Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

If radium and chlorine combinetofomradiumchloride, the compound would be

Answer»

half as radioactive as RADIUM
twice as rdioactive
as radioactive as radium
not radioactive.

SOLUTION :Radioactivity REMAINS same in free atom and if it is there in a compound.
2.

If (X) turn line water milky , then X may be

Answer»

`CO_(2)`
`SO_(2)`
`NO_(2)`
`O_(2)`

ANSWER :a,B,
3.

If r_(1) is the radius of the first orbit of hydrogen atom, then the radii of second, third and fourth orbitals in terms of r_(1) are

Answer»

`r_(1)^(2),r_(1)^(3),r_(1)^(4)`
`8r_(1),27r_(1),64r_(1)`
`4r_(1),9r_(1),16r_(1)`
`2r_(1),6r_(1),8r_(1)`

Solution :`r_(N)=0.059n^(2)` (for H-atom)
`r_(1)=0.059(1)^(2)`
`r_(2)=0.059(2)^(2)=4r_(1)`
`r_(3)=0.059(3)^(2)=9r_(1)`
`r_(4)=0.059(4)^(2)=16r_(1)`
Ratio : `4r_(1):9r_(1),16r_(1)`
4.

If X molal solution of a compound is benzene has mole fraction of solute equal to 0.4. Then the value of X is

Answer»

4.2
8.5
3.2
5.1

Answer :B
5.

If R_(1) and R_(2)are the resistance of two solution of equal volume, then the conductance of the mixture in the same conductivity cell is:

Answer»

`(1)/(2)((1)/(R_1) +(1)/(R_2))`
`(1)/(2)((1)/(R_(1)+R_(2)))`
`(1)/(sqrtR_(1) R_(2)`
none of these

Solution : `G_("net") = G_(1) + G_(2)`
`K_("net") = (V_(1) + V_(2))`, `K_("net") = (G_(1)G^astxxG_(2)G^astV)/(2V)` , `K_("net") = (1)/(2)((1)/(R_(1)+ (1)/(R_(2))))G^ast = G_("net") G^ast`
6.

If X is the specific resistance of the solution and M is the molarity of the solution, the molar conductivity of the solution is given by:-

Answer»

`(1000X)/(M)`
`(1000)/(MX)`
`(1000M)/(X)`
`(MX)/(1000)`

SOLUTION :Molar CONDUCTIVITY`=(1000)/(MX)`.
7.

If R is the radius of octahedral void and r is the radius of the atoms in close packing, then (r )/(R ) is equal to

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0.414
0.225
2.41
4.44

Solution :
8.

If x is the solubility in mol L^(-1)of Ca_(3)(PO_(4))_(2). Its K_(sp)is equal to :

Answer»

`X^(5)`
`108X^(5)`
`6x^(5)`
`4X^(4)`

Answer :B
9.

If r is the radius of an atom in face-centred cubic unit cell of edge length a then

Answer»

`R=(a)/(2sqrt(2))`
`r=(4)/(sqrt(3))a`
`r=2sqrt(2)a`
`r=sqrt((3)/(4))a`

Answer :A::B
10.

If q is the heat added to the system, w is the work done by the system and Delta U is the change in internal energy, then according to first law of thermodynamics :

Answer»

<P>`Delta U = q + w`
`Delta U = q - w`
`Delta U = q + p Delta V`
`Delta U = q + Delta H`

ANSWER :B
11.

If x is the conduction of 1 cm^(3) of the solution and C is the concentration of the solution . The molar conductivity of the solution is given by

Answer»

`(1000 C)/(x)`
`(1000 x)/(N)`
`(C)/(x)`
`(x)/(C)`

Solution :Molar conductivity ` = (1000 XX "conductance")/("CONCENTRATION")`
12.

If P,V,M,Tand R are pressure, volume, molar mass, temperature and gas respectively, then for an ideal gas , the density is given by

Answer»

<P>`(RT)/(PM)`
`(P)/(RT)`
`(M)/(V)`
`(PM)/(RT)`

SOLUTION :`PV=nRT=(m)/(M ) RT`
`:. (m)/(V)=(PM)/(RT)=` DENSITY
13.

If x is the amount of adsorbateand m is the amount of adsorbent , which of the following relations is not relatedto adsorption process ?

