Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

consider the reaction 2A_(g) + B_(g) hArr 2C_(g) for which K_c = 350.if 0.001 mole of each of the reactant and product are mix in a 2.0 L flux in the reaction quotient and spontaneous direction of the system will be

Answer»

`Q_c `= 0.002, the EQUILIBRIUM shifts to the left
`Q_c` = 2000, the equilibrium shifts to the left
`Q_c` =0.002, the equilibrium shifts to right
`Q_c` = 2000, the equilibrium shifts to right

Answer :B
Discussion
2.

Consider the reaction 2Al (g) + 3Cl_(2) (g) rArr 2Al Cl_(3) (g). The approximate volume of chlorine that would react with 324 g of aluminium at STP is :

Answer»

112 L
134 L
260 L
403 L

Solution :324 g AL `-= (324)/(27) = 12mol Al -= (12 xx 3)/(2) mol Cl_(2) = 18mol Cl_(2) = -= 18 xx 22.4` It of `Cl_(2)`ats.T.P.= 403.2 lt
Discussion
3.

Consider the reaction 2A + B to C + D Following results was obtained in experiments designed to study the rate of reaction" a) Write the rate law for the reaction b) Calculate the value of rate constant for the reactio. c) Which of the following possible reaction mechanisms is consistent with the rate law found in (a) ? I. A + B to C + E (slow) A + E to D (fast) IIgt B to C+E (slow) A + E to F (fast) A + F to D (fast)

Answer»


Solution :The rate LAW may be expressed as:
Rate = `k[A]^(p)[b]^(q)`…………….(i)
`("Rate")_(1) = k[0.1]^(p)[0.10]^(q)=1.5 xx 10^(-3)`……………(i)
`("Rate")_(2)=k[0.20]^(p)[0.20]^(q)=3.0 xx 10^(-3)`………..(II)
`("Rate")_(3) = k[0.20]^(p)[0.40]^(q)=6.0 xx 10^(-3)`...............(iii)
Divide equation (iii) by (ii)
`(k[2.0]^(p)[0.20]^(q))/(k[0.10]^(p)[0.1]^(q)) = (6.0 xx 10^(-3))/(3.0 xx 10^(-3)) = 2`
`[2]^(q) =[2]^(1)` or q=1
Divide equation (ii) by (i)
`(k[0.20]^(p)[0.20]^(q))/(k[0.10]^(p)[0.1]^(q)) = (3.0 xx 10^(-3))/(1.5 xx 10^(-3))=2`
`[2]^(p)[2]^(q)=2` or `[2]^(p)[2]^(1)=2`
or `[2]^(b)[2]6(1) = [2]^(1)[2]^(0)` or p=0
Order w.r.t. p=0, Order w.r.t to q=1
a) Rate law for the reaction =`k[A]^(0)[B]^(1)`
b) Value of rate constant from expt. No. 1.
`k[0.10]^(0)[0.10]^(1) = 1.5 xx 10^(-3)` or k`=1.5 xx 10^(-2)`
c) SINCE the order of reaction is ONE, reaction mechanism (II) is in consistent with the rate law. In this, the rate determining steps is:
`B to C +E` (slow)
Discussion
4.

Consider the reaction2A + B to2C. Supposethat ataparticularmomentduringthereaction , rateof disappearanceof Ais 0.076 m//s (a) Whatis the rateofformationof C ? ( b )What is therateof consumptionof B ? (c) What is therateof thereaction ?

Answer»


Solution :GIVEN : `2A + B to 2C`
Rateof disappearanceof A= 0.076 `Ms^(-1)`
(a) Rateof FORMATIONOF C= ?
( b) Rate ofconsumptionof B = ?
(c ) Rateof reaction = ?
Rateof disappearanceof `A =(d[A])/(dt) = 0.076 Ms^(-1)`
(a) Rateof formationof `C= (d[C ])/(dt) = (d[A])/(dt)`
`=0.076 Ms^(-1)`
( b) Ratedisappearanceof `B= (d[B])/(dt) = - (1)/(2) (d[A])/(dt)`
`= (1)/(2) xx0.076 =0. 038Ms^(-1)`
( c) Rate OFREACTION`=- (1)/(2) .(d[A])/(dt) = (-d[B])/(dt) = (1)/(2) (d[C])/(dt)`
`=(1)/(2)(0.076)= 0.038= (1)/(2) xx 0.076`
`= 0.038 Ms^(-1)`
Discussion
5.

