This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
For the reaction: 2A + B_2 + C to A_2B + Bc ,the rate law expression has been determined experimentally to be R = k [A]^2[C]withk = 3.0 xx 10^(-4) M^(-2)"min"^(-1)(i) Determine the initial rate of the reaction, started with concentrations:[A] = 0.1 M, [B.] =0.35 M and [C] = 0.25 M.(ii) Determine the rate after 0.04 mole per litre of A has reacted. |
| Answer» Solution :`7.5 XX 10^(-7) M "MIN"^(-1) , 2.5 xx 10^(-7) M "min"^(-1)` | |
| 2. |
For the reaction, 2A+Brarr3C, the reaction rate is equal to |
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Answer» `1/2 (d[A])/(DT)` |
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| 3. |
For the reaction 2A+Bto Products, it is found thatdoubling the concentration of both reactants increases the rate by a factor of 8. But doubling the concentration of B alone, only doubles the rate. What is the order of the reaction w.r.t to A? |
| Answer» ANSWER :A | |
| 4. |
For the reaction : 2A+B to A_(2)B, the rate =k[A][B]^(2) with k=2.0xx10^(-6)"mol"^(-2)L^(2)s^(-1). Calculate the initial rate of the reaction when [A]=0.1"mol L"^(-1) and [B]=0.2"mol L"^(-1). Calculate the rate of reaction after [A] is reduced to 0.06 mol L^(-1). |
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Answer» Solution :SUBSTITUTING the values in the rate equation, we get INITIAL rate `=K[A][B]^(2)` `=(2.0xx10^(-6)"mol"^(-2)L^(2)s^(-1))(0.1 "mol L"^(-1))(0.2" mol L"^(-1))^(2)` When [A] is reduced from 0.10 mol `L^(-1)` to 0.06 mol `L^(-1)`, 0.04 mol `L^(-1)` of A has reacted. Amount of B reacted `=(1)/(2)xx0.04 "mol L"^(-1)=0.02"mol L"^(-1)` Hence, [B] at that TIME `=0.2-0.02=0.18"mol L"^(-1)` Now,rate `=(2.0xx10^(-6)"mol"^(-2)L^(2)s^(-1))(0.06"mol L"^(-1))(0.18" mol L"^(-1))^(2)` `=3.89xx10^(-9)" mol L"^(-1)s^(-1)`. |
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| 5. |
For the reaction 2A+B rarr A_(2)B. The rate = k[A] [B]^(2) with 2.0xx10^(-6)mol^(-2)L^(2)s^(-1). Calculate the initial rate of the reaction, when [A] = 0.1 "mol L"^(-1), [B] = 0.2 "mol L"^(-1). Calculate the rate of reaction after [A] is reduced to 0.06 "mol L"^(-1). |
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Answer» Solution :The initial rate of the REACTION is Rate `= k[A] [B] 2` `= (2.0xx10^(-6)MOL^(-2)L^(2)s^(-1))(0.1 "mol L"^(-1)) (0.2 "mol L"^(-1))^(2)` `= 8.0xx10^(-9)mol^(-2)L^(2)s^(-1)` When [A] is reduced from `0.1 "mol L"^(-1)` to `0.06 mol^(-1)`, the concentration of A reacted `=(0.1-0.06)"mol L"^(-1)=0.04 "mol L"^(-1)`. `therefore` The concentration of B reaction `=(1)/(2)xx0.04 "mol L"^(-1)`. `=0.02 " mol L"^(-1)`. Then, concentration of B available `[B]=(0.2-0.02)"mol L"^(-1)`. `= 0.18 " mol L"^(-1)`. Aften [A] is reduced to `0.06 "mol L"^(-1)`, the rate of the reaction is given by, Rate `= k[A][B]2` `=(2.0xx10^(-6)mol^(-2)L^(2)s^(-1))(0.06"mol L"^(-1)) (0.18 "mol L"^(-1))^(2)` `= 3.89"mol L"^(-1)s^(-1)`. |
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| 6. |
For the reaction 2A+B rarr product, doubling the initial concentrations of both the reactants increases the rate by a factor of 8 and doubling the concentration of B above double the rate. This rate-law for the reaction is |
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Answer» `r=k[A][B]^(2)` `i.e.""rprop[A]^(2)[B]` or`r=k[A]^(2)[B]` |
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| 7. |
For the reaction : 2A+B+CtoA_(2)B+C, the rate law has been determined to be Rate =k[A][B]^(2)" with "k=2.0xx10^(-6)" mol"^(-2)L^(2)s^(1) For this reaction determine the initial rate of the reaction with [A]=0.1" mol L"^(-1),[B]=0.2" mol L"^(-1),[C]=0.8" mol L"^(-1). Determine the rate after 0.04" mol L"^(-1). Determine the rate after 0.04 "mol L"^(-1) of A has reacted. |
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Answer» After `0.04" mol L"^(-1)" of A has REACTED. "[A]=0.1-0.04=0.06" mol L"^(-1)` `[B]=0.2-0.02=0.18" mol L"^(-1)` Then rate `=(2XX10^(-6))xx(0.06)xx(0.18)^(2)=3.9xx10^(-9)" mol L"^(-1)s^(-1).` |
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| 8. |
For the reaction, 2A+Bto2C,/_\G^0=2kJ. Mol^(-1) at 500K. Calculate the value of equilibrium constant for the reaction, A+1/2BtoC, at the same temperature. |
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Answer» SOLUTION :`/_\G^0=/_\G^0(PCl_3)+/_\G^0(Cl_2)-/_\G^0(PCl_5)` `=(-68.42+0+77.6)kcal=+9.18kcal=+3.84xx10^4J` `:.-2.303RT" "logK=3.84xx10^4` or `logK=-6.73" ":.K=1.86xx10^(-7)` |
