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Two pendulums of time period 3 s and 8 s respectively starts oscillating simultaneously from two oppositee extreme positions. After how much time they will be in the same phase ?A. `(24)/(5)s`B. `(12)/(5)s`C. `(24)/(11)s`D. `(12)/(11)s` |
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Answer» Correct Answer - B `y_(1)=Asin (omega_(1)t+pi//2)` and `y_(2)=A sin (omega^(2)t-pi//2)` When, `omega_(1)t+pi//2=omega_(2)t-pi//2` then `t=(pi)/(omega_(2)-omega_(1))=(pi)/((2pi//T_(2))-(2pi//T_(1)))=(T_(1)T_(2))/(2(T_(1)-T_(2)))` `=(8xx3)/(2(8-3))=(24)/(10)=(12)/(5)s` |
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