Consider the radioactive disintegration ""_(82)A^(210) to B to C to ""_(82)D^(206) The sequence of emission can be

Answer»

`BETA, beta, beta `
`alpha, alpha , beta`
`beta, beta, gamma`
`beta, beta, alpha`

SOLUTION :`""_(82)A^(210) overset(-beta)(rarr)""_(83)B^(210) overset(-beta)(rarr)""_(84)C^(210) overset(-alpha)(rarr)""_(82)D^(206)`.
Discussion
6.

Consider the reaction 1/2H_(2)(g)+AgCI(s)rarrH^(+)(aq)+CI^(-)(aq)+Ag(s) In which of the following galvanic ell the abvoe reaction occurs ?

Answer»

`AG|AgCI(s)|KCI(aq)||AgNO_(3)(Aq)|Ag(s)`
`Pt|H_(2)(g)|HCI(Aq)||AgNO_(3)(aq)||Ag(s)`
`Pt|H_(2)(g)|HCI(aq)||AgCI(s)||Ag(s)`
`Pt|H_(2)(g)|KCI(aq)||AgCI(s)||Ag(s)`

Solution :`H_(2)`UNDERGOES oxidation and `AgCI(ag^(+)`
undergoesreduction therefore cell MAYBE represent as
`Pt|H_(2)(g)|HCI(aq)||AgCI(s)||Ag(s)`
Discussion
7.

Consider the reaction 2A+B rarr C+D. If the rate expression is rate=K [A]^2 [B]^1 and if concentration of the reactants are increased by three times, the rate of the reaction will increase by:

Answer»

9 times
81 times
64 times
27 times

Answer :D
Discussion
8.

Consider the radii 0.095 nm (Na^+), 0.181 nm (CI^-), 0.074 nm (Zn^(2+)), 0.184 nm (S^(2-)) , 0.068 nm (Ti^(4+)), 0.140 nm (O^(2-)), 0.169 nm (Cs^+) . Choose the correct option from among the following. (Use radius ratio rules)

Answer»

`Na^+`ions are packed in octahedral HOLES between the PLANES of close-packed `Cl^-` ions
`Zn^(2+)`ions are packed in tetrahedral holes
`Cs^+`ions are packed in a simple cubic ARRAY of `Cl^-` ions
All of these

Solution :Calculate the `(r^+)/(r^-)`ratio to get the limiting ratio value and CONSULT the table. All are correct.
Discussion
9.

Consider the proposed mechanism for the destruction of ozone in the stratosphere O_3 + Cl to ClO +O_2 ClO + O_3 to Cl + 2 O_2 Which of the statements about the mechanism is/are correct

Answer»

CL is catalyst
`O_(2)` is in intermediate
Equal amounts of Cl and ClO are present at any TIME
The number of moles of `O_(2)` produced equals the number of moles of `O_(3)` consumed

SOLUTION :Cl ACTS a catalyst
`to` AMOUNT of Cl and ClO present at any time are equal.
Discussion
10.

Consider the proposed mechanism for the destruction of ozone in the stratosphere: O_(3) +Cl rarr ClO. +O_(2) ClO +O_(3) rarr Cl. +2O_(2) Which of the statements about this mechanism is correct?

Answer»

CL. Is a CATALYST
`O_(2)` is in intermediate.
Equal amounts of Cl. and CIO. Are present.
The number of moles fo `O_(2)` produced equals the number of moles of `O_(3)` consumed.

Answer :A
Discussion
11.

Consider the pathway of a well known organic reaction I and II are reacted with NaOH//Br_2 then in the solution which product exist.

Answer»




SOLUTION :RDS (Slow STEP) of HOFFMANN's bromide REACTION is unimolecular REARRAGEMENT of bromaide anion. There are no cross products in this reaction
Discussion
12.

