Related InterviewSolutions

• A pendulum  of length 1m  is released  from theta =60 degree . The rate of change of speed  of the bob at  theta = 30 degree is
• The equation  of shm  y= asin (2pi Nt  + â) . Calculate  the phase of the given equation  at time =t
• The two particle  are oscillating along two close  parallel straight line in opposite  direction towards the mean position The time taken by the particle  X=0 to x=A/2 is T/12 and x=A to x=A/2 is T/6. Then calculate the time difference.Ans-T/3