This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
how to find atomic weight of an element? |
| Answer» how to find atomic weight of an element? | |
| 2. |
According to C.E.vanderwaal the interatomic piotential varies with the average interatomic dis†an ce (R) as a)R^{-2} b)R^- |
| Answer» According to C.E.vanderwaal the interatomic piotential varies with the average interatomic dis†an ce (R) as a)R^{-2} b)R^- | |
| 3. |
The enthalpy of neautralization of a weak monoprotic acid (HA) in 1M solution with a strong monoacidic base is −55.95 kJ/mol. If the unionized acid requires 1.4 kJ/mol heat for its complete ionization and enthalpy of neutralization of the strong monobasic acid with a strong monoacidic base is −57.3 kJ/mol. What is the percentage ionization of the weak acid in molar solution? (Put your answer upto two decimal points) |
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Answer» The enthalpy of neautralization of a weak monoprotic acid (HA) in 1M solution with a strong monoacidic base is −55.95 kJ/mol. If the unionized acid requires 1.4 kJ/mol heat for its complete ionization and enthalpy of neutralization of the strong monobasic acid with a strong monoacidic base is −57.3 kJ/mol. What is the percentage ionization of the weak acid in molar solution? (Put your answer upto two decimal points) |
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| 4. |
Pick the incorrect option about ionic bond. |
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Answer» Pick the incorrect option about ionic bond. |
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| 5. |
Y don't we get tertiary or secondary amines in reduction of nitrile?? |
| Answer» Y don't we get tertiary or secondary amines in reduction of nitrile?? | |
| 6. |
Which of the following relations is dimensionally incorrect? (A) 1 a.m.u =931.5MeV. (B). 1 a.m.u = 931.5MeV/c2 (C) 1 a.m.u = 1.67×10-27Kg. (D). None of these |
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Answer» Which of the following relations is dimensionally incorrect? (A) 1 a.m.u =931.5MeV. (B). 1 a.m.u = 931.5MeV/c2 (C) 1 a.m.u = 1.67×10-27Kg. (D). None of these |
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| 7. |
Explain how Newtown found r3/t2. |
| Answer» Explain how Newtown found r3/t2. | |
| 8. |
More will be the electron density,more will be the basic nature.Explain why?How the basic nature depends on electron density? |
| Answer» More will be the electron density,more will be the basic nature.Explain why?How the basic nature depends on electron density? | |
| 9. |
Ethane and benzene illustrate law of multiple proportion. How? |
| Answer» Ethane and benzene illustrate law of multiple proportion. How? | |
| 10. |
When lead storage battery is charged [MP PET 1993; MP PMT 2000] |
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Answer» When lead storage battery is charged [MP PET 1993; MP PMT 2000] |
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| 11. |
In the following reaction, which species acts as an oxidising agent? Fe2++2H++NO−3→Fe3++NO2+H2O |
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Answer» In the following reaction, which species acts as an oxidising agent? |
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| 12. |
3.No of possible structures of amines C7H9N having one benzene ring is A_5 B_3 c_4 d_6 |
| Answer» 3.No of possible structures of amines C7H9N having one benzene ring is A_5 B_3 c_4 d_6 | |
| 13. |
Alcohol and thiol functional groups are present in which of the following compounds? |
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Answer» Alcohol and thiol functional groups are present in which of the following compounds? |
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| 14. |
3-Phenyl propene on reaction with HBr gives (as a major product): |
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Answer» 3-Phenyl propene on reaction with HBr gives (as a major product): |
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| 15. |
does oxidation state mean the charge preset on atom when it is oxidised or reduced?? |
| Answer» does oxidation state mean the charge preset on atom when it is oxidised or reduced?? | |
| 16. |
The ionization constant of phenol is 1.0 ×10^{-10} what is the concentration phenolate ion in 0.05 M solution of phenol? What will be its degree of ionization of the solution is also 0.01 M in sodium phenolat |