Consider the partial decomposition of A as 2A(g)hArr2B(g)+C(g) At equilibrium 700 mL gaseous mixture contains 100 mL of gas Cat 10 atm and 300 K. What is the value of K_(p) for the reaction?

Answer»

`(40)/(7)`
`(1)/(28)`
`(10)/(28)`
`(28)/(10)`

Solution :`:.` Initially only A is PRESENT so at eqm. B and C should be present in 2:1
`underset("At eqm.")(2A(g))hArrunderset(400ML)(2B(g))+underset("200mL 10mL")(C(g))`
for IDEAL gases valume % -=mole %
`K_(p)=(((200)/(700)xx10)^(2)((100)/(700)xx10))/(((400)/(700)xx10)^(2))=(10)/(28)`
Discussion
13.

Consider the possible formation of an aldehyde or ketone product when each of the ten compounds in the column on the left is treated with each of the reagents shown in the top row . Check the designated answer box if you believe an aldehyde or ketone will be formed . Assume that the reagents may be present in excess . For each checked reaction , try to draw the structure of the major product (s) .

Answer»


SOLUTION :FORMATION of ALDEHYDES and KETONES
Discussion
14.

Consider the pairs of ethers A through F shown below. To the right of each pairs is a description of reaction conditions to be applied to each. One compound of the pair will react more rapidly than the other. Find out number of reactions in which first ether more rapidly cleaved than second.

Answer»


ANSWER :3BCF
Discussion
15.

Consider the oxy acids HClO_nseries here value of n is 1 to 4. then incorrect statement regarding these oxyacids Is:

Answer»

ACIDIC character of oxy acids increases with INCREASING value of n
Oxidising POWER of oxy acids increases with decreasing value of n
Thermal stability of oxy acids DECREASES with increasing value of n
`Cl-O` bond order decreases with decreasing value of n

Answer :C
Discussion
16.

Consider the order O^(2-) lt F^(+) lt Na^(+) lt Mg^(3+). Then correct statement(s) is/are :

Answer»

INCREASING order of `Z_(eff)`.
Increasaing order of size
Increasing order of I.E
Increasing order of E.A

Solution :Increasing order of size : `Mg^(2+) LT NA^(+ ) lt F^(-) lt O^(2-)`.
Discussion
17.

Consider thenitrogenatom is amines, whichon of the followingstatementis correct ?

Answer»

It is `SP^(3)`- hybridised
ITIS `sp^(2)` - hydridised
It is`sp^(3)`-hydridised
It is `sp^(2)` - hydridised

ANSWER :A
Discussion
18.

Consider the oxidation of nitric oxide to form NO_2 2NO_((g))+O_(2(g))rarr2NO_(2_((g)) (a) Express the rate of the reaction in terms of changes in the concentration of NO , O_2 and NO_2. (b) At a particular instant , when [O_2] is decreasing at 0.2 "mol L"^(-1)s^(-1) at what rate is [NO_2] increasing at that instant ?

Answer»

SOLUTION :(a) Rate `=-1/2(d[NO])/(dt)=(-d[O_2])/(dt)=1/2(d[NO_2])/(dt)`
(b)`(-d[O_2])/(dt)=1/2(d[NO_2])/(dt)`
`(d[NO_2])/(dt)=2XX(-d[O_2])/(dt)=2xx0.2" MOL L"^(-1)s^(-1) = 0.4 "mol L"^(-1)s^(-1)`
Discussion
19.

Consider the order of a reaction. Choose the incorrect statement(s).

Answer»

Order of a reaction may be zero, INTEGER or FRACTIONAL
Overall order of the reactio never be negative.
The order of an elementary step is ALWAYS equal to tis molecularity.
For the CHEMICAL EQUATION `N_(2)+3H_(2)to2NH_(3)` the order of reaction is 4.

Solution :Order Act=0,1,2,3,(-ve) or (+)ve (or)fractional
Discussion
20.

Consider the molecule Which reagent will not give a positve test with this compound?

Answer»

Cold conc.`H_(2)SO_(4)`<BR>`Br_(2)//C Cl_(4)`
NaOH(aq)
DILUTE `KMnO_(4)//H_(2)O`

Answer :c
Discussion
21.

