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Two simple pendulum `A` and `B` of lengths `1.69m` and `1.44m` start swinging at the time from a location where acceleration due to gravity is `10ms^(-1)`. Answer the following question. After how much time, the two pendulums will be in phase again ?A. `5.5s`B. `10.0s`C. `12.6s`D. `15.5s` |
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Answer» Correct Answer - D `t=nT_(1)=6xx2pisqrt((1.69)/(10))=12xx(22)/(7)sqrt(169)/(1000)` `=12xx(22)/(7)xx(13sqrt(10))/(100)=12xx(22)/(7)xx(13xx3.162)/(100)` `=15.5s` |
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