Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In Duma's method for the estimation of nitrogen 0.25 g of an organic compound gave fumes of nitrogen collected at 300 K temperature and 725 mm pressure, if the aqueous tension at 300 K is 25 mm the percentage of nitrogen in the compound is?

Answer»

In Duma's method for the estimation of nitrogen 0.25 g of an organic compound gave fumes of nitrogen collected at 300 K temperature and 725 mm pressure, if the aqueous tension at 300 K is 25 mm the percentage of nitrogen in the compound is?

2.

the correct set of quantum number for the unpaired electrons of F atom is

Answer» the correct set of quantum number for the unpaired electrons of F atom is
3.

The IUPAC name of CH3CH2O-CH2-CHOH-CH3 is:

Answer»

The IUPAC name of CH3CH2O-CH2-CHOH-CH3 is:


4.

√x +√y=4, then dy/dx at x=1 is given by

Answer» √x +√y=4, then dy/dx at x=1 is given by
5.

what is Claisen condensation reaction?

Answer» what is Claisen condensation reaction?
6.

The kinetic energy of an electron is 9.1×10−25 J. Calculate the de Broglie wavelength for the same.(Planck's constant,h=6.6×10−34 Js, mass of electron=9.1×10−31 kg)

Answer»

The kinetic energy of an electron is 9.1×1025 J. Calculate the de Broglie wavelength for the same.

(Planck's constant,h=6.6×1034 Js, mass of electron=9.1×1031 kg)

7.

16. What is the empirical formula of vanadiam oxide if 2.74 g of metal oxide contains 1.53 g of metal? A V2O3 B VO C V2O5 D V2O7

Answer» 16. What is the empirical formula of vanadiam oxide if 2.74 g of metal oxide contains 1.53 g of metal? A V2O3 B VO C V2O5 D V2O7
8.

To discover the relation between rules, paradigms, and normal science, consider first how the historian isolates the particular loci of commitment that have been described as accepted rules. Close historical investigation of a given specialty at a given time discloses a set of recurrent and quasi-standard illustrations of various theories in their conceptual, observational, and instrumental applications. These are the community’s paradigms, revealed in its textbooks, lectures, and laboratory exercises. By studying them and by practicing with them, the members of the corresponding community learn their trade. The historian, of course, will discover in addition a penumbral area occupied by achievements whose status is still in doubt, but the core of solved problems and techniques will usually be clear. Despite occasional ambiguities, the paradigms of a mature scientific community can be determined with relative ease. That demands a second step and one of a somewhat different kind. When undertaking it, the historian must compare the community’s paradigms with each other and with its current research reports. In doing so, his object is to discover what isolable elements, explicit or implicit, the members of that community may have abstracted from their more global paradigms and deploy it as rules in their research. Anyone who has attempted to describe or analyze the evolution of a particular scientific tradition will necessarily have sought accepted principles and rules of this sort. Almost certainly, he will have met with at least partial success. But, if his experience has been at all like my own, he will have found the search for rules both more difficult and less satisfying than the search for paradigms. Some of the generalizations he employs to describe the community’s shared beliefs will present more problems. Others, however, will seem a shade too strong. Phrased in just that way, or in any other way he can imagine, they would almost certainly have been rejected by some members of the group he studies. Nevertheless, if the coherence of the research tradition is to be understood in terms of rules, some specification of common ground in the corresponding area is needed. As a result, the search for a body of rules competent to constitute a given normal research tradition becomes a source of continual and deep frustration. Recognizing that frustration, however, makes it possible to diagnose its source. Scientists can agree that Newton, Lavoisier, Maxwell, or Einstein has produced an apparently permanent solution to a group of outstanding problems and still disagree, sometimes without being aware of it, about the particular abstract characteristics that make those solutions permanent. They can, that is, agree in their identification of a paradigm without agreeing on, or even attempting to produce, a full interpretation or rationalization of it. Lack of a standard interpretation or of a agreed reduction to rules will not prevent a paradigm from guiding research. Normal science can be determined in part by the direct inspection of paradigms, a process that is often aided by but does not depend upon the formulation of rules and assumption. Indeed, the existence of a paradigm need not even imply that any full set of rules exists. Q. What is the author attempting to illustrate through this passage?