Consider the isoelectric species Na^(+), Mg^(2+),F^(-) and O^(2-). The correct order of increasing length of their radii is

Answer»

`F^(-) LT O^(2-) lt MG^(2+) lt Na^(+)`
`Mg^(2+) lt Na^(+) lt F^(-) lt O^(2-)`
`O^(2-) lt F^(-) lt Na^(+) lt Mg^(2+)`
`O^(2-) lt F^(-) lt Mg^(2+) lt Na^(+)`

ANSWER :B
Discussion
22.

Consider the isoelectronic series : K^(+), S^(2-) , Cl^(-) and Ca^(2+), the radii of the ions decrease as

Answer»

`Ca^(2+) gt K^(+) gt CL^(-) gt S^(2-)`
`Cl^(-) gt S^(2-) gtK^(+) gt Ca^(2+)`
`S^(2-) gt Cl^(-) gt K^(+) gt Ca^(2+)`
`K^(+) gt Ca^(2+) gt S^(2-)gt Cl^(-)`

Solution :Amongest isoelectronic ions, ionic , radii of ANIONS is more than that of cations. Further size of the anion INCREASES with increases with INCREASE in -ve charge and size of cation decreases with increase +ve charge.
Discussion
23.

Consider the ions : S_(2)O_(3)^(2-)(X) and S_(2)O_(4)^(2-)(Y). How many statements are correct regarding (X) and (Y).(d stands for bond length) ,brgt (a) d_(s-s):X lt Y (b) d_(s-o): X lt Y ( c) Average oxidation state of S in (X) is less than that in (Y). (d) In both (X) and (Y), the central S atom is sp^(3) hybridised.

Answer»


Solution :`{:(""^(ϴ)O-underset(O)underset(||) OVERSET(S)overset(||)(S)-O^(ϴ),"" ^(ϴ)O-underset(..)overset(O)overset(||)(S)-underset(..)overset(O)overset(||)(S)-O^(ϴ)),(""(X),""(Y)),(" AvgO.S.= +2","Avg O.S.= +3"), (" "B.L.(S-S),""Y GT X):}`
`"B.L (S-O) Y (151 pm)" gt" X(147 pm)"`
Discussion
24.

Consider the ionic reaction : HC_(2)O_(4)^(-) +PO_(4)^(-3) hArr HPO_(4)^(2-) +C_(2) O_(4)^(2-) Identify the incorrect statement (s)

Answer»

The above equilibrium mixture can act as buffer (both acids have nearly the same dissociation constant )
`HC_2O_4^(-) and C_(2) O_(4)^(-2)` areconjugate acid - base pairs
The P - O bond order in `PO_(4)^(-3) ` is 1.75
The C - O bond order in `C_(2)O_(4)^(2-)` is 1.50

Solution :Buffer : Solution of WEAK acid and its SALT . Since both `HC_(2)O_(5)^(-) and HPO_(4)^(2-)` same dissociation constant the solution can act as buffer.
`underset("acid")(HC_(2)O_4^(-))+underset("base")(PO_4^(-3))hArrunderset("acid")underset("conjugate")(HPO_4^(2-))+underset("base")underset("conjugate")(C_2O_4^(2-))`

Bond order =` ("No of BONDS in any one resonating structure")/("Total no. of resonating structure")`
`B.O(PO_4^(3-))=5/4=1.25 , underset(("C-O bond"))(B.O(C_2O_4^(2-)))=3/2=1.5`
`:Nunderset(15e^(-))overset(...)(=)O:overset(e^(-))rarrunderset(14e^(-))(NO^(+))`
Discussion
25.

Consider the imaginary equilibrium 4A+5B hArr4X+6Y The equilibrium constant K_(c) has the unit

Answer»

`"MOLE"^(2)litre^(2)`
`"Litre mole"^(-1)`
`"Mole litre"^(-1)`
`"Litre"^(2)"mole"^(2)`

Solution :Unit of`K_(C)=("unit of concentration")^(DELTAN)="(""molelitre"^(-1)")"^(Deltan)`
`Deltan=10-9=1`
`thereforeK_(c)="mol Litre"^(-1).`
Discussion
26.

