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The slope of the normal to the curve `y=2x^2+3`sin x at `x = 0`is(A) 3 (B) `1/3` (C)`-3` (D) `-1/3`A. 3B. `1/3`C. `-3`D. `-1/3` |
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Answer» Correct Answer - D Equation of curve `y = 2x^(2) + 3 sin x` ` rArr (dy)/(dx) = 4x + 3 cos x` slope of tangent at `x=0 is 0+3=3` ` rArr "at "x=0," slope of normal "=-1/3` |
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