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A body executed SHM of time period 6s. If its mass be 0.1kg, its velocity, 1s after it passes throuh mean position be `3ms^(-1)`, find its (i) KE (ii) PE and (iii) total energy. |
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Answer» Here, `T=6s,m=0.1kg, t=1s,` `v=3ms^(-1)` `v=Aomegacosomegat=A(2pi)/(T)cos(2pi)/(T)t` `3=Axx(2pi)/(6)cos((2pi)/(6)xx1)=Axx(2pi)/(6)xx(1)/(2)` `A=(18)/(pi)m` KE`=(1)/(2)mv^(2)=(1)/(2) xx0.1xx(3)^(2)=0*45J` `TE=(1)/(2)momega^(2)A^(2)=(1)/(2)m(4pi^(2))/(T^(2))xx(18^(2))/(pi^(2))` `=(1)/(2)xx0.1xx(4)/(6^(2))xx18^(2)=1*8J` `PE=TE-KE=1.8-0.45=1.35J` |
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