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What is the equilibrium constant of the following reaction: 4NH3 + 5O2 → 4NO + 6H2O?(a) [NO][H2O]/[NH3][O2](b) [C]^c[D]^d/[A]^a[B]^b(c) [NO4[H2]^6/NH3]^4[O2]^5(d) [NO]^4[H2O]^6/[NH3]^4[O2]^5This question was posed to me in my homework.My question is from Law of Chemical Equilibrium and Equilibrium Constant topic in chapter Equilibrium of Chemistry – Class 11

Answer»

Correct answer is (d) [NO]^4[H2O]^6/[NH3]^4[O2]^5

The explanation is: the above GIVEN chemical reaction 4NH3 + 5O2 → 4NO + 6H2O is in the form of aA + BB → cC + DD. We KNOW that the equilibrium constant of this reaction is [C]^c[D]^d/[A]^a[B]^b, show the required answer is [NO]^4[H2O]^6/[NH3]^4[O2]^5.



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