Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Heroin is a derivative of:

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morphine
cocaine
NICOTINE
caffeine.

Answer :A
2.

Head-to-tail addition takes place in chain-growth polymerisation, when monomer is

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`CH_2 = CH - CH =CH_2`
`CH_2 = UNDERSET(CH_3)underset(|)C-underset(O)underset(||)(COCH_3)`
`CH_2=CH -C -=N`

ANSWER :A
3.

Heaematite and tin stone are purified by …………

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GRAVITY SEPARATION process
Magnetic separation process
Froth FLOATATION process
Hand picking

Answer :A
4.

Head-to-tail addition take palce in chain-growth polymerisation when monomer is

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`CH_(2)=CH-CH=CH_(2)`
`CH_(2)=UNDERSET(CH_(3))underset(|)(C)-underset(O)underset(||)(C)OCH_(3)`
`CH_(2)=CH-C-=N`

Solution :Vinyl derivatives containingelectron withdrawinggroup stabilises FREE radicaland READILY undergo HEAD to tail addition polymerisation .
5.

The number of moles of KI required to prepare one mole of K_(2)[HgI_(4)] is

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4
3
2
1

Answer :A
6.

The metal which can form cation having metal - metal bond

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Mercury
Copper
Osmium
Iron

Answer :A
7.

Among the following which has higher electron affinity value

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Iodine
Chlorine
Bromine
Fluorine

Answer :B
8.

heflashpointin indiaisfixedat :

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317K
308K
295.8K
303K

Answer :A
9.

Heroin is a derivative of

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Cocaine
Morphine
Caffeine
Nicotine

Answer :B
10.

HDPE is formed in the presenceof catalyst

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PEROXIDE
Ziegler-Natta
`H_(2)//Ni`
`Br_(2)//Ni`

Solution :Ziegler-Natta catalyst is present in the formation of HDPE.
11.

Heroin is

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NARCOTIC ANALGESIC
NON narcotic analgsic
antimalerial
antiseptic

Answer :A
12.

HDP is used in preparation of…………..

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Light and soft devices
HARD and DURABLE devices
COTTON and WOOL
Light and CHEAP devices

Solution :Hard and durable devices
13.

Hereditary traits are carried by ______.

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nucleic ACID
PROTEIN
lipid
CARBOHYDRATE

Solution :Nucleic acid
14.

HCOONa overset(350^(@))underset(Delta) to Gas(X) + Residue (Y)overset(CoCl_(3)) to "Complex" (Z) Choose the correct statement regarding (X).

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It is paramagnetic
Its bond order is ONE
It can't ACT as `pi-acid`
It is a POWERFUL OXIDISING agent.

Answer :D
15.

HCOOHoverset(Conc.H_(2)SO_(4))rarrXuarr overset(X,HCl)underset(AlCl_(3))rarrY What is Y ?

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SOLUTION :`H C COHoverset(Conc.H_(2)SO_(4))rarrCO+H_(2)O`
16.

Here the question contain statement given in two columns which have to be matched. Statements in Column I are lebelled as A, B, C and D, whereas statement in Column II are labelled as p, q, r and s. the answers are to these questions have to be appropriately bubbled as illustrated in the following example. If the correct match as a-p, A-s, B-q, B-r, C-p, C-q and D-p, their correctly labelled 4 xx 4 matrix should look like as under.

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ANSWER :`(##DIN_OBJ_CHM_V02_C08_E01_480_A01##)`
17.

HCOONa overset(350^(@))underset(Delta) to Gas(X) + Residue (Y)overset(CoCl_(3)) to "Complex" (Z) Complex (Z) is:

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an outer ORBITAL complex
optically active
oxidised when exposed to air
paramagnetic

Solution :`HCOONaunderset(Delta)overset(350^(@)C)rarrH_(2)(X)+NaC_(2)O_(4)(Y)overset(CoCl_(3))rarrNa_(3)[Co(C_(2)O_(4)](Z)`
(i) `"GAS" (X) to H_(2)`
-It is diamagnetic
-B.O.=1
-It acts as `pi`-acid (into `sigma_(1s)^(**))`
(ii) `Na_(3)[Co(C_(2)O_(4)]`
`[M(AA)_(3)]`

Optically active
18.