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| 9. |
For the reaction 2A +B rarr 3C +D Which of the following does not express reaction rate ? |
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Answer» `-(d[B])/(DT)` |
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| 10. |
For the reaction 2A+B+Cto2D. The observed rate law is Rate =K[A][B]^(2). Correct statements are : |
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Answer» increase of CONC. Of C does not EFFECT RATE |
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| 11. |
For the reaction 2A+B +C rarr A_(2)B+C the rate law has been found to be Rate = k[A] [B]^(2)withk = 2.0xx10^(-6) mol^(-2) L^(2)s^(-1) . The initial rate of reaction with [A] =0.1 mol L^(-1) [B] = 0.2 mol L^(-1) and [C] = 0.8 mol L^(-1) s^(-1) |
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Answer» `6.4xx10^(-8) "MOL L"^(-1)s^(-1)` `= (2.0xx10^(-6))(0.1) (0.2)^(2)` `=8xx10^(-9)` |
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| 12. |
For the reaction, 2A + B to C + D, the order of reaction is |
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Answer» ONE with respect to [B] |
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| 13. |
For the reaction : 2" NH"_(3)(g)overset("Pt")to"N"_(2)(g)+3" H"_(2)(g), Rate = k (i) Write the order andmolecularity of this reaction. (ii) Write the units of k. |
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Answer» SOLUTION :(i) Rate = k shows that the rate of reaction is independent of the concentrations of the reactants. Hence, it is a reaction of zero order. As two molecules of the REACTANT are persent in the reaction, molecularity is two. (ii) UNITS of k will be same as that of the rate of reaction viz. `"mol L"^(-1)s^(-1)`. |
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| 14. |
For the reaction : 2 NH_(3) (g) rarr N_(2) (g) + 3H_(2) (g). What is the % of NH_(3) converted if the mixture diffuses twice as fast as that SO_(2) under similar conditions. |
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Answer» 3.125 decomposition `(r_("mix"))/(r_(SO_(2))) = 2 = SQRT((M_(SO_(2)))/(M_("Mix")))` `M_("mix") = (64)/(4) = 16 = M_("avg")` `M_(avg) = (1 xx 17)/(1 + 2x) = 16` `17 = 16 + 32 x` 1 = 32 x `x = (1)/(32)` `% NH_(3) = (2x)/(1) xx 100` `= (1)/(16) xx 100 = 6.25 %` |
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| 15. |
For the reaction : 2 NH_(3)(g) rarr N_(2)(g) + 3 H_(2)(g) |
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Answer» `q_(p) = (q_(V))^(2)` |
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| 16. |
For the reaction 2 N_(2) O_(5(g)) to 4 NO_(2 (g)) to O_(2(g)) , if concentration of NO_(2) in 100 seconds is increased by 5.2 xx 10^(-3) m . Then the rate of reaction will be |
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Answer» `1.3 xx 10^(-5) ms^(-1)` Rate of REACTION with RESPECT to `NO_(2)` `=(1)/(4) (d[NO_(2)])/(DT) = (1)/(4) xx (5.2 xx 10^(-3))/(100) = 1.3 xx 10^(-5) ms^(-1)`. |
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| 17. |
For the reaction 2" A"+" B"toA_(2)B," rate "=k[A][B]^(2) with k=2.0xx10^(-6)mol^(-2)L^(2)s^(-1). Calculate the initial rate of the reaction when [A]=0.1molL^(-1)" and "[B]=0.2molL^(-1). Calculate the rate of reaction after [A] is reduced to 0.06molL^(-1). |
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Answer» Solution :Initial rate `=K[A][B]^(2)=(2.0xx10^(-6)mol^(-2)L^(2)s^(-1))(0.1molL^(-1))(0.2molL^(-1))^(2)=8xx10^(-9)MOLL^(-1)s^(-1)` When [A] is reduced from `0.10molL^(-1)" to "0.06molL^(-1)`, i.e., `0.04molL^(-1)` of A has reacted, B reacted `=(1)/(2)xx0.04molL^(-1)=0.02molL^(-1).` Hence, new `[B]=0.2-0.02=0.18molL^(-1).` Now,rate `=(2.0xx10^(-6)mol^(-2)L^(2)s^(-1))(0.06molL^(-1))(0.18molL^(-1))^(2)=3.89xx10^(-9)molL^(-1)s^(-1).` |
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| 18. |
For the reaction 2 HI hArr H_(2)+ I_(2) the equilibrium constant K at 440^(@)C is 0.022 . The equilibrium constant for I_(2) + H_(2) hArr 2 HI is |
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Answer» `45.45` |
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| 19. |
For the reaction 2 A (s) + B^(2+) (aq) to 2 A^(+) (aq) + B(s) , Nernst equation for the EMF of the cell is |
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Answer» `E = E^(@) - (RT)/(2F) "ln" ([A^(+)])/([B^(2+)])` |
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| 20. |
