(1)) = (V_(2))/(T_(2))` here, `(V_(1))/(T_(1)) =(V_(2))/(1.25T_(1))` or `V_(1)=0.8V_(2)` which MEANS that if temperature has increased by 25% then volume also INCREASES by the same percentage.
33.

If the t_(1//2) for a first order reaction is 0.4 min, the time for 99.9% completion of the reaction is……………. Min.

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SOLUTION :`t_(99.9%)=10xxt_(50.0%)=10xx0.4=4min`
34.

If the temperature increases from 0^(@)C to 50^(@)C at atmospheric pressure, which of the following processes is expected to take place more in case of liquids

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FUSION
VAPORISATION
solubilization
none

Solution :An INCREASE in temperaturefavoures evaporationdue to increase in AVERAGE kinetic ENERGY of molecules.
35.

If the temperature increases from 0^@C to 50^@C at atmospheric pressure, which of the following processes is expected to take place more in case of liquids?

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Fusion
Vaporisation
Solubilization
None

Answer :B
36.

If the system CaF_2(s) hArrCa^(2+) + 2F^- increasing the concentration of Ca^(2+) ions 4 times will cause the equilibrium concentration of F^- ions to change to :

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1/4 of the INITIAL value
1/2 of the initial value
2 TIMES of the initial value
None of these

Answer :B
37.

If the supply of oxygen is limited, H_2S reacts with O_2 to form

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`H_2O + SO_3`
`H_2O+ S`
`H_2SO_4 + S`
`H_2O + SO_2`

ANSWER :B
38.

If the starting materical is 1-methyl-1, 2-epoxy cyclopentane, of absolute configuration, decide which one compound correctly represent the product of its reaction with sodium methoxide in methanol

Answer»




ANSWER :B
39.

If the standard electrode potential of Cu^(2+)//Cu electrode is 0.34 V.What is the electrode potential of 0.01 M aqueous solution of Cu^(2+)at 298K?

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`0.399` V
`0.281` V
`0.222` V
`0.176` V

Answer :B
40.

If the standard electrode protential of Cu^(2+)// Cu electrode is 0.34 V , what is the electrode potential at 0.01 M concentration of Cu^(2+) ? (T = 298^(@)K)

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`0.399V`
`0.281V`
`0.222V`
`0.176 V`

ANSWER :B
41.

If the standard electrodepotential (E^(@)) of ametal is "______"and "______" the metalis a powerfulreductingagent .

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largenegative
largepositive
smallnegative
smallpostive

ANSWER :A
42.

If the standard electrode potential of an electrode is greater than zero, then we can infer that its

Answer»

REDUCED from is more STABLE COMPARED to hydrogen GAS.
oxidised from is more stable compared to hydrogen gas.
reduced and oxidised forms are equally stable.
reduced from is less stable than the hydrogen gas.

Answer :A
43.

If the spin quantum number can have the following values (-(3)/(2), (1)/(2) , 0 + (1)/(2) + (3)/(2)) then, number of elements in 10 ^(th) period of periodic table.

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ANSWER :180
44.

If the SRP of nickel and chlorineelectrodes are -0.25 Vand + 1.36 V respectively . The EMF of the cellNi//Ni^(2+) (0.01M)// // Cl^(-) (0.01M) // Cl_2 , Pt is - V

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`+1.61`
`-1.61`
`+1.79`
`-1.79`

ANSWER :C
45.

If the specific conductance and conductance of a solution are same, then its cell constant is equal to

Answer»

1
0
10
100

Answer :A
46.

If the solution of mercurycyanide of strenght 3gl/1 has an osmotic pressure 0.3092xx10^(5)Nm^(-2) at 298 K, what is the apparent molecular weight and degree of dissociation of Hg(CN)_(2)?

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ANSWER :`2.4567%`
47.

If thesolution of copper sulphate in which a copper rod is immersed, is diluted 100 times, what is thechange in electrode potential (Reduction) ?

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INCREASES by 29.5 MV
DECREASES by 29.5 mV
Increases by 59.0 mV
Decreases by 59.0 mV

Answer :D
48.

If the solution boils at a temperature T _(1 )and the solvent at a temperature T _(2) the elevation ofboiling point is given by

Answer»

`T_(1) + T_(2)`
`T_(1)- T_(2)`
`T_(2) -T_(1)`
`T_(1) + T_(2)`

Solution :Solution always boil at higher TEMPERATURE
`T_(1) -T_(2) = DELTA T_(B)`
49.

If the solubility products of AgCl and AgBr are 1.2 xx 10^(-10) and 3.5 xx 10^(-13) respectively, then the relation between the solubilities (denoted by the symbol'S') of these

Answer»

S of AgBr is less than that of AgCl
S of AgBr is GREATER than that of AgCl
S of AgBr is EQUAL to that of AgCl
S of AgBr is `10^(6)` TIMES greater than that of AgCl

Solution :`AgCl K_(sp) = 1.2 xx 10^(-10)`
`S = sqrt((1.2 xx 10^(-10))), S = 1.09 xx 10^(-5)`
`AgBr K_(sp) = 3.5 xx 10^(-13)`
`S = sqrt(3.5 xx 10^(-13)) = 5.91 xx 10^(-6)`
So that S of AgBr is less than that of AgCl.
50.

If the solubility product of lead iodide (Pbl_(2)) is 3.2 xx 10^(-8), then its solubility in moles/litre will be

Answer»

`2 xx 10^(-3)`
`4 xx 10^(-4)`
`1.6 xx 10^(-5)`
`1.8 xx 10^(-5)`

Solution :`K_(SP) = 4S^(3)`
`4S^(3) = 3.2 xx 10^(-8), S = 2 xx 10^(-3) M`.