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When Cu powder is heated with `CuCl_(2)` solution, the compound obtained isA. `Cu[CuCl_(4)]`B. `Cu_(2)[CuCl_(4)]`C. `Cu_(2)O`D. `Cu_(2)Cl_(2)` |
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Answer» Correct Answer - D Cu reduces `CuCl_(2)` to `Cu_(2)Cl_(2)` |
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