1.

The distance between two consecutive nodes in a stationary wave is 25cm. If the speed of the wave is `250ms^(-1)`, calculate the frequency.

Answer» Distance between two consecutive nodes is
`(lambda)/(2)=25cm=0.25m,`
`lambda=2xx0.25m =0.5m`
`v=(upsilon)/(lambda)=(2500)/(0.5)=500Hz`


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