Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In alkene structure, three carbon atoms are joined by

Answer»

THREE `pi`- bonds only
Three`SIGMA`- and three `pi` bonds
TWO `sigma` and two `pi`- bonds
Two `sigma`- and one `pi`-bonds

Answer :C
Discussion
2.

In alkaline medium which of the following oxyanion can oxidize I^(-)(aq).

Answer»

`Cr_(2)O_(7)^(2-)`
`MnO_(4)^(-)`
`MoO_(4)^(2-)`
`WO_(4)^(2-)`

Solution :In acidic medium alcohol undergo reaction.
Discussion
3.

In alkanes the bond angle is :

Answer»

`109.5^@`
`109^@`
`120^@`
`180^@`

ANSWER :A
Discussion
4.

In alkaline medium, KMnO_(4) gets changed into :

Answer»

`MnO_(2)`
`K_(2)MnO_(4)`
`MN^(2+)`
Mn.

Answer :B
Discussion
5.

In alkaline medium KMnO_4 can be converted into MnO_3. The decreas in oxidation sate in n so equivalent mass of KMnO_(4) = ("Molar mass")/(n),what is n ?

Answer»


SOLUTION :`M^(+7) NO_(4)^(-) RARR M^(+4) nO_2`
Discussion
6.

In alkaline medium fructose is -

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An ALDOSE
A REDUCING SUGAR
A NON reducing sugar
A furanose

Answer :C
Discussion
7.

In alkaline medium, alanine exists predominantly as

Answer»

Anion
Zwitter ion
Cation
Covalent FORM

Solution :Alanine EXISTS as a zwitter ion in neutral solution. In acidic medfium, `COO^(-)` ion of the zwitter ion accepts a PROTON to form a cation while in alkaline medium `NH_(3)^(+)` loses a proton to form an anion.
Discussion
8.

In alkaline hydrolysis of tert-Butyl bromide, _________.

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RATE of reaction is doubled as the concentration of the substrate is doubled
rate of reaction is HALVED as the concentration of any one of REACTANT is doubled
rate is DOUBLES, as concentration of nucleophile is doubled
rate is INDEPENDENT of concentration of the reactants

Answer :A
Discussion
9.

In alkaline medium KMnO_(4) reacts as follows, 2KMnO_(4)+2KOHto2K_(2)MnO_(4)+H_(2)O+O . Therefore its equivalent weight will be

Answer»

`158.0`
`52.7`
`79.0`
`31.6`

ANSWER :A
Discussion
10.

In alkaline condition KMnO_(4) reacts as follows : 2KMnO_(4)+2KOH to 2K_(2)MnO_(2) +H_(2)O +Othe eq.wt of KMnO_(4) is

Answer»

`52.7`
158
`31.6`
79

Answer :B
Discussion
11.

In alkali metal group which is the strongest reducing agnet and why?

Answer»

Solution :Li is the STRONGEST REDUCING agent. Since I.P. DECREASES down the group we would EXPECT that Li will have the lowest reducing power in that group. But since it.s hydration energy is very high and which in FACT decreases down the group, Li will have highest reducing power,
Discussion
12.

In aldehydes and ketones

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CARBONYL CARBON is NUCLEOPHILIC and carbonyl OXYGEN is electrophilic
Carbonyl carbon, is slectrophilic and carbonyl oxygen is nucleophilic
Both are electrophilic
Both are nucleophilic

Answer :B
Discussion
13.

In aldehydes and ketones, carbon of carbonyl group is

Answer»

`sp^(3)` hybridised
`sp^(2)` hybridised
sp hybridised
Unhybridised

Solution :`underset(sp^(2)"hybridised")(GT C =O)`
Discussion
14.

In alkalin solution D-glucose, D-mannose and D-fructose are in equilibrium. This reaction is known as

Answer»

FRIES rearrangement
Lobry DE Bruyn-van Enkelstein rearrangement
Hofmann rearrangement
Kolbe's reaction

Answer :B
Discussion
15.

In AgBr crystal, theion size lies in the order Ag^(+) lt lt Br^(-). The AgBr crystal exhibit, in which of the following defect?

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DEFECT LESS (PERFECT) crystal
SCHOTTKY defect
FRENKEL defect
Both Schottky and Frenkel defect

Answer :D
Discussion
16.