| Answer» The ionization constant of phenol is 1.0 ×10^{-10} what is the concentration phenolate ion in 0.05 M solution of phenol? What will be its degree of ionization of the solution is also 0.01 M in sodium phenolat | |
| 17. |
which one of the following act only as a base1] h2s 2]hs^- 3] s^2- 4] h2o |
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Answer» which one of the following act only as a base 1] h2s 2]hs^- 3] s^2- 4] h2o |
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| 18. |
The curve showing the variation of adsorption with pressure at constant temperature is called: |
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Answer» The curve showing the variation of adsorption with pressure at constant temperature is called: |
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| 19. |
On mixing an alkane with chlorine and irradiating with ultraviolet light, it forms only one monochloro alkane. The alkane is |
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Answer» On mixing an alkane with chlorine and irradiating with ultraviolet light, it forms only one monochloro alkane. The alkane is |
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| 20. |
The resultant dipole moment of water is 1.85 D, Calculate the bond moment of OH bond (in D), bond angle in water molecule is 104o C. Given: cos 104o = -0.25 (Ignore the dipole moment due to lone pair) |
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Answer» The resultant dipole moment of water is 1.85 D, Calculate the bond moment of OH bond (in D), bond angle in water molecule is 104o C. Given: cos 104o = -0.25 (Ignore the dipole moment due to lone pair) |
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| 21. |
ph of a solution obtained by mixing 600 ml n/2 ch3cooh and 200 ml n/2 naoh |
| Answer» ph of a solution obtained by mixing 600 ml n/2 ch3cooh and 200 ml n/2 naoh | |
| 22. |
Which of the following is strongest Lewis base? |
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Answer» Which of the following is strongest Lewis base? |
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| 23. |
24. If the difference in atomic size of : Na - Li = x; Rb - K = y; Fr - Cs = z. Then correct order will be :- (1) x=y=z (2) x>y>z (3) x |
| Answer» 24. If the difference in atomic size of : Na - Li = x; Rb - K = y; Fr - Cs = z. Then correct order will be :- (1) x=y=z (2) x>y>z (3) x | |
| 24. |
Value of heat of fusion of NaCI is |
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Answer» Value of heat of fusion of NaCI is |
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| 25. |
What is a chemical reaction? |
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Answer» What is a chemical reaction? |
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| 26. |
30. What is the precipitate formed when 15ml of 16.9% of AgNO3 is mixed with 50ml of 5.8 % NaCl solution? 1) 7g 2)14g 3) 28g 4) 3.5g |
| Answer» 30. What is the precipitate formed when 15ml of 16.9% of AgNO3 is mixed with 50ml of 5.8 % NaCl solution? 1) 7g 2)14g 3) 28g 4) 3.5g | |
| 27. |
Which of the following is correct for a salt of weak acid and strong base? Here C is the concentration of the salt. |
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Answer» Which of the following is correct for a salt of weak acid and strong base? |
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| 28. |
During an adiabatic reversible change, the density becomes 116th of the initial value. Then find P1P2 is : (γ=1.5) |
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Answer» During an adiabatic reversible change, the density becomes 116th of the initial value. Then find P1P2 is : (γ=1.5) |
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| 29. |
ntAn aqueous solution have a density of 1.25 g/ml. If molecular weight of solute is 62.5 g/mol then calculate molarity of solution.n |
| Answer» ntAn aqueous solution have a density of 1.25 g/ml. If molecular weight of solute is 62.5 g/mol then calculate molarity of solution.n | |
| 30. |
The major product formed when methyl iodide reacts with sodium nitrite is |
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Answer» The major product formed when methyl iodide reacts with sodium nitrite is |
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| 31. |
Two moles of an ideal mono atomic gas undergoes compression from A to B as shown in the figure: If for the process AB, PT2 = constant Then the work done (in kcal) on the system for the process AB is |
