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The pressue of air in the bulb of a constant volume gas thermometer of `0^0 C` and `100^0 C` are `73.00cm and 100cm` of mercury respectively.Calculate the pressure at the room temperature `20^0 C`. |
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Answer» `t= (P_1 - P_0)/P_100 - P_0) xx 10^0 C`. Thus `20^0 C= (P_i - 73.00 cm of Hg)/(100cm of Hg - 73.00cm of Hg) xx 10^0 C` or, `P_t = 78.4cm` of mercury. |
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