Answer»

<P>x/m=F(P) at CONSTANT T
x/m = f(T) at constant P
P=f(T) at constant x/m
x/m=PT

SOLUTION :x/m=PT
14.

If [PtCl_6]^(x-)follows the Sidgwick rule of stability, what is the oxidation state of Pt and complex ?

Answer»

SOLUTION : `[PtCl_6]^(X-)` following Sidgwick rule of STABILITY ,thus EAN of Pt is to be equal to the atmic number of nearest inert gas 86(Rn). Let the oxidation state of platinumin `[PtCl_6]^(x-)` COMPLEX ion is y
`y + 6(-1) = -x (or) y = 6 - x`
`86 = 78 - (6-x) + 2xx 6 = 78 - 6 + x + 12 , x = 2`
Oxidation state of platinum forming the complex `=6 -x = 6-2 = +4`
Oxidation state of the complex = -2
15.

If x is the amount of adsorbate and m is the amount of adsorbent, which of the following relations is not related to adsorption process?

Answer»

<P>x/m = F(P) at CONSTANT T
x/m =f(T) at constant P
P = f(T) at constant x/m
x/m = PT

Answer :D
16.

If P_((S)) (solution pressure of metal tendency) gt P_(O) (osmotic pressure of ions in solution tendency) , then

Answer»

the electrode gets NEGATIVE charged
the electrode gets positively charged
Both 'a' and 'b'
the electrode remains neutral

SOLUTION :Solution PRESSURE of metal tendency also known as de-electronation, where metal has a tendency to pass into the solution in the form of cation leaving electrons (negative charge) on the SURFACE of metal (electrode) .
17.

If x is amount of adsorbate and m is amount of adsorbent, which of the following relations is not related to adsorption process ?

Answer»

<P>`X/mpxxT`
`x/m=f(p)` at constant T
`x/m=f(T)` at constant p
`p=f` (T) at constant `((x)/(m))`

SOLUTION :`x/m =pxxT` is not a correct relation.
18.

If x is amount of adsorbate and m is amount of adsorbent, which of the followingrelations is related to adsorption process ?

Answer»

<P>x/m = `p xx T`
x/m = f(P) at constant T
x/m = f(T) at constant P
P = f(T) at constant (x/m)

ANSWER :B
19.

If P.T would have contained 10 periods, maximum elements in that P.T. would be :-

Answer»

72
190
144
290

Solution :Till `7^(th)` period = 118 element (TOTAL magic no. add`""^(n)`)
`8^(th)` period = 59
`9^(th) ` period = 50 next magic no.
`10^(th)` period = 72
Total 290
20.

If x is amount of adsorbate and m is amount of adsorbent, which of the following relations is not related to adsorption process?

Answer»

<P>`(X)/(m)=F(p)` at CONSTANT T.
`(x)/(m)=f(T)` at constant p.
`p=f(T)` at constant `((x)/(m))`.
`(x)/(m)=p*T`

ANSWER :D
21.

If pressure increases then its effect on given equlibrium C_((s))+H_(2)O_((g))hArrCO_((g))+H_(2(g)) it is satisfied in

Answer»

Forward DIREACTION
Backward DIRECTION
No EFFECT
NONE of these

Answer :B
22.

If x is amount of adsorbate and ‘m’ is amount of adsorbent, which of the following relations is not related to adsorption process

Answer»

<P>`x/m=pxT`
`x/m=f(p) at CONSTANT T`
`x/m=f(T)` at constant P
`P=f(T)` at constant `(x/m)`

ANSWER :A
23.

If pressure greater than osmotic pressure is applied on the solution separated from the solvent by a semipermeable membrane, the flow of solvent is from …………….to …………………. The process is called………….. .

Answer»

SOLUTION :solution, SOLVENT, REVERSE OSMOSIS
24.

If X is a member of chalcogen family, the highest stability of X^(-2) is exhibited by

Answer»

OXYGEN
SELENIUM
TELLURIUM
SULPHURE

ANSWER :A
25.

If pressure becomes double at the same absolute temperature on 2L CO_(2), then the volumeof CO_(2) becomes

Answer»

<P>2L
4L
25L
1L

Solution :`(P_(1))/(P_(2))=(1)/(2) , :' (V_(1))/(V_(2))=(P_(2))/(P_(1))=(2)/(1)`
`(2L)/(V_(2))=(2)/(1) , V_(2)1L`
26.

