Which of these is the vibrational rate equation?(a) \(\frac {de_{vib}}{dt} = \frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)(b) τ = \(\frac {1}{k_{1, 0} (1 – e^{- hv/kT} )}\)(c) evib = τ(e\(_{vib}^{eq}\) – evib)(d) \(\frac {de_{vib}}{dt}\) = \(\frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)I had been asked this question in an online quiz.This intriguing question originated from Vibrational Rate Equations in division Properties of High Temperature Gases of Aerodynamics

Which of these is the vibrational rate equation?(a) \(\frac {de_{vib}}

1.	Which of these is the vibrational rate equation?(a) \(\frac {de_{vib}}{dt} = \frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)(b) τ = \(\frac {1}{k_{1, 0} (1 – e^{- hv/kT} )}\)(c) evib = τ(e\(_{vib}^{eq}\) – evib)(d) \(\frac {de_{vib}}{dt}\) = \(\frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)I had been asked this question in an online quiz.This intriguing question originated from Vibrational Rate Equations in division Properties of High Temperature Gases of Aerodynamics
Answer» Correct choice is (a) \(\frac {de_{VIB}}{dt} = \frac {1}{τ}\)(e\(_{vib}^{EQ}\) – evib) Best explanation: The vibrational rate equation gives a RELATION between evib which is the time rate change with the difference between the equilibrium and the local instantaneous NON – equilibrium value (e\(_{vib}^{eq}\) – evib). It is given by the following relation which is a differential equation: \(\frac {de_{vib}}{dt} = \frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)

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