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The sides of an equilateral triangle are increasing atthe rate of 2 cm/sec. Find the rate at which the area increases, when theside is 10 cm. |
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Answer» Correct Answer - `10 sqrt3 cm^(2)//s` `A = (sqrt3)/(4) a^(2) rArr (dA)/(da) = (sqrt3)/(2) a rArr (dA)/(dt).(dt)/(da) = (sqrt3)/(2) a` `rArr (dA)/(dt) xx (1)/(2) = (sqrt3)/(2) a rArr (dA)/(dt) = sqrt3 a rArr [(dA)/(dt)]_(a = 10) = sqrt3 xx 10 cm^(2)` |
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