The enthalpy of vapourisation of water from the following equations is – InterviewSolution

1.	The enthalpy of vapourisation of water from the following equations is: H2(g)+12O2(g)→H2O(l),△H=−286 kJ H2(g)+12O2(g),→H2O(g),△H=−245.5 kJ
Answer» The enthalpy of vapourisation of water from the following equations is: $H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l), △ H = - 286 kJ$ $H_{2} (g) + \frac{1}{2} O_{2} (g), \to H_{2} O (g), △ H = - 245.5 kJ$

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