Related InterviewSolutions

• Which of the statement are correct?A. Physical quantity represented by work in joule is `kg m^(2) s^(-2)`B. physical quantity represented by force in newton is `kg m^(2) S^(-1)`C. physical quantity represented by work in joule is `kg m s^(-2)`D. Physical quantity represented by fore in newton is `kg m^(2) s^(-2)`
• Whichof the statement are ture about the law of chemical combination?A. Potassium combines with two isotopes of chlorine `.^(35)Cl` and `.^(37)Cl`) to form two samples of `KCl`. Their formation follows the law of definite composition.B. Different proportion of oxygen in the varius oxidies of sulphur prove the law of multiple proportiens.C. `H_(2) O` and `H_(2)S` contains `11.11%` hydrogen and `5.88%` hydrogen, respectively, whereas `SO_(2)` contains 50% sulphur. The above data prove the law of reciprocal proportions.D. In the decomposition of `NH_(3), 2NH_(3) overset(Delta)rarr N_(2) + 3H_(2)`, the ratio of volumes of `NH_(3),N_(2)` and `H_(2)` is `2 : 1 : 3` The above data proves the Gay Lussac law.
• Which of the following pair of compounds illustrate the law of multiple proportions?A. `SO_(2)` and `SO_(3)`B. `NO_(2)` and `N_(2) O`C. `MgO` and `Mg(OH)_(2)`D. `NO` and `N_(2)O_(5)`
• Which of the following statements are correct?A. A sample of `CaCO_(3)` contains `Ca = 40%`, C = 12%`, and ``O = 48%`. If the law of constant compositon is true, then the mass of `Ca` in `10 g` `CaCO_(3)` from another source is `4.0 g`B. `12 g` of carbon is heated in vacuum and there is no change in the mass, is the best example of the law of conservation of mass.C. Air is heated at constant pressure and there is no change in mass but the increases, is the best example of the law of conservation of mass.D. `SO_(2)` gas was prepared by (i) heating `Cu` with cone `H_(2)SO_(4)` (ii) burning sulphur in oxygen, (iii) reacting observed that is each case, `S` and `O` combines in the ratio of 1:1. This data illustrates the law of constant composition.
• How many moles of electrons weigh `1 kg`?A. `6.023 xx 10^(23)`B. `(1)/(9.108) xx 10^(31)`C. `(6.023)/(9.108) xx 10^(54)`D. `(1)/(9.108 xx 6.023) xx 10^(8)`
• If 0.50 mol of `BaCl_(2)` is mixed with 0.20 mol of `Na_(3)PO_(4)`, the maximum number of moles of `Ba_(3)(PO_(4))_(2)` that can be formed isA. 0.7B. 0.5C. 0.2D. 0.1