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The distance between two consecutive nodes in a stationary wave is 25cm. If the speed of the wave is `250ms^(-1)`, calculate the frequency. |
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Answer» Distance between two consecutive nodes is `(lambda)/(2)=25cm=0.25m,` `lambda=2xx0.25m =0.5m` `v=(upsilon)/(lambda)=(2500)/(0.5)=500Hz` |
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