Answer»

To discover the relation between rules, paradigms, and normal science, consider first how the historian isolates the particular loci of commitment that have been described as accepted rules. Close historical investigation of a given specialty at a given time discloses a set of recurrent and quasi-standard illustrations of various theories in their conceptual, observational, and instrumental applications. These are the community’s paradigms, revealed in its textbooks, lectures, and laboratory exercises. By studying them and by practicing with them, the members of the corresponding community learn their trade. The historian, of course, will discover in addition a penumbral area occupied by achievements whose status is still in doubt, but the core of solved problems and techniques will usually be clear. Despite occasional ambiguities, the paradigms of a mature scientific community can be determined with relative ease.

That demands a second step and one of a somewhat different kind. When undertaking it, the historian must compare the community’s paradigms with each other and with its current research reports. In doing so, his object is to discover what isolable elements, explicit or implicit, the members of that community may have abstracted from their more global paradigms and deploy it as rules in their research. Anyone who has attempted to describe or analyze the evolution of a particular scientific tradition will necessarily have sought accepted principles and rules of this sort. Almost certainly, he will have met with at least partial success. But, if his experience has been at all like my own, he will have found the search for rules both more difficult and less satisfying than the search for paradigms. Some of the generalizations he employs to describe the community’s shared beliefs will present more problems. Others, however, will seem a shade too strong. Phrased in just that way, or in any other way he can imagine, they would almost certainly have been rejected by some members of the group he studies. Nevertheless, if the coherence of the research tradition is to be understood in terms of rules, some specification of common ground in the corresponding area is needed. As a result, the search for a body of rules competent to constitute a given normal research tradition becomes a source of continual and deep frustration.

Recognizing that frustration, however, makes it possible to diagnose its source. Scientists can agree that Newton, Lavoisier, Maxwell, or Einstein has produced an apparently permanent solution to a group of outstanding problems and still disagree, sometimes without being aware of it, about the particular abstract characteristics that make those solutions permanent. They can, that is, agree in their identification of a paradigm without agreeing on, or even attempting to produce, a full interpretation or rationalization of it. Lack of a standard interpretation or of a agreed reduction to rules will not prevent a paradigm from guiding research. Normal science can be determined in part by the direct inspection of paradigms, a process that is often aided by but does not depend upon the formulation of rules and assumption. Indeed, the existence of a paradigm need not even imply that any full set of rules exists.

Q. What is the author attempting to illustrate through this passage?
9.

If A vector=2 i cap+3 j cap+4 k cap and B vector= i cap+j cap+k cap then mode of A vector-b vector is what?

Answer» If A vector=2 i cap+3 j cap+4 k cap and B vector= i cap+j cap+k cap then mode of A vector-b vector is what?
10.

The orbital angular momentum of an electron in 2s orbital is

Answer» The orbital angular momentum of an electron in 2s orbital is
11.

What is Carbocation?

Answer»

What is Carbocation?

12.

Which is has high solubility intermolecular hydrogen bonding or intermolecular hydrogen bonding?

Answer» Which is has high solubility intermolecular hydrogen bonding or intermolecular hydrogen bonding?
13.

For the homogeneous elementary reaction,ABC, the unit of rate constant is(2) s-1 mol L-1-1ST(3) s1 mo-1 L

Answer» For the homogeneous elementary reaction,ABC, the unit of rate constant is(2) s-1 mol L-1-1ST(3) s1 mo-1 L
14.

While one of the following dienes would you expect to be the most stable?

Answer» While one of the following dienes would you expect to be the most stable?
15.

A certain amount of current liberates 0.5 g of hydrogen in 2 hours. How many grams of copper can be produced by the same current flowing for the same time in copper sulphate solution?

Answer»

A certain amount of current liberates 0.5 g of hydrogen in 2 hours. How many grams of copper can be produced by the same current flowing for the same time in copper sulphate solution?


16.

22 Which of the following compound can't be oxidised by o3? (1) ki (2) kmno4 (3) k2 mno4. (4) feso4

Answer» 22 Which of the following compound can't be oxidised by o3? (1) ki (2) kmno4 (3) k2 mno4. (4) feso4
17.

Match the class of compounds given in Column I with their functions given in Column II Column IColum IIA. Antagonists1. Communicate message between two neurons and that between neuros to muscles.B. Agonists2. Bind to the receptor site and inhibit itsnatural function.C. Chemical messenger3. Crucial to body's communication process.D. Inhibitors4. Mimic the natural messenger.E. Receptors5. Inhibit activites enzymes.

