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`(yz)^(log y - log z) xx (zx) ^(log z - log x) xx (xy) ^(log x - log y)` बराबर हैA. 2B. 1C. 4D. 3 |
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Answer» Correct Answer - B माना `k = (yz)^(log y - log z)` ` (zx)^(log z - log x )*(xy)^(log x - log y)` ` rArr log k = log (yz)^(log y - log z)` `+ log (zx) ^(log z - log x)+log (xy)^(log x - log y)` ` = (log y - log z) (log y + log z)` ` + (log z - log x) xx(log z + logx)` ` + (log x - log y) (log x + log y)` ` = (log y)^(2) - (log z)^(2) + log (z)^(2)` ` - (log x)^(2) + (log x)^(2) - (log y)^(2)` ` = 0 rArr log k =0 rArr k = 1` |
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