Related InterviewSolutions

• The value of tan2 60° is :(A) 3(B) 1/3(C) 1(D) ∞
• The value of cos2 = 45° is :(A) 1/√2(B) √3/2(C) 1/2(D) 1/√3
• If cosecθ = 2/√3 then value of θ is(A) π/4(B) π/3(C) π/2(D) π/6
• If sec θ = √2, then value of θ will be :(A) π/8(B) π/6(C) π/4(D) π/3
• It tan θ = 1, then cos θ will be :(A) 1(B) 1/2(C) √3/2(D) 1/√2
• If tan 3x = sin 45° cos 45° + sin 30°, then find value of x.
• Given sin α = 1/2 and cos β = 1/2, then  value of (α + β) is :(A) 0°(B) 30°(C) 60°(D) 90° 
• If sin θ = cos θ (θ = acute angle), then value of θ will be ;(A) 30°(B) 45°(C) 60°(D) 75°
• Show that \(\frac{1}{1+cos(90° -θ)}+\frac1{1-cos(90° – θ)}\) = 2 cosec2 (90° – θ)
• The value of sin 0° + cos 30° – tan 45° + cosec 60° + cot 90° is equal to(a) \(\frac{5\sqrt3-6}{6}\)(b) \(\frac{-6+7\sqrt3}{6}\)(c) 0 (d) 2