For the reaction, (1)/(2)A_(2)+(1)/(2)B_(2) to AB,DeltaH=-50 kcal If the bond energies of A_(2),B_(2) and AB are respectively x,(x)/(2) and x kcal, the value of x is |
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Answer» 50 |
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| 21. |
For the reaction2 A + B to A_(2) B, the rate law given is |
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Answer» `K[2A][B]` |
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| 22. |
For the reaction 2 A + B to 3 C + D which of the following does not express the reaction rate |
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Answer» `(d [D])/(DT)` |
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| 23. |
For the reactin uNO_((g))+Cl_(2(g))hArr2NOCl_((g)) which is true |
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Answer» <P>`K_(p)=K_(c)xxRT` `K_(p)=K_(c)(RT)^(Delta_(NG))` Given `Delta_(ng)=2-3=-1` Puttinvlaue of `Delta_(ng)` we GET `K_(p)=K_(c)(RT)^(-1)` or ` K_(p)(K_(c))/(RT).` |
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| 24. |
Forthe reactin C_((s))+CO_(2(g))hArr2CO_((g)), The partial pressure of CO_(2) and CO are 2.0 and 4.0 atm respectively at equlibrium. The K_(p) or the reaction is |
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Answer» `0.5` |
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| 25. |
For the reaction N_2+3H_2=2NH_3, triangleH=? |
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Answer» `triangleE=2RT` |
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| 26. |
For the reaaction, CO(g) +H_2O(g) |
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Answer» Increasing the pressure |
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| 27. |
For the rate of the reaction 2H_(2)O_(2)to2H_(2)O+O_(2),r=K[H_(2)O_(2)] it is |
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Answer» Zero order reaction |
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| 28. |
For the purpose of systematic qualitative analysis, cations are classified into various groups on the basisof their behaviour against some reagents. The group reagents used for the classification of most common cations are hydrochloric acid, hydrogen sulphide, ammonium hydroxide, and ammonium carbonate. Classification id based on wheather a certain reacts with these reagents by the formation of precipitates or not. To avoid the precipitation of hydroxides of Ni^(2+),Co^(2+),Mn^(2+) along with those of the third group cations, the solutions should be : |
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Answer» Heated with few drops of concentrated `HNO_3` |
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| 29. |
For the raction A+3Bto2C+D, which one of the following is not correct ? |
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Answer» Rate of DISAPPEARANCE of A = Rate of FORMATION of D |
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| 30. |
For the purpose of systematic qualitative analysis, cations are classified into various groups on the basisof their behaviour against some reagents. The group reagents used for the classification of most common cations are hydrochloric acid, hydrogen sulphide, ammonium hydroxide, and ammonium carbonate. Classification id based on wheather a certain reacts with these reagents by the formation of precipitates or not. An aqueous solution contains Hg^(2+),Hg_2^(2+),Pb^(2+) and Cd^(2+).The addition of 2 M HCl will precipitate : |
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Answer» `HgCl_2` only |
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| 31. |
For the production of equalamounts of hydrogen fromthe following reactions, which metal, An or Al,is less expensive if Zn costsabouthalf as much as Al an a mass basisand by how much ? {:(An + 2HCl to ZnCl_(2)+H_(2) ),(2Al+6HCl to2AlCl_(3)+3H_(2)):} |
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Answer» Solution :1 mole of `H_(2)` is produced by 1 mole, i.e., 65 g of Zn and 1 mole of `H_(2)`is produced by `(2)/(3)` mole, i.e., `(2 xx 27)/( 3)` g of AL = 18 g of Al Now that Zn costs about half as MUCHAS Al, to purchase Zn and Al to PRODUCE the same AMOUNT of `H_(2)` the costratio of Znand Al will be 65:36 Al is thus lessexpensive by `(65-36)/( 65) xx 100` ,i.e.,`44.61 %` |
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| 32. |