Answer» Two moles of an ideal mono atomic gas undergoes compression from A to B as shown in the figure:![]() If for the process AB, PT2 = constant Then the work done (in kcal) on the system for the process AB is |
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| 32. |
Which one is the most reactive towards an electrophilic reagent? |
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Answer» Which one is the most reactive towards an electrophilic reagent? |
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| 33. |
3. Aromatic compounds can be halogenated using molecular halogen in the presence of an acid. Benzene when treated with molecular bromine in the presence of ferric chloride gives bromobenzene. Naphthalene undergoes bromination with bromine in acetic acid. The kinetics of this reaction is interesting. The kinetic expression involves a term that is second order in bromine for the reaction in glacial acetic acid, and first order in bromine for the reaction in 50% aqueous acetic acid. Naphthalene: Aluminium chloride is much more active Lewis acid than ferric chloride and the halogenations can be carried out using AlCl3. The bond energies of Al-Cl and Al-Br are 502 kJ mol1 and 430 kJ mol1, respectively. The correct statement(s) is/are (A) The reaction of benzene with bromine in the presence of AlCl3 gives a substantial amount of chlorobenzene. (B) The reaction of naphthalene with bromine in the presence of glacial acetic acid involves reaction of two molecules of bromine with one molecule of naphthalene, and no involvement of acetic acid, in the rate determining step. (C) The reaction of naphthalene with bromine in 50% aqueous acetic acid involves bromine and acetic acid in the rate determining step. (D) When 1-methylnaphthalene is reacted with bromine in the presence of a Lewis acid 4-bromo-1-methylnaphthalene is formed as the major product. |
| Answer» 3. Aromatic compounds can be halogenated using molecular halogen in the presence of an acid. Benzene when treated with molecular bromine in the presence of ferric chloride gives bromobenzene. Naphthalene undergoes bromination with bromine in acetic acid. The kinetics of this reaction is interesting. The kinetic expression involves a term that is second order in bromine for the reaction in glacial acetic acid, and first order in bromine for the reaction in 50% aqueous acetic acid. Naphthalene: Aluminium chloride is much more active Lewis acid than ferric chloride and the halogenations can be carried out using AlCl3. The bond energies of Al-Cl and Al-Br are 502 kJ mol1 and 430 kJ mol1, respectively. The correct statement(s) is/are (A) The reaction of benzene with bromine in the presence of AlCl3 gives a substantial amount of chlorobenzene. (B) The reaction of naphthalene with bromine in the presence of glacial acetic acid involves reaction of two molecules of bromine with one molecule of naphthalene, and no involvement of acetic acid, in the rate determining step. (C) The reaction of naphthalene with bromine in 50% aqueous acetic acid involves bromine and acetic acid in the rate determining step. (D) When 1-methylnaphthalene is reacted with bromine in the presence of a Lewis acid 4-bromo-1-methylnaphthalene is formed as the major product. | |
| 34. |
22. Why NaH2po2 is not amphiprotic ion |
| Answer» 22. Why NaH2po2 is not amphiprotic ion | |
| 35. |
Reaction of a carbonyl compound with one of the following reagents involves a nucleophilic addition followed by a dehydration. The reagent is: |
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Answer» Reaction of a carbonyl compound with one of the following reagents involves a nucleophilic addition followed by a dehydration. The reagent is: |
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| 36. |
what is rayleigh scattering ? |
| Answer» what is rayleigh scattering ? | |
| 37. |
ch3ch2cl reacts with kcn to form a ch3ch2nc b ch3ch2cn c c h3ch2nh2 d ch3ch2ch2nh2 |
| Answer» ch3ch2cl reacts with kcn to form a ch3ch2nc b ch3ch2cn c c h3ch2nh2 d ch3ch2ch2nh2 | |
| 38. |
Down cell costruction in Na extraction |
| Answer» Down cell costruction in Na extraction | |
| 39. |
2. Two half-reactions of an electrochemical cell are given below :MnO – 4 (aq) + 8H + (aq) + 5e – → Mn 2+ (aq) + 4H 2 O (I) , E° = 1.51 VSn 2+ (aq) → Sn 4+ (aq) + 2e – , E° = + 0.15 V.Construct the redox reaction equation from the two half-reactions and calculatethe cell potential from the standard potentials and predict if the reaction isreactant or product favoured. |