If X' is a Anti cancerous drug which of the following conversions will give 'X'

Answer»

`[PtCl_(4))]^(2-) OVERSET(NH_(3))to Y overset(NH_(3))to X`
`[Pt(NH_(3))_(4)]^(2+) overset(CL^(-))to Y overset(Cl^(-))to X`
`[Pt(NH_(3))_(4)]^(2+) overset("Acid")to Y overset("Alkali")to X`
`cis [Pt(NH_(3))Cl_(2)]^(2+) overset("Acid")to Y overset("Alkali")to X`

Answer :A::B::C::D
27.

If pressure becomes double at the same absolute temperature of 2 litre CO_(2), then the volumme of CO_(2) becomes

Answer»

2 litre
4 litre
5 litre
1 litre

Answer :B
28.

If 'x' dm^3 of N_2 reactwith 10dm^3 of H_2 to form NH_3 under suitable conditions, then

Answer»

`H_2` is LIMITING REAGENT
`N_2` is limiting reagent
Both REACTANTS are limiting REAGENTS
`NH_3` is limiting reagent

Answer :A
29.

If P^(oo) and P are the vapour pressures of the pure solvent and solution and n_(1) and n_2 are the moles of solute and solvent repectively in the soluiton then the correct relation betweenP and p^(@) is

Answer»

<P>`P^(@) = P[(n-1)/(n_1 + n_2)]`
`P^(@)=P[(n_2)/(n_1+n_2)]`
`P= P^(@)[(n_2)/(n_1 +n_2)]`
`P= P^(@)[(n_1)/(n_1+n_2)]`

Solution :We know ACCORDING to RAOULT .s law,
`P = P^(@) . X_("solute") rarr P = P^(@)[ (n_2)/(n_1 =n_2)]`
30.

If x denotes the number of valence electrons of the element, then its valency is equal to:

Answer»

x-8
Xe
8-x
B and C

Answer :D
31.

If pOH of a solution is 6.0, then its pH will be

Answer»

6
10
8
14

Solution :PH+ POH = 14, pH = 14 - pOH , pH = 14 - 6 = 8.
32.

If x and y are total number of electrons which are present in non-axial and axial set off d-orbitals respectively in Ni cation of [Ni(DMG)_(2)], then calculate the value of (2x^(2))/(y)

Answer»


ANSWER :36
33.

If pK_("In") of an indicator is 10.5, the pH transition range for which it is most suitable is

Answer»

`8.5-10.5`
`10.5-12.5`
`10.0-11.0`
`9.5-11.5`

SOLUTION :The pH transition range for an indicator `=pK_("in") pm1`
`=10.5 PM 1`
THEREFORE, suitable range is , 9.5-11.5
34.

If (X) decolourises acidfied KMnO_(4) solution , then X may

Answer»

`S^(2-)`
`SO_(3)^(2-)`
`FE^(2+)`
`SO_(2)`

ANSWER :a,B,c,d
35.

If PK_bfor fluoride ion at 25^@C is 10.83. predict the ionisation constant of hydrofluoric acid in water at this temperature.

Answer»

`1.74xx10^(-5)`
`3.52xx10^(-3)`
`6.75xx10^(-4)`
`5.38xx10^(-2)`

ANSWER :C
36.

If work done by an ideal gas in process 1-2 on the given graph is 0.4 kJ then product of pressure and volume at point B (in bar-L) is (Enthalpy of gas in process 3-4 is constant) (1 bar-L = 100 J)

Answer»


ANSWER :8
37.

If pK_(b) for fluoride ion at 25^(@)C is 10.83, the ionisation constant of hydrofluoric acid in water at this temperature is

Answer»

`1.74 xx 10^(-5)`
`3.52 xx 10^(-3)`
`6.75 xx 10^(-4)`
`5.38 xx 10^(-2)`

Solution :`HF + H_(2)O overset(K_(a))rarr H_(3)O^(+) + F^(-)`
`:. K_(a) = ([H_(3)O^(+)][F^(-)])/([HF][H_(2)O])`...(i)
`F^(-) + H_(2)O overset(K_(b))rarr HF + OH^(-)`
`:. K_(b) = ([HF][OH^(-)])/([F^(-)][H_(2)O])`...(ii)
`:. K_(a) xx K_(b) = [H_(3)O^(+)][OH^(-)] = K_(w) = 10^(-14)`
Given, `pK_(b) = 10.83 rArr K_(b) = 1.48 xx 10^(-11)`
`:. K_(a) = (10^(-14))/(1.48 xx 10^(-11)) = 6.75 xx 10^(-4)`
38.

If we use phenolphthalein as an indicator in a titration of Na_(2)CO_(3) with HCl, the usual result is

Answer»

No visible change is occur
The indicator REACTS with the acid
The indicator reacts with the base
Sodium chloride and CARBONIC acid will be formed

SOLUTION :The resulting solution is colourless.
39.

If pK_(a) of acetic acid and pK_(b) of ammonium hydroxide are 4.76 each. The pH of ammonium acetate is

Answer»

7
Less than 7
More than 7
Zero

Solution :pH of a SALT of weak ACID and weak BASE is
`pH = 7 + (1)/(2)pK_(a) - (1)/(2)pK_(a)`
`pH = 7 + (1)/(2) xx 4.76 - (1)/(2) xx 4.76 = 7`.
40.

If we want to study relative arrangement of atoms in a molecule we study

Answer»

EMPIRICAL formula
Molecular formula
Structural formula
None of these

Solution :N//A
41.

If Pk_b for CN^- at 25^@C is 4.7. Find the pH of 0.5 M aqueous NaCN solution,

Answer»

12
10
11.5
11

Answer :C
42.

If pi_(1) is the osmotic pressure of solution containing 6 g. of acetic acid per dm^(3) and pi_(2) is that of a solution containing 5.85 g. of NaCl per dm^(3) at the same temperature then

Answer»

`pi_(1) lt pi_(2)`
`pi_(1) gt pi_(2)`
`pi_(1) = pi_(2)`
`2pi2pi_(1)=pi_(2)`

SOLUTION :Both the SOLUTIONS are one molar but NaCl being an electrolyte will have more, O.P. then acetic acid which is non electrolyte.
43.

If we use pyrene (C Cl_(4)) in the Riemer-Tiemann reaction in place of chloroform, the product formed is :

Answer»

Salicylaldehyde
phenolphthalein
Salicylic ACID
Cyclohexanol

Solution :N//A
44.

If we use pyrene (C Cl_(4)) in the Reimer-Tiemann reaction in place of chloroform, the product formed is

Answer»

salicylaldehyde
phenolphthalein
SALICYLIC acid
cyclohexanol

Answer :C
45.

If we use carbon tetrachloride in Reimer Tiemann reaction in place of chloroform, the product formed is

Answer»

SALICYLIC ACID
Salicylaldehyde
Cyclohexanol
PHENOLPHTHALEIN

ANSWER :A
46.

If phi denotes reduction potential, then which is true ?

Answer»

`E_("CELL")^(@)= phi_("RIGHT")-phi_("LEFT")`
`E_(cell)^(@)=phi_("left")+phi_("right")`
`E_(cell)^(@)=phi_("left")-phi_("right")`
`E_(cell)^(@)= - (phi_("left")+phi_("right"))`

Answer :A
47.

If we take two 1 litre flasks, one containing He at STP and other containing CH_(4) at STP [Assume size of CH_(4) is much larger than He ]

Answer»

Mean free PATH of He GAS will be more than `CH_(4)` gas
Average velocity of He gas will be more than `CH_(4)` gas.
Total TRANSLATIONAL kinectic energy of `CH_(4)` will be more than He.
Most probable SPEED of He will be more than `CH_(4) (g)`

Answer :A::B::D
48.

If pH of hydrogen electrode is 10, then what is the potential of it. . .

Answer»

0.59 V
0.00 V
`-0.59V`
`-0.059V`

Solution :`H_((AQ))^(+)+e^(-) to (1)/(2)H_((g))` (reduction)
`E=E^(@)-(0.059)/(N)"LOG"(1)/([H^(+)])`
`=0.0-(0.059)/(1)pH`
`=0-0.059xx10`
`=-0.59V`
49.

If we use carbon tetrachloride in Reimer- Tiemann reaction in place of chloroform, the product formed is

Answer»

Salicylic ACID
SALICYLALDEHYDE
Cyclohexanol
PHENOLPHTHALEIN

Answer :A
50.

If pH of A, B, C and D are 9.5, 2.5, 3.5 and 5.5 respectively, then strongest acid is

Answer»

A
C
D
B

SOLUTION :LESS TH PH, more ACIDIC is the solution.