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The maximum acceleration of a simple harmonic oscillatore is `a_(0)` and maximum velocity is `v_(0)`. What is the displacement amplitude? |
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Answer» Let A be the amplitude and `omega` be the angular frequency of SHM. Then Maximum velocity, `v_(0)=omegaA or omega=v_(0)//A` Maximum acceleration, `a_(0)=omega^(2)A=(v_(0)^(2))/(A^(2))A=(v_(0)^(2))/(A)` `:.` Amplitude `A=(v_(0)^(2))/(a_(0))` |
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