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The eccentricity of the ellipse `3x^2+4y^2=12` is decreasing at the rate of 0.1 per sec.The time at which it will coincide with auxiliary circle is:A. 2 secondsB. 3 secondsC. 5 secondsD. 6 seconds |
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Answer» Correct Answer - C Eccentricity of ellipse `=(1)/(2)` `(de)/(dt)=-0.1" (given)"` Eccentricity of auxiliary circle = 0 `rArr" "int_(1//2)^(0)de=-0.1 int_(0)^(T)dt` T is time at which it will touch the auxiliary circle. `rArr" "-(1)/(2)=-0.1 (T-0)" "thereforeT=5 " seconds."` |
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