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Two simple harmonic motions act on a particle. These harmonic motions are `x=Acos (omegat+delta), y=Acos (omegat+alpha)` When `delta=alpha+(pi)/(20,` the resulting motion isA. an ellipse and the actual motion is counter clockwiseB. an ellipse and the actual motion is clockwiseC. a circle and the actual motion is counter clockwiseD. a circle and the actual motion is clockwise |
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Answer» Correct Answer - C `x=Acos(omegat+alpha+(pi)/(2))=-A sin (omegat+alpha)` `:. x^(2)+y^(2)=A^(2)[sin^(2)(omegat+alpha)+cos^(2)(omegat+alpha)]=A^(2)` which is an equation of a circle. Since y is `+ve` and `x` is `-ve` , so the circular motion is couter clockwise. |
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