Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

How many isomers are possible for Bromo methyl cyclopentane (Ignoring chirality)

Answer»


SOLUTION :
2.

How many isomers are possible for a compound with formula, [Co(en)_(2)Cl(NO_(2))]Cl ?

Answer»

2
4
6
8

Answer :C
3.

How many isomeric structural alkene on catalytic hydrogenation gives 3-Methyl hexane.

Answer»

`3`
`4`
`5`
`6`

SOLUTION :
4.

How many isomeric ether are represented by the molecular formula C_4H_10O

Answer»

3
2
4
5

Solution :`C_4H_10O` SHOWS the following isomeric ether.
(i)`CH_3-O-CH_2CH_2CH_3`
(ii)`CH_3-O-underset(CH_(3))underset(|)CHCH_3`
(iii) `CH_3CH_2-O-CH_2CH_3`
5.

How many isomeric forms of C_(7)H_(9)N contain a benzene ring ?

Answer»

4
5
6
7

Solution :
6.

How many isomeric compounds will be obtained when a disubstituted derivative of benzene is prepared from its monosubstituted derivative?

Answer»

3
4
5
6

Answer :A
7.

How many isomeric butanes are formed by the diazotization of n-Bu-NH_(2)?

Answer»


SOLUTION :
8.

How many isomeric amines have the molecular formula C_(4)H_(11)N?

Answer»

The total number of optically active COMPOUNDS from the following list is
`C_(2)H_(5)NHCH_(3),""CH_(3)CH_(2)CH(CH_(3))N(CH_(3))C_(2)H_(5),""[Ph(CH_(3))(C_(2)H_(5))OVERSET(+)(N)H]I^(-),[(CH_(3))_(2)(C_(2)H_(5))overset(+)(N)H]I^(-),C_(6)H_(5)(CH_(3))(C_(2)H_(5))overset(+)(N)-O^(-),(CH_(3))(C_(2)H_(5))NCH(CH_(3))_(2)`.

Solution :Eight amines are possible.
9.

How many isomeric alkynes oncatalytic hydrogenation gives 3-Ethyl-4-methylheptane ?

Answer»


SOLUTION :`HC-=C-CH_(2)-UNDERSET(CH_(3))underset(|)(CH)-underset(CH_(2)-CH_(3))underset(|)(CH)-CH_(2)-CH_(3)`" "`CH_(3)-C-=C-underset(CH_(3))underset(|)(CH)-underset(CH_(2)-CH_(3))underset(|)(CH)-CH_(2)-CH_(3)`
`CH_(3)-CH_(2)-CH_(2)-underset(CH_(3))underset(|)(CH)-underset(CH_(2)-CH_(3))underset(|)(CH)-C-=-CH`
10.

How manyisomeric alkyne on hydrogenation gives 3,3-Dimethylhexane.

Answer»


SOLUTION :N//A
11.

How many isomeric acyclic alcohola and ethers are possible for C_(4)H_(8)O ?

Answer»

3
4
5
7

Solution :`CH_(3)CH_(2)CH_(2)CH_(2)OH,CH_(3)CH_(2)-UNDERSET(OH)underset(|)CHCH_(3),CH_(3)-underset(OH)underset(|)overset(CH_(3))overset(|)C-CH_(3),CH_(3)-underset(CH_(3))underset(|)CH-CH_(2)OH,CH_(3)CH_(2)CH_(3),CH_(3)CH_(2)OCH_(3),CH_(3)-underset(CH_(3))underset(|)CH-O-CH_(3)`
12.

How many isomaric alkenes (structural only) on hydrogenation can give following compound?

Answer»

`7`
`8`
`9`
`10`

SOLUTION :
13.

How many isomeres are possible for compounds having the molecular formubal CH_(5)H_(11)Br

Answer»

nine
eight
six
seven

Solution :1. `underset("1-bromo pentane") (CH_(3)-CH_(2)-CH_(2))-CH_(2)-Br`
2.`underset(2-"bromo pentane")(CH_(3)-CH_(2)-CH_(2)- underset(Br) underset(|)(CH)-CH_(3))`
3. `underset(3-"bromo pentane")(CH_(3)-CH_(2)-CH_(2)- underset(Br) underset(|)(CH_(2))-CH_(3))`
4. `underset(1-"bromo 2-2dimethyl propane") underset(CH_(3)) underset(|) overset(CH_(3)) overset(|)(CH_(3)-C-CH_(2))-Br`
5. `underset(2-"bromo 3-methyl butane")(CH_(3)- overset(CH_(3)) overset(|)(CH)- underset(Br)underset(|)(CH-CH_(3)))`
6. `underset(1-"bromo 2-methyl butane") (CH_(3)CH-underset(C_(2)H_(5)) underset(|)(CH_(2))-Br)`
7. `underset(1-"bromo 2-methyl butane")(CH_(3)-overset(CH_(3)) overset(|) underset(Br) underset(|)C-C_(2)H_(5)`
8. `underset("1-bromo 3-methyl butane") (CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(2)-Br)`
14.