Here the reagent is

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`Zn + NH_(4)Cl`
`Zn + NAOH`
`Sn + HCL`
`LiAlH_(4)`

ANSWER :C
19.

HCOONa underset(heat)to X+H_(2). X is

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`Na_(2)CO_(3)`
`CO_(2)`
`(COONA)_(2)`
CO

Answer :C
20.

Here the question contain statement given in two columns which have to be matched. Statements in Column I are lebelled as A, B, C and D, whereas statement in Column II are labelled as p, q, r and s. the answers are to these questions have to be appropriately bubbled as illustrated in the following example. If the correct match as a-p, A-s, B-q, B-r, C-p, C-q and D-p, their correctly labelled 4 xx 4 matrix should look like as under.

Answer»


ANSWER :`(##DIN_OBJ_CHM_V02_C08_E01_479_A01##)`
21.

HCOOHand CH_(3)COOH can be distinguished by

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Tollen's reagent
FEHLING's solution
`KMnO_(4)`
`NaHCO_(3)`

Solution :(a) `HCOOH` GIVES silver mirror with Tollen's reagent, acetic acid does not.
(b) `HCOOH` form red pptwith Fehling's solution,acetic acid does not.
(c ) `HCOOH`decolouries `KMnO_(4)` but acetic and does not.
(d) Both REACT with `NaHCO_(3) :.` (d) is not.
22.

HCOOH reacts wihth conc. H_(2)SO_(4) to produce

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CO
`CO_2`
NO
`NO_2`

ANSWER :A
23.

Here the question contain statement given in two columns which have to be matched. Statements in Column I are lebelled as A, B, C and D, whereas statement in Column II are labelled as p, q, r and s. the answers are to these questions have to be appropriately bubbled as illustrated in the following example. If the correct match as a-p, A-s, B-q, B-r, C-p, C-q and D-p, their correctly labelled 4 xx 4 matrix should look like as under.

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Answer :(A)-R (B)-s (C)-p (D)-Q
24.

HCOOH shows all tests of aldehyde because

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It has ONE ALDEHYDE group
It is member of aldehyde
All ACIDS show tests of aldehyde
Does not show any test

Answer :A
25.

Here the question contain statement given in two columns which have to be matched. Statements in Column I are lebelled as A, B, C and D, whereas statement in Column II are labelled as p, q, r and s. the answers are to these questions have to be appropriately bubbled as illustrated in the following example. If the correct match as a-p, A-s, B-q, B-r, C-p, C-q and D-p, their correctly labelled 4 xx 4 matrix should look like as under.

Answer»

<P>

Answer :(A)-p, q, s, t (B)-p, QS, t, c-p, q, (D)-R
26.

HCOOC - (CH_2)_5 - COOH overset(Ca(OH)_2//Delta)to X. Compound X is

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ANSWER :A
27.

Here the question contain statement given in two columns which have to be matched. Statements in Column I are lebelled as A, B, C and D, whereas statement in Column II are labelled as p, q, r and s. the answers are to these questions have to be appropriately bubbled as illustrated in the following example. If the correct match as a-p, A-s, B-q, B-r, C-p, C-q and D-p, their correctly labelled 4 xx 4 matrix should look like as under.

Answer»

<P>

ANSWER :(A)-p,s (B)-p, s (C)-r (D)-p, q, s
28.

HCO_3^- contains carbon in the oxidation state :

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`+5`
`+1`
`+4`
`+6`

ANSWER :C
29.