Answer»

Match the class of compounds given in Column I with their functions given in Column II
Column IColum IIA. Antagonists1. Communicate message between two neurons and that between neuros to muscles.B. Agonists2. Bind to the receptor site and inhibit itsnatural function.C. Chemical messenger3. Crucial to body's communication process.D. Inhibitors4. Mimic the natural messenger.E. Receptors5. Inhibit activites enzymes.

18.

How to name tricyclic organic compounds?

Answer» How to name tricyclic organic compounds?
19.

Why are plastic buckets preferred over iron buckets?

Answer» Why are plastic buckets preferred over iron buckets?
20.

Gadolinium belongs to 4f series. Its atomic number is 64. Which of the following is the correct electronic configuration of gadolinium?

Answer»

Gadolinium belongs to 4f series. Its atomic number is 64. Which of the following is the correct electronic configuration of gadolinium?

21.

Which value value is more precise 1:05:40 P.M. or 1:20:49P.M. of true value is 1:00:00 P.M.?

Answer» Which value value is more precise 1:05:40 P.M. or 1:20:49P.M. of true value is 1:00:00 P.M.?
22.

Reaction of diborane with chlorine gives

Answer»

Reaction of diborane with chlorine gives


23.

The enthalpy of vapourisation of water from the following equations is: H2(g)+12O2(g)→H2O(l),△H=−286 kJ H2(g)+12O2(g),→H2O(g),△H=−245.5 kJ

Answer»

The enthalpy of vapourisation of water from the following equations is:
H2(g)+12O2(g)H2O(l),H=286 kJ
H2(g)+12O2(g),H2O(g),H=245.5 kJ

24.

1litre of 0.5N HCl solution is heated and reduced to 750ml. In the process 2.92 gm HCl is lost. Find normality of the solution formed

Answer» 1litre of 0.5N HCl solution is heated and reduced to 750ml. In the process 2.92 gm HCl is lost. Find normality of the solution formed
25.

37. If S+ O2-SO2; AH =-298.2 kJ>SO2 + 1/202 SOg, AH-98.7 kJSO3+ H20 H2SO4i AH =-130.2 kJH2+ 1/202 H20; AH -287.3 kJthen the enthalpy of formation of H2SO at 298 K is3'4(1) -814.4 kJ(2) -650.3 kJ(3) -320.5 kJ(4) -433.5 kJ

Answer» 37. If S+ O2-SO2; AH =-298.2 kJ>SO2 + 1/202 SOg, AH-98.7 kJSO3+ H20 H2SO4i AH =-130.2 kJH2+ 1/202 H20; AH -287.3 kJthen the enthalpy of formation of H2SO at 298 K is3'4(1) -814.4 kJ(2) -650.3 kJ(3) -320.5 kJ(4) -433.5 kJ
26.

what is bio\log ical evolution explain in detail

Answer» what is bio\log ical evolution explain in detail
27.

Ethanol boils at 78.4oC and the enthalpy of vaporisation of ethanol is 42.4 kJ mol−1 . What will be the entropy of vaporisation of ethanol:

Answer»

Ethanol boils at 78.4oC and the enthalpy of vaporisation of ethanol is 42.4 kJ mol1 . What will be the entropy of vaporisation of ethanol:

28.

37. P4 has how many electron pair

Answer» 37. P4 has how many electron pair
29.

3. One mole of magnesium in the vapour state absorbs 1200 k joule per mole of energy if the first and the second ionization energy of magnesium 750 and 1450k joule per mole respectively the final composition of the mixture is

Answer» 3. One mole of magnesium in the vapour state absorbs 1200 k joule per mole of energy if the first and the second ionization energy of magnesium 750 and 1450k joule per mole respectively the final composition of the mixture is
30.

a container of fixed volume has a mixture of 1 mole of hydrogen and 1 mole of helium in equilibrium at temperature T. the average energy per mole of the gas mixture is ?

Answer» a container of fixed volume has a mixture of 1 mole of hydrogen and 1 mole of helium in equilibrium at temperature T. the average energy per mole of the gas mixture is ?
31.

What volume of 1.10 M sodium formate solutionshould be to 50 mL of 0.05 M formic acid to produce a buffer solution of pH4.0? (pKa for formic acid is 3.80).