In AgBr, there can occur :

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SCHOTTKY DEFECT
Frenkel defect
Both (A) and (B)
None of these.

Answer :C
Discussion
17.

In adsorption, if the concentration of a substance in the interface is high, it is called .............

Answer»

SOLUTION :POSITIVE ADSORPTION
Discussion
18.

In adsorption of acetic acid on charcoal, the acetic acid is:

Answer»

ADSORBATE
ADSORBENT
ABSORBENT
INNER phase.

Answer :A
Discussion
19.

In adsorption of oxalic acid on activated charcoal, the activated charcoal is called

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Adsorbent
Adsorbate
Adsorber
Adsorber

Answer :A
Discussion
20.

In adiabatic conditions 1 mole of CO_(2) gas at 300 K is expanded such that its volume becomes 27 times. Calculate the work done. (C_(V)=6" cal "mol^(-1) and gamma=1.33 is given)

Answer»

1400 cal
1000 cal
900 cal
1200 cal

Solution :In adiabatic conditions `(T_(2))/(T_(1))=((V_(1))/(V_(2)))^(gamma-1)`
`(T_(2))/(T_(1))=((1)/(27))^(1.33-1)=((1)/(27))^(0.33)=((1)/(27))^(1//3)=(1)/(3)`
`T_(2)=300xx(1)/(3)=100K`
Thus, `T_(2) lt T_(1)` hence cooling TAKES place due to EXPANSION under adiabatic CONDITION
`DeltaE=q+W`
`DeltaEneW`(q=0 for adiabatic change)
`DeltaE=-ve` because gas exapands.
`W=-DeltaE=-C_(V)(T_(2)-T_(1))`
`=-6(100-300)=1200" cal "mol^(-1)`
Discussion
21.

In addition to the standard ring systems (such as cyclohexane), cyclic compounds can also be bicyclic, tricyclic, etc., or they can be spirocyclic, bicyclic or bridge head carbons. The point of attachment of two rings are called bridge head carbons. The point of attachment of two rings are called bridge head atoms Some bicyclic compounds like camphor are commonly found in plants. Others like norbornane can be synthesized in the laboratory. The formal names of of bicyclic and related ring systems are based on : (1) Total number of atoms in the molecule. (2) The number of atoms in each bridge connecting the bridge head atoms. These numbers are written in square bracket in decreasing order. Spirocyclic compounds have two fused rings, but only one bridge head atom. Spirocyclic compounds are named like bicyclic compounds, but have the prefix spirocyclo. Answer the following questions : Which of the following is the correct structure of bicyclo [1.1.0] butane ?

Answer»



`{:(CH_(2)-CH_(2)),("||"),(CH_(2)-CH_(2)):}`

ANSWER :a,B
Discussion
22.

In addition polymer monomer used is

Answer»

UNSATURATED COMPOUNDS
saturatedcompounds
bifunctionalsaturated compounds
trifunctional SATURATED compounds

ANSWER :A
Discussion
23.

In acidic solution, KMnO_(4)is reduced to

Answer»

 `MN^(2+)`
 `MnO_(2)`
`Mn_(2)O_(3).
 `MnO_(4)^(2-)`

ANSWER :A
Discussion
24.

In acidic solution an amino acid, when placed in an electric field ________.

Answer»

MOVES towards cathode
moves towards the ANODE
dissociates to CATION and anion
does not move either towards the cathode or anode

SOLUTION :moves towards cathode
Discussion
25.

In acidic medium Zn reduces nitrate ion ot NH_(4)^(+) ion according to the reaction underset("(unbalanced)")(Zn+NO_(3)^(-))rarrZn^(2+)+NH_(4)^(+)+H_(2)O How many moles of HCl are required to reduce half a mole of NaNO_(3) completely? Assume the availability of sufficient Zn.

Answer»

5
4
3
2

Answer :A
Discussion
26.

In acidic medium, which of the following becomes colourless ?

Answer»

`FeO_(4)^(2-)`
`CrO_(4)^(2-)`
`MnO_(4)^(-)`
`MnO_(4)^(2-)`

Solution :`MnO_(4)^(-)` CHANGES to `Mn^(2+)`
Discussion
27.