HCNoverset("Hydrolysis")rarracid -1 CH_(3)C Cl_(3)overset("Hydrolysis")rarr acid-2 The heat of ionisation of HCN and acid-2 respectivley are x kcal and y kcal [x lt y]. The order of their pK_(a) values will be

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`(pK_(a))_(HCN)gt(pK_(a))_("acid-2")`
`(pK_(a))_(HCN(=(pK_(a))_("acid-2")`
`(pK_(a))_(HCN)lt(pK_(a))_("acid-2")`
All of the above

Solution :Acid-2 is ACETIC acid. HCN is a weaker acid as its HEAT of inoisation is LESS than acetic acid. Hence,
`(pK_(a))_(HCN)gt(pK_(a))_("acid-2")`
30.

Here the question contain statement given in two columns which have to be matched. Statements in Column I are lebelled as A, B, C and D, whereas statement in Column II are labelled as p, q, r and s. the answers are to these questions have to be appropriately bubbled as illustrated in the following example. If the correct match as a-p, A-s, B-q, B-r, C-p, C-q and D-p, their correctly labelled 4 xx 4 matrix should look like as under.

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ANSWER :(A)-r, s (B)-p, Q (C)-p, q (D) -p, s
31.

HCN+H_(2)Orarr[X]+NH_(3), [X]rarr[Y]+H_(2)O (Unbalanced equations) [Y] May be prepared by which one of the following methods?

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By DEHYDRATION of Malonic acid with `P_(2)O_(5)`
By THERMAL decomposition of carbon sub - OXIDE in air.
By heating potassium hexacyanoferrate (II) with CONC. `H_(2)SO_(4)`
By the action of conc. `HNO_(3)` on charcoal.

Answer :C
32.

Here the product ‘X’ is

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ANSWER :B
33.

HCN and HNC are :

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METAMERS
Functional
Position isomers
Chain isomers

Answer :B
34.

Here P is/are :

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All of these

Solution :This is an EXAMPLE of NUCLEOPHILIC substitution. Since phenoxide ion is an AMBIDENT nucleophile, with negative charge on both O and on the ortho C atoms of the ring, it will produce both (a) and (B) products.
35.

HClO is a weak acid. The concentration of H^(+) ions in 0.1 M solution of HClO (K_(a) = 5 xx 10^(-8)) will be equal to

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`7.07 xx 10^(-5) m`
`5 xx 10^(-9) m`
`5 xx 10^(-7) m`
`7 xx 10^(-4) m`

Solution :`[H^(+)]^(2) = C.alpha = 0.1 xx 5 xx 10^(-8)`
`H^(+) = sqrt(5 xx 10^(-9)) = 7.07 xx 10^(-5) M`.
36.

Here how many ligands are ambidentate? CN^(-), ONO^(-), S_(2)O_(3)^(2-), CNO^(-), C_(2)O_(4)^(2-), CH_(3)COO^(-)en

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ANSWER :4
37.

Hclo is a weak acid. What is the concentration of H^+ions in 0.1 solution of Hclo '(K_a = 5 xx 10^-8)?

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`7.07xx10^(-5)` M
`5XX10^(-7)` M
`5xx10^(-7)` M
`7XX10^(-4)` M

Answer :A
38.

Here each questions contains statements given in two columnns which have to be matched. Statements in Column I are labelled as A, B C and D wheras the statements in Coloumn II are labelled as p,q,r and s. the answer to these questions are to be appropriately bubbled as illustrated below in the following example. if the correct matches are A-P, A-s,B-q, B-r, C p ,C-q and D-p, their correctly labelled 4 x 4 matrix should look the . {:("Column I",,"Column II"),("(A) GeO",,"(p) Amphoteric "),("(B) CO",,"(q) Boric"),("(C) " SnO_(2),,"(r) Acidic"),("(D)" Te_(2)O,,"(s) Neutral"):}

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Solution :GeO is acidic , CO is neutral , `SnO_(2)` is neutral `Te_(2)O` is BASIC OXIDE.
39.

HCl cannot form H_2Cl_2 whille HF can form H_2F_2 the reason is

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FLUORINE is more reactive
HF is more reactive
Fluorine atom is SMALL and can FORM HYDROGEN bonds
None

ANSWER :C
40.