How many iron atoms are present in a stainless stell ball bearing having a radius of 0.254 cm? the stainless steel contains 85.6% Fe by weight and has density of 7.75 g//cm^(3).

Answer»


ANSWER :`4.91xx10^(21)`
15.

How many ions per molecules are produced in the solution when Mohr's salt is dissolved in excess of water ?

Answer»

4
5
6
10

Answer :B
16.

How many ions are produced from the complex [Co(NH_3)_6]Cl_2 in solution ?

Answer»

6
4
3
2

Answer :C
17.

How many ions per molecule are produced in the solution when Mohr salt is dissolved in excess of water ?

Answer»

6
4
10
5

Answer :D
18.

How many ions are produced from the complex [Co(NH_(3) )_(5) CI]CI_(2) in solution?

Answer»

4
2
3
5

Answer :C
19.

How many ions are produced from the complex Co(NH_(3))_(6)Cl_(2) in solution ?

Answer»

6
4
3
2

Solution :Coordination number of COBALT = 6. Hence, the COMPLEX is [Co(NH3)6]Cl2. It IONISES in the solution as : `[Co(NH_(3))_(6)]Cl_(2) to [Co(NH_(3))_(6)]^(2+) + 2Cl^(-)`. Thus, THREE ions are produced. Option (iii) is correct.
20.

How many ions are produced from the complex, Co(NH_(3))_(6)Cl_(2) in solution ?

Answer»

6
4
3
2

Solution :COORDINATION number of cobalt =6. HENCE, the complex is `[Co(NH_(3))_(6)]Cl_(2)`. It ionizes in the solution as :
`[Co(NH_(3))_(6)]Cl_(2)overset(+aq)rarr[Co(NH_(3))_(6)]^(2+)+2Cl^(-)`
Thus, THREE ions are produced.
21.

How many ions are produced from the compex,[Co(NH_3)_6] Cl_2 is solution ?(i) 6(ii) 4(iii) 3 (iv) 2

Answer»

Solution :The CORRECT option is (III)
Co- ORDINATION number of cobalt= 6. It isionizes in the solution as :
`[Co(NH_3)_6 ] Cl_2 overset(Aq)to [Co(NH_3)_6]^(2+) + 2Cl^(-)` . Hence three IONS are PRODUCED.
22.

How many ions can be produced from [Co(NH_3)_6]Cl_3 in aqueous solution.

Answer»

6
4
3
2

Answer :B
23.

How many ions are formed by the complex [Co(NH_(3))_(6)]Cl_(3) in aqueous solution?

Answer»

Solution :FOUR ions: `[CO(NH_(3))_(6)]Cl_(3) overset(aq)ltimplies [Co(NH_(3))_(6)]^(3+) (aq) + 3Cl^(-) (aq)`
24.

How many ions are formed per molecule of potassium hexacyano ferrate (II) when dissolved in water?

Answer»

SOLUTION :FIVE or 5.
25.

How many inches are there in 3.00 km ? Given that 1 km = 1000 m, 1 m = 1.094 yd, 1 yd = 36 in.

Answer»

Solution :The UNIT conversion factors will be :
`1=(1000M)/(1km)=(1km)/(1000m),""1=(1.094yd)/(1 m)=(1m)/(1.094yd),""1=(36"in")/(1yd)=(1yd)/("36 in")`
Here, the conversion involves a number of steps. Hence, the unit conversion factors are applied in such a WAY that the units of the PRECEDING factor cancel out. Thus,
`3.00km=3.00 cancel(km)xx(1000cancelm)/(1cancel(km))xx(1.094cancel(yd))/(1cancelm)xx("36 in")/(1 cancel(yd))=1.18xx10^(5)" in".`
Note that the answer has been reported to contain THREE significant figures (because 1000 m and 36 in. are exact numbers).
26.

How many interhalogen compounds are not possible ? IC l,IB r,Brl,ClBr_(3),ClF_(3),BrCl_(5),BrI_(5),Icl_(3),IF_(7)

Answer»


ANSWER :3
27.

