During an adiabatic reversible change, the density becomes 116th of th – InterviewSolution

1.	During an adiabatic reversible change, the density becomes 116th of the initial value. Then find P1P2 is : (γ=1.5)
Answer» During an adiabatic reversible change, the density becomes $\frac{1}{16}$ th of the initial value. Then find $\frac{P_{1}}{P_{2}}$ is : $(γ = 1.5)$

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