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Answer» 2. Two half-reactions of an electrochemical cell are given below : MnO – 4 (aq) + 8H + (aq) + 5e – → Mn 2+ (aq) + 4H 2 O (I) , E° = 1.51 V Sn 2+ (aq) → Sn 4+ (aq) + 2e – , E° = + 0.15 V. Construct the redox reaction equation from the two half-reactions and calculate the cell potential from the standard potentials and predict if the reaction is reactant or product favoured. |
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| 40. |
How one equivalent weight equals 1F? |
| Answer» How one equivalent weight equals 1F? | |
| 41. |
which of the following complexes is sigma as well as pi complexes ?a)Ni(CO)_4b){Fe_2{(CO)_9c)only 2d)both 1 and 2 |
| Answer» which of the following complexes is sigma as well as pi complexes ?a)Ni(CO)_4b){Fe_2{(CO)_9c)only 2d)both 1 and 2 | |
| 42. |
The number of atoms in 100 g of a FCC crystal with density d=10 g/cm3 and cell edge length equal to 100 pm, is equal to: |
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Answer» The number of atoms in 100 g of a FCC crystal with density d=10 g/cm3 and cell edge length equal to 100 pm, is equal to: |
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| 43. |
If the equilibrium consatnt for the reaction H+(aq)+OH−(aq)⇌H2O(l) at a certain temperature is 10−26, then what is the E0 for the reaction, 2H2O(l)+2e−⇌H2(g)+2OH−(aq)(Given: 2.303RTF=0.066) |
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Answer» If the equilibrium consatnt for the reaction H+(aq)+OH−(aq)⇌H2O(l) at a certain temperature is 10−26, then what is the E0 for the reaction, 2H2O(l)+2e−⇌H2(g)+2OH−(aq) |
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| 44. |
Whichof the following compounds would undergo aldol condensation, whichthe Cannizzaro reaction and which neither? Write the structures ofthe expected products of aldol condensation and Cannizzaro reaction.(i) Methanal (ii) 2-Methylpentanal(iii) Benzaldehyde (iv) Benzophenone(v) Cyclohexanone (vi) 1-Phenylpropanone(vii) Phenylacetaldehyde (viii) Butan-1-ol(ix) 2,2-Dimethylbutanal |
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Answer» Which (i) Methanal (iii) Benzaldehyde (iv) Benzophenone (v) Cyclohexanone (vi) 1-Phenylpropanone (vii) Phenylacetaldehyde (viii) Butan-1-ol (ix) 2, |
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| 45. |
Iron(111)hexacyaniodoferrate(11)How the Formula of this coordination compound is formed? |
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Answer» Iron(111)hexacyaniodoferrate(11) How the Formula of this coordination compound is formed? |
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| 46. |
Buna-s is a polymer of |
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Answer» Buna-s is a polymer of |
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| 47. |
Which of the following reactions gives a racemic mixture? |
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Answer» Which of the following reactions gives a racemic mixture? |
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| 48. |
Find the value of y.zx, if the following molecules undergo dimerization: I. ClO3 II. OF2 III. GaH3 IV. AlCl3 V. ICl3 VI. BeH2 VII. NO2 x: Number of molecules which are hypervalent in dimeric form y: Number of molecules with a complete octet in dimeric form z: Number of molecules which are hypovalent in dimeric form |
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Answer» Find the value of y.zx, if the following molecules undergo dimerization: I. ClO3 II. OF2 III. GaH3 IV. AlCl3 V. ICl3 VI. BeH2 VII. NO2 x: Number of molecules which are hypervalent in dimeric form y: Number of molecules with a complete octet in dimeric form z: Number of molecules which are hypovalent in dimeric form |
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| 49. |
3. pyridine is less basic than triethyl amine. A)pyridine has aromatic character. B)N in pyridine is sp2 hybridised C)in Pyridine lone pair of N is decolalised |
| Answer» 3. pyridine is less basic than triethyl amine. A)pyridine has aromatic character. B)N in pyridine is sp2 hybridised C)in Pyridine lone pair of N is decolalised | |
| 50. |
Pls provide me with the various equations of molality,normality,molarity,formality and it's application with definition |
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Answer» Pls provide me with the various equations of molality,normality,molarity,formality and it's application with definition |
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