Consider the ground state of Cr atom (Z=24). The number of electrons with azimuthal quantum numbers,l=1 and 2 are respectively.

Answer»

16 and14
12 and 5
12 and 4
16 and 5

Solution :`Cr:1s^(2)2s^(2)2P^(6)3s^(2)3p^(6)3d^(5)4s^(1)`
No.of electrons `l=1` or `p(12), l=2` or `d(5)`
Discussion
27.

Consider the graph under question 8. Which of the following options does not show instaneous rate of reactiono at 40^(th) second?

Answer»

`(V_(5)-V_(2))/(50-30)`
`(V_(4)-V_(2))/(50-30)`
`(V_(3)-V_(2))/(40-30)`
`(V_(3)-V_(1))/(40-20)`

ANSWER :B
Discussion
28.

Consider the ground state of Cr atom (Z = 24 ). The number of electrons with the azimuthal quantum numbers l= 1 and 2 are respectively

Answer»

12 and 4
12 and 5
16 and 4
16 and 5

Solution :`""_(24)Cr=1s^(2)2s^(2)2p^(6)3S^(2)3P^(6)3d^(5)4s^(2)`
l = 1 means p-sub-shell and l = 2 means d-sub-shell.
l=1 is for `2p^(6)` and `3p^(6). Therefore` TOTAL electrons=12
l=2 is for `3d^(5). Therefore` Total electrons=5
Discussion
29.

Consider the graph given in question no. 8 . Which of the following options does not show instantaneous rate of reaction at 40th second.

Answer»

`(V_(5)-V_(2))/(50-30)`
`(V_(4)-V_(2))/(50-30)`
`(V_(3)-V_(2))/(40-30)`
`(V_(3)-V_(1))/(40-20)`

Answer :B
Discussion
30.

Consider the graph given in the above questions. Which of the following options does not show instanetaneous rate of reaction at 40 th second ?

Answer»

`(V_(5)-V_(2))/(50 - 30)`
`(V_(4)-V_(2))/(50 -30)`
`(V_(3)-V_(2))/(40 - 30)`
`(V_(3)-V_(1))/(40 - 20)`

Answer :B
Discussion
31.

Consider the given reaction : R-COOAg overset(Br_2//Delta)to R-Br Which one of the following acid will give maximum yield of R–Br in the above reaction:

Answer»

`CH_3-undersetunderset(CH_3)|CH-COOH`
`CH_3-CH_2-CH_2-COOH`
`CH_3-underset(CH_3)underset|oversetoverset(CH_3)|C-COOH`
All will GIVE same YIELD

ANSWER :B
Discussion
32.

Consider the graph given in Q.9Which of the following options does not show instantaneous rate of reaction at 40^(th) second?

Answer»

`(V_(5) - V_(2))/(50 -30)`
`(V_(4) - V_(2))/(50 - 30)`
`(V_(3) - V_(2))/(40 - 30)`
`(V_(3) - V_(1))/(40 - 20)`

SOLUTION :Instantaneous rate can be determind graphically by DRAWING a tangent on the curve.
Thus, volume change during 50-30 SEC. interval =
`V_(5) - V_(2)` and not `v_(4) - V_(2)` Hence, `(V_(4) - V_(2))/(50 - 30)` does not show
Instantaneous rate of reaction at `40^(th)` second.
Discussion
33.

Consider the graph given in Fig. in Q. 8. Which of the following options does not show instantaneous rate of reaction at 40th second ?

Answer»

`(V_(5)-V_(2))/(50-30)`
`(V_(4)-V_(2))/(50-30)`
`(V_(3)-V_(2))/(40-30)`
`(V_(3)-V_(1))/(40-20)`

Solution :Instantaneous rate at 40TH sec. will be change in volume during small interval of time close to 40 sec. VIZ. `40-30,50-40,50-30" or "40-20` sec. Volume change during `50-30` sec. interval `=V_(5)-V_(2)` and not `V_(4)-V_(2)`. Hence, (B) is not CORRECT.
Discussion
34.