In acidic medium, the reaction, MnO_4^(1-) rarr Mn^(2+) involves :

Answer»

OXIDATION by 3 ELECTRONS
Reduction by 3 electrons
Oxidation by 5 electrons
Reduction by 5 electrons

Answer :D
Discussion
28.

In acidic medium, the rate of reaction between BrO_(3)^(-) and Br^(-) is given by the expression -(d[BrO_(3)^(-)])/(dt)=k[BrO_(3)^(-)][Br^(-)][H^(+)]^(2) It means

Answer»

Rate CONSTANT of the REACTION DEPENDS upon the concentration of `H^(+)` ions.
Rate of reaction is independent of the concentration of the acid added.
The CHANGE in pH of the solution will affect the rate of reaction.
Doubling the concentration of `H^(+)` ions will increase the reaction rate by 4 times.

Solution :Is wrong because rate constant at constant temperature, (b) is wrong because rate depends upon `[H^+]^2`, (c ) is correct be4cause change in pH mense change in `[H^+]^2`, (d) is correct because rate `prop [H^+]^2`.
Discussion
29.

In acidic medium the rate of reaction between(BrO_3)^- and Br^- ions is given by the expression.-(d(BrO_3^-))/dt=K[BrO_3^-][Br^-][H^+]^2 It means:

Answer»

RATE constant of overall reaction is` 4 sec^-1`
Rate of reaction is INDEPENDENT of the conc.of acid
The CHANGE in PH of the solution will not AFFECT the rate
Doublic the conc, of`H+` ions will increase the reaction rate by 4’times

Answer :D
Discussion
30.

In acidic medium the rate of reaction between [BrO_(3)^(-)] and [Br^(-)] ions given by the expression - (d[BrO_(3)^(-)])/(dt) = k [BrO_(3)^(-)][Br^(-)][H^(+)]^(2) It means (i) rate of constant of the reaction depends upon the concentration of H^(+) ions (ii) rate of reaction is independent of the concentration of acid added (iii) the change in pH of the solution will affect the rate of reaction (iv) doubling the concentration of H^(+) ions will increase the reactions rate by 4 items.

Answer»

only (ii)
only (III)
only (i) and (ii)
only (iii) and (IV)

Solution :Is wrong because rate CONSTANT does not DEPEND upon the CONCENTRATIONS of the reactant. (ii) is wrong because rate depends upon `[H^(+)]^(2)`
(iii)is correct because change in pH means change in `[H^(+)]` ions
(iv) is correct because rate `prop [H^(+)]^(2)`
Discussion
31.

In acidic medium the rate of reaction between (BrO_(3))^(-) and Br^(-) ions is given by the expression -(d(BrO_(3)^(-)))/(dt)=k[BrO_(3)^(-)][Br^(-)][H^(+)]^(2) it means

Answer»

RATE CONSTANT of overall reaction is 4 `sec^–1`
Rate of reaction is independent of the CONCENTRATION of acid
The change in pH of the solution will not AFFECT the rate
Doubling the concentration of `H^+` ions will increase the reaction rate by 4 times

Answer :D
Discussion
32.

In acidic medium, the equivalent weight of K_(2)Cr_(2)O_(7)(molecular weight = M) is

Answer»

M
M/2
M/3
M/6

Solution :Equivlent WEIGHT `=("Molecular weight")/("CHANGE in oxidation state/valency/no. of electron involved")`
Reaction involved is
`Cr_(2)O_(7)^(2-) + 14H^(+) + 6e^(-) to 2Cr^(3+) + 7H_(2)O`
It is quite clear that in this reaction, `Cr(+6)` is reduced to `Cr(+3)`.
`therefore` Equivalent weight of `K_(2)Cr_(2)O_(7) = ("MOL. wt")/6 = M/6`
Discussion
33.

In acidic medium, permanganate is reduced to Mn^(2+) by excess of reducing agent as MnO_4-+8H^+5e Mn_(2+) +4H_2O.Therefore, the equivalent mass of KMnO_4 is obtained on dividing its nolecular mass by :

Answer»

8
1
5
1

Answer :C
Discussion
34.

