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यदि `F(x)=[{:(cosx,-sinx,0),(sinx,cosx,0),(0,0,1):}]` सिद्ध कीजिए कि `F(x)*F(y)=F(x+y)`. |
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Answer» `F(x)=[{:(cosx,-sinx,0),(sinx,cosx,0),(0,0,1):}]` `rArrF(y)=[{:(cosy,-siny,0),(siny,cosy,0),(0,0,1):}]` और `F(x+y)=[{:(cos(x+y),-sin(x+y),0),(sin(x+y),cos(x+y),0),(0,0,1):}]` अब ` L.H.S. =F(x)*F(y)` `=[{:(cosx,-sinx,0),(sinx,cosx,0),(0,0,1):}][{:(cosy,-siny,0),(siny,cosy,0),(0,0,1):}]` `[{:(cosxcosy-sinxsiny,),(sinxcosy+cosxsiny,),(" "0,),(-sinycosx-sinxcosy0,),(-sinxsiny+cosxcosy0,),(" "0" "1,):}]` `=[{:(cos(x+y),-sin(x+y),0),(sin(x+y),cos(x+y),0),(" "0," "0,1):}]` =F(x+y)=R.H.S. यही आज सिद्ध करना था । |
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