Consider the given reaction sequence Theproduct C is

Answer»




Solution :`(NH_4)_2S` is USED for the partial REDUCTION of 1,3 - dinitro BENZENE
Discussion
35.

consider the given reaction, 3A(g) + B(g) hArr 2C(g) at a given temperature if a mixture of 2 mol each of A, B and C exist at equilibrium and K_c =9 then volume of the flask will be

Answer»

3L
6L
9L
36L

Answer :B
Discussion
36.

Consider the given figure showing the formation of H_(2)^(+) ion dependin on internuclear distance versus potential energy of the systemWhich is correct statement :

Answer»

Curve-1 REPRESENTS the most stable state of the system for `H_(2)^(+)`
Curve-2 represents the most stable state of the system for `H_(2)^(+)`
Curve-1 INDICATES that the MOLECULAR hydrogen ion is formed
Curve-2 represents the energy LEVEL of the antibonding region

Answer :B
Discussion
37.

Consider the given figure and mark the correct option.

Answer»

Activation energy of forward reaction is `E_(1) + E_(2)` and product is less stable than REACTANT.
Activation energy of forward reaction is `E_(1) + E_(2)` and product is more stable than reactant.

Activation energy of both forward and BACKWARD reaction is `E_(1) + E_(2)` and reactant is more stable than product.
Activation energy of backward reactioni is `E_(1)` and product is more stable than reactant.

Answer :A
Discussion
38.

Consider the given figure showing that possible levels of the energy of H_(2)^(+) ion depending on internuclear distance versus potential energy of the system. It may be easily assumed that the ground state of the molecular hydrogen ion H_(2)^(+) corresponds to the lowest level which means that

Answer»

curve 1 represents the most stasble STATE of the system for `H_(2)^(+)` ion
curve 2 represents the most stable state of the system of `H_(2)^(+)` ion
data is insufficient
None of these

Solution :Curve 2 represents the most stable state becausein this curve energy decreases as the atoms come CLOSE together and there is a minimum is thecurve where energy is minimum and HENCE stability is MAXIMUM.
Discussion
39.

Consider the gas-phase hydration of hexafluoroacetone, (CF_(3))_(2) CO : (CF_(3))_(2)CO(g) + H_(2)O (g) underset(k_(r))overset(k_(f))hArr(CF_(3))_(2)C(OH)_(2)(g) At 76° C, the forward and reverse rate constants are k_(f) = 0.13 M^(-1) s^(-1) and k_(r) = 6.02 x× 10^(-4) s^(-1). What is the value of the equilibrium constant K_(c) ?

Answer»


ANSWER :216
Discussion
40.

Consider the given compounds :(a)CH_(3)-CH_(2)-NH_(2)(b) CH_(3)-CH=NH (c ) CH_(3)-C=N(d) C_(2)H_(5)-NH-C_(2)H_(5) Arrange basicity of these compounds in decreasing order :

Answer»

`4 gt 1 gt 2 gt 3`
`1 gt 2 gt 3 gt 4`
`1 gt 4 gt 2 gt 3`
`4 gt 1 gt 3 gt 2`

ANSWER :A
Discussion
41.

Consider the Galvanic cell Zn|ZnSO_(4)||CuSO_(4)|Cu the reaction at cathode is

Answer»

`ZN^(2+)+2e^(-)toZn`
`CU^(2+)+2e^(-)toCu`
`Cu^(2+)+ZntoCu+Zn^(2+)`
`Zn^(2+)+CutoZn+Cu^(2+)`

Solution :
Discussion
42.

Consider the given compound.: Correct statements is/are regarding these compound:

Answer»

in structure (I), both MARKED H-atoms are on axial position.
In structure (II), both marked H-atoms are on axial position.
In structure (I), one H-atom is on axial position and other is on equatorial position.
in structure (II), one H-atom is on equatorial and other is one axial position.

Solution :(A). `1^(@)` AMINE EVOLVED `N_(2)` gas with `NaNO_(3)//HCl`
(B). Aromatic aldehyde does not give fehling solution TEST.
(C).
Gives IODOFORM test.
(D). Since carbon is not present in `H_(2)N-NH_(2)`. it does not gives lassigne's test.
Discussion
43.