In acidic medium " MnO"_(4)^(-) is an oxidising agent as " MnO"_(4)^(-) +8H^(+)+5e^(-) rarr Mn^(2+)+4H_(2) O. If H^(+) concentration is doubled, electrode potential of the half-cell " MnO"_(4)^(-)// " Mn"^(2+), Pt will :

Answer»

INCREASE by `28.46` m V
decrease by `28.46` m V
increase by `142.3` m V
decrease by `142.30` m V

Answer :A
Discussion
35.

In acidic medium, KMnO_(4) oxidises FeSO_(4) solution. Which of the following statements is correct?

Answer»

10 ml of 1 N `KMnO_4` solution oxidises 10 ml of 5 N `FeSO_4` solution
10mlof1M`KMnO_4`solutionoxidises 10 ml of 5M `FeSO_4` solution
10 ml of 1M `KMnO_4` solution oxidises 10 ml of 1 M `FeSO_4` solution
10 ml of 1 N `KMnO_4` solution oxidises 10 ml of 0.1 M `FeSO_4` solution.

Solution :`2KMnO_(4)+8H_(2)SO_(4)+10FeSO_(4)RARR K_(2)SO_(4)+2MnSO_(4)+5Fe_(2)(SO_(4))_(3)+8H_(2)O`
One mole of `KMnO_(4)` oxidises five moles of `FeSO_(4)` i.e. 1 M `KMnO_(4)` can oxidise equal amount of 5M `FeSO_(4)`.
Discussion
36.

In acidicmedium, MnO_(4)^(2-)

Answer»

disproportionates to `MnO_(2)`to `MnO_(4)^(-)`
is OXIDIZED to `MnO_(4)^(-)`
is REDUCED to `MnO_(2)`
is reduced to `Mn^(2+)`

Solution :`MnO_(4)^(2-)`disproportionates in ACIDIC medium asfollows `:`
`3MnO_(4)^(2-) + 4H^(+) RARR 2MnO_(4)^(-) + MnO_(2) + 2H_(2)O`
Discussion
37.

In acidic medium KMnO_(4) oxidises FeSO_(4) solution. Which of the following statements is correct?

Answer»

10 mL of 1 N `KMnO_(4)` solution oxidises 10 mL of 5 N `FeSO_(4)` solution
10 mL of 1M `KMnO_(4)` solution oxidises
10 mL of 5 N `FeSO_(4)` solution
10 mL of 1 M `KMnO_(4)` solution oxidises
10 mL of 1 M `FeSO_(4)` solution
10 mL of 1 N `KMnO_(4)` solution oxidises
10 mL of 0.1 M `FeSO_(4)` solution

Solution :1M `KMnO_(4)-=5NKMnO_(4)-=5NFeSO_(4)`
`therefore 10xx1M-=10xx5N-=10xx5N)`
`KMnO_(4)""KMnO_(4)""FeSO_(4)`
Discussion
38.

In acidic medium, KMnO_4 oxidises FeSO_4 solution. Which of the following statements is correct?

Answer»

10 mL of 1 N `kMnO_4` solution OXIDISES 10 mL of 5 N `FeSO_4` solution.
10 mL of 1 M `KMnO_4` solution oxidises 10 mL of 5 M `FeSO_4` solution.
10 mL of 1 M `KMnO_4` solution oxidises 10 mL of 1 M `FeSO_4` solution.
10 mL of 1 N `KMnO_4` solution oxidises 10 mL of 0.1 M `FeSO_4` solution.

Solution :`2KmO_4+8H_2SO_4+10FeSO_4 to K_2SO_4+2MnSO_4+5Fe_2(SO_4)_3+8H_2O`
ONE mole of `KMnO_4` oxidises five mole of `FeSO_4` i.e. 1M `KMnO_4` can oxidise equal amount5 of 5 M `FeSO_4`.
Discussion
39.

In acidic medium if potassium permanganate is used as an oxidising agent, we get :

Answer»

`MnO_(4)^(2-)`
`MN^(2+)`
`MnO_(2)`
`Mn_(2)O_(3)`

SOLUTION :`MnO_(4)^(-) + 8H^(+) + 5e^(-) to Mn^(2+) + 4H_(2)O`
Discussion
40.

