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The normal at the point (1,1) on the curve `2y+x^2=3`is(A) `x + y = 0` (B) `x y = 0` (C) `x + y +1 = 0`(D) `x y = 0`A. x+y=0B. x-y= 0C. x+y+1=0D. x-y=1 |
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Answer» Correct Answer - B Given curve, ` 2y+x^(2)=3` ` rArr 2(dy)/(dx) + 2x - 0 rArr (dy)/(dx) - " "-x` `:. ` slope of tangent at point (1, 1) =- 1 ` rArr" slope of normal at "(1, 1) = (-1)/(((dy)/(dx))_(1, 1)) = (-1)/(-1) = 1` ` :. " equation of normal at "(1, 1) y-1=1*(x-1)` ` rArr x-y=0` |
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