Equilibrium constants K_1 and K_2 for the following equilibria (a) NO_((g)) + 1/2 O_(2(g)) hArr NO_(2(g)) (b) 2NO_(2(g)) hArr 2NO_((g)) + O_(2(g))are related as :

Answer»

`K_(2)=(1)/(K_(1))`
`K_(2)=(K_(1))/(2)`
`K_(2)=(1)/(K_(1)^(2))`
`K_(2)=K_(1)^(2)`

SOLUTION :`K_(1)=([NO_(2)])/([NO][O_(2)]^(1//2))`
and`K_(2)=([NO]^(2)[O_(2)])/([NO_(2)])=(1)/(K_(1)^(2))`
`THEREFORE K_(2)=(1)/(K_(1)^(2))`
Discussion
44.

Consider the galvanic cell : Pb(s)| Pb^(2+) (aq) (x_1 M)| | Cu^(2+)(aq) )x_2M) | Cu(s) E_("cell")= 0.48V which of the following graphs is correct ?

Answer»




ANSWER :B
Discussion
45.

Consider the followng changes: M(s) to M(g). . . (1) M(s) to M^(2+)(g) +2e^(-). . . (2) M(g)to M^(+)(g)+e^(-). . . (3) M^(+)(g) to M^(2+)(g)+e^(-) . .(4) M(g) to M^(2+)(g)+2e^(-) . . . (5) The second ionization energy of M could be calculated from the enrg values associated with:

Answer»

1+3+4
2-1+3
1+5
`5-3`

Solution :Drvonf IONIZATION ENERGY is amount of enegy required to take out an electron from the monopositive cation.
Hence, `M(G)to M^(2+)+2e^(-)` . . . (5)
`M(g)TOM^(+)+e^(-)`. . . (3)
Discussion
46.

Consider the followng compounds Which of the above compounds reacts with NaHCO_(3) given CO_(2).

Answer»

I,II and III
I and III
II and III
I and II
Discussion
47.

Consider the followinng reactions, ethanoloverset(PCl_(5))toXoverset("alc. KOH")to Y underset((ii)" "H_(2)O,heat)overset((i)" "H_(2)SO_(4)," room temperature")toZ The product Z is:

Answer»

`C_(2)H_(4)`
`CH_(3)CH_(2)OCH_(2)CH_(3)`
`CH_(3)CH_(2)OSO_(3)H`

Solution :`underset("ETHANOL")(CH_(3)CH_(2)OH)overset(PCl_(5))to underset((X))(CH_(3)CH_(2)Cl) underset(-HCL)overset("alc. KOH")to underset((Y))(CH_(2)=CH_(2)) underset((ii)" "H_(2)O,heat)overset((i)" "H_(2)SO_(4),r.t.)to underset(("Ethanol (Z)")(CH_(3)CH_(2)OH)`
Discussion
48.

Consider the following values of I.E.(eV) for elements W and X: {:("Element",I.E_(1),I.E_(2),I.E_(3),I.E_(4)),(W,10.5,15.5,24.9,79.8),(X,8,14.8,78.9,105.8):} Other two element Y and Z hav outer electronic configuration ns^(2)np^(4) and ns^(2)np^(5) respectively. then according to given information which of the following compound(s) is/are not possible?

Answer»

`W_(2)Y_(3)`
`X_(2)Y_(3)`
`WZ_(2)`
`XZ_(2)`

Answer :B::C
Discussion
49.

Consider the following vapour presure compositon graph. Hence.

Answer»

VAPOUR PRESSURE of A=SZ
vapour pressure of B=BY
vapour pressure of `B=SY`
vapour pressure of SOLUTION at `X=SZ+SY`

ANSWER :A::C::D
Discussion
50.

Consider the following vapour pressure composition graph. Hence,

Answer»

VAPOUR PRESSURE of A = SZ
vapour pressure of B= ZY
vapour pressure of B = SY
vapour pressure of solution at `X = SZ + SY`

ANSWER :A::C::D
Discussion