Related InterviewSolutions

• The axial length of 16 coils = axial length of each coil * 16.(a) true(b) falseThe question was posed to me at a job interview.I would like to ask this question from Overall Dimensions topic in portion Design of Transformers of Design of Electrical Machines
• What is the formula for number of turns/coil axially?(a) number of turns/coil axially = axial length / diameter of the insulated conductor(b) number of turns/coil axially = axial length * diameter of the insulated conductor(c) number of turns/coil axially = axial length – diameter of the insulated conductor(d) number of turns/coil axially = axial length + diameter of the insulated conductorThe question was posed to me during an interview.My doubt stems from Overall Dimensions in division Design of Transformers of Design of Electrical Machines
• What is the relation of the height of the window with the winding height with respect to the rectangular conductors?(a) winding height = 60% * window height(b) winding height = 50% * window height(c) winding height = 80% * window height(d) winding height = 70% * window heightI have been asked this question in exam.My question is taken from Overall Dimensions topic in division Design of Transformers of Design of Electrical Machines
• What is the range for the current density at HT side for a distribution transformer?(a) 2.4-3.5 Amp per mm^2(b) 2-2.5 Amp per mm^2(c) 1-3.5 Amp per mm^2(d) 2-3.5 Amp per mm^2I got this question by my school principal while I was bunking the class.My question is based upon Overall Dimensions topic in section Design of Transformers of Design of Electrical Machines
• What is the assumption for width of the largest stamping for the stepped core transformer?(a) 0.9*d(b) 0.71*d(c) 0.85*d(d) 0.8*dThe question was asked in an internship interview.My question is taken from Overall Dimensions in portion Design of Transformers of Design of Electrical Machines
• What is the formula for the inside diameter of the low voltage windings?(a) inside diameter = diameter of the circumscribing circle + pressboard thickness insulation between l.v winding and core(b) inside diameter = diameter of the circumscribing circle – pressboard thickness insulation between l.v winding and core(c) inside diameter = diameter of the circumscribing circle + 2*pressboard thickness insulation between l.v winding and core(d) inside diameter = diameter of the circumscribing circle – 2* pressboard thickness insulation between l.v winding and coreI have been asked this question in a national level competition.I'm obligated to ask this question of Overall Dimensions in division Design of Transformers of Design of Electrical Machines
• What is the formula for the window clearance of the transformer?(a) window clearance = (height of the window + axial depth)/2(b) window clearance = (height of the window – axial depth)(c) window clearance = (height of the window – axial depth)/2(d) window clearance = (height of the window + axial depth)I had been asked this question in homework.The doubt is from Overall Dimensions topic in portion Design of Transformers of Design of Electrical Machines
• What is the formula to calculate the radial depth of low voltage windings?(a) radial depth of the lv windings = number of layers * radial depth of the conductors * insulation between layers(b) radial depth of the lv windings = number of layers * radial depth of the conductors – insulation between layers(c) radial depth of the lv windings = number of layers / radial depth of the conductors + insulation between layers(d) radial depth of the lv windings = number of layers * radial depth of the conductors + insulation between layersI got this question during an interview.I would like to ask this question from Overall Dimensions topic in section Design of Transformers of Design of Electrical Machines
• What is the formula for axial depth of low voltage winding?(a) axial depth = number of secondary turns / width of the conductor(b) axial depth = number of secondary turns * width of the conductor(c) axial depth = number of secondary turns + width of the conductor(d) axial depth = number of secondary turns – width of the conductorThe question was posed to me during an interview for a job.Question is from Overall Dimensions topic in chapter Design of Transformers of Design of Electrical Machines
• What is the formula for the conductor dimensions in transformer?(a) conductor dimensions = conductor width * conductor thickness + 0.5 mm(b) conductor dimensions = conductor width / conductor thickness + 0.5 mm(c) conductor dimensions = conductor width + conductor thickness + 0.5 mm(d) conductor dimensions = conductor width – conductor thickness + 0.5 mmI have been asked this question by my school teacher while I was bunking the class.Question is taken from Overall Dimensions in division Design of Transformers of Design of Electrical Machines