HClO is:

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An oxide
A chloride
A hydride
An acid

Answer :D
41.

Here each questions contains statements given in two columnns which have to be matched. Statements in Column I are labelled as A, B C and D wheras the statements in Coloumn II are labelled as p,q,r and s. the answer to these questions are to be appropriately bubbled as illustrated below in the following example. if the correct matches are A-P, A-s,B-q, B-r, C p ,C-q and D-p, their correctly labelled 4 x 4 matrix should look the . {:("Column I",,"Column II"),("(A) Sn",,"(P) Highest density amongst group 14 elements "),("(B) Pb",,"(q) Lowestmelting point amongst group 14 elements "),("(C) Si",,"(r) Lowest I.E. amongst group 14 elements"),("(D) Ge",,"(s) Semiconductor used in transistor"):}

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SOLUTION :SN has the LOWEST mp and the lowest IE and Pb has highest density among carbon family members and both Si and GE are used as semiconductors in TRANSITION.
42.

HCl When reacts with finely powdered iron. It forms ferrous chloride not ferric chloride why?

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Solution :Its reaction with iron produces `H_(2)`.
`Fe+2HClrarr FeCl_(2)+H_(2)`
LIBERATION of HYDROGEN prevents the formation of ferric chloride.
43.

Here each question contains statements in two column which have to be matched statements in column I are labelled as A, B, C and D and the statements in column II are labelled as p,q,r and s. The answers are to be appropriately bubbled as illustrted in the following examples . Ifthe correct matches are A-p, A-s, B-q, B-r, C-p, C-q, and D-p then correctly bubbled 4xx4 matrix should look like the following.

Answer»


ANSWER :A::B::C::D
44.

HCl is weaker than HI. Explain.

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SOLUTION :Bond dissociation ENERGY HCl is greater than HI.
45.

Here each question contains statements in two column which have to be matched statements in column I are labelled as A, B, C and D and the statements in column II are labelled as p,q,r and s. The answers are to be appropriately bubbled as illustrted in the following examples . Ifthe correct matches are A-p, A-s, B-q, B-r, C-p, C-q, and D-p then correctly bubbled 4xx4 matrix should look like the following.

Answer»


ANSWER :A::B::C::D
46.

HCl is covalent in:

Answer»

AQUEOUS SOLUTION
ETHEREAL solution
Gaseous state
None

Answer :C
47.

Here each question contains statements in two column which have to be matched statements in column I are labelled as A, B, C and D and the statements in column II are labelled as p,q,r and s. The answers are to be appropriately bubbled as illustrted in the following examples . Ifthe correct matches are A-p, A-s, B-q, B-r, C-p, C-q, and D-p then correctly bubbled 4xx4 matrix should look like the following.

Answer»


ANSWER :A::B::C::D
48.

HCI is labelled as 3.65% (w/v) 10ml of the solution is diluted to 1 lit. The proton concentration in the resulting solution is

Answer»

`10^(-3)`M
`2.5xx10^(-2)M`
`7.5xx10^(-2)M`
`10^(-2)M`

ANSWER :D
49.

Here each question contains statements given in two columns which have to be matched. Statements in Column I are labelled as A, B, C and D whereas the statements in Column II are labelled as p, q, r and s. The answers to these questions are to be appropriately bubbled as illustrated below in the following example. If the correct matches are A-p, A-s, B-q, B-r, C-p, C-q and D-p, their correctly labelled 4 xx 4 matrix should look like :

Answer»


SOLUTION :`F_2` is a GAS and shows variable oxidation state. `Br_2` is a liquid at room temperature and `I_2` is a SOLID at room temperature. Both these halogens SHOW variable oxidation states.
50.

HCl is a gas but HF is a low boiling liquid. This is because

Answer»

H-F bond is strong
H-F bonding is weak
Molecules AGGREGATE because of HYDROGEN bonding
HF is weak ACID

Answer :C