Related InterviewSolutions

• In the following reaction `3Br_(2)+6CO_(3)^(2-)+3H_(2)O=5Br^(-)+BrO_(3)^(-)+6HCO_(3)^(-)`A. bromine is oxidised carbonate is reduced,B. bromine is reduced, carbonate is oxidisedC. bromine in neither reduced nor oxidisedD. bromine is reduced as well as oxidised
• Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be `-4,-2 0,+2,-1` etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as `"Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C)` Where, `n_(H), n_(O) and n_(C)` are number of respective atoms Which of the following oxides of carbon has fractional oxidation state?A. Carbon monoxideB. Carbon dioxideC. Carbon suboxideD. All of these
• Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be `-4,-2 0,+2,-1` etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as `"Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C)` Where, `n_(H), n_(O) and n_(C)` are number of respective atoms Which of the following compounds have zero oxidation state at carbonA. `C_(6)H_(12)O_(6)`B. `HCOOH`C. HCHOD. `CH_(4)`
• The valancy of carbons is generally `4`, but its oxidation state may be `-4, -2, 0, +2, -1`, etc. In the compounds containing `C, H`, and `O`, the oxidation number of `C` is calculated as Oxidation number of `C= (2n_(O)-n_(H))/(n_(C ))` Where `n_(O), n_(H)` and `n_(C )` are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. In which of the following compounds is the oxidation state of carbon is zero?A. `CH_(4)`B. `CH_(3)OH`C. `CH_(2)O`D. HCOOH
• In which of the following pairs. the oxidation states, of sulphuric and chromium are same?A. `SO_(3)^(2-),CrO_(4)^(2-)`B. `SO_(3),CrO_(4)^(2-)`C. `SO_(2),CrO_(4)^(2-)`D. `SO_(2),Cr_(2)O_(7)^(2-)`
• Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be `-4,-2 0,+2,-1` etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as `"Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C)` Where, `n_(H), n_(O) and n_(C)` are number of respective atoms In which of the following compounds, the valency of carbon is two?A. CarbenesB. AllenesC. AlkenesD. Ketenes
• The oxidation state of chromium in chromoium trioxide is:A. `+3`B. `+4`C. `+5`D. `+6`
• In that compounds `KMnO_(4) and K_(2)Cr_(2)O_(7)` the highest oxidation state the element:A. potassiumB. chromiumC. oxygenD. maganse
• Nitrogen forms a variety of compounds in all oxidation states ranging from:A. `-3 "to"+5`B. `-3 "to"+3`C. `-3 "to"+4`D. `-3 "to"+6`
• When `SO_(2)` is passed through acidic solution of potassium dichromate, then chromium sulphate is formed. Change in valency of chronium isA. `+4 "to" +2`B. `+6"to"+3`C. `+7"to"+2`D. `+5"to"+3`