In acidic medium , H_(2)O_(2) changes sigmaCr_(2)O_(7)^(2-) to CrO_(5)which has two ( -O-O-) bonds . Oxidation state of Cr in CrO_(5) is

Answer»

`+5`
`+3`
`+6`
`-10`

Solution :`CrO_(5)` has butterfly structure having two peroxo BONDS.

OXIDATION state of peroxo oxygen `= -1`
`:. `If oxidation state of Cr is x, then
`x+ 4 ( -1) + 1( - 2) = 0` or `x= + 6`
Discussion
41.

In acidic medium, dichromate ion oxidises ferrous ion to ferric ion. If the gra molecular weight of potassium dichromate is 294 grams, its gra equivalent weight is . . . . Grams

Answer»

294
127
49
24.5

Solution :In ACIDIC MEDIUM potassium dichromate shows +6 oxidation STATE `(M)/(6)=(294)/(6)=49`
Discussion
42.

In acidic medium, CrO_(4)^(2-) changes to

Answer»

`Cr_(2)O_(7)^(2-)`
`Cr^(3+)`
`Cr(IV)`
`Cr_(2)O_(3)`

Solution :In acidic condition, chromate ions are changed to dichromate ions.
`UNDERSET("Yellow")(2CrO_(4)^(2-))+2H^(+)rarrunderset("ORANGE")(Cr_(2)O_(7^(2-)))+H_(2)O`
Discussion
43.

In acid solution, the reaction MnO_(4)^(-) rarr Mn^(2+) involves

Answer»

OXIDATION by 3 ELECTRONS
Reduction by 3 electrons
Oxidation by 5 electrons
Reduction by 5 electrons

Solution :`MnO_(4)^(-) rarr Mn^(2+)`. In this REACTION `5E^(-)` are needed for the reduction of `Mn^(2+)` as :
`MnO_(4)^(-)+5e^(-) rarr Mn^(2+)`.
Discussion
44.

In acid medium, potassium permanganate oxidizes oxalic acid to

Answer»

oxalate
Carbon dioxide
acetate
acetic acid

Solution :`5(COO)_(2)^(2-)+ 2MnO_(4)^(-)+ 16H^(+) overset(DELTA)to 2Mn^(2+)+ 10CO_(2)+ 8H_(2)O`
Discussion
45.

In acid leaching process, the insoluble sulphide is converted into soluble sulphate and elemental _______.

Answer»

carbon
lead
sulphur
zinc

Answer :C
Discussion
46.

In acid catalysed hydration of alkenes, reaction intermediate formed is

Answer»

FREE radical
Carbocation
Carbanion
Carbene

Answer :B
Discussion
47.

In acid base titration using the above mentioned acids100mL M/10NaOHis used which of the following is correct ?

Answer»

`5XX10^(-3)` MOLES of `H_(2)C_(2)O_(4)`
`5xx10^(-3)` moles of `H_(2)C_(2)O_(4)+H_(2)SO_(4)`
`5xx10^(-3)` moles of `H_(2)SO_(4)`
All of the above

Solution :100mL`(M)/(10)`NaOHto 10 mmol es of NaOH
this can neutralise` to` 5mmol es of `H_(2)C_(2)O_(2)` or 5mmoles of `H_(2)SO_(4)`
Discussion
48.

In acetylene molecule, the two carbon atoms are linked by

Answer»

one sigma bond and two pi bonds
two sigma BANDS and one pi bond
three sigma bonds
 three pi bonds.

Solution :`HC underset(2pi)OVERSET(1sigma)-=CH`
Discussion
49.

In acetylene molecule, between the carbon atoms there are

Answer»

three pi bonds
one SIGMA and two pi bonds
two sigma and one pi bonds
three sigma bonds

Solution :Acetylene - `H-Coverset(sigma)UNDERSET(2pi)EQUIV C-H`
`therefore` Number of `sigma` bonds = 1
Number of `pi` bonds = 2
`therefore (1 sigma + 2pi)` bonds are present between 2 carbon atoms.
Discussion
50.

In acetylationof aminesone ormorehydrogenatoms are removedform

Answer»

CARBONATOM only
NITROGEN atomonly
bothcarbonand nitrogenatoms
FORM acetylcholrideonly

ANSWER :B
Discussion