How many hygroscopic compounds are formed when Cl_(2) reacts with hot aqueous NaOH.

Answer»


Solution :`3Cl_(2) + 4NaOH to 5NaCl + NaClO_(3) + 3H_(2)O`
NACL and `NaClO_(3)` both are hygrocopic in nature.
28.

How many incomplete orbitals are present in inner transition elements ?

Answer»


SOLUTION :`4f,5d,6s`
29.

How many hydrogen bonds are present between pair of thymine and adenine in DNA?

Answer»

1-hydrogen BOND
2-hydrogen bond
3-hydrogen bond
No bonds occur

Solution :The TWO hydrogen bonds are present between PAIR of thymine and adenine while THREE hydrogen bonds are present between CYTOSINE and guanine.
30.

Number of hydorxyl groups present in pyrosulphuric acid is

Answer»


Solution :Pyrosulphuric ACID `H_(2)S_(2)O_(7)" "HO-underset(O)underset(||)OVERSET(O)overset(||)S-O-underset(O)underset(||)overset(O)overset(||)S-OH :. -OH` GROUPS are two.
31.

How many hydrocarbons having molecular mass 68 can give while precipitate with Tollen's reagent ?

Answer»

`1`
`2`
`3`
`4`

SOLUTION :
32.

How many hours does it take to reduce 3 mol of Fe^(3+) to Fe^(2+) with 2.00 A current (1 Faraday=96,500 C mol^(-1),R=8.314JK^(-1)mol^(-1)).

Answer»


SOLUTION :`Fe^(3+)+e^(-)toFe^(2+)` i.e., 1 mol requires 1F. `therefore3` moles will require=3F=`3xx96500C`
`t=Q//I=(3xx96500)//2.0=144750s=40.2`HRS.
33.

How many homopolymer are given below ? (a) PVA(b) Gutta percha (c ) Gltptal(d) Buna-S (e ) Bakelite(f) Natural rubber (g) Buna -N(h) Nylon-66 (i) Terylene(j) Novalac

Answer»


SOLUTION :N//A
34.

How many hours are needed to deposit the metal based on the reaction . Fe^(2+)(aq) + 2e^(-) to Fe(s). using a current strength of 0.02amp.

Answer»


ANSWER :268 H
35.

How many hours are required for a current of 3 amp of decompose electrolitically 18 g of water ?

Answer»


ANSWER :18 HOURS
36.

How many halogen atoms will be removed in the following E_(2) reaction ?

Answer»

4
6
8
10

Answer :B
37.

How many half cells are present in an electrochemical cell?

Answer»

3
4
2
6

Answer :C
38.

How many H-atoms are present in 0.046g ofethanol

Answer»

`6 XX 10^(20)`
`1.2 xx 10^(21)`
`3 xx 10^(21)`
`3.6 xx 10^(21)`

Solution :Mol. wt of `C_(2)H_(5)OH`
`= 2 xx 12 + 5 + 16 + 1 = 46`
`:' 46g C_(2)H_(5)OH` has H atom = `6xx N_(A)`
`:' 0.046 g` of `C_(2)H_(5)OH` has `H` atoms
`= (6 xx 6.02 xx 10^(23) xx 0.046)/(46) = 3.6 xx 10^(21)`
39.

How many groups are o//p director in the electrophilic aromatic substitution ? (i) -NH_(2) (ii) -COH (iii) -N = O (iv) -COOH (v) -OMe (vi) - O - overset(O)overset(||)(C) - Me (vii) -Et (viii) - overset(O)overset(||)(C) - NH - Me (ix) - N = NH_(2) (x) - SO_(3)H

Answer»


SOLUTION :(i) `-NH_(2)` (III) `-N = O`, (v) `-OME`, (vi) `- overset(..)(O) - overset(O)overset(||)(C) - Me`
(VII) `-Et` (IX) `-N = NH_(2)`
40.

How many grams of urea should be added in 500CC of water (k = 1.86) to produce a depression of 0.186^(@)C in freezing point.

Answer»


ANSWER :3
41.

How many grams of water will be electrolysed by 96500 coulomb charge ?

Answer»


ANSWER :9
42.

