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The equation of the normal to the curve `y=sqrt(x-3)`, which is parallel to the curve `6x+3y-4=0` areA. 2x+y+9=0, 2x+y+7=0B. 2x-y+9=0, 2x+y+7=0C. 2x+y-9=0, 2x+y-7=0D. 2x-y-9=0, 2x+y-7=0 |
| Answer» Correct Answer - C | |