For the production of y L H_2 at STP at cathode, cost of electricity is x then cost of production of y LO_2 at STP at anode will be |
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Answer» X |
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| 33. |
For the process X(g)toproducts, (order ne 0), rates of disappearances of X at t = 0,t = 50sec & t = 30 sec respectively are p, q&r mol/lit/sec then |
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Answer» `pltqltr` |
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| 34. |
For the process, melting of ice at 260 K theDelta H is - |
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Answer» NEGATIVE |
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| 35. |
For the process, melting of ice at 260 K the DeltaH is - |
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Answer» Negative |
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| 36. |
For the process H_(2)O(l)rarrH_(2)O(g)at T=100^(@)C and 1 atmosphere pressure, the correct choice is |
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Answer» `DeltaS_("system")gt0and DeltaS_("surroundin gs")gt0` `therefore DeltaS_("system")gt0 and DeltaS_("surrounding")lt0`. |
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| 37. |
For the process H_(2)O(l) to H_(2)O(g) at T=100^(@)C and p=1 atm, the correct choice is |
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Answer» DeltaS_(sys)gt0"and"Delta_(SUR)gt0` |
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| 38. |
For the process H_(2)O(l) (1 bar, 373 K) rarr H_(2)O (1 bar, 373 K), the correct set of thermodynamic parameters is |
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Answer» `DeltaG=0, DeltaS=+ve` |
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| 39. |
For the process H_2O(l) (1 bar , 373 K)hArr H_2O(g) (1 bar , 373 K), the correct set of thermodynamic parameters is : |
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Answer» `DELTAG=0` `DELTAS` gt0 `DeltaH` gt 0 `DeltaG` gt 0 |
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| 40. |
For the process : H_(2)O(l) (1 bar, 373 K) rarr H_(2)O(g) (1 bar, 373 K), the correct set of thermodynamic parameter is : |
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Answer» `Delta G = 0, Delta S = + ve` |
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| 41. |
For the process H_(2)O(l) (1 bar, 373 K) to H_(2)O(g) (1 bar, 373 K), the correct set of thermodynamic parametes is |
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Answer» `DeltaG=0,DeltaS=+ve` |
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| 42. |
For the process: H_(2)O(1)(1"bar",373K)toH_(2)O(g)(1"bar",373K), the correct set of the thermodynamic parameters is |
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Answer» `DeltaG=0,DeltaS=+ve` |
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| 43. |
For the process dry ice rarr CO_(2)(g) |
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Answer» `DELTAH` is positivewhile `Deltarho` is NEGATIVE |
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| 44. |
For the process - CO_(2)(s)toCO_(2)(g) |
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Answer» Both `DeltaH and DELTAS` are POSITIVE |
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| 45. |
For the process : CO_(2)(s) rarr CO_(2)(g) |
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Answer» Both `DELTA H and Delta S` are +ve |
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| 46. |
For the process, CO_2(s)rarrCO_2(g): |
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Answer» Both `TRIANGLEH` and `TRIANGLES` are +ve |
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| 47. |
For the process 2A toproducts, rate of reaction w.r.t A at 10thsecond is 2xx10^(-2)M-s^(-1)then rates of same process at 5th & 15th seconds (order ne 0) respectively are (in M/s) |
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Answer» `10^(-4) & 4 XX 10^(-2)` |
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| 48. |
For the process, |
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Answer» The efficiency of the cyclic process `= 50%` |
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| 49. |
For the proces H_(2)O(l)toH_(2)O(g) at T=100^(@)C and 1 atomsphere pressure, the correct choice is : |
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Answer» `DeltaS_("system")gt0andDeltaS_("SURROUNDINGS")gt0` |
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