How many grams of sucrose (M. wt. = 342) should be dissolved in 100 g water in order to produce a solution with 105.0^(@)C difference between the freezing point and the boiling point ? (K_(f)=1.86^(@)C//m, K_(b)=0.51^(@)C//m)

Answer»

Solution :`DeltaT_(b)=K_(b)xxm`
`"B. PT of solution "(T_(b))=100+DeltaT_(b)=100+K_(b)m`
`"F. pt of solution "(T_(b))=0-DeltaT_(f)=0-K_(f)m, T_(b)-T_(f)=(100+K_(b)m)-(-K_(f)m)`
`"F. pt. of solution "(T_(f))= 0-DeltaT_(f)=0-K_(f)m,""T_(b)-T_(f)=(100+K_(b)m)-(K_(f)m)`
`""105=100+0.51xxm+1.86m.`
This gives m = 2.11, i.e., 1000 G of water contain sucrose = 2.11 MOLE `=2.11xx342 g`
`therefore"Mass of sucrose to be dissolved in 100 g of water "=(2.1xx342)/(1000)xx100=72g.`
43.

How many grams of sucrose should be dissolved in 100g water in order to produce a solution having difference between the free zing point and the boiling point temperatures at 105.0^@C

Answer»

`34.2`
72
342
460

Answer :B
44.

How many grams of sucrose (Molecular weight = 342) should be dissolved in 100 g water to produce a solution with a 105^(@) difference between the freezing point and the boiling temperatures? [K_(l)= 1.86, K_(b) = 0.51]

Answer»

34.2 g
72 g
342 g
460 g

Answer :B
45.

How many grams of silver could be plated out on a serving tray by electrolysisof a solution containing silver in +1 oxidation state for a period of 8.0 hours at a current of 8.46 amp? What is the area of the tray if the thickness of the silver plating is 0.00254 cm? Density of silver is 10.5 g//cm^3

Answer»

SOLUTION :`271.65 G, 1.02 XX 10^4 cm^2`
46.

How many grams of sodium acetate are to be added to a litre of 0.4 M CH_3 COOH solution so that the [H^+] of the resultant solution is 2 xx10^(-4)g ion/L? (Given K_a for acetic acid = 1.8 xx 10^(-5) )

Answer»

`3.502 g`
`2.952 g`
`4.252 g `
`5.162g `

Solution :`pH =pK_a+ log (["SALT"])/(["base"])`
`-log( 2xx 10^(-4) ) =- log( 1.8 XX 10^(-5) ) + log(["salt"])/( 0.4)`
`3.699 = 4.74+ log(["salt"])/(0.4 )`
` thereforelog(["salt"])/( 0.4 ) =- 1.041 or(["salt "])/(0.4 ) =0.091`
or `["salt "] = 3.6 xx 10^(-2)`
` therefore `AMOUNTOF sodiumacetateto beadded`= 3.6 xx 10^(-2)xx 82 = 2.952`g ( molarmass of`CH_3 COONa=82`)
47.

How many grams of silver could be plated out on a serving tray be electrolysis of a solution containing silver in +1 oxidation state for period of 8.0 hours at a current of 8.46 amperes? What is the area of the tray if the thickness of the silver plating is 0.00254 cm? Density of silver is 10.5g/cm^(3).

Answer»


Solution :Calculate mass of Ag deposited. It comes out to be 271.65 g. VOLUME of Ag deposited `=(271.65)/(10.5)=25.9cm^(3)`
AREA of tray`=(25.9)/(0.00254)=1.02xx10^(4)cm^(2)`.
48.

How many grams of nickel are deposited by a current of 100 milliampere in 20 minutes in the electrolysis of aqueous nickel sulphate solution ? (Given atomic mass of Ni =58.7 amu.)

Answer»


Solution :The reaction at the cathode is :
`underset(1MOL)Ni^(2+)(aq)+underset((2 Faradays))underset(2mol)(2e^(-))to underset((58.7 G))underset(1mol)(Ni(s))`
Quantity of charge PASSED (Q)`="Current in ampere" xx"time in seconds "`
`=(100//1000 amp.)xx(20xx60 s)=120 As =120 C`
`2xx96500 C`of charge deposit Ni=58.7 g
120 C of charge Ni`=((58.7 g))/((2xx96500C))xx(120C)=0.0365 g`.
49.

How many grams of NaOH will be required to prepare 500 gram solution containing 10% W/W NaOH solution ?

Answer»

5 g
50 g
100 g
0.5 g

Answer :B
50.

How many grams of NaOH should be dissolved to make 100 cm^(3) of 0.15 M NaOH solution?

Answer»

SOLUTION :`1000cm^(3)` of 0.15 M NaOH cotain NaOH = 0.15 mole
`therefore""100cm^(3)" of 0.15 M NaOH cotain NaOH"=(0.15)/(1000)xx100=0.015" mole"=0.015xx40g=0.6g`
`""("Molar mass NaOH = 40 g mol"^(-1))`