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Three `10 Omega , 2 W` resistors are connected as in Fig. `7.34`. The maximum possible voltage between points `A and B` without exceeding the power dissipation limits of any of the resistors is A. `5 sqrt(3) V`B. `3 sqrt(5) V`C. `15 V`D. ` (5)/(3) V` |
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Answer» Correct Answer - B Power `= (V^(2))/( R )` or `V = sqrt(PR) = sqrt(2 xx 10) = sqrt(20) = 2sqrt(5) V` Clearly, voltage across single resistor of `10 Omega` cannnot exceed `2 sqrt(5) V`. Note that the resistance of parallel combination is half of `10 Omega` . Thus, the maximum possible voltage between `A and B` is `3 sqrt(5) V`. |
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