Answer»

What volume of 1.10 M sodium formate solution
should be to 50 mL of 0.05 M formic acid to produce a buffer solution of pH
4.0? (pKa for formic acid is 3.80).


32.

What will be the coordination number of Al in crystalline state of AlCl3? ___

Answer»

What will be the coordination number of Al in crystalline state of AlCl3? ___

33.

Thecorrect order of decreasing boiling points of CH3CONH2(A) CH3COCl (B) CH3COOH (C) and (CH3CO)2O(D) is:

Answer»

The
correct order of decreasing boiling points of CH3CONH2
(A) CH3COCl (B) CH3COOH (C) and (CH3CO)2O
(D) is:


34.

How many quantum numbers are required to specify the position of electron:- (1)1 (2)2 (3)3 (4)4

Answer» How many quantum numbers are required to specify the position of electron:- (1)1 (2)2 (3)3 (4)4
35.

7.Deferentiate between unsaturated and concentrated solution

Answer» 7.Deferentiate between unsaturated and concentrated solution
36.

Why does electron withdrawing group increases the acidity and releasing groups decrease the acidity of phenol?(proper and lucid explanation needed)

Answer» Why does electron withdrawing group increases the acidity and releasing groups decrease the acidity of phenol?(proper and lucid explanation needed)
37.

Two bodies of masses m and 4m are placed at a dis†an ce of r . Find the gravitational potential at a point on the line joining them where the gravitational field is zero

Answer» Two bodies of masses m and 4m are placed at a dis†an ce of r . Find the gravitational potential at a point on the line joining them where the gravitational field is zero
38.

What is the general formula for oxide of element M with atomic number 87?

Answer»

What is the general formula for oxide of element M with atomic number 87?

39.

What is Bronsted lowry theory? Explain

Answer» What is Bronsted lowry theory? Explain
40.

The correct order of acidic strength of the following :

Answer»

The correct order of acidic strength of the following :


41.

Sodium nitrate decomposes above −800oC to give (IIT-JEE, 1998)

Answer»

Sodium nitrate decomposes above 800oC to give
(IIT-JEE, 1998)

42.

The percentage degree of dissociation of water at 25oC is 1.9×10−7 and density is 1.0 g cm−3 The ionic constant for water is:

Answer»

The percentage degree of dissociation of water at 25oC is 1.9×107 and density is 1.0 g cm3 The ionic constant for water is:

43.

oxidation state of oxygen in HOF

Answer» oxidation state of oxygen in HOF
44.

Why is helium used in diving apparatus?

Answer»

Why is
helium used in diving apparatus?

45.

Which of the following reaction(s) are feasible?

Answer»

Which of the following reaction(s) are feasible?

46.

The reaction, CO(g) + 3H2(g)CH4(g) + H2O(g) is at equilibrium at 1300 K in a 1L flask. It also contain 0.30 mol of CO, 0.10 mol of H2 and 0.02 mol of H2O and an unknown amount of CH4 in the flask. Determine the concentration of CH4 in the mixture. The equilibrium constant, Kc for the reaction at the given temperature is 3.90.

Answer»

The reaction, CO(g) + 3H2(g)CH4(g) + H2O(g) is at equilibrium at 1300 K in a 1L flask. It also contain 0.30 mol of CO, 0.10 mol of H2 and 0.02 mol of H2O and an unknown amount of CH4 in the flask. Determine the concentration of CH4 in the mixture. The equilibrium constant, Kc for the reaction at the given temperature is 3.90.

47.

Considering the elements K,Ca,Rb and Cs, the correct order of their metallic character is:

Answer»

Considering the elements K,Ca,Rb and Cs, the correct order of their metallic character is:

48.

If 10 g of a molecule contains 1.505×1022 molecules what will be the molar mass of the molecule?

Answer»

If 10 g of a molecule contains 1.505×1022 molecules what will be the molar mass of the molecule?

49.

The right order of the solubility of sulphates alkaline earth metals is:

Answer»

The right order of the solubility of sulphates alkaline earth metals is:

50.

What is the volume ratio of the product gases obtained from the decomposition of phosphorous pentachloride?PCl5(g)→PCl3(g)+Cl2(g)

Answer»

What is the volume ratio of the product gases obtained from the decomposition of phosphorous pentachloride?

PCl5(g)PCl3(g)+Cl2(g)