Saved Bookmarks
| 1. |
The equation of a simple harmonic wave is given by`y = 3 sin"(pi)/(2) (50t - x)` where `x` and `y` are in meters and `x` is in second .The ratio of maximum particle velocity to the wave velocity isA. `2pi`B. `(3)/(2)pi`C. `3pi`D. `(2)/(3)pi` |
|
Answer» Correct Answer - B The given equation is `y=rsin((2pit)/(T)-(2pix)/(lambda))` `(2pi)/(T)=25pi` or `T=(2)/(25)s` and `(2pi)/(lambda)=(pi)/(2) ` or `lambda=4m` Wave velocity, `upsilon=(lambda)/(T)=(4)/(2//25)=50m//s` Particle velocity, `(dy)/(dt)==3cos(25pit-(pix)/(2))xx25pi` Max. particle velocity `=((dy)/(dt))_(max)=75pi` Now, `((dy//dt)_(max))/(upsilon)=(75pi)/(50)